60
\$\begingroup\$

This might be a very simple challenge, but I am surprised it hasn't been done on code-golf yet:

Print all Integers from 1 to 10 inclusive in ascending order to standard output.

Your output format can be whatever your language supports. This includes arbitrary separators (commas, semicolons, newlines, combinations of those, etc., but no digits), and prefixes and postfixes (like [...]). However, you may not output any other numbers than 1 through 10. Your program may not take any input. Standard loopholes are disallowed.

This is , so shortest answer in bytes wins!

Leaderboard

var QUESTION_ID=86075,OVERRIDE_USER=42570;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

\$\endgroup\$
17
  • 10
    \$\begingroup\$ Related (duplicate?) \$\endgroup\$
    – Luis Mendo
    Jul 21, 2016 at 9:07
  • 17
    \$\begingroup\$ If the only change is hard-coding a single parameter then that falls under the banner of "trivial change", and by the standards of this site still counts as a dupe. \$\endgroup\$ Jul 21, 2016 at 9:54
  • 11
    \$\begingroup\$ @PeterTaylor The other challenge has a huge problem with the integer limits though. The way it's specified every TC language that doesn't have 64-bit integers needs to implement them. (And that affects quite a lot of languages.) \$\endgroup\$ Jul 21, 2016 at 10:01
  • 20
    \$\begingroup\$ @xnor Quite frankly, I'd rather close the other challenge as a duplicate of this one. The requirement pretty much ruins it. \$\endgroup\$
    – Dennis
    Jul 21, 2016 at 14:09
  • 11
    \$\begingroup\$ I can't believe every single of the (currently) 71 answers assumes the base should be decimal… \$\endgroup\$ Jul 22, 2016 at 15:05

268 Answers 268

1
5 6 7
8
9
1
\$\begingroup\$

Intcode, 49 bytes

4,15,1001,15,1,15,8,15,16,14,1006,14,0,99,-1,1,11

Why am I still doing this? Because it's fun. That's why.

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1
\$\begingroup\$

Wren, 28 bytes

System.write((1..10).toList)

Try it online!

Explanation

System.write(              )  // Output
             (1..10)          // Numbers from 1 to 10
                    .toList   // Converted to a list
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1
\$\begingroup\$

Keg, 8 bytes

Still wasn't used to the flags...


Ï_(. ,

Try it online!

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1
\$\begingroup\$

W z, 4 bytes

10aM

Just does a range from (implicit) 1 to 10.

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1
\$\begingroup\$

Spice, 55 bytes

My solution is posted as to the language spec, which currently fails because of an interpreter bug. To run against the interpreter the score falls to 63 bytes due to 2 NUL statements being required.

;a@ADD a 1 a;SWI a 10 0;LOD std::sort.spice ^a a;OUT a;

Or with the additional NULs.

;a@NUL;NUL;ADD a 1 a;SWI a 10 2;LOD std::sort.spice ^a a;OUT a;

Un-golfed Explanation

;a@          - declare variable 'a'
ADD a 1 a;   - ADD a[0] to 1 and insert at a[0], empty "a" implicitly 0
SWI a 10 0;  - If a[0] < 10, jump to line 0 (ADD...)
LOD std::sort.spice ^a a; - Use std lib to sort a 1->10
OUT a;       - Output a
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1
\$\begingroup\$

GolfScript, 6 bytes

It hasn't been done? Then great. Generates 0 to 10 and removes 0, then it evaluates.

11,1>`

Try it online!

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1
\$\begingroup\$

Rogex, 27 bytes

90B300d00901e00100701a20f00

Try it online!

Explained

90B 300 d00 # Set the loop value to 11
901         # Set the buffer to 1
e00         # While the buffer isn't equal to 11
    100 701 # Print the buffer then increment it
    a20     # Print a space
f00         # End loop

Rogex answer number 2! Also, my 101st answer! (´• ヮ •`)

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1
\$\begingroup\$

Intcode, 44 42 bytes

-2 bytes thanks to rootbeersoup

204,8,9,8,1205,8,0,99,1,2,3,4,5,6,7,8,9,10

Try it online!

Isn't it unfortunate that a just-hardcode solution outgolfs the other intcode answer by six bytes?

