Episode #125 of the Stack Overflow podcast is here. We talk Tilde Club and mechanical keyboards. Listen now

# Tag Info

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53,268 29,596 29,306 total precision Private communication with @A.Rex led to this solution, in which we construct a neural net that memorizes the answers. The core idea is that every function $f\colon S\to\mathbf{R}$ over a finite set $S$ enjoys the decomposition $$f(x) = \sum_{s\in S}f(s)\cdot \left\{\begin{array}{cl}1&\text{if }x=s\\0&\... 5 14,674,000,667 5,436,050 5,403,448 10,385 5,994 4,447 3,806 total precision For a baseline, I investigated the following approach: Select $M,\delta,\epsilon>0$ such that if we sample the polynomial $p(x)=x^3+ax^2+bx+c$ at$$ S:=\{-M,-M+\delta,-M+2\delta,\ldots,M\},  then the largest sample point $s^\star\in S$ satisfying \\$p(s^\star)<\...

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182 white squares Inspired by Robin Ryder's answer, I tried to squeeze in a couple more white squares. I believe this solution is unique, and I will soon post verification code accordingly. Computer-readable grid: HETERONORMATIVE OVEROPINIONATED POSSESSEDNESSES B############## INCOMMUNICATIVE NEUROANATOMICAL DETERMINATENESS ############### ...

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Octave, 96 88 87 84 76 54 50 weights & biases This 6-layer neural net is essentially a 3-step sorting network built from a very simple min/max network as a component. It is basically the example network from wikipedia as shown below, with a small modification: The first two comparisons are done in parallel. To bypass negative numbers though the ReLU, ...

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180 white squares My strategy was simply to find a smaller rectangle with no black squares, such that it can be filled in uniquely. All 2×k rectangles have multiple solutions. For 3×k rectangles, there are multiple solutions for k between 3 and 14, but there is a exactly one solution for k=15. I then fit 4 such rectangles in the grid. This means that ...

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[Python 3] (644449*2+0) 1288898 points Perfect accuracy in only 644449 bytes import zlib,base64 as s t=enumerate(zlib.decompress(s.b64decode(b'###')).decode());a=lambda c:next(t)[1] The full code cannot fit in an answer, so I have put it here and replaced the large binary string literal with b'###' in the answer text. This is generated with the ...

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