#Answer 5 - SOGL 0.8.2, 9 b∫I:b;?t"Gw~) %n=int(input()) %i=1 %div=[] %while (i<=n): % if n % i == 0: % div.append(i) % i+=1 %print(div)Rḍ⁸T”

Explanation:

b∫              repeat input times                [0]
  I             increment (the loop is 0-based)   [1]
   :b           duplicate                         [1, 1]
     ;          put the input one under the stack [1, 114, 1]
      \?        if divides                        [1, 1]
        t        output                           [1, 1]
         "...”   push that long string            [1, 1, "Gw\~...Rḍ⁸T"]

Note: the interpreter currently needs the \ns be replaced with ¶ in order to not count it as input, but the parser itself considers both interchangable.

Answer 5 - SOGL 0.8.2, 9

b∫I:b;\?t"Gw\~)
%n=int(input())
%i=1
%div=[]
%while (i<=n):
%    if n % i == 0:
%        div.append(i)
%    i+=1
%print(div)Rḍ⁸T”

Explanation:

b∫              repeat input times                [0]
  I             increment (the loop is 0-based)   [1]
   :b           duplicate                         [1, 1]
     ;          put the input one under the stack [1, 114, 1]
      \?        if divides                        [1, 1]
        t        output                           [1, 1]
         "...”   push that long string            [1, 1, "Gw\~...Rḍ⁸T"]

Note: the interpreter currently needs the \ns be replaced with ¶ in order to not count it as input, but the parser itself considers both interchangable.

#Answer 5 - SOGL 0.8.2, 9 b∫I:b;?t"Gw~)¶%n=int(input())¶%i=1¶%div=[]¶%while (i<=n):¶% if n % i == 0:¶% div.append(i)¶% i+=1¶%print(div)Rḍ⁸T”

#Answer 5 - SOGL 0.8.2, 9 b∫I:b;?t"Gw~) %n=int(input()) %i=1 %div=[] %while (i<=n): % if n % i == 0: % div.append(i) % i+=1 %print(div)Rḍ⁸T”

Explanation:

b∫              repeat input times                [0]
  I             increment (the loop is 0-based)   [1]
   :b           duplicate                         [1, 1]
     ;          put the input one under the stack [1, 114, 1]
      \?        if divides                        [1, 1]
        t        output                           [1, 1]
         "...”   push that long string            [1, 1, "Gw\~...Rḍ⁸T"]

Note: the interpreter currently needs the \ns be replaced with ¶ in order to not count it as input, but the parser itself considers both interchangable.