Timeline for Hiccup a string
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jun 17, 2020 at 9:04 | history | edited | CommunityBot |
Commonmark migration
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| Nov 25, 2016 at 19:23 | history | edited | acrolith | CC BY-SA 3.0 |
added 40 characters in body
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| Nov 25, 2016 at 18:19 | comment | added | FlipTack |
You can write this 1 byte shorter as a recursive function: import random,time, then def F(s): newline if s:n=random.randint(1,10);time.sleep(n);print s[:n];F(s[n:])
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| Nov 24, 2016 at 19:20 | comment | added | Esolanging Fruit |
Adapting this to minipy (Python 3): while v1:n=ri(1,10);_i("time").sleep(n);p(v1[:n]);v1=v1[n:]; (Takes input from command line args)
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| Nov 24, 2016 at 19:08 | comment | added | george | Python 3 is one byte longer. Insert a '(' between print and 'i' and a ')' before the bracket | |
| Nov 24, 2016 at 17:57 | comment | added | Erik the Outgolfer |
from random,time import* doesn't work because Python doesn't know from which module you want to import libraries from.
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| Nov 24, 2016 at 17:55 | history | answered | acrolith | CC BY-SA 3.0 |