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Oct 20, 2017 at 0:18 comment added FrownyFrog 23 b.&32&.(3&u:)
Oct 20, 2017 at 0:12 comment added FrownyFrog (32(23)b.])&.(3&u:), should be 5 bytes shorter.
Oct 6, 2013 at 16:57 comment added Dan Bron Cool. But your Befunge solution still has J beat by 4 characters. Obviously I can't let that stand :) I'm trying to see if trim the J solution down by following your lead in relying solely on '@', rather than both '@' and 'Z'.
Oct 6, 2013 at 16:49 comment added FireFly Ah, I've played around some with J myself.. I managed to come up with u:(a.i.x)+32*1='@Z'I.x=.1!:1]1, which matches your length but is much less interesting (as it doesn't make use of 'under'). Speaking of which, I didn't know about dyadic I., so thanks for using that. :-)
Oct 6, 2013 at 16:45 comment added Dan Bron Nice catch, thanks. I'm also impressed you were able to fix the code yourself: J isn't the most immediately-accessible language out there :)
Oct 6, 2013 at 16:43 history edited Dan Bron CC BY-SA 3.0
fix: UPPER->lower instead of lower->UPPER (thanks to Firefly for catch & correction).
Oct 6, 2013 at 16:33 comment added FireFly Nice! Unfortunately, it seems your solution is going the WRONG WAY. ;-) Should be an easy fix though. (Edit: '@Z'(]+32*1=I.)&.(a.&i.)1!:1]1 should do it)
Oct 6, 2013 at 16:32 review First posts
Oct 7, 2013 at 11:24
Oct 6, 2013 at 16:14 history answered Dan Bron CC BY-SA 3.0