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Your task is to display the letter "A" alone, without anything else, except any form of trailing newlines if you cannot avoid them, doing so in a program and/or snippet. Code that returns (instead of printing) is allowed.

Both the lowercase and uppercase versions of the letter "A" are acceptable (that is, unicode U+0061 or unicode U+0041. Other character encodings that aren't Unicode are allowed, but either way, the resulting output of your code must be the latin letter "A", and not any lookalikes or homoglyphs)

You must not use any of the below characters in your code, regardless of the character encoding that you pick:

  • "A", whether uppercase or lowercase.

  • "U", whether lowercase or uppercase.

  • X, whether uppercase or lowercase.

  • +

  • &

  • #

  • 0

  • 1

  • 4

  • 5

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  • 7

  • 9

Cheating, loopholes, etc, are not allowed.

Since this is , the shortest solution, in bytes, that follows all the rules, is the winner.


Validity Checker

This Stack Snippet checks to make sure your code doesn't use the restricted characters. It might not work properly for some character encodings.

var t = prompt("Input your code.");

if (/[AaUuXx+&#0145679]/.test(t)) {
  alert("Contains a disallowed character!");
} else {
  alert("No disallowed characters");
}

This Stack Snippet that makes sure you don't have a disallowed character is also available on JSFiddle.

Leaderboard

var QUESTION_ID=90349,OVERRIDE_USER=58717;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

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  • 7
    \$\begingroup\$ @ColdGolf You seem to be saying "yes" to functions, but functions don't display, they usually return. \$\endgroup\$
    – xnor
    Aug 19, 2016 at 23:06
  • 2
    \$\begingroup\$ Is ending up with a variable that contains just a also good enough ? \$\endgroup\$
    – Ton Hospel
    Aug 19, 2016 at 23:17
  • 1
    \$\begingroup\$ That's not what I meant. The supposed code doing a variable assignment would not contain any of the forbidden characters. I'm just trying to understand what is covered by "display by means other than printing". If "return from a function" is OK, what about "assign to a variable" ? \$\endgroup\$
    – Ton Hospel
    Aug 20, 2016 at 0:05
  • 1
    \$\begingroup\$ Why those particular characters? \$\endgroup\$
    – user253751
    Aug 22, 2016 at 1:32
  • 7
    \$\begingroup\$ @immibis A for obvious reasons. U for Unicode escape strings (\u0041 is A), X for hex escape strings (\x41), + for Unicode ordinals (U+0041), & for HTML entities, # for I actually don't know, 65 is the decimal ordinal of A, 41 is the hex ordinal of A, 97 is the decimal ordinal of a, and 0 for a few of the previous reasons. \$\endgroup\$
    – user45941
    Aug 22, 2016 at 6:26

218 Answers 218

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0
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Kustom, 33 bytes

$tc(reg,tc(type,أ),".....$","")$

explained:

$tc(reg,      regex replace
  tc(type,أ),  text type of some Arabic character (="ARABIC")
  ".....$",   replace 5 characters at the end...
  ""          ... with the empty string
)$
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0
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Thunno, \$ 5 \log_{256}(96) \approx \$ 4.12 bytes

Z23-C

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Explanation

Z23-C  # No inputs
Z2     # Push 100
  3    # Push 3
   -   # Subtract to get 97
    C  # Get the character at that codepoint ('a')
       # Implicit output

Thunno, \$ 6 \log_{256}(96) \approx \$ 4.94 bytes

Z3Z2/h

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Explanation

Z3Z2/h  # No inputs
Z3      # Push 1000
  Z2    # Push 100
    /   # Divide to get 10
     h  # Convert to hexadecimal to get 'a'
        # Implicit output

Thunno, \$ 7 \log_{256}(96) \approx \$ 5.76 bytes

88 23-C

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Explanation

88 23-C  # No inputs
88       # Push 88
   23    # Push 23
     -   # Subtract to get 65
      C  # Get the character at that codepoint ('A')
         # Implicit output
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  • \$\begingroup\$ How does the character encoding work in this language? it's physically impossible to have a fraction of a bit! \$\endgroup\$ Apr 12, 2023 at 15:13
  • \$\begingroup\$ @Hippopotomonstrosesquipedalian it doesn't actually have a fraction of a bit. It's just an approximation of how much it would take up, since Thunno uses only the 96 printable ASCII characters. It's allowed by Meta rules. \$\endgroup\$
    – The Thonnu
    Apr 12, 2023 at 15:34
0
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Fig, \$3\log_{256}(96)\approx\$ 2.469 bytes

[cB

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Didn't see that there was another Fig answer, but here's a different version.

[cB
 cB # "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz"
[   # First char of the above
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0
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GolfScript, 7 bytes

'B'{(}%

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0
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Python 3, 17 Bytes

print(chr(88-23))

$$88-23=65$$

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0
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C89, 22 bytes

f(){printf("%c",833);}

Explanation

$ man 3 printf || info '(libc)Other Output Conversions'

"%c ... the int argument is [first] converted to an unsigned char,"

  1. 'A' == 65
  2. \$833 \equiv 65\ (\textrm{mod}\ 256)\$

Try it online!

\$\endgroup\$
0
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Deadfish~, 10 bytes

iisiiiisic

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\$\endgroup\$
-1
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Python, 32 bytes

print(chr(ord("@")-(-ord("pretend this is SOH"))))

The character in the second ord there is SOH. SOH, which is ASCII 1, is negated and subtracted from @, which is ASCII 64, to make ASCII 65, which is A.

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