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user:1234 user:me (yours) |
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score:3 (3+) score:0 (none) |
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title:apples body:"apples oranges" |
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This tag denotes challenges where parsing input is a large / the main part of the challenge.
0
votes
Line up the CSV
Python 2.7 - 242 bytes
bleh
import os
c=[r.split(',')for r in os.read(0,99).split('\n')]
k=sorted(list(set(sum([[s.split('=')[0]for s in r]for r in c],[]))))
print','.join(k)
for l in c:
t=[''for i i …
6
votes
Brainf*ckish directions
Python 2.7 - 154 147 134 128 bytes
l=r=p=0
exec"exec raw_input('%s->','p+=r+1;r=0%s<-','p-=l+1;l=0%s>','r+=1;p+=1%s<','l+=1;p-=1;')"%((";').replace('",)*4)
print p
Serious changes have been made to …
14
votes
Remove all occurrences of the first letter of a string from the entire string
brainfuck, 219 bytes
+[+[>+<+<]>],[<+<+>>-]>[<<[->]>[<]>-]++++[<++++++++>-]<<[[-]----[>-<----]>-<<[>+>+<<-]<,[[>+>>>+>>+>+<<<<<<<-]>>[<<+>>-]<<[>->+<<-]>[[-]+<]>[>]<<[>>+<<-]>>[<-<+>>-]<[[-]+>]>>[<]< …
0
votes
Implement an integer parser
Python 2.7 - 102 bytes
def p(n):
a,r,l=0,range(10),list(n);d=dict(zip(map(str,r),r))
while l:a*=10;a+=d[l.pop(0)]
return a
I believe this is valid, but I'm not 100% sure about rule 3.
Creates a …