Commonmark migration

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edited Jun 17, 2020 at 9:04

#C, 68 bytes

C, 68 bytes

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010");}

Somehow, this is the shortest C answer so far…

EDIT: I was missing 1000 somehow. Well, it’s still winning.

#C, 68 bytes

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010");}

Somehow, this is the shortest C answer so far…

EDIT: I was missing 1000 somehow. Well, it’s still winning.

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010");}

Somehow, this is the shortest C answer so far…

EDIT: I was missing 1000 somehow. Well, it’s still winning.

added 70 characters in body

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edited Mar 13, 2017 at 19:46

#C, 6368 bytes

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010");}

Somehow, this is the shortest C answer so far…

EDIT: I was missing 1000 somehow. Well, it’s still winning.

#C, 63 bytes

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1001 1010");}

Somehow, this is the shortest C answer so far…

#C, 68 bytes

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010");}

Somehow, this is the shortest C answer so far…

EDIT: I was missing 1000 somehow. Well, it’s still winning.

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created Feb 28, 2017 at 21:32

#C, 63 bytes

f(){puts("0000 0001 0010 0011 0100 0101 0110 0111 1001 1010");}

Somehow, this is the shortest C answer so far…

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