105
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This year's UEFA Euro 2016 is over and besides a couple of negative headlines there has been a very positive surprise as well – the Iceland national football team. Let's draw their national flag.

Input

Well, obviously this challenge has no input.

Output

  • Draw the flag of Iceland in any applicable visual format of at least 100 x 72 pixels or 25 x 18 characters.
  • Save the output to a file or present it instantly – example formats are: images like png, jpg etc., vector graphics, draw on HTML canvas or even use non-whitespace characters for visualization.
  • Use these colors: blue: #0048e0, white: #ffffff and red: #d72828.
  • If your language doesn't support specific color values, use the standard values for red, blue and white from the ANSI color codes.
  • Draw the flag with the correct proportions, as shown in the figure below:

Boilerplate

  • You can write a program or a function. If it is an anonymous function, please include an example of how to invoke it.
  • This is so shortest answer in bytes wins.
  • Standard loopholes are disallowed.

Leaderboard

var QUESTION_ID = 85141; // Obtain this from the url
// It will be like https://XYZ.stackexchange.com/questions/QUESTION_ID/... on any question page
var ANSWER_FILTER = "!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe";
var COMMENT_FILTER = "!)Q2B_A2kjfAiU78X(md6BoYk";
var OVERRIDE_USER = 41859; // This should be the user ID of the challenge author.
var answers = [], answers_hash, answer_ids, answer_page = 1, more_answers = true, comment_page;function answersUrl(index) {return "https://api.stackexchange.com/2.2/questions/" +  QUESTION_ID + "/answers?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + ANSWER_FILTER;}function commentUrl(index, answers) {return "https://api.stackexchange.com/2.2/answers/" + answers.join(';') + "/comments?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + COMMENT_FILTER;}function getAnswers() {jQuery.ajax({url: answersUrl(answer_page++),method: "get",dataType: "jsonp",crossDomain: true,success: function (data) {answers.push.apply(answers, data.items);answers_hash = [];answer_ids = [];data.items.forEach(function(a) {a.comments = [];var id = +a.share_link.match(/\d+/);answer_ids.push(id);answers_hash[id] = a;});if (!data.has_more) more_answers = false;comment_page = 1;getComments();}});}function getComments() {jQuery.ajax({url: commentUrl(comment_page++, answer_ids),method: "get",dataType: "jsonp",crossDomain: true,success: function (data) {data.items.forEach(function(c) {if (c.owner.user_id === OVERRIDE_USER)answers_hash[c.post_id].comments.push(c);});if (data.has_more) getComments();else if (more_answers) getAnswers();else process();}});}getAnswers();var SCORE_REG = /<h\d>\s*([^\n,]*[^\s,]),.*?(-?\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/;var OVERRIDE_REG = /^Override\s*header:\s*/i;function getAuthorName(a) {return a.owner.display_name;}function process() {var valid = [];answers.forEach(function(a) {var body = a.body;a.comments.forEach(function(c) {if(OVERRIDE_REG.test(c.body))body = '<h1>' + c.body.replace(OVERRIDE_REG, '') + '</h1>';});var match = body.match(SCORE_REG);if (match)valid.push({user: getAuthorName(a),size: +match[2],language: match[1],link: a.share_link,});});valid.sort(function (a, b) {var aB = a.size,bB = b.size;return aB - bB});var languages = {};var place = 1;var lastSize = null;var lastPlace = 1;valid.forEach(function (a) {if (a.size != lastSize)lastPlace = place;lastSize = a.size;++place;var answer = jQuery("#answer-template").html();answer = answer.replace("{{PLACE}}", lastPlace + ".").replace("{{NAME}}", a.user).replace("{{LANGUAGE}}", a.language).replace("{{SIZE}}", a.size).replace("{{LINK}}", a.link);answer = jQuery(answer);jQuery("#answers").append(answer);var lang = a.language;if (! /<a/.test(lang)) lang = '<i>' + lang + '</i>';lang = jQuery(lang).text().toLowerCase();languages[lang] = languages[lang] || {lang: a.language, user: a.user, size: a.size, link: a.link, uniq: lang};});var langs = [];for (var lang in languages)if (languages.hasOwnProperty(lang))langs.push(languages[lang]);langs.sort(function (a, b) {if (a.uniq > b.uniq) return 1;if (a.uniq < b.uniq) return -1;return 0;});for (var i = 0; i < langs.length; ++i){var language = jQuery("#language-template").html();var lang = langs[i];language = language.replace("{{LANGUAGE}}", lang.lang).replace("{{NAME}}", lang.user).replace("{{SIZE}}", lang.size).replace("{{LINK}}", lang.link);language = jQuery(language);jQuery("#languages").append(language);}}
body { text-align: left !important}#answer-list {padding: 10px;width: 290px;float: left;}#language-list {padding: 10px;width: 290px;float: left;}table thead {font-weight: bold;}table td {padding: 5px;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script><link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/Sites/codegolf/all.css?v=617d0685f6f3"><div id="answer-list"><h2>Leaderboard</h2><table class="answer-list"><thead><tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead><tbody id="answers"></tbody></table></div><div id="language-list"><h2>Winners by Language</h2><table class="language-list"><thead><tr><td>Language</td><td>User</td><td>Score</td></tr></thead><tbody id="languages"></tbody></table></div><table style="display: none"><tbody id="answer-template"><tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td><a href="{{LINK}}">{{SIZE}}</a></td></tr></tbody></table><table style="display: none"><tbody id="language-template"><tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td><a href="{{LINK}}">{{SIZE}}</a></td></tr></tbody></table>

If you can't find your answer, format your language and byte count as explained in the Leaderboard's "Info Section".


This challenge is inspired by Draw the national flag of france.

