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JavaScript (Node.js), 209 bytes p=>p.map(n=>a.push(y=+n?[+n,...Buffer(36)]:n<0+a.pop()?a.pop().map((o,i)=>(m=y[i],i)?n<'+'?o+m:n<'/'?o-m?E:o:o-m:eval(o+n+m)):(y[parseInt(n,36)]=1,y)),a=[])&&a.map(x=>x …

JavaScript (Node.js), 103 bytes -2bytes by l4m2 p=>p.split` `.reduce(([a=[],b=[],...S],i)=>[{A:a+b,S:b-a,X:[b,a],P:b}[i]??[1/i?+i:a,a,b],S].flat(2),[]) Attempt This Online! Operators: A: Add S: Sub …

Cracks Javastack 0);
<!--　place　your　code　here　
console.log(`42`)
//

JavaScript, 249 bytes P=>{for(Q=[...P],P.M=[],Q.M=[],I=J=Q.p=1;E=I+J&&P[P.$??=0];[P,Q]=[Q,P])with(P)I=J,J=1,([[,O],X,Y]=E.split` `).map(C=>P[C]??=0),eval({g:X+`>0&&($+=${Y}-1)`,n:`Q.M.push(${X})`,c:`M …

JavaScript (V8), 189 bytes f=([C,...P],X=T=L='',Y,...S)=>C?eval(`f(P,${L*(L-=C=='('?-1:C==')')?'X+C,Y':` ^P.unshift(...X)&&Y ~Y,X :X,X,Y !Y *Y+X a'('+X+')',Y S(T+=X,Y) ('',X,Y )X,Y`.match(` [${C}](.* …

JavaScript (V8), 125 bytes a=>eval("for(d=5,w=a[x=y=0].length,h=a.length;(c=a[y%=h][x%=w])<9;d%2?x+=w+m:y+=h+m)a[y][x]='T',d=c>2?c:d,m=(d%3-1)*-~!+c;c") Try it online! '<': '3', '^': '6', …

JavaScript, 118 bytes s=>s.replace(/.+?\?/g,x=>x[i=x.length-2]>','?'& ?!%/.:0123456789=+-<>@*'[i-2]:String.fromCharCode(x[i]<'+'?96+i:63+i)) Try it online! JavaScript, 118 bytes s=>s.replace(/.!+( …

JavaScript (Node.js), 50 bytes f=a=>a[1]?f(a.replace(/\((.>)?(.)(<.)?\)/,'$2')):a Try it online! Repeat apply regex replace until only 1 char left. The regex /\((.>)?(.)(<.)?\)/ get the calculate re …

Retina 0.8.2, 22 bytes {`\((.>)?(.)(<.)?\) $2 Try it online! Basically the port of my JavaScript answer in Retina. I just learnt how to write loop in past 10 minutes and got this. {` loops the replac …

JavaScript (Node.js), 264 bytes S=>I=>[...S].map(s=>K?K=0:1/s?C=+(C+s):eval("A*=C;[A,C]=[C,A];K=!A;;K=A;K=A>0;A%=C;K=A<=0;A=A/C|0;I=I.replace(/-?\\d+/,n=>(A=+n,''));K=A>=0;O+=A;K=A<0;A+=C;C=0;;[A]= …

JavaScript, 172 bytes f=(a,d=3,x=0,y=0,n=1)=>(p=a[y]||[],q=p[x])?(p[x]=~(t='^<V>'.indexOf(q))?'^<V>'[d^2]:q=='/'?(t=3-d,'\\'):q=='\\'?(t=d^1,'/'):(t=d,q),f(a,t,x+(t&1&&t-2),y+(~t&1&&t-1),n+1)):n Bu …