Timeline for How much do I have to write?
Current License: CC BY-SA 3.0
14 events
| when toggle format | what | by | license | comment | |
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| Mar 16, 2017 at 22:22 | history | edited | micsthepick | CC BY-SA 3.0 |
64 bytes!
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| Mar 16, 2017 at 22:09 | history | edited | micsthepick | CC BY-SA 3.0 |
added 71 byte version
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| Mar 16, 2017 at 13:40 | comment | added | Felipe Nardi Batista |
lambda x:sum(map(len,map(str,(range(x+1)if x>0 else range(0,x-1,-1))))) for 71 bytes
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| Mar 11, 2017 at 6:04 | history | edited | micsthepick | CC BY-SA 3.0 |
fixed some arithmetic
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| S Mar 10, 2017 at 7:46 | history | suggested | numbermaniac | CC BY-SA 3.0 |
added TIO links
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| Mar 10, 2017 at 7:16 | review | Suggested edits | |||
| S Mar 10, 2017 at 7:46 | |||||
| Mar 10, 2017 at 6:27 | history | edited | micsthepick | CC BY-SA 3.0 |
added my own version
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| Mar 10, 2017 at 6:21 | history | edited | micsthepick | CC BY-SA 3.0 |
78-char version
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| Mar 10, 2017 at 6:16 | history | edited | micsthepick | CC BY-SA 3.0 |
added 3 characters in body
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| Mar 10, 2017 at 6:14 | comment | added | micsthepick |
@numbermaniac here is an equivalent: print sum(map(len,map(str,(range(x+1)if x>0 else range(0,x-1,-1)))))
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| Mar 10, 2017 at 6:12 | comment | added | micsthepick | @numbermaniac can I do something similar this way? | |
| Mar 10, 2017 at 6:09 | history | edited | micsthepick | CC BY-SA 3.0 |
sum instead of ''.join()
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| Mar 10, 2017 at 6:07 | comment | added | numbermaniac |
You can use map on the second line for 78 bytes: print len(''.join(map(str,(range(x+1)if x>0 else range(0,x-1,-1))))). You might save even more by making it a lambda.
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| Mar 10, 2017 at 5:57 | history | answered | micsthepick | CC BY-SA 3.0 |