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  • 18
    \$\begingroup\$ Far more challenging would be the flag of my country, who also did a lot better than expected in the Euros this year - Wales. :-) \$\endgroup\$ – Gareth Jul 11 '16 at 10:54
  • 22
    \$\begingroup\$ @Gareth I'm looking forward to a waterproof specification of the dragon. ;) \$\endgroup\$ – Martin Ender Jul 11 '16 at 11:04
  • 3
    \$\begingroup\$ It looks like the blue in the above image is darker than the actual #0048e0 \$\endgroup\$ – Luis Mendo Jul 11 '16 at 12:32
  • 9
    \$\begingroup\$ @MartinEnder Does carving it on a stone tablet count? That's waterproof. \$\endgroup\$ – immibis Jul 12 '16 at 11:11
  • 4
    \$\begingroup\$ @MartinEnder Mathematica will have one. \$\endgroup\$ – gcampbell Jul 12 '16 at 18:57

79 Answers 79

256
\$\begingroup\$

Python 3, 190 172 171 169 167 160 159 147 143 bytes

Using PIL version 1.1.7 which has a deprecated but not removed offset method.

from PIL.ImageDraw import*
i=Image.new('RGB',(25,18),'#d72828')
Draw(i).rectangle((1,1,23,16),'#0048e0',~0)
i.offset(9).resize((100,72)).show()

Creates a 25*18 pixel image filled with red then draws a 23*16 pixel rectangle filled with blue with white outline of one pixel. It then offsets the image by (9,9) which wraps on the edges, resizes it to 100*72 then shows it in a window.

Flag before offsetting:

enter image description here (resized to 100*72)

Output:

enter image description here

Animated:

enter image description here

Edit1: Golfed 18 bytes by removing the cropping by initially creating a 25*18 image.

Edit2: Golfed 1 byte by using #fff instead of white.

Edit3: Golfed 2 bytes by aliasing imports.

Edit4: Golfed 2 bytes by removing the second argument of the offset method .

Edit5: Golfed 7 bytes by showing the image instead of saving. (needs imagemagick installed on Unix)

Edit6: Golfed 1 byte by rewriting imports.

Edit7: Golfed 12 bytes by rewriting imports again. (thanks by @Dennis)

Edit8: Added animation.

Edit9: Updated animation as it was missing the last frame.

Edit10: Golfed 4 bytes thanks to Albert Renshaw!

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  • 40
    \$\begingroup\$ Really nice answer. \$\endgroup\$ – insertusernamehere Jul 11 '16 at 14:30
  • 15
    \$\begingroup\$ This is genius! (Viking)Hat off to you. \$\endgroup\$ – Ioannes Jul 11 '16 at 15:59
  • 22
    \$\begingroup\$ Wow, it's rare that I vote on code-golf type questions on SO, but it's even rarer that I'll join a whole new community just to do so. This offset hack is reminiscent of what we used to have to do before you young whippersnappers got your oodlebytes of memory to work with. Excellent job. \$\endgroup\$ – user56228 Jul 12 '16 at 0:53
  • 4
    \$\begingroup\$ genius,really! 💡 \$\endgroup\$ – InuYaksa Jul 12 '16 at 7:22
  • 3
    \$\begingroup\$ If you do from PIL.ImageDraw import*, I becomes Image and D.Draw becomes Draw, saving 11 bytes. \$\endgroup\$ – Dennis Jul 12 '16 at 16:44
115
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x86 real-mode machine code for DOS COM, 69 65 63 62 bytes

Iceland flag produced

The code is meant to be executed as a DOS COM executable.

Special thanks

  • meden, saved four bytes.
  • meden, saved two bytes and removed the flickering.

Machine code (in hex bytes)

68 00 A0 07 B8 13 00 CD      10 BE 23 01 AD 91 AD 91 
AC E3 FE 60 30 ED F3 AA      61 81 C7 40 01 FE CD 75 
F2 EB E9 FA B4 00 00 09      28 B4 46 00 0F FA 28 80 
57 0F 14 B4 0C 50 00 FA      14 0C 00 64 00 00

Assembly source

Source is for NASM.

ORG 100h

push 0a000h
pop es

mov ax, 13h
int 10h

mov si, data


_draw:
 lodsw
 xchg ax, cx

 lodsw
 xchg ax, di

 lodsb

_cycle:
 jcxz _cycle

 ;al = color
 ;cl = col
 ;ch = row

rect:
 pusha
 xor ch, ch
 rep stosb
 popa
 add di, 320
 dec ch
 jnz SHORT rect

jmp SHORT _draw


data: 

        db 250d
        db 180d
        dw 0000h
        db 09h


        db 40d
        db 180d
        dw 0070d
        db 0fh


        db 250d
        db 40d
        dw 22400d
        db 0fh

        db 20d
        db 180d
        dw 80d
        db 0ch


        db 250
        db 20
        dw 25600d 
        db 0ch


        dw 0000h
\$\endgroup\$
  • 12
    \$\begingroup\$ This is a really cool first answer! Welcome! \$\endgroup\$ – AdmBorkBork Jul 11 '16 at 21:00
  • 4
    \$\begingroup\$ You can save 2 bytes by replacing 'mov' with 'xchg' at 10h & 13h and another 2 bytes by replacing 'test cx,cx/jz' with 'jcxz' at 16h \$\endgroup\$ – meden Jul 12 '16 at 10:10
  • 2
    \$\begingroup\$ Some more thoughts. Since the program runs in the infinite loop, you can avoid flickering just by making the loop shorter: _loop: jcxz _loop. You can also cut 2 bytes from the end of the data chunk if you change the loading order of cx and di \$\endgroup\$ – meden Jul 12 '16 at 13:47
  • \$\begingroup\$ Thanks again @meden. The flickering was completely unnecessary in effect :) I also removed the mov bx, 320 and moved the 320 into add di, 320 (previously add di, bx). \$\endgroup\$ – Margaret Bloom Jul 12 '16 at 14:04
  • \$\begingroup\$ Great. Now you've got a firm edge over all machine code answers in this challenge. Just for the sake of correctness: it'd better to move jcxz _cycle right after xchg ax,cx so it wouldn't load bytes past the end of the data. And there's some misleading comments in the source: ;dx = row. dx is not used anywhere in code. \$\endgroup\$ – meden Jul 13 '16 at 12:46
55
\$\begingroup\$

C, 194 191 183 Bytes

#define C "\x1b["
#define A "@@@@@@"
y;f(){for(;y++<14;)printf(y>5&&y<10?y>6&&y<9?C"31m"A A A A"@\n":C"0m"A"@@"C"31m@@"C"0m"A A"@@@\n":C"34m"A"@"C"0m@"C"31m@@"C"0m@"C"34m"A A"@@\n");}

