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Code-golf is a competition to solve a particular problem in the fewest bytes of source code. If you want to score by characters instead of bytes, please state this explicitly in the challenge. If source code length is not the primary scoring criterion, consider using another tag instead.

3
votes
Python3, it's Montecarlo Time! To solve this problem, I first count how many "clicks" you need with the default keyboard (intially: abc,def,ghi,jkl,mno,pqrs,tuv,wxyz). Then I modify this keyboard and …
answered Mar 30 '14 by Antonio Ragagnin
0
votes
JS, 503 Following @xem idea: s='Ù¦¶3V§K)°¬*ªm¸KLø¶*¬¡KN¥³çÉLIY쳪lZM9uìê$ÌÓ-Ã8N·¦\nÒµ7#T­yªnIURZ§:jéäRÍ-y­Æµ[´vQNó¢çjUMNJ£\/«c̵¦¤.ÃØ©õ3"[¢âÌ'+"'"+'ÔèÛ¤9ʪ[O6$ÓÆö­×q$á±Åïe5l×%ß]À²oZW(½Afí¢Rɬ³lV~ÑÆÌ …
answered Mar 26 '14 by Antonio Ragagnin
2
votes
JS, 254 240 245 z='replace';r={};p=eval(('[{'+prompt()+'}]')[z](/\n/g,'},{')[z](/;/g,','));for(i in p){l=p[i];c=0;for(k in l){if(!c){c=k;r[c]=0;}else{r[c]-=l[k];}};for(j in p){w=p[j][c];if(w!=null)r[ …
answered Mar 28 '14 by Antonio Ragagnin
1
vote
JavaScript, 190 x=prompt(r=[]);p=RegExp;s="MDCLXVI";for(i=-1;++i<7;){u=x.match(new p(s[i],'g'));if(u)r=r.concat(u)};for(r=r.join("");--i>0;){r=r.replace(new p(s[i]+'{'+(i%2==0?5:2)+'}','g'),s[i-1] …
answered Mar 27 '14 by Antonio Ragagnin
0
votes
Javascript (without using loops!) To do this, I used a well-known numerical approximation of the inverse of the Stirling Factorial approximation, (and also got inspiration by this ..cough.. cough.. c …
answered Mar 7 '14 by Antonio Ragagnin