Print numbers from 1 to 10

Question

This might be a very simple challenge, but I am surprised it hasn't been done on code-golf yet:

Print all Integers from 1 to 10 inclusive in ascending order to standard output.

Your output format can be whatever your language supports. This includes arbitrary separators (commas, semicolons, newlines, combinations of those, etc., but no digits), and prefixes and postfixes (like [...]). However, you may not output any other numbers than 1 through 10. Your program may not take any input. Standard loopholes are disallowed.

This is code-golf, so shortest answer in bytes wins!

Leaderboard

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Answer 1

Carrot, 20 bytes

1 2 3 4 5 6 7 8 9 10

Or if we don't need a separator for 11 bytes:

12345678910

Anything before a ^ in Carrot is placed onto the stack and then that is implicitly output at the end of the program.

With the current version of Carrot this seems to be the shortest way of doing it although I would like to post a none hard coded version if I find one.

Answer 2

Charcoal, 5 bytes

Ｉ…·¹χ

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Explanation:

Ｉ        Implicitly print the elements (casted as string) of
  …·      the inclusive range
    ¹χ    from 1 to 10 (default value of the χ variable)

Answer 3

T-SQL, 27 bytes

Boring answer.

PRINT'1,2,3,4,5,6,7,8,9,10'

Less boring with a WHILE, 51 bytes

DECLARE @ INT=1WHILE @<11BEGIN PRINT @ SET @+=1 END

Answer 4

Cubically, 16 bytes

(*1+1/1%@LUL'B)8

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(*1+1/1%@LUL'B)8
(                 do..while loop
 *1+1/1            add 1 to notepad
       %           print notepad as integer
        @          output notepad as ASCII (delimiters)
         LUL'B     algorithm with period 10
              )8  loop while cube unsolved

Output (? denotes an unprintable):

1?2?3?4?5?6?7?8?9   10

Answer 5

Pyth, 4 2 bytes

Well, I guess I think more about legitimate functionality/usability, but this is Code Golf, where usability comes after functionality.

-2 by not formatting my output.

ST

Explanation:

S        1-indexed range from 1 - ...
 T       Ten

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Pyth, 4 bytes

VSTN

Explanation:

V        For...
 ST      in the 1-indexed range from 1 - 10 (T)
   N     Print the current item

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Or alternatively...

VThN

Explanation:

V        For...
 T       In range from 0 - 9
  hN     Print (the current item + 1)

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Pretty simple.

Answer 6

Kotlin: 30?/31/49 bytes

---

Variable of function type: 30 bytes

val a={(1..10).map(::println)}

This might be considered cheating.

Invokable via a() like the later function. Functions are first-class citizens in Kotlin, so they can be assigned to variables aswell. The type of ´val a´ is technically () -> List<Unit>, a function that takes nothing and returns a "list of nothing", but we wouldn't be on code golf using a language that doesn't have implicit types, would we? 😊

---

Function: 31 bytes

fun a(){(1..10).map(::println)}

---

Executable: 49 bytes

fun main(a:Array<String>){(1..10).map(::println)}

Answer 7

Julia 0.6, 11 bytes

show.(1:10)

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Answer 8

Pip, 3+1 = 4 bytes

\,t

Runs with the -n flag to separate the output with newlines.

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Explanation:

\,         Inclusive range of 1 to
  t        10

Answer 9

Forte, 64 bytes

12PRINT42-41:LET42=42+1:LET11=11+3
13LET99=11
99LET12=12+3
40END

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How?

In Forte, you do things by redefining numbers. For example, LET 4=5 is a statement that defines 4 to be 5. From now on, anytime 4 occurs in the program, it is replaced by 5--even as the result of expressions like 2+2. There are no looping constructs in the language; control flow is accomplished by redefining line numbers.

With that introduction, let's look at what this program does.

The first line executed is line 12. This prints 42-41, which (currently) results in 1. Next, it redefines 42 to be 42+1--that is, 43. From now on, anytime 42 occurs in the program, we'll actually use the value 43. Finally, it redefines 11 to be 11+3--that is, 14. This is setup for the loop we're about to enter.

• Redefinitions: 11->14; 42->43

Line 13 is executed next. It redefines 99 to be 11--except 11 has previously been redefined, so 99 actually becomes 14.

• Redefinitions: 11,99->14; 42->43

Now, the previous instruction has an effect on the control flow, because 99 happens to be a line number. Line 99 is now considered to be line 14, and thus we execute it next (rather than line 40, which would otherwise have come next). This line redefines 12 to be 12+3--that is, 15.