-3 adding one @ on the #define A
-8 adding [ on #define C

Usage

main(){f();}

Output

image

valid basing on this comment from the OP

Double Size Output, 204 Bytes

#define C "\x1b["
#define B "████"
#define A B B B
y;f(){for(;y++<28;)printf(y>10&&y<19?y>12&&y<17?C"31m"A A A A"██\n":C"0m"A B C"31m"B C"0m"A A B"██\n":C"34m"A"██"C"0m██"C"31m"B C"0m██"C"34m"A A B"\n");}

image2

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  • 21
    \$\begingroup\$ the 5th upvote triggered a +810 rep network wide... Thanks! (Yes it's the first site where i reach the 200 rep :D) \$\endgroup\$ – Giacomo Garabello Jul 11 '16 at 14:58
  • 1
    \$\begingroup\$ Doesn't the result have to be "at least 100 x 72 units, where a unit is a pixel or a character"? This doesn't meet this requirement, but I suspect the OP made a mistake when formulating that definition. \$\endgroup\$ – Kritzefitz Jul 12 '16 at 14:07
  • 4
    \$\begingroup\$ @Kritzefitz Well, a character takes up many pixels, so it can be a pixel instead of a character. Found a hole. \$\endgroup\$ – Erik the Outgolfer Jul 13 '16 at 9:17
  • \$\begingroup\$ @GiacomoGarabello Whats the first site in the at pic where you got +150? I don't recognise the icon. \$\endgroup\$ – user8777 Jul 14 '16 at 4:41
  • \$\begingroup\$ @LegoStormtroopr It's PPCG!! Take a look at this GitHub Project! \$\endgroup\$ – Giacomo Garabello Jul 14 '16 at 5:29
31
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Excel VBA, 254 228 153 bytes

Couldn't really find a way to set column/row size to pixels(thereby making them square) because of the way Excel handles it so make them nice and square first.

Edit 1: Replaced RGB with returned values for colors, -26 bytes

Edit 2: Tried to add as many suggestions as I could, -75 bytes. I was not able to use &48e0 as a color and I am not sure why. Thanks everyone

Sub e()
c "A1:CV72", rgbBlue
c "AC1:AR72", -1
c "A29:CV44", -1
c "AG1:AN72", 255
c "A33:CV40", 255
End Sub

Sub c(d, f)
Range(d).Interior.Color = f
End Sub

Picture: Iceland Flag

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  • \$\begingroup\$ How did you make the cells square? Did you do it manually, or with some other script not included? I'd like to see it, even if it's not part of your scored program. \$\endgroup\$ – mbomb007 Jul 11 '16 at 16:49
  • \$\begingroup\$ I did it manually, the code to change the cell width is easy enough where I could have added it but the sizes aren't consistent between Row/Column or monitor resolutions unless you set the size based on pixels which can't be done from what I could find. From what I read you have to find the resolution and do some math to convert the pixels to the size the function accepts. \$\endgroup\$ – tjb1 Jul 11 '16 at 17:03
  • 1
    \$\begingroup\$ Also the code to convert it to pixels looks like it requires you hard code either some part of the resolution or PPI (I don't really understand the formula) so it seems it wouldn't work across all devices either. \$\endgroup\$ – tjb1 Jul 11 '16 at 17:10
  • 2
    \$\begingroup\$ And, just for completeness (to do with setting up square cells rather than the solution itself), if you switch to page layout view, you can set cell height and width to specific values like 0.2cm. This will be maintained once you switch back, and no need to try and work out the bizarre Excel aspect ratios :-) By the way, if you want some more cool Excel tricks, look up Joel Spolsky's "You suck at Excel" video. \$\endgroup\$ – user56228 Jul 12 '16 at 12:10
  • 3
    \$\begingroup\$ I think extra whitespace can be removed, even though it is added automatically later. \$\endgroup\$ – Erik the Outgolfer Jul 12 '16 at 16:00
29
\$\begingroup\$

MATL, 57 56 52 49 48 bytes

7:g2IvtPvt!9Mh2$X>2YG[0E28]8*255/7B[43DD]51/v2ZG

This produces the following figure (tested with the compiler running on Matlab and on Octave).

enter image description here

EDIT: You can experimentally try at MATL Online! (you may need to reload the page if it doesn't work initially).

How it works

7:g         % Range from 1 to 7 converted to logical: push array [1 1 1 1 1 1 1]
2           % Push 2
I           % Push 3
v           % Concatenate vertically into a 9×1 array
tPv         % Duplicate, flip vertically, concatenate. Gives a 18×1 array
t!          % Duplicate, transpose: 1×18 array
9M          % Push [1 1 1 1 1 1 1] again
h           % Concatenate horizontally: gives 1×25 array
2$X>        % Maximum of the two arrays, with broadcast. Gives a 18×25 array
            % with 1 for blue, 2 for white, 3 for red
2YG         % Show image with default colormap
[0E28]8*    % Push array [0 72 224] (blue)
255/        % Divide each entry by 255. Colors are normalized between 0 and 1
7B          % 7 converted into binary: push array [1 1 1] (white, normalized)
[43DD]51/   % Push array [215/255 40/255 40/255] (red, normalized)
v           % Concatenate vertically. Gives a 3×3 array
2ZG         % Use as colormap
\$\endgroup\$
26
\$\begingroup\$

CSS, 285 284 264 bytes

*,:before,:after{background:#fff;width:100;height:72}body{background:#0048e0;margin:0}:before,:after{content:"";position:fixed}:after{background:#d72828}html:before{top:28;height:16}body:before{left:28;width:16}html:after{top:32;height:8}body:after{left:32;width:8

Saved 1 byte thanks to @insertusernamehere.

Saved 20 bytes thanks to @user2428118, by removing all the pxs. Note that this requires the page to be rendered in quirks mode, so it doesn't work in Stack Snippets.

I could copy the Python approach of wrapping an image around at an offset, but it wouldn't be interesting to.