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1
  • \$\begingroup\$ Saves 2 chars: 204,8,9,8,1205,8,0,99,1,2,3,4,5,6,7,8,9,10 \$\endgroup\$ Jan 30, 2020 at 5:33
1
\$\begingroup\$

MAWP, 13 bytes

25W[1A~!:1M~]

Try it!

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2
  • 1
    \$\begingroup\$ The integer complexity thing in 1+ is frustrating... \$\endgroup\$ Aug 13, 2020 at 2:56
  • \$\begingroup\$ yup lol, I should try golfing 1+ sometime \$\endgroup\$
    – Razetime
    Sep 8, 2020 at 6:44
1
\$\begingroup\$

1+, 25 22 bytes

1:1(|1+":1+":1+":)()()

...

EDIT: The boring solution is shorter.

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1
\$\begingroup\$

Rockstar, 32 bytes

X's0
while 10-X
let X be+1
say X

Try it here (Code will need to be pasted in)

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1
\$\begingroup\$

BitCycle -u, 40 bytes

v0 ~
v1~/
AB~
v000000<
AB\ 000^
v =@
!1<

Try it online!

Explanation pending. I need to sleep first.

(I also found a 36-byte program that outputs 0 through 9, but I haven't found a good way to turn it into 1 through 10.)

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1
\$\begingroup\$

Headascii, 50 bytes

++++[]]]][]]]+O^+O+O+O+O+O+O+O+ODONE.{UPN)!@}:R-P!

Try it here! Code will need to be copied and executed like this:

erun("++++[]]]][]]]+O^+O+O+O+O+O+O+O+ODONE.{UPN)!@}:R-P!")

Outputs each number separated by newline. Nontrivial challenges scare me :')

++++[]]]][]]]+O^+O+O+O+O+O+O+O+ODONE.{UPN)!@}:R-P!  full program
                                    .               code block delimiter

++++[]]]][]]]+O^+O+O+O+O+O+O+O+ODONE  block 0
              O  O O O O O O O O O    send
++++[]]]][]]]+                        49 (ascii 1)
                +                     50 (ascii 2)
                  +                   51 (ascii 3)
                    +                 52 (ascii 4)
                      +               53 (ascii 5)
                        +             54 (ascii 6)
                          +           55 (ascii 7)
                            +         56 (ascii 8)
                              +       57 (ascii 9)
               ^                D     49 (ascii 1)
                                  NE  to code block 1

{UPN)!@}:R-P!  block 1
{      }       Loop
   N)   :      Until last value
 UP              Put value on string register
     !@          Print and clear string register
         R     Recall last value (49)
          -    Minus 1 (48, ascii 0)
           P!  Concatenate to string register and print

Sending inputs to code block to loop print saves 5 bytes over printing each individually, but it might be possible to save more bytes by doing some sort of for-loop type structure from the beginning. Storing 9 as well as 48 seems expensive, though.

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1
\$\begingroup\$

Julia 1.7, 14 bytes

print((1:10)')

Try it online!

1:10 returns a Range. Note that in Julia 0.2 we can just use print(1:10). This does not work in later versions (I've tested this starting from Julia 0.4).

We could use print(collect(1:10)). But this is costly. But we can use a trick by using the ' transpose operator.

There is also an answer for Julia 0.6 which uses show.(1:10) as this prints 1-10, it prints additional stuff in newer Versions of Julia due to the nature of broadcasting, namely,

12345678910
10-element Vector{Nothing}:
 nothing
 nothing
 nothing
 nothing
 nothing
 nothing
 nothing
 nothing
 nothing
 nothing
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3
  • \$\begingroup\$ use show instead of print for -1 byte \$\endgroup\$
    – MarcMush
    Feb 17, 2022 at 17:22
  • \$\begingroup\$ show.(1:10) is fine in any version as the additional output is produced only in the REPL. You can mute it by appending a ; \$\endgroup\$
    – amelies
    Feb 17, 2022 at 18:45
  • \$\begingroup\$ @amelies cool! I didn't know that. \$\endgroup\$ Feb 17, 2022 at 19:42
1
\$\begingroup\$

Ly, 13 4 bytes

`9`R

I found a better way. :)

`     incrementing the empty top of stack pushes a 1
 9    push 9 onto the stack
  `   increment the top of stack to get "10"
   R  generate the inclusive range of int between the top 2 stack entries

The stack entries are printed as numbers by default when the code exits.

Try it online!

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1
\$\begingroup\$

Ruby, 20 bytes

(1..10).each{|i|p i}

Cannot be any simpler than this.