• Redefinitions: 11,99->14; 12->15; 42->43

And now the next instruction is the newly christened line 15, which prints 42-41 again... except that 42 is now 43, so it actually outputs 2. It then redefines 42 43 as 44 and 11 14 as 17.

• Redefinitions: 11,14,99->17; 12->15; 42,43->44

The next instruction is line 17 (the original line 99), which redefines 15 to be 18. And so lines 12/15/18 and 99/11/14/17 keep alternating back and forth, incrementing each other and printing ever-increasing values of 42-41, until we reach line 39. This prints 10 (42 now having reached a value of 51), redefines 42 and 11 again (but that won't matter), and then we move on to the next statement, line 40--which ends the program.

Simple, right?

Answer 10

17, 48 bytes

17 was made after the challenge was released, so it is not competing, though it still scored worse than most other answers because it isn't a golfing language, or very usable at all.

Outputs 1 to 10 seperates by \x11 (ascii value 17)

0{#
1 +
:
10 @
9 >
0 @
# $$
$}777{0 10 @
0 0 @}

Block 777(first block run): Initialises value 17 to 0. Runs block 0

Block 0: Loads value 17(relies on returning of 17 from stack when empty stack), adds 1, duplicates, stores at 17, if value > 9 pushes 1, else 0, stores value at 0, loads from 17, prints number, print ascii charater 17(relies on returning of 17 from stack when empty stack again)

Answer 11

Perl 6, 11 bytes

Two solutions with the same count:

print ^10+1

and

print 1..10

Output: 1 2 3 4 5 6 7 8 9 10

Try both of them on Try It Online!

Answer 12

Sd, 50 Bytes

++++++++++@**********.-/.-/.-/.-/.-/.-/.-/.-/.-/.!

How it works:

++++++++++                                          | Set variable 1 to 10
          @                                         | Mark read location
           **********                               | Set variable 2 to 10
                     .                              | Replace the instruction in position given by variable 2 with the ascii character given by variable 1
                      -/.                           | Subtract one from each variable and repeat
                         -/.-/.-/.-/.-/.-/.-/.-/.   | Repeat some more
                                                 !  | Print all values before the @ (as ascii)

Answer 13

Pyt, 3 bytes

1ᴇř

1     push 1
 ᴇ    10^1
  ř   range from 1 to 10
      Implicit output

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Answer 14

Stax, 2 bytes

Am

Run online

Added for completeness.

A       Push 10
 m      Map over range, implicit output

Answer 15

Canvas, 4 2 bytes

ＡＲ

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Answer 16

Jotlin, 15 12 bytes

p((0..9)+10)

Gets the numbers 0..10, makes a list out of them, and then prints the result

Answer 17

QUARK, Non competing 7 bytes

5.625 bytes encoded.

1 10⋯

This is incredibly simple. Just pushes 1 and 10 to the stack, and creates a inclusive range out of them. The interpreter prints out the contents of the stack when the program ends, so no print command is needed. (Plus the print command doesn't work with arrays yet, and prints out a garbled mess, so :P)

Answer 18

KoopaScript, 78 (28, 20) bytes

def i a if \%va is \%v set a 0;setath a \%va + 1;if \%va smaller 11 print \%va

This prints the numbers 1 to 10, as well as a lot of information about the currently running code (because reasons). KS doesn't actually have a way to break loops yet, so this keeps running until the interpreter is reloaded. It stops printing at 10, though.

def i a               - Define a function with the name i and call it 1000/NaN (i.e. many) times a second
if \%va is \%v        - if the variable with the name a is undefined,
set a 0;              - set it to 0
setath a \%va + 1;    - set the variable a to <the variable with the name a> + 1
if \%va smaller 11    - if the variable with the name a is smaller than 11,
print \%va            - trace the variable with the name a

To avoid printing debug info, either load this in an init script, or use this slightly longer (90) version that disables logging:

def i a set verbose;if \%va is \%v set a 0;setath a \%va + 1;if \%va smaller 11 print \%va

set verbose;          - set the variable called 'verbose' (which handles whether to trace debugging stuff) to ""

Alternatively,

print "1 2 3 4 5 6 7 8 9 10"

This is only 28 bytes and technically does what the specification entails. Other commands, e.g. if, display all the numbers, but, as it's caused by an error in the program, it doesn't display if logging is disabled.