Ungolfed:

*, *::before, *::after {
  background: #fff;
  width: 100px;
  height: 72px;
}

body {
  background: #0048e0;
  margin: 0;
}

*::before, *::after {
  content: "";
  position: fixed;
}

*::after { background: #d72828 }

html::before { top: 28px; height: 16px }
body::before { left: 28px; width: 16px }
html::after { top: 32px; height: 8px }
body::after { left: 32px; width: 8px }

This uses the pseudo-elements (elements that aren't written in HTML) ::before and ::after to create the lines on the flag. The reason it works with no HTML is that in HTML5 the <html> and <body> elements are optional, so browsers automatically create them if they're not present.

More fun:

*, *::before, *::after {
  background: white;
  width: 100px;
  height: 72px;
}

body {
  background: #0048e0;
  margin: 0;
}

*::before, *::after {
  content: "";
  position: fixed;
}

*::after { background: #d72828 }

html::before { top: 28px; height: 16px }
body::before { left: 28px; width: 16px }
html::after { top: 32px; height: 8px }
body::after { left: 32px; width: 8px }

@keyframes change-color {
  from { filter: none }
  50% { filter: hue-rotate(360deg) }
  to { filter: none }
}

@keyframes transformations {
  from { transform: translate(150%, 100%) rotateZ(0deg) scale(0.7) }
  15% { transform: translate(150%, 100%) rotateZ(54deg) scale(1.8) }
  to { transform: translate(150%, 100%) rotateZ(360deg) scale(0.7) }
}

html {
  animation:
    0.7s linear infinite change-color,
    1s linear infinite transformations;
}

\$\endgroup\$
  • 2
    \$\begingroup\$ You can still save 1 byte by replacing white with #fff. \$\endgroup\$ – insertusernamehere Jul 11 '16 at 21:11
  • \$\begingroup\$ @insertusernamehere Yep, thanks. \$\endgroup\$ – gcampbell Jul 12 '16 at 5:40
  • 1
    \$\begingroup\$ If you apply the CSS in quirks mode (page without doctype) you can bring it down to 264 bytes by omitting px everywhere. \$\endgroup\$ – user2428118 Jul 12 '16 at 10:11
  • \$\begingroup\$ @user2428118 Even more useful considering that there's no HTML, therefore no <!doctype html>! \$\endgroup\$ – wizzwizz4 Jul 12 '16 at 17:32
  • \$\begingroup\$ @user2428118 For some reason it doesn't work for me in mobile Safari. I'll have a look when I'm next at a computer. \$\endgroup\$ – gcampbell Jul 12 '16 at 19:05
25
\$\begingroup\$

Bash + Imagemagick 7, 94 90 86 85 bytes

magick -size 84x56 xc:#0048e0 ${s=-splice 8x8}+28+28 -background \#d72828 $s+32+32 x:

Saved 8 bytes, thanks to @manatwork, and 1 byte, thanks to @GlennRanders-Pehrson

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  • 5
    \$\begingroup\$ If you specify x: instead of output file name, convert will display the result in a window, which is also acceptable. And is enough to just escape the sharp, no need to quote: \#d72828. \$\endgroup\$ – manatwork Jul 11 '16 at 15:29
  • 2
    \$\begingroup\$ Usually we label such answers as Bash + Imagemagick. On bash side you can save another 4 characters: convert -size 84x56 xc:#0048e0 ${s=-splice 8x8}+28+28 -background \#d72828 $s+32+32 x:. \$\endgroup\$ – manatwork Jul 12 '16 at 10:36
  • \$\begingroup\$ Just a stupid question: Can you do ${s=-splice 8x8}+56? \$\endgroup\$ – Erik the Outgolfer Jul 13 '16 at 9:48
  • \$\begingroup\$ @EʀɪᴋᴛʜᴇGᴏʟғᴇʀ +56 is treated as +56+0, not +28+28. \$\endgroup\$ – bodqhrohro Jul 13 '16 at 10:16
  • 2
    \$\begingroup\$ You can save another byte by using a recent version of ImageMagick; then the command can be "magick" instead of "convert". \$\endgroup\$ – Glenn Randers-Pehrson Jul 13 '16 at 11:17
20
\$\begingroup\$

ZX Spectrum BASIC, 210 141 92 bytes

1 LET n=-VAL "8.5": FOR y=n TO -n: FOR x=n TO VAL "16": LET p=VAL "271"(PI-(ABS x<SQR PI OR ABS y>SQR PI)-NOT INT ABS x*INT ABS y): PRINT PAPER p; BRIGHT p>PI;" ";: NEXT x: PRINT : NEXT y

enter image description here

Size determined as the size of the BASIC program on tape via SAVE. A lot of the golfing credit to some members of the ZX Spectrum group on Facebook, in particular @impomatic and Johan Koelman.

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  • \$\begingroup\$ Seeing those PAPER and BRIGHT brings so many good memories :-) \$\endgroup\$ – Luis Mendo Jul 12 '16 at 0:01
  • \$\begingroup\$ Is there any info on how much memory a ZX Spectrum BASIC program takes? I thought it was a "tokenized" language, i.e. I expected FOR, NOT etc to take up only 1 or maybe 2 bytes each \$\endgroup\$ – Luis Mendo Jul 12 '16 at 0:19
  • 1
    \$\begingroup\$ @LuisMendo Yes, it is tokenized - FOR is precisely one byte. However, numbers are "anti-tokenized" in that they are stored as both their text and binary forms and take up 5 more bytes than you'd expect, hence NOT PI instead of zero and the like. \$\endgroup\$ – Philip Kendall Jul 12 '16 at 5:13
  • \$\begingroup\$ 132 bytes by removing the AT and adjusting the boundary test twitter.com/john_metcalf/status/752760203007791105 \$\endgroup\$ – impomatic Jul 12 '16 at 7:06
  • 1
    \$\begingroup\$ 122 bytes with some further optimizations twitter.com/john_metcalf/status/752783690179211264 \$\endgroup\$ – impomatic Jul 12 '16 at 8:37
14
\$\begingroup\$

ZX Spectrum Z80 Assembly, 65 bytes

    ld hl,22528
    ld b,7
    ld de,120*256+8 ; white, blue
    ld a,16         ; red

