Alphabet triangle strikes again

Question

Task

Your task is to print this exact text:

A
BCD
EFGHI
JKLMNOP
QRSTUVWXY
ZABCDEFGHIJ
KLMNOPQRSTUVW
XYZABCDEFGHIJKL
MNOPQRSTUVWXYZABC
DEFGHIJKLMNOPQRSTUV
WXYZABCDEFGHIJKLMNOPQ
RSTUVWXYZABCDEFGHIJKLMN
OPQRSTUVWXYZABCDEFGHIJKLM
NOPQRSTUVWXYZABCDEFGHIJKLMN
OPQRSTUVWXYZABCDEFGHIJKLMNOPQ
RSTUVWXYZABCDEFGHIJKLMNOPQRSTUV
WXYZABCDEFGHIJKLMNOPQRSTUVWXYZABC
DEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKL
MNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVW
XYZABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJ
KLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXY
ZABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOP
QRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHI
JKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZABCD
EFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZA
BCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZ

Specs

• You may do it in all-lowercase instead of all-uppercase.
• Trailing newlines at the end of the triangle is allowed.
• Trailing spaces after each line is allowed.
• You must print to STDOUT instead of outputting an array of strings.

Scoring

This is code-golf. Program with lowest byte-count wins.

Answer 1

Vim, 29 bytes

:h<_↵↵↵y$ZZ26P0qqa↵♥βjllq25@q

Where ↵ represents the Return key, ♥ the Escape key, and β the Backspace key.

Answer 2

Python 2, 65 bytes

i=1
a=bytearray(range(65,91))*26
while a:print a[:i];a=a[i:];i+=2

Answer 3

Jelly, 10 bytes

26RḤ’RØAṁY

Try it online!

How it works

26RḤ’RØAṁY  Main link. No Arguments.

26          Set the return value to 26.
  R         Range; yield [1, 2, ..., 25, 26].
   Ḥ        Unhalve; yield [2, 4, ..., 50, 52].
    ’       Decrement; yield [1, 3, ..., 49, 51].
     R      Range; yield [[1], [1, 2, 3], ..., [1, ..., 49], [1, ..., 51]].
      ØA    Yield the uppercase alphabet.
        ṁ   Mold the alphabet as the array of ranges. This repeats the uppercase
            letters over an over again, until all integers in the range arrays
            have been replaced with letters.
         Y  Join, separating by linefeeds.

Answer 4

Haskell, 67 bytes

_#53=[]
s#i=take i s:drop i s#(i+2)
mapM putStrLn$cycle['A'..'Z']#1

A simple recursion over the length i of the line. In each step the next i chars are taken from an infinite repetition of the alphabet.

Answer 5

Pyramid Scheme, 1492 bytes

    ^         ^
   / \       / \
  /set\     /do \
 ^-----^   ^-----^
/a\   ^-  /!\   /[\
---  ^-  ^---  ^---^
    ^-  /=\   ^-  / \
   ^-  ^---^  -^ /out\
  ^-  ^-  /a\ ^- -----^
 ^-  / \  ---/[\     / \
 -^ /51 \   ^---^   /chr\
 ^- -----  ^-  / \  -----^
 -^       ^-  /do \     / \
 ^-      ^-  ^-----^   /10 \
 -^     /[\  -^   ^-   -----
 ^-    ^---^  -^  -^ 
 -^   / \  -^ /c\ ^-  
 ^-  /set\ /[\--- -^    
^-  ^-----^---^   ^-
-^ /a\   /+\  -^  -^
^- ---  ^---^  -^  -^
-^     /a\ /2\ / \  -^
 -^    --- ---/set\  -^
  -^         ^-----^ ^-
   -^       /c\   /a\-^
    -^      ---   --- -^
     -^               /[\
      -^             ^---^
       -^           ^-   -^
       /]\         / \    -^
      ^---^       /set\    -^ 
     ^-   -^     ^-----^    -^
    / \   ^-    /c\   /-\    -^
   /set\ ^-     ---  ^---^    -^
  ^-----^-          /c\ /1\    -^
 /b\   / \          --- ---    /]\
 ---  / -1\                   ^---^
      -----                  ^-  / \
                            / \ /out\
                           /set\-----^
                          ^-----^    -^
                         /b\   /?\    -^
                         ---  ^---^   / \
                             /!\  -^ /chr\
                            ^---  /+\-----^
                           /=\   ^---^   /+\
                          ^---^ /b\ /1\ ^---^
                         /b\ / \--- ---/ \ /b\
                         ---/25 \     /65 \---
                            -----     -----

Try it online!