Technically,

1 2 3 4 5 6 7 8 9 10

prints all the numbers with commas between them, in the debug log. That brings it down to 20. I guess it's up to the reader (stacker? golfer?) to decide which one is the most correct

Answer 19

Stack Cats, 28 + 4 (-nm) = 32 bytes

-(:!_:!_:-_-_]>{<:_-!:]}]<)-

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Stack Cats is a reversible esoteric language by Martin Ender. All of its commands can be reversed by applying the command's mirror image, and the whole code itself must be the mirror image of itself. Since half of the code is always redundant, it has -l and -m flags which allow to omit half of the program. -m appends the mirror image to the right (except the center character), so the full program is -(:!_:!_:-_-_]>{<:_-!:]}]<)-(>[{[:!-_:>}<[_-_-:_!:_!:)-.

Stack Cats operates on an infinite tape of stacks, all of which are initially empty with infinite amount of implicit zeroes at the bottom. Here is a summary for the relevant commands:

• - Negate the top.
• ! Apply bitwise NOT to the top.
• : Exchange top two elements of the current stack.
• _ Pop a, Pop b, Push b, Push b-a.
• >, < Move the cursor right or left.
• ], [ Move the cursor right or left, along with the top. (Also called "Push")
• (, ) Enter or exit a loop if the top is strictly positive.
• { Enter a loop and remember the top.
• } Exit a loop if the current top is equal to the remembered top.

Also, due to the limitations of the language, the input/output occurs only at the start/end of the program. At the start of the program, each input is pushed to the initial stack, which has a -1 at the bottom. At the end of the program, all values on the stack are printed from top to bottom, with optional -1 at the bottom ignored. So this program starts with a single -1 on the stack, and ends with 1..10 on the current stack.

How the code works:

Code    Stack                  Description
        [-1]
-(      [1]                    Negate the top; Enter the loop
:!_     [1 0]->[1 -1]->[1 2]   Swap top two (with implicit zero); Bit-NOT; Subtract
:!_     [2 1]->[2 -2]->[2 4]   Same
:-_     [4 2]->[4 -2]->[4 6]   Swap; Unary minus; Subtract
-_      [4 -6]->[4 10]         Generate 10
]>      [4] [10] [*]           Push 10 to a new stack; Move right again
{                              Remember 0
<:      [4] [n 0*] [...]       Swap with implicit zero
_-!     [4] [n n-1*] [...]     Generate n-1
:]      [4] [n-1] [... n*]     Push n to the right
}                              Loop while n is not zero
]<                             Remove last zero
)                              Top is 1; Exit the loop
-(...)-                        Skip the rest

There is a standard construct <(...)*(...)> which allows to ignore half of the program, in order to program more effectively by human. I used a similar one -(...)-(...)- which utilizes the initial -1, but it only works with no-input programs and the final top should be strictly positive.

Ignoring half of the program is quite a waste of space, so there is an open bounty for more efficient golfing with both halves. I'm aiming for this in the long run, though it's not yet clear how to even start tackling the problem.

Answer 20

cQuents, 6 4 bytes

#t&$

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Explanation

#t       Set default input (n) to 10
  &      Mode: Sequence 2 (print first n items in sequence, 1-indexed)
   $     Each item in the sequence is the current index

Answer 21

Deadfish~, 4 bytes

{io}

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Increment, then output; repeat ten times.

Answer 22

(K+R)eg, 6 bytes (SBCS)

6 bytes:

\
ï_(.

11 bytes:

9(9|:"1-)1$

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One byte longer

How it works

9(9|:"1-) # A countup program from 1 to 9 and then (astonishingly) adds a 0; I have no idea how it works.
1         # Push 1
$         # Swap top 2 items
# The stack is implicitly outputted.

Answer 23

TacO, 7 bytes

@%10
 i

try it online! The number 10 is the first branch of the looping construct %, so TacO runs the second branch, which just contains i, 10 times, giving i numbers 1-10.

Answer 24

Seed, 4232 4039 3981 bytes

To be golfed.

