##R, 46 bytes

`z=pi;x=z*z;y=exp;j=z/y(z);floor(y(x)/(x-j-j))`

Not especially efficient, but I had a lot of fun messing around with this.  I'm sure there's a shorter way using just those two numbers

Long-form, subbing in the variables:
`floor(exp(pi*pi)/((pi*pi) - pi/exp(pi) - pi/exp(pi))`

In real-person numbers:
`floor(19333.69 / (9.869604 - 0.1357605 - 0.1357605))` =
`floor(2014.328)`