Attempt This Online!

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6
  • \$\begingroup\$ 1.upto(10){p _1} is 16 \$\endgroup\$
    – Razetime
    May 1, 2022 at 6:24
  • \$\begingroup\$ @Razetime Damn you are right. \$\endgroup\$
    – oeuf
    May 1, 2022 at 8:06
  • \$\begingroup\$ @Razetime For some reason when running on ATO it refuse to run and running on TIO returns error so I am gonna leave this for a while. \$\endgroup\$
    – oeuf
    May 1, 2022 at 8:10
  • \$\begingroup\$ You should report this problem to pxeger. If you wanna verify it, try running it on irb in your terminal. \$\endgroup\$
    – Razetime
    May 1, 2022 at 8:41
  • 1
    \$\begingroup\$ 8 bytes \$\endgroup\$
    – Jordan
    Nov 15, 2022 at 22:43
1
\$\begingroup\$

Flobnar, 22 bytes

+<> v:
,-|\@1
.9>> +
:

Try it online!

\@1
> +   Set TOS to 1 on init (and increment TOS on every iteration)
  :

:
+<    Print TOS as number, print 0 (return value of `.`) as char,
,-|   and check if TOS - 9 is zero
.9
:

> v
| @1  Return to start with updated TOS if nonzero,
>  +  evaluate to TOS+1 (10) otherwise (which is printed at the end)
   :
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1
\$\begingroup\$

rig, 3 bytes

rig is a work-in-progress esoteric stack-based language. I'm just having fun with looking for challenges it can already solve, with its few commands.

τr+

is a valid code that prints "1,2,3,4,5,6,7,8,9,10"

Try it here

Why?

τ    - push 10 to the stack              [10]
 r   - push range(10) to the stack       [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
  +  - increment every element           [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
     - implicit print
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0
1
\$\begingroup\$

Fig, \$3\log_{256}(96)\approx\$ 2.469 bytes

a10

Try it online!

I dare you to golf this further.

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1
\$\begingroup\$

Go, 52 bytes

import."fmt"
func f(){for i:=1;i<11;i++{Println(i)}}

Attempt This Online!

Go, 39 bytes, prints to STDERR

func f(){for i:=1;i<11;i++{println(i)}}

Attempt This Online!

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1
\$\begingroup\$

shell commands, 7 bytes

seq 10

or also

jot 10

Thanks.

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3
1
\$\begingroup\$

Uiua SBCS, 5 bytes

+1⇡10

Try it!

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1
  • \$\begingroup\$ Some alternate 5s: dedup where range 11, drop 1 range 11, negate range negate 10 or under negate range 10 \$\endgroup\$
    – noodle man
    Apr 2 at 13:04
1
\$\begingroup\$

YASEPL, 10 bytes

=a`1+<}4,9
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2
  • \$\begingroup\$ Welcome to Code Golf SE, nice language \$\endgroup\$
    – noodle man
    Feb 8 at 14:49
  • \$\begingroup\$ @noodle-man thank you noodle man \$\endgroup\$ Feb 8 at 14:58
1
\$\begingroup\$

awk - doing it the grade school arithmetic approach

  • the OP only said "arbitrary separators" - so empty string ("") in between the numbers qualify OP's criteria, since OP never mentioned the separators must be positive in length.

awk '$_=int(3E-3^-4)-102' <<<''

12345678910
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1
  • \$\begingroup\$ I love how this is longer than the output because of the empty separators :D \$\endgroup\$
    – Clashsoft
    Apr 2 at 12:58
1
\$\begingroup\$

TECO, 9 bytes

` is interpreted as ASCII 27, ESC. Assume current buffer is empty.

10<I1`Z=>

Which outputs

1
2
3
4
5
6
7
8
9
10

Explanation

10< ! do 10 times      !
I1` ! insert "1" into buffer !
Z=  ! print number of characters in buffer !
>   ! end do !
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0
\$\begingroup\$

jq, 12 characters

(11 characters code + 1 character command line option.)

range(1;11)

Sample run:

bash-4.3$ jq -n 'range(1;11)'
1
2
3
4
5
6
7
8
9
10

On-line test

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0
\$\begingroup\$

JavaScript (using external library) (39 bytes)

x=>console.log(_.Range(1,10).Write(""))