Why? Why not?

Answer 6

Mathematica, 90 bytes

StringRiffle[Flatten[Alphabet[]&~Array~26]~Internal`PartitionRagged~Range[1,51,2],"
",""]&

Anonymous function. Takes no input and returns a string as output. Golfing suggestions welcome. An example of what Internal`PartitionRagged does:

In[1]:= Internal`PartitionRagged[{2, 3, 5, 7, 11, 13}, {2, 3, 1}]               

Out[1]= {{2, 3}, {5, 7, 11}, {13}}

Answer 7

C, 79 bytes

main(i,j){for(i=0,j=1;i<676;i++){putchar(i%26+65);if(j*j==i+1){puts("");j++;}}}

My first answer in C \o/

Golfing suggestions are more than welcome.

Answer 8

Brachylog, 37 bytes

26~l<:1aLc~j[@A:I],L~@nw
=:2%1,.#@l?,

Try it online!

Explanation

• Main predicate:

  26~l         Let there be a list of 26 elements
  <            This list is an ascending list of integers
  :1aL         Apply predicate 1 to that list ; the resulting list of strings is L
  c            Concatenate the list of strings into one big string
  ~j[@A:I],    That big string is the result of juxataposing the alphabet I times to itself
  L~@n         Create a string which when splitted on line breaks results in L
  w            Write that string to STDOUT
  

• Predicate 1: used to generate variable strings of odd lengths.

  =            Assign a value to the Input
  :2%1,        That value must be odd
  .#@l?,       Output is a string of length Input
  

Answer 9

Perl, 42 41 39 bytes

perl -E '@b=(A..Z)x26;say splice@b,0,$#a+=2for@b'

Just the code:

@b=(A..Z)x26;say splice@b,0,$#a+=2for@b

An obvious shorter version unfortunately triggers an internal perl problem (Use of freed value in iteration):

say splice@b,0,$#a+=2for@b=(A..Z)x26

Answer 10

VBA Excel (80 bytes, 1742 bytes)

---

Excel, 1742 bytes

Inspired by the ugoren's creative answer, I managed to find an Excel formula to create the pattern as shown in the OP.

=MID(REPT("ABCDEFGHIJKLMNOPQRSTUVWXYZ",26),(ROW()-1)^2+1,2*ROW()-1)

Paste this formula in cell A1, then drag all over range A1:A26.

The length of the formula is 67 bytes but you have to replicate it 26 times, so it's equal to 67*26=1742 bytes. Here is the output:

---

Excel VBA, 80 bytes

Now it's possible we integrate Excel with VBA to automate the process and to save many bytes since VBA is built into most Microsoft Office applications, including Excel. Write and run the following code in the Immediate Window (use combination keys CTRL+G to display it in Visual Basic Editor):

[A1:A26]="=MID(REPT(""ABCDEFGHIJKLMNOPQRSTUVWXYZ"",26),(ROW()-1)^2+1,2*ROW()-1)"

The program works by printing the Excel formula above to the range A1:A26. Unfortunately, both Excel and VBA have no built-in alphabet.

Answer 11

Pyth, 12 bytes

jtc*G26*Rd26

Try it online!

Answer 12

JavaScript (ES6), 77 82 88

EcmaScript 6 required just to save 1 byte using a template string literal for newline.

for(i=r=l=o='';l+52;r++||(r=l-=2,o+=`
`))o+=(i++%26+10).toString(36);alert(o)

Less golfed

for(i = r = l = o = '';
    l + 52;
    r++ || (r = l -= 2, o += `\n`))
  o += (i++ % 26 + 10).toString(36);
alert(o);

Test

for(i=r=l=o='';l+52;r++||(r=l-=2,o+=`
`))o+=(i++%26+10).toString(36);alert(o)

Answer 13

Husk, 10 bytes

Cİ1ṠṁK…"AZ

Try it online!

