###1: 5 operators
    RESULT = B ^ (A ^ B)*(A > B)

###2: 13 operators
    RESULT = B ^ (A ^ B)*(A > B) ^ (A ^ C)*(A > C) ^ (B ^ C)*(B > C)

###3: xx operators
I want to see some more shots before I post this, WolframH is at 39 operators plus what it takes him to iron out a little glitch, but better is definitely possible.