; create the first row

blueleft:
    ld (hl),e
    inc hl
    djnz blueleft

    ld (hl),d
    inc hl
    ld (hl),a
    inc hl
    ld (hl),a
    inc hl
    ld (hl),d
    inc hl

    ld b,14
blueright:
    ld (hl),e
    inc hl
    djnz blueright

; copy the first row to the next 17 rows

    ld l,b
    ld de,22528+32
    ld bc,17*32
    ldir

; add the horizontal stripe

    ld hl,22528+7*32
    dec d
    ld e,b
    ld c,2
midrep:
    ld b,25
midstripe:
    cp (hl)
    jr z,red
    ld (hl),120
red:
    ld (de),a
    inc hl
    inc de
    djnz midstripe

    ld hl,22528+10*32
    ld e,9*32
    dec c
    jr nz,midrep
    ret

Icelandic Flag

\$\endgroup\$
14
\$\begingroup\$

Minecraft 1.10.2, 734 characters

It might be 734 characters, but it's the only submission so far made of actual wool!

summon FallingSand ~ ~1 ~ {Block:log,Time:1,Passengers:[{id:FallingSand,Block:redstone_block,Time:1,Passengers:[{id:FallingSand,Block:activator_rail,Time:1,Passengers:[{id:MinecartCommandBlock,Command:"fill 0 ~ 0 100 ~ 72 wool 11"},{id:MinecartCommandBlock,Command:"fill 28 ~ 0 44 ~ 72 wool"},{id:MinecartCommandBlock,Command:"fill 0 ~ 28 100 ~ 44 wool"},{id:MinecartCommandBlock,Command:"fill 32 ~ 0 40 ~ 72 wool 14"},{id:MinecartCommandBlock,Command:"fill 0 ~ 32 100 ~ 40 wool 14"},{id:MinecartCommandBlock,Command:setblock ~ ~ ~1 command_block 0 replace {Command:fill ~ ~-3 ~-1 ~ ~ ~ air}},{id:MinecartCommandBlock,Command:setblock ~ ~-1 ~1 redstone_block},{id:MinecartCommandBlock,Command:kill @e[type=MinecartCommandBlock]}]}]}]}

Go to about -5x -5z, paste into an Impulse command block, set it to "Always Active" and press Done.

Flag spans from 0, 0 to 100, 72; and is 3 blocks above the command block as placed. It casts a fairly large shadow, and monsters spawn under it. Whether this is accurate to the country of Iceland, however, is anyone's guess.

Fair warning - will /kill all MinecartCommandBlocks in the world in the interest of saving four characters. Don't run this in a world you're overly attached to.

Flag

Used MrGarretto's command combiner and tweaked the output a little bit (808 -> 734)

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  • 1
    \$\begingroup\$ "Whether this is accurate to the country of Iceland..." 😂 \$\endgroup\$ – Jordan Aug 1 '16 at 17:43
  • 2
    \$\begingroup\$ Can't you just use kill @e without the target selector argument? It'll kill the player but hey the flag will still be there \$\endgroup\$ – Kuilin Li Dec 29 '16 at 4:33
11
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Logo, 216 188 bytes

Using Calormen.com's implementation. For you purists, the implementation uses some antialiasing which feathers the edges a little. I did waste 3 bytes hiding the turtle, though, so that should make up for it.

This could be reduced greatly if your Logo implementation lets you set the size of the window. Then you could wrap and make the turtle plow on through to make the cross in four strokes, and skip having to trim it up with a border.

generated flag screenshot

TO X :C :S
setpc :C
setpensize :S
home
pd
setx 100
setx 36
bk 36
fd 72
pu
END
setpc "#48e0
fill
X 7 16
X "#d72828 8
fd 4
pe
pd
setx -4
bk 80
setx 104
fd 80
setx 0
ht
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  • \$\begingroup\$ I didn't know there was an English speaking version of Logo! \$\endgroup\$ – Vincent Jul 13 '16 at 14:47
  • 1
    \$\begingroup\$ Absolutely. I think I first saw it over 30 years ago on an Apple IIe. I also had it on my TRS-80 Color Computer. It was my first taste of using angles in geometry, years before I was to officially learn it in school. \$\endgroup\$ – GuitarPicker Jul 13 '16 at 14:49
  • \$\begingroup\$ Why the white border around it? \$\endgroup\$ – Solomon Ucko Jul 14 '16 at 23:37
  • \$\begingroup\$ I drew the lines using a large pen, which leaves rounded edges on the tips of the cross, so I had to sweep around it with a large eraser to square them up. I was writing another version of this which used a completely different method in Logo and turned out to be smaller. I also was working on a third version that prints a big Unicode Latin cross and paints it, but the proportions weren't right and the size looked like it would exceed this one. \$\endgroup\$ – GuitarPicker Jul 15 '16 at 14:08
10
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Java 8, 449 447 bytes:

import java.awt.*;import javax.swing.*;class A extends JPanel{public void paintComponent(Graphics G){super.paintComponent(G);G.setColor(new Color(0,72,224));G.fillRect(0,0,175,126);G.setColor(Color.WHITE);G.fillRect(49,0,28,126);G.fillRect(0,49,175,28);G.setColor(new Color(215,40,40));G.fillRect(56,0,14,126);G.fillRect(0,56,175,14);}public static void main(String[]a){JFrame J=new JFrame();J.add(new A());J.setSize(175,147);J.setVisible(true);}}

A very late answer, and also the longest one here, apparently. Uses the java.awt.Graphics class to create and open a window with the flag in it, which is created by 5 total rectangles consisting of 1 for the blue blocks, 2 for the white stripes, and 2 for the red stripes. Uses 7 pixels:1 unit ratio. In other words, for each unit, 7 pixels are used. Here is an image of the output on a Macintosh with OS X 10.11:

Example Output

Now to find a way to golf this down a bit more...

