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user:me (yours)
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Sections title:apples
body:"apples oranges"
URL url:"*.example.com"
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Results tagged with Search options user 13448

This challenge involves creating or parsing pictures using text characters as the paint. Typically this uses only 95 printable (from a total of 128) characters defined by the ASCII Standard from 1963.

1
vote
Swift 4, 119 bytes func f(s:[String])->String{return s[0].split{$0=="\n"}.enumerated().map{$0.1+s[1].split{$0=="\n"}[$0.0]+"\n"}.joined()} Explanation func f(s: [String]) -> String { return s[ …
answered Mar 18 '18 by Tamás Sengel
1
vote
Swift, 118 bytes var s="";for i in 0..<26{for _ in 0..<25-i{s+=" "};for j in 0..<26-i{s+="\(UnicodeScalar(90-i-j)!)"};s+="\n"};print(s) Prettyfied: var s = "" for i in 0 ..< 26 { for _ in 0 . …
answered Apr 26 '18 by Tamás Sengel
1
vote
Swift 3, 134 bytes import Foundation;func r(s:String)->Bool{let i=s.components(separatedBy:"\n");return i.filter{$0.characters.count != i.count}.isEmpty} Try it online!
answered Mar 22 '18 by Tamás Sengel
0
votes
Swift, 218 169 bytes Sadly, I could not use map instead of for loops, since it timed out. func r(i:Int)->String{var l="";for j in(0...i*2){for k in(0..<i*2-1){l+=j==0&&k<i||j>0&&(j>i ?j-i-1:i-j)...( …
answered Apr 21 '18 by Tamás Sengel
1
vote
Swift, 74 bytes func r(i:Int)->String{return i>1 ?"CE"+(1..<i).map{_ in"C"}.joined():"EC"} Try it online!
answered Apr 5 '18 by Tamás Sengel