_(yes, "generating generating" in the title is correct :) )_

# Context

In middle (?) school we are taught about sequences and, in particular, we are taught about linear sequences where the `n`th term is generated with an expression of the form `an + b`, where `a` and `b` are some coefficients. In this challenge, we will deal with sequences generated by polynomials of arbitrary degree.

# Task

Given the first `m` terms of a sequence, find the coefficients of the polynomial of **_lowest_** degree that could have generated such a sequence.

A polynomial, and thus the generating expression you are looking for, is to be seen as a function \$p(n)\$ that takes `n` as an argument and returns

$$a_0 + a_1 n + a_2 n^2 + a_3 n^3 + \cdots + a_k n^k$$

where \$k \geq 0\$ and \$a_i, 0 \leq i \leq k\$ have to be found by you.

You will assume that the `m` terms you were given correspond to taking `n = 0`, `n = 1`, ..., `n = m-1` in the generating polynomial above.

## Examples

If I am given the sequence `[2, 2, 2]` then I realize this is a constant sequence and can be generated by a polynomial of degree `0`: `p(n) = 2`.

If I am given the sequence `[1, 2, 3]` then I realize this cannot come from a constant polynomial but it could come from a linear polynomial `p(n) = n + 1`, so that is what my output should be. Notice how

```
p(0) = 1
p(1) = 2
p(2) = 3    # and NOT p(1) = 1, p(2) = 2, p(3) = 3
```

# Input

Your input will be the first terms of a sequence, which you can take in any reasonable format/data type. A standard list is the most obvious choice.

You may assume the input sequence is composed of integers (positive, 0 and negative).

# Output

The coefficients of the polynomial of **_lowest_** degree that could have generated the input sequence. The output format can be in any sensible way, as long as the coefficients can be retrieved unambiguously from the output. For this, both the value of each coefficient and the degree of each coefficient are important. (e.g. if using a list, `[1, 0, 2]` is different from `[0, 1, 2]`).

You can assume the polynomial you are looking for has integer coefficients.

# Test cases

For these test cases, the input is a list with the first terms; the output is a list of coefficients where (0-based) indices represent the coefficients, so `[1, 2, 3]` represents `1 + 2x + 3x^2`.

```
[-2] -> [-2]
[0, 0] -> [0]
[2, 2, 2] -> [2]
[4, 4] -> [4]
[-3, 0] -> [-3, 3]
[0, 2, 4, 6] -> [0, 2]
[2, 6] -> [2, 4]
[3, 7] -> [3, 4]
[4, 8, 12, 16] -> [4, 4]
[-3, -1, 5, 15, 29] -> [-3, 0, 2]
[0, 1, 4, 9] -> [0, 0, 1]
[3, 2, 3, 6, 11] -> [3, -2, 1]
[3, 4, 13, 30, 55] -> [3, -3, 4]
[4, 12, 28, 52, 84] -> [4, 4, 4]
[2, 4, 12, 32, 70] -> [2, 1, 0, 1]
[3, 6, 21, 54] -> [3, -1, 3, 1]
[4, 2, 12, 52, 140] -> [4, -2, -3, 3]
[10, 20, 90, 280] -> [10, 0, 0, 10]
[-2, 8, 82, 352, 1022, 2368, 4738] -> [-2, 4, -1, 4, 3]
[4, 5, 32, 133, 380] -> [4, -2, 0, 2, 1]
[1, 0, 71, 646, 2877, 8996, 22675] -> [1, -1, 0, -3, 0, 3]
[4, 2, 60, 556, 2540, 8094, 20692] -> [4, -2, -1, 0, -2, 3]
[1, 2, -17, 100, 1517, 7966, 28027, 78128, 186265] -> [1, 3, -2, 4, -3, -2, 1]
[4, 5, 62, 733, 4160, 15869, 47290, 118997] -> [4, 3, -1, -3, 1, 0, 1]
```

Test cases generated with [this code][ref]

---

This is [tag:code-golf] so shortest submission in bytes, wins! If you liked this challenge, consider upvoting it! If you dislike this challenge, please give me your feedback. Happy golfing!

[ref]: https://tio.run/##XVLRboMwDHzPV1h9StYwQanUbVL3IyhCqJgOqQ0sSTtNVb@d2QHK1AdIcr6zz0763/DV2XwYGtedwVW2pqU9950L4BFrHbHWBsEnucuVEDU2cESLrgooDx02Xn0IgBqPDhH2cEI7wZBARhGP3wQXhrZN56CF1nLaI8pJs56ryEznKmYDuJImjTsWEVMDZ2Ux2sv5ufwoWe8j6aXvfmSrWaVijCy8Vn2PtpZXRhyGi7MMDwF9KA@VR88mKSZTDQV9qeHVKD1jycaM/xHajLRMw1bDu5lEBEzxnJCMz8TI3jTkOzMhE49yCyMEt2eXmWzS2I/D6lSSfzI1D4c0OzYfm2azcyChUlv1PNw5gzI04GKZ8FaZx6U83SPhyzjmgT0SadKMl@AVvYN/TE/vRaqxlVLDwmM3C4/76h27aFY3It0h@YRbJN5XavgD