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  • \$\begingroup\$ Try overriding paint instead of paintComponent. Consider using an anonymous class for the JPanel. Consider just using a BufferedImage and outputting to a file. \$\endgroup\$ – Justin Jul 12 '16 at 14:12
  • \$\begingroup\$ @Justin Actually, I was already using Blue as 1 huge rectangle for the background. I just got mixed up between this and another version I made in Python. Regardless, thanks for the other tips! :) \$\endgroup\$ – R. Kap Jul 12 '16 at 17:42
  • \$\begingroup\$ Some more suggestions: Don't use a JPanel, just override the JFrame. If you do this and just override paint, you don't need Swing, just AWT, so change the JFrame to Frame and remove the import. Don't call super.paint. Rearrange the main method; move the setSize into the paint method of our Frame, remove the variable J, and append .setVisible(true) to the end of the anonymous class. Finally, change .setVisible(true) to be show(), yes it's a deprecated method, but it's shorter. Use an interface to remove the public from the main method. \$\endgroup\$ – Justin Jul 12 '16 at 18:05
  • \$\begingroup\$ Final result at 338 chars (had to change the height as well since it's a frame): import java.awt.*;interface A{static void main(String[]a){new Frame(){public void paint(Graphics G){setSize(175,119);G.setColor(new Color(0,72,224));G.fillRect(0,0,175,126);G.setColor(Color.WHITE);G.fillRect(49,0,28,126);G.fillRect(0,49,175,28);G.setColor(new Color(215,40,40));G.fillRect(56,0,14,126);G.fillRect(0,56,175,14);}}.show();}} \$\endgroup\$ – Justin Jul 12 '16 at 18:05
  • 1
    \$\begingroup\$ Even better: don't paint the first rectangle, just call setBackground(color) (also the size was still wrong). Now at 317: import java.awt.*;interface A{static void main(String[]a){new Frame(){public void paint(Graphics G){setSize(175,126);setBackground(new Color(0,72,224));G.setColor(Color.WHITE);G.fillRect(49,0,28,126);G.fillRect(0,49,175,28);G.setColor(new Color(215,40,40));G.fillRect(56,0,14,126);G.fillRect(0,56,175,14);}}.show();}} \$\endgroup\$ – Justin Jul 12 '16 at 18:11
10
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R, 197 195 187 bytes

w="white";r="#d72828";png(w=100,h=72);par(mar=rep(0,4),bg="#0048e0",xaxs="i",yaxs="i");frame();rect(c(0,7,0,8)/25,c(7,0,8,0)/18,c(1,.44,1,.4),c(11/18,1,5/9,1),c=c(w,w,r,r),b=NA);dev.off()

Indented, with new lines and explanations:

w="white"
r="#d72828"
png(w=100,h=72) #Creates in working directory a png called Rplot001.png 
                #with a width and a height of 120 and 72 pixels respectively.
par(mar=rep(0,4), #No margin around the plot
    bg="#0048e0", #Blue background
    xaxs="i",yaxs="i") #Axes fits range exactly
frame() #Creates an empty plot which range is xlim=c(0,1) & ylim=c(0,1)
rect(c(0,7,0,8)/25, #Because rect is vectorized
     c(7,0,8,0)/18,
     c(1,.44,1,.4), #i. e. c(25,11,25,10)/25
     c(11/18,1,5/9,1), #i. e. c(11,18,10,18)/18
     c=c(w,w,r,r), # c= is the same as col=, thanks to argument name completion
     b=NA)#No borders
dev.off()

Island flag

Edit: turns out frame(), contrary to plot() or plot.new() doesn't by default add a border to the plot, meaning bty="n" was unnecessary here.

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9
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Atari 8-bit executable, 123 bytes

Another "just for fun" entry, this program is meant to be run on an Atari 8-bit computer or emulator. For example, to load the program on Atari800, just run:

atari800 iceland.xex

Machine code (in hex bytes)

ff ff 00 06 74 06 a9 1b 8d 30 02 a9 06 8d 31 02
a9 44 8d c4 02 a9 0f 8d c5 02 a9 84 8d c6 02 d0
fe 70 70 70 48 57 06 48 57 06 48 57 06 48 57 06
48 57 06 48 57 06 48 57 06 48 61 06 48 6b 06 48
6b 06 48 61 06 48 57 06 48 57 06 48 57 06 48 57
06 48 57 06 48 57 06 48 57 06 41 1b 06 ff fe 5b
ff ff ff c0 00 00 00 aa aa 5a aa aa aa 80 00 00
00 55 55 55 55 55 55 40 00 00 00

Assembler source code (can be compiled with MADS):

        org $0600
        lda <dlist
        sta $0230
        lda >dlist
        sta $0231
        lda #$44
        sta $02c4
        lda #$0f
        sta $02c5
        lda #$84
        sta $02c6
loop    bne loop
dlist   dta $70, $70, $70
        dta $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1)
        dta $48, a(line2)
        dta $48, a(line3), $48, a(line3)
        dta $48, a(line2)
        dta $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1), $48, a(line1)
        dta $41, a(dlist)
line1   dta $ff, $fe, $5b, $ff, $ff, $ff, $c0, $00, $00, $00
line2   dta $aa, $aa, $5a, $aa, $aa, $aa, $80, $00, $00, $00
line3   dta $55, $55, $55, $55, $55, $55, $40, $00, $00, $00

How it works:

The program uses a custom display list that's based on ANTIC Mode 8 (40 pixels per line, 2 bpp). Repeated lines are loaded from the same memory location. After setting up the display, the program enters an infinite loop.

Screenshot:

iceland.xex running on Atari800

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9
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Python, 119 118 114 112 bytes

Nothing special, straightforward:

b,w,r="\0H\xe0"*28,"\xff"*12,"\xd7(("*8
A,B=28*(b+w+r+w+2*b),4*(8*w+r+15*w)
print"P6 100 72 255 "+A+B+100*r+B+A

Output as binary PPM, usage

python golf_iceland.py > iceland.ppm
  • Edit1: shoved a byte between print and the quotation mark
  • Edit2: slighty shorter as binary PPM
  • Edit3: Figured that \0 can be used instead of \x00

If someone knows how to use the non-printable ASCII-character directly, please let know.