11 806065440241409087125357198607542800075970572928765093042958164984128856153119364694304946533565974155065813564463607464907294493213625991570210498180131922642836049048379926678214090306958078942950505666942158861663318082805922649360548872276728753092705551896201785489318797454097467866454815778688721780170362909784978852186756623253868868917034035335528463229661772327867673360158173714723733025733656646487909489808220640703644162017799947346882823939914644265408484708544566367174322747059393061445510836708923637982737011363312927325448282786060215442674975310709523697911998742881715764878830975686475127091070151990734113230052589483007904386955837951416230150553553131824081272209795780490205576443141598594094128682959852257277648831764416301409205933849585487706444517684177487650836580944108733813423567329150282262574305747736976499413900964122878760201959007114022481011295839141271138446203186069264532462250500186116493184286012088625239590991537830133224608224949348931933311034455280978164515936125672561757104517575527099692465553902153481143524868360127998596923638301974413167583429193105287970847431486813381197765539764522094782334194830005111603128673518265195317929281022739571069159575305773074583173243911197334517405412628068284686691469982559791730541223895403558031955848768117060646768348463561209935808045637507281128179915889035768211511504144114447348017724691523076211025635445333081644368060430405389019848215116047520242946447978917490619742817523907421559319563570816232286092378925478777387843124296450405990835394943021252863488969545687903232603331252281246680860082655523490245738107512918342578050153655018310720283275985429190062871812385817909146120892975424714212971890662091259299688100739835789852338707333214399083184648552682989269071097042033924364887158088125417342061047907455595001558776113845342454604060641417114322284932278126981432767955018317987960683429833483125151020913178712494155310545261553444170641615117711305756617133820567957209040625095889033833683868477968222981257864647555382502179925116320599028456728151421211950504164587366555426478479957000176097833838329163859553682184378396176530388849222864560228925976975341162944244301834305126128097819354250219559409487388887032429560483598135806164050794728591878728116747953265919795701481292222092677282626562421120330436952746759320383166496345689472683465785160396471114988424810146619802843389460581036625456336614635949441077117888570209114560201469774858952308539634363125726651042307946127813908314293240378846347559662225224004298822713302904050471977675138246925540751643515879128105969891674920959645532198204680833150120401421252646736795292132103275342152265451058336500878555688383134027160586652276624279294501247326175308886148638933724425782375226226354458022684652099014849380343822015940473137950787091045988775407006084669595433268270085699081145780497235745383972369977375564713816849012360495596752065665250235877504147680897910657602532177993907221958136528121236676455264099257048759319470710174615005668917675853889646496531814039709503285164186416096735666867062585670181891889551756178657495723233678891549411496581200696462439988553007997103954989290028776888309286564702133992674291744804531900851060090385178725409757099606879757766288322010567612896350258272282241111517435795569303408578713936760574865986977532034796036053889911992836923158428809242575557886427002935479153509101800373188079516076598125218940752155364580400861924119667725548877677649837117601878482958020472764206345843076482381692875591020886968748894499648171413242376922343979630964910668516043571246988639289969853916731069660002514237788846617524295024699798200028558752532671916185460167291108476912591550362203490594401624213451585637461718363114331483866061411154610681167668195013207060532734483192219734129165226320299742868143084807270641847983148272764305800992489421803505337228286598600236556437401089147741524552516814465259338644189950504662

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Answer 25

Javascript 45 Bytes

alert("10charstrn".split("").map((e,i)=>i+1))

This is currently quite poor, but if there happens to be a JS constant which is an array of length 10, this could improve a lot.

Answer 26

ROOP, 15 bytes

123456789
h(10)

Solution with hardcoded numbers, I'm still trying to find a shorter program.

In this language each digit becomes an individual object. Number 10 is written in parenthesis to make it a single object. The operator h prints all objects that are currently in the program, separated by a space, then halt.

Answer 27

Keg, 5 bytes

I am too lazy to change my answers to conform the new code page, unless I get notified.

ėÏ_(.

Push 10(saving a byte), take iota [10..0], remove last, and then print.

Answer 28

Perl 5, 13 bytes

say for 1..10

Example execution

perl -E 'say for 1..10'

Answer 29

PHP (with goto) - 46 38 34 bytes

More byte-saving suggestion from Shaggy:

<?php Z:echo@++$i;if($i<10)goto Z;

And people say that goto is the work of the Devil. Or something.

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PHP (goto-less) - 30 29 bytes

<?php while(@$i<11)echo@$i++;

PHP - 11 bytes

12345678910

Well, someone had to?

Answer 30

Poetic, 163 bytes

this is asking a lot
o,i admit i was a victim
i was tired of this situation
o,i had a break
i couldnt be sicker of it
thats a very different outcome than i thought

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Outputs the numbers from 1 to 10, separated by ASCII 0 (NUL) characters.

For being such a simple type of program, this was an interesting challenge to golf.