50
votes
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Create the shortest possible obfuscated FizzBuzz implementation.

To be considered obfuscated, it should satisfy at least one of the following:

  1. Does not contain any of the words "Fizz", "Buzz", or "FizzBuzz"
  2. Does not contain the numbers 3, 5, or 15.
  3. Use any of the above in a misleading way.

Remember: The goal is to be short and hard to follow.

The code sample which inspired this question follows:

public class Default
{
        enum FizzBuzz
        {
            Buzz = 1,
            Fizz,
            FizzBuzz
        }
        public static void Main(string[] args)
        {
            byte[] foo = 
              Convert.FromBase64String("IAmGMEiCIQySYAiDJBjCIAmGMEiCIQySYA==");
            MemoryStream ms = new MemoryStream(foo);
            byte[] myByte = new byte[1];
            do
            {
                FizzBuzz fb;
                ms.Read(myByte, 0, 1);
                for (int i = 0; i < 4; i++)
                {
                    fb = (FizzBuzz)(myByte[0] >> (2 * i) 
                         & (int)FizzBuzz.FizzBuzz);
                    Console.Out.WriteLine( (((int)fb > 0) ? "" + fb : "" 
                         + ((ms.Position - 1) * 4 + i + 1)));
                }
            } while (ms.Position < ms.Length);
        }
}
\$\endgroup\$
  • \$\begingroup\$ How do you know the bound ? In your solution you have ms.Length but in some solutions there is no such bound... \$\endgroup\$ – Labo Nov 10 '15 at 9:20
  • \$\begingroup\$ I'm voting to close this question as off-topic because it does not have an objective validity criterion, making it impossible to indisputably decide whether a submission follows the rules. \$\endgroup\$ – Dennis Sep 20 '16 at 21:49

41 Answers 41

0
votes
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PHP - 157 154 95 chars

<?$x="zz";for(;++$i<=100;){?> <?$j=$i%(4-1)^0?"":"Fi$x";$j.=$i%(4+1)^0?"":"Bu$x";echo$j?$j:$i;}

And no whitespace! Only one space!

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0
votes
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Python, 180 chars

from random import*;seed(0);_,y=''.join(sample('zzzzuiFB',8)),5**2<<2
print chr(int(`y`[::2])).join(filter(bool,map(lambda z:(not z%(y>>5))*_[:1<<2:]+(1>z%5)*_[1<<2::],range(1,y))))
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0
votes
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K

-1',/'$(+`fizz`buzz,,1+!100)@'&:'+(a,,~|/[a:100#'(001b;00001b)])
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0
votes
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Here's a fun one in C. It can be shorter, but then it won't be as much fun!

#define i(bu,zz,fi) printf("?"[1]|""[0]?"fi":"%"#zz"\n",bu)
#define x(a,i,p) {-0xf##i&(3+5-1),{z(z,a,p,),""}}
#define z(b,f,z,l) #z#f""#b""#l#b
main(b){struct{char z;char*u[2];}u[]={x(i,d,f),x(u,b,b),{0}};for(b=1;b<'e';b++)
{int z=0;char f[3+5+1]={0};for(b;u[z].z;z++)strcat(f,u[z].u[!!(b%u[z].z)]);*f&&
i(f,s,3)||i(b,d,5);}}
\$\endgroup\$
0
votes
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JavaScript, 80 characters

for(i=0;i<100;a=++i%3,b=i%5,alert(i+"FizzBuzz".slice(t=a&&!b*4,t?8:!a*4+!b*4)));
\$\endgroup\$
  • \$\begingroup\$ Your code uses "FizzBuzz" which is disallowed by the rules. \$\endgroup\$ – Fatalize Aug 27 '15 at 11:16
  • \$\begingroup\$ Fatalize's comment isn't the full story: you could either remove the FizzBuzz, or the 3 and 5`, or you could use any of those "in a misleading way" (whatever that means). \$\endgroup\$ – Martin Ender Aug 27 '15 at 12:17
  • \$\begingroup\$ Ok, I'll see what I can come up to in that sense. Thanks for exposing the rules, didn't paid attention to those on the first run. \$\endgroup\$ – Frederik.L Aug 27 '15 at 20:06
0
votes
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C Solution

    #include  <stdio.h>
    #define a b b b b b
    #define b c c c c c
    #define c d d d d d
   #define  h(k,s)k?s:""
  #define x !(n%('0'>>4))
  #define y !(n%('P'>>4))
  #define d if(100>=++n)\
printf("%s%s%s",h(x,"Fizz"\
),h(y,"Buzz"),h(x|y,"\n"));
int main(){static int n; a}
\$\endgroup\$
0
votes
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C, 283 bytes

#include "stdio.h"
#include "string.h"
#define z 122
int main(){char f[]={70,105,z,z,0},b[]={66,117,z,z,0},i=1,B[z],g;for(i=1;i<=100;i++){g=0;if(i%3<1)strcpy(B,f),g=1;if(i%5<1){if(g>0)strcat(B,b);else if(g<1)strcpy(B,b),g=1;}if(g<1)printf("%d\n",i);else printf("%s\n",B);}return 0;}

Obscure? Maybe. Golfed? A little more so than it is obscure. Ugly? YES.

\$\endgroup\$
0
votes
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C 213 Bytes

int c=1,m,n,O,z='z';void main(){O=0;m=c%5-c%3;if(c>2){O=!m&&n?printf("Fiz%cBuz%c",z,z):O;O=m<0&&n+1?printf("Buz%c",z):O;O=m!=n&&m+1&&!O?printf("Fiz%c",z):O;}n=m;O?0:printf("%i",c);putchar(10);c++;if(c<101)main();}

Everything is based on counter % 5 - counter % 3.

\$\endgroup\$
0
votes
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C++ (478 Bytes)

It beats the previous C++ code easily.

#include<iostream>
#include<string>
using namespace std;int main() {string K = "FBiuzzzz";for (int i = 1; i <= 100; i++) {if (i % ((35 / 10)*(35 % 10))==0) {for (int j = 0; j < 8; j += 2)cout << K.at(j);for (int j = 1; j < 8; j += 2)cout << K.at(j);cout << endl;}else if (i % (35 / 10) == 0) {for (int j = 0; j < 8; j += 2)cout << K.at(j);cout << endl;}else if (i % (35 % 10) == 0) {for (int j = 1; j < 8; j += 2)cout << K.at(j);cout << endl;} else cout << i << endl;}return 0;}
\$\endgroup\$
  • \$\begingroup\$ Lol, I have made FBiuzzzz instead of FizzBuzz (Scrambling trick intensifies) \$\endgroup\$ – user54200 Jun 26 '16 at 2:54
0
votes
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gs2, 1 byte

f

prints fizzbuzz, gs2 has a very simple function

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0
votes
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JavaScript - 166 chars

Here's another JavaScript solution which uses an encoded for loop body to hide 3, 5, Fizz, and Buzz. It's relatively terse, but you can still kind of see what's going on.

for(i=0;++i<101;)console.log(eval(String.fromCharCode(...'286925333f27273a2746697a7a27292b286925353f27273a2742757a7a27297c7c69'.match(/../g).map(n=>parseInt(n,16)))))

For something a bit more interesting, we can encode all the programming logic in zero-width whitespace characters and have something that looks concise but is actually not at all. This is similar to dzuc's Ruby solution.

eval('​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​‌​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​'.split('‌').map(ᅠ=>String.fromCharCode(ᅠ.length)).join('')) 

Personally, I like playing with fire.

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