Converted to PNG

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  • 2
    \$\begingroup\$ Congratulations! You beat me by a lot :D \$\endgroup\$ – Gábor Fekete Jul 12 '16 at 13:52
  • 2
    \$\begingroup\$ @GáborFekete beat you in bytes, yes. But your answer is much more clever with that offset \$\endgroup\$ – Karl Napf Jul 12 '16 at 14:17
  • \$\begingroup\$ Why not have the results of the escapes instead of the escapes themselves? \$\endgroup\$ – Solomon Ucko Jul 14 '16 at 23:41
  • \$\begingroup\$ @SolomonUcko I tried b,w,r="\0Hà"*28,"ÿ"*12,"×(("*8 and using Python 3, but it does not work. \$\endgroup\$ – Karl Napf Jul 15 '16 at 10:35
  • \$\begingroup\$ @KarlNapf, how did it fail? Did it draw incorrectly, or give an error message? It could also be an encoding issue. \$\endgroup\$ – Solomon Ucko Jul 16 '16 at 14:41
8
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JavaScript, 267 bytes

document.write("<div style='width:250px;height:180px;background:"+[[b="bottom",44.4,d="d72828",55.6],[r="right",32,d,40],[b,38.9,e="fff",61.1],[r,28,e,44]].map(([d,a,c,o])=>`linear-gradient(to ${d+(t=",transparent ")+a}%,#${c} ${a}%,#${c} ${o}%${t+o}%)`)+",#003897'")

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  • 1
    \$\begingroup\$ Sure the 7 - 14 ratio of left and right blue widths is correct? \$\endgroup\$ – manatwork Jul 11 '16 at 10:20
  • 1
    \$\begingroup\$ @manatwork Oops, for some reason I thought 100 / 25 = 5, so everything ended up 25% too wide. \$\endgroup\$ – Neil Jul 11 '16 at 10:30
8
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FFmpeg, 339 184 bytes

ffplay -f lavfi color=d72828:100x36[r];color=white:64x32[w];color=0048e0:56x28[b];[w][b]overlay=4,split[x][y];[r][x]overlay=-32[d];[d][y]overlay=40,split[t][m];[m]vflip[n];[t][n]vstack

Will try to golf this down ..further.

100x72 image of Iceland flag

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7
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SVG+Javascript, 190 165 164 bytes

No expert there, repeating one path just to change the color and line width looks silly javascript ftw!

document.write(`<svg><rect width=100 height=72 fill="#0048e0"/>${a='<path d="M0 36L100 36M36 0L36 72"style="stroke-width:'}16;stroke:#fff"/>${a}8;stroke:#d72828">`)

More readable:

document.write(`<svg><rect width=100 height=72 fill="#0048e0"/>
${a='<path d="M0 36L100 36M36 0L36 72"style="stroke-width:'}16;stroke:#fff"/>
${a}8;stroke:#d72828">`)
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  • \$\begingroup\$ You can use path d="m0,0h100v72H0" instead of the rectangle to save two bytes. Likewise, use M0 36H100M36 0V72 for the other path's data, which saves another five bytes. And you can drop the style attribute in favour of declaring both stroke-width and stroke as attributes to save another five bytes. \$\endgroup\$ – Joey Jul 15 '16 at 5:01
7
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Processing, 136 bytes

size(100,72);noStroke();background(#0048e0);fill(255);rect(28,0,16,72);rect(0,28,100,16);fill(#d72828);rect(0,32,100,8);rect(32,0,8,72);

Ungolfed

//open the window
size(100,72);
//turn off borders that surround shapes by default
noStroke();
//draw blue as the background
background(#0048e0);
//set color to white
fill(255);
//draw 2 white bars
rect(28,0,16,72);
rect(0,28,100,16);
//set color to red
fill(#d72828);
//draw 2 red bars
rect(0,32,100,8);
rect(32,0,8,72);

Output:

enter image description here

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  • 1
    \$\begingroup\$ You can shave off two more bytes by using fill and rect instead of size and background. 134 bytes: noStroke();fill(#0048e0);rect(0,0,100,72);fill(255);rect(0,28,100,16);rect(28,0,16,72);fill(#d72828);rect(0,32,100,8);rect(32,0,8,72); \$\endgroup\$ – GuitarPicker Jul 12 '16 at 16:42
  • \$\begingroup\$ Adding on to what GuitarPicker said, fill(-1) is one byte shorter than fill(255) \$\endgroup\$ – Cows quack Apr 23 '17 at 15:39
7
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Mathematica 174 157 bytes

Without builtins:

157 bytes

r=Rectangle;c=RGBColor;Graphics@{c[{0,72,224}/255],r[{0,0},{25,18}],White,r[{7,0},{11,18}],r[{0,7},{25,11}],c[{43,8,8}/51],r[{8,0},{10,18}],r[{0,8},{25,10}]}

enter image description here

or alternatively

232 bytes

x=Join[Unitize/@Range@7,{0},{2,2},{0},Unitize/@Range@14]&/@Range@7;y=Join[ConstantArray[0,8],{2,2},ConstantArray[0,15]];z=ConstantArray[2,25];ArrayPlot[Join[x,{y},{z,z},{y},x]/.{2->RGBColor[{43,8,8}/51],1->RGBColor[{0,72,224}/255]}]

enter image description here

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  • 1
    \$\begingroup\$ you're welcome. same can be applied to your second longer version. u=Unitize;c=ConstantArray etc ^_^ \$\endgroup\$ – Dan Oak Jul 12 '16 at 11:36
  • 1
    \$\begingroup\$ Wait, there's something Mathematica doesn't have a builtin for? I'm surprised. \$\endgroup\$ – Morgan Thrapp Jul 13 '16 at 20:13
  • \$\begingroup\$ @MorganThrapp I'm sure there used to be another Mathematica answer using a builtin. \$\endgroup\$ – gcampbell Jul 14 '16 at 9:12
  • 3
    \$\begingroup\$ There is CountryData["Iceland", "Flag"] \$\endgroup\$ – dwa Jul 18 '16 at 4:51
7
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JavaScript (ES6), 231 240

Code inside the snippet below. Run it to test.

d=(w,h,c)=>`<div style=float:left;width:${w}em;height:${h}em;background:#${['0048e0','fff','d72828'][~~c]}>`;document.write(d(25)+(a=[252,61,94,61,476]).concat(b=[261,70,485],810,b,a).map(v=>d(v>>5,v/4&7,v&3)).join(e='</div>')+e+e)

