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Fastest-algorithm competitions are won by the answer with the smallest asymptotic time complexity. For challenges based on actual runtime, use [fastest-code] instead.

4 votes

(Cops) Fast and Golfiest Season 1: The Lord of the Strings

Concatenated Words, Python, 177 bytes, \$O(n)\$ time assuming input is a set where \$n\$ is the number of words, Cracked by Cursor Coercer, 7 points This is \$O(2^L)\$ where \$L\$ is the length of eac …
mousetail 'he-him''s user avatar
4 votes

(Cops) Fast and Golfiest Season 1: The Lord of the Strings

Generate Parenthesis, ><> (Fish), 178 bytes, \$O(n!)\$, Cracked by C-- Time: 2023-07-21 12:35:24Z Hover over any symbol to see what it does. If this appears glitched unformulated version …
mousetail 'he-him''s user avatar
2 votes

(Cops) Fast and Golfiest Season 1: The Lord of the Strings

Reverse words in string, Python, 47 bytes, \$O(n)\$ complexity, Cracked by The Thonnu, 6 point lambda g:print(*map(str.strip,g.split()[::-1])) Given an input string s, reverse the order of the words …
mousetail 'he-him''s user avatar
1 vote

(Cops) Fast and Golfiest Season 1: The Lord of the Strings

Generate Parenthesis, Rust, 193 bytes, \$O(n!)\$ Cracked by C--, 1 point C-- generously helped me save 1 point before cracking it in an actually significant way fn f(z:i32)->Vec<String>{if z<1{vec![ …
mousetail 'he-him''s user avatar
1 vote

(Robbers) Fast and Golfiest Season 1: The Lord of the Strings

C (GCC), 66 bytes (7.04% reduction), cracks Sum of Scores for buit strings f(s,l,i)char*s;{for(i=0;s[i]&&s[l+i]==s[i];++i);s=l?i+f(s,l-1):i;} Attempt This Online! Based on This C tip from G B
mousetail 'he-him''s user avatar