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Naruyoko
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JavaScript, 47 bytes

f=(a,b,c,h,i,j)=>(l=Math.log)(a)/l(h)*b**c>i**j

Surprisingly, the test cases doesn't show any floating-point error. I don't know if it ever does at this size.

This just compares the logarithm of the numbers.

Naruyoko
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  • 10