## Hipster, Ruby

    if ARGV.length == 0
        puts rand(2)
    else
        last_round = ARGV[0].split(',').last
        n_players = last_round.length
        puts last_round.count('1') > n_players/2 ? 0 : 1
    end

Simply goes with last round's minority, just because everything else is mainstream.

Run like

    ruby hipster.rb