Explanation

Cİ1ṠṁK…"AZ
      …"AZ    Get the alphabet
   ṠṁK        Replace each letter with the whole alphabet
C             Cut the resulting string into lines with lengths
 İ1            equal to the list of odd numbers

Answer 14

JavaScript, 129 bytes

z=1,i=0,g=a=>{b=0,c="";while(a+a-1>b){c+='ABCDEFGHIJKLMNOPQRSTUVWXYZ'.split``[i>26?i=0:i++];b++}console.log(c)};while(z<26)g(z++)

Answer 15

Pyke, 14 bytes

G26*WDoh<
Ko>D

Try it here!

Answer 16

Go, 133 bytes

package main
import S "strings"
func main(){s:=S.Repeat("ABCDEFGHIJKLMNOPQRSTUVXXYZ",26)
for i:=1;s!="";i+=2{println(s[:i]);s=s[i:]}}

Answer 17

MATLAB, 112 109 95 79 77 bytes

This will also work with Octave, you can try online here.

a=['' 65:90 65:90]';j=0;for i=1:2:52;b=circshift(a,j);j=j-i;disp(b(1:i)');end

So after some major changes, I've saved a further 14 32 bytes. This one is getting to be much more like the length I would have expected from MATLAB. I've left the old version below as it is substantially different.

a=['' 65:90 65:90]';        %Create 2 copies of the upper case alphabet
j=0;                        %Initialise cumulative sum
for i=1:2:52;               %For each line length
    b=circshift(a,j);       %Rotate the alphabet string by the cumulative offset
    j=j-i;                  %Update cumulative negative sum of offsets.
    disp(
         b(1:i)'            %Extract first 'line length' characters from rotated alphabet.
               );           %Display next line (disp adds newline automatically)
end

---

Original version:

a=['' repmat(65:90,1,26)];c=cumsum(1:2:51);disp(cell2mat(arrayfun(@(s,f)[a(s:f) 10],[1,c(1:25)+1],c,'Un',0)))

Wow that one ended up being longer than I thought it would. I'll see if I can't knock a few bytes off it.

An ungolfed version to explain:

a=['' repmat(65:90,1,26)]; %Create 26 copies of the upper case alphabet
c=cumsum(1:2:51);          %Calculate the end index of each row in the above array, by cumulatively summing the length of each line
disp(
     cell2mat(
              arrayfun(@(s,f)
                             [a(s:f) 10], %Extract the part of the alphabet and insert a new line.
                                         [1,c(1:25)+1],c, %start index is the previous end of line plus 1. End index is as calculated by cumsum.
                       'Un',0 %The returned values are not all the same length
                       )   %Do this for each line
              )            %Convert back to a matrix now new lines inserted
     )                     %And display it

---

Acknowledgements

• 3 bytes saved - thanks @LuisMendo

Answer 18

XPath 3.0 (and XQuery 3.0), 84 bytes

codepoints-to-string((0 to 25)!(subsequence(((1 to 26)!(65 to 90)),.*.+1,2*.+1),10))

Explanation:

(1 to 26)!(65 to 90) is the alphabet 26 times

(0 to 25)!(subsequence(XX, start, len),10) takes 26 subsequences of this, each followed by newline

subsequence(X, .*.+1, 2*.+1) takes successive subsequences with start position and length: (1, 1), (2, 3), (5, 5), (10, 9) etc.

codepoints-to-string() turns Unicode codepoints into characters

Answer 19

Ruby, 46 bytes

26.times{|i|puts ([*?A..?Z]*26)[i*i,i*2+1]*""}

See it on ideone: http://ideone.com/3hGLB0

Answer 20

05AB1E (alternate) 15 bytes

A2×52µ¼D¾£,¾¼FÀ

Try it online!