Link to lib:https://github.com/mvegh1/Enumerable/

Explanation of code: _.Range creates the array [1,..10], Write joins the array into a string, console.log puts to StdOut

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4
  • \$\begingroup\$ I was thinking about using something like Underscore's range, but figured something pure would be a bit more impressive. Nice solution! \$\endgroup\$
    – Swivel
    Jul 21, 2016 at 20:03
  • \$\begingroup\$ Thanks! Yeah yours is way shorter than mine hahaha, I need to learn the ... syntax! \$\endgroup\$ Jul 21, 2016 at 20:31
  • \$\begingroup\$ MDN has an article on the Spread Operator :) -- I started with [...Array(10)].map((v,i)=>++i), but that was 30 bytes and I was hoping to do better than the first JavaScript answer on here (24 bytes)! Then I realized that a String is, more or less, just an array of characters. So I tried the spread operator, and viola! \$\endgroup\$
    – Swivel
    Jul 21, 2016 at 20:36
  • \$\begingroup\$ Ahhhh ok wow I see what its doing. Not bad!! \$\endgroup\$ Jul 21, 2016 at 20:40
0
\$\begingroup\$

JavaScript (Node.JS 5 / Harmony / ES2015), 19 bytes

[...`123456789`,10]

Output

[ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ]

Try it here or run node -p -e "[...'123456789',10]"

(For older versions of Node.js, like LTS 4.4.7, use node --harmony)

\$\endgroup\$
7
  • \$\begingroup\$ Previous attempts were: [...Array(10)].map((v,i)=>++i) and [...Array(11).keys()].slice(1), but both ended up with 30 bytes, which was less than the other JavaScript submissions here. \$\endgroup\$
    – Swivel
    Jul 22, 2016 at 14:41
  • 1
    \$\begingroup\$ 1) Your code does not print the integers; but as -p clearly adds functionality to it, there should be some penalty for it imo. 2) When I log that to my console (without node), I get an array with nine strings and one integer 3) This is pretty close to a hard coded result. \$\endgroup\$
    – Titus
    Jul 22, 2016 at 14:56
  • \$\begingroup\$ There were both an [...Array(10)].map((_,i)=>i+1) and an [...Array(11).keys()].slice(1) elsewhere, just wrapped with alert making them 37 bytes \$\endgroup\$ Jul 22, 2016 at 16:45
  • \$\begingroup\$ @Titus (1) This is Node.JS, not browser-based JavaScript. They are two different things. However, I can kind of see your point with -p. (2) "This includes arbitrary separators (commas, semicolons, newlines, combinations of those, etc., but no digits), prefixes and postfixes (like [...])." (3) Arguable. \$\endgroup\$
    – Swivel
    Jul 22, 2016 at 20:05
  • \$\begingroup\$ @PaoloBonzini You're late to the party. Both of those were posted by Titus four hours ago. Both of which I left in the comments here and on another answer roughly 24 hours ago :) Granted, I didn't put them in my solution, but that's beside the point. -- As for using an alert instead, I defer to (1) in my response to Titus. I primarily develop in Node.JS and use the Node.JS REPL, not browser-based JavaScript. These are two different platforms; similar implementations of a similar spec, but arguably not the same exact thing. I respect the position, though. \$\endgroup\$
    – Swivel
    Jul 22, 2016 at 20:10
0
\$\begingroup\$

LibreLogo, 20 bytes

Code:

print set range 1 11

Output:

enter image description here

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0
\$\begingroup\$

Triangular, 15 bytes

S]([email protected]/AS%<

Formats into this triangle:

    S
   ] (
  l . U
 @ . . i
/ A S % <
  1. The first command, S, stashes the top of stack (0) in memory. (This is only so that the U will work the first time.)
  2. ( opens a loop.
  3. U pulls memory onto stack.
  4. i increments the stack value.
  5. < directs the IP left, hitting %, which prints the top of stack as an integer.
  6. S stashes the top of stack in memory.
  7. A pushes 10 to the stack.
  8. / directs the IP up-right, hitting @, which prints the top of stack (10) as ASCII (\n).
  9. l checks if the second-to-last stack value (the counter value) is less than 10.
  10. If so, jump back to (. Otherwise, exit the program.
\$\endgroup\$
1
  • \$\begingroup\$ 14 \$\endgroup\$
    – squid
    Sep 16, 2019 at 13:17
1
5 6 7
8
9

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