Explanation:

A2×              # push a string containing a-za-z
   52µ           # Loop the rest of the program until counter = 52
      ¼          # increment counter (it's 0 initially)
       D         # Duplicate the alpha string on the stack
        ¾£       # Replace alpha with alpha[0..counter]
          ,      # Pop the substring and print it
           ¾¼FÀ  # rotate the alpha string left counter++ times.

Answer 21

R, 120 115 111 bytes

v=c();for(i in 1:26){v=c(v,c(rep(LETTERS,26)[(sum((b=seq(1,51,2))[1:i-1])+1):sum(b[1:i])],"\n"))};cat(v,sep="")

Ungolfed :

a=rep(LETTERS,26)
b=seq(1,51,2)
v=vector()

for(i in 1:26)
    {
    v=c(v,c(a[(sum(b[1:i-1])+1):sum(b[1:i])],"\n"))
    }

cat(v,sep="")

Basically, b is the vector of the odd numbers between 1 and 51, thus giving the length of each line. Obviously, the sum function sums the numbers of this vector, and gives the starting and ending indexes.

-5 bytes thanks to @plannapus !
-4 bytes thanks to @plannapus !

Answer 22

R, 81 73 65 63 bytes

A simple for loop approach. Repeat the alphabet 26 times and loop through a sliding index range that is calculated using (i^2-2*i+2):i^2.

for(i in 1:26)cat(rep(LETTERS,26)[(i^2-2*i+2):i^2],"\n",sep="")

Answer 23

Batch, 123 bytes

@set s=
@for /l %%i in (1,2,51)do @call set s=%%s%%ABCDEFGHIJKLMNOPQRSTUVWXYZ&call echo %%s:~0,%%i%%&call set s=%%s:~%%i%%

Answer 24

05AB1E, 18 17 bytes

26FA26×N>n£NnF¦},

Explanation

26F                 # for N in range(0, 26) do
   A26×             # the alphabet repeated 26 times
       N>n£         # take (N+1)^2 letters
           NnF¦}    # throw away the first N^2 letters
                ,   # print with newline

Try it online!

Answer 25

Rexx, 74 72 bytes

i=1;m=1;do 26;say substr(copies(xrange('A','Z'),26),i,m);i=i+m;m=m+2;end

Ungolfed:

i=1
m=1
do 26
  say substr(copies(xrange('A','Z'),26),i,m)
  i=i+m
  m=m+2
end

Answer 26

TSQL, 129 bytes

USE MASTER in the beginning of the script is to ensure that the query is run in the master database which is default for many users(not counting bytes for that).

Golfed:

USE MASTER

SELECT SUBSTRING(REPLICATE('ABCDEFGHIJKLMNOPQRSTUVWXYZ',26),number*number+1,number*2+1)FROM spt_values WHERE number<26and'P'=type

Ungolfed:

USE MASTER

SELECT SUBSTRING(REPLICATE('ABCDEFGHIJKLMNOPQRSTUVWXYZ',26),number*number+1,number*2+1)
FROM spt_values
WHERE number<26and'P'=type

Fiddle

Fiddle for older version using xml path

Answer 27

PowerShell, 68 bytes

$a=-join(65..90|%{[char]$_})*26;26..1|%{$a=$a.Insert($_*$_,"`n")};$a

The section before the first semicolon produces a string containing 26 copies of the uppercase alphabet. The next section injects linebreaks at the index of each square number (working backward so I don't have to account for the shifting). Finally, the $a at the end just shoves that string variable onto PowerShell's equivalent of STDOUT.

Answer 28

Dyalog APL, 18 bytes

↑2{⍺↓⍵⍴⎕a}/×⍨0,⍳26

Answer 29

C, 60 bytes

i;main(j){for(;j<27;j*j^++i||puts("",j++))putchar(i%26+65);}

Answer 30

C++, 111 bytes

void a(){int c=65,i,j;for(i=0;i<26;i++){for(j=0;j<=2*i;j++){std::cout<<(char)c;c++;if(c==91)c=65;}std::cout<<'\n';}}

First try at one of these. Uses an int "c" to record which letter it needs to print at any given time. Once "c" passes 90 ('Z') it gets reset to 65 ('A'). Prints the pyramid using for loops.