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7
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ZX Spectrum Z80 Assembly, 51 bytes

https://github.com/ralphbecket/Z80/blob/master/IcelandFlag/IcelandFlag.asm

                zeusemulate "48K", "ULA+"
ZeusEmulate_PC  equ Main
ZeusEmulate_SP  equ $FF40

                org $8000

MinWhite        equ 7
MinRed          equ MinWhite + 1
TopRed          equ MinRed + 2
TopWhite        equ TopRed + 1
Height          equ TopWhite + MinWhite - 2
Width           equ TopWhite + 2 * MinWhite - 1

White           equ %01111000
Red             equ %01010000
Blue            equ %01001000

Main            ld hl, $5800 + ((Height - 1) * 32) + (Width - 1)
                ld c, Height

YLoop           ld b, Width

XLoop           ld (hl), Red
                ld de, MinRed * $100 + TopRed
                call Test
                jr c, Next

                ld (hl), White
                ld de, MinWhite * $100 + TopWhite
                call Test
                jr c, Next

                ld (hl), Blue

Next            dec hl
                djnz XLoop
                ld de, -(32 - Width)
                add hl, de
                dec c
                jr nz, YLoop
                ret

Test            equ *
TestX           ld a, b
                cp d
                jr c, TestY
                cp e
                ret c
TestY           ld a, c
                cp d
                ccf
                ret nc
                cp e
                ret

enter image description here

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7
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Java, 335 bytes

The function is

void w()throws Exception{int w=100,h=72;BufferedImage i=new BufferedImage(w,h,1);Graphics g=i.getGraphics();g.setColor(new Color(18656));g.fillRect(0,0,w,h);g.setColor(WHITE);g.fillRect(0,28,w,16);g.fillRect(28,0,16,h);g.setColor(new Color(14100520));g.fillRect(0,32,w,8);g.fillRect(32,0,8,h);ImageIO.write(i,"png",new File("f.png"));}

And it writes the desired image as f.png, with a size of 100x72

(Note that this is not a direct competitor to the Answer by R. Kap, because it writes a file, and does not display the image on the screen)

Here is the ungolfed version that can be compiled and run:

import static java.awt.Color.WHITE;

import java.awt.Color;
import java.awt.Graphics;
import java.awt.image.BufferedImage;
import java.io.File;

import javax.imageio.ImageIO;

public class Iceland
{
    public static void main(String[] args) throws Exception
    {
        Iceland i = new Iceland();
        i.w();
    }

    void w() throws Exception
    {
        int B=0x0048e0,R=0xd72828,w=100,h=72;
        BufferedImage i=new BufferedImage(w,h,1);
        Graphics g=i.getGraphics();
        g.setColor(new Color(B));
        g.fillRect(0,0,w,h);
        g.setColor(WHITE);
        g.fillRect(0,28,w,16);
        g.fillRect(28,0,16,h);
        g.setColor(new Color(R));
        g.fillRect(0,32,w,8);
        g.fillRect(32,0,8,h);
        ImageIO.write(i,"png",new File("f.png"));
    }
}

A side note, regarding the related questions: Maybe one should create a challenge to paint the flags of

  • Indonesia
  • Poland
  • Finland
  • France
  • Netherlands
  • Thailand
  • Norway

at the same time:

enter image description here

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7
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J, 86 84 83 bytes

   load'viewmat'
   (255,0 72 224,:215,2#40)viewmat _9 _9|.2(b=.[,~[,.~[,[,.])0 b 14 21$1

The approach is the same as @Gábor Fekete's with Python.

Left argument colors for viewmat is an array of RGB values, in our case:

255 255 255
  0  72 224
215  40  40

And the right argument is a matrix of indices of colors.
(_9 _9 |. matrix) instructs to shift matrix 9 items in each dimension.
Scary construction (border ([,~[,.~[,[,.]) matrix) wraps matrix with number border.
And (14 21 $ 1) makes 14×21 matrix of ones.

The output is displayed in separate resizable window, pretty large by default. enter image description here

Thanks

miles - saved 2 bytes with reordering the colors, used the feature of , that duplicates the numbers (255) for the shape agreement.

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  • 1
    \$\begingroup\$ It looks like the height of the flag is 26 units instead of 25. \$\endgroup\$ – Gábor Fekete Jul 12 '16 at 13:51
  • \$\begingroup\$ @GáborFekete hm, you meant height is 19 instead of 18? didn't mention that, just noticed after your comment \$\endgroup\$ – Dan Oak Jul 12 '16 at 14:34
  • \$\begingroup\$ Oh right I wrote height but used the width values... \$\endgroup\$ – Gábor Fekete Jul 12 '16 at 14:35
  • \$\begingroup\$ yeeeah, indeed. i made a mistake in values. the shape of initial matrix should be 14 21 (18 25 - 4 4). correcting... thank you! \$\endgroup\$ – Dan Oak Jul 12 '16 at 14:37
  • 1
    \$\begingroup\$ You can save 2 bytes reordering the rgb values (255,0 72 224,:215 40 40)viewmat _9 _9|.2(b=.[,~[,.~[,[,.])0 b 14 21$1 \$\endgroup\$ – miles Jul 14 '16 at 6:05
6
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TI-BASIC (non-competing), 323 bytes

Code is written for the TI-84, 83, and variants. I sure hope it isn't an issue that dimensions vary by device, and that the code isn't colored.

Setup:

:18→Xmax:¯18→Xmin
:10→Ymin:¯10→Ymin
:AxesOff

Drawing:

:Line(¯15,9,¯8,9)
:Line(¯8,9,¯8,2)
:Line(¯8,2,¯15,2)
:Line(¯15,2,¯15,9)

:Line(¯15,¯9,¯8,¯9)
:Line(¯8,¯9,¯8,¯2)
:Line(¯8,¯2,¯15,¯2)
:Line(¯15,¯2,¯15,¯9)

:Line(¯4,9,10,9)
:Line(¯4,2,10,2)
:Line(¯4,9,¯4,2)
:Line(10,9,19,2)

:Line(¯4,¯9,10,¯9)
:Line(¯4,¯2,10,¯2)
:Line(¯4,¯9,¯4,¯2)
:Line(10,¯9,19,¯2)

:Line(¯15,1,¯7,1)
:Line(¯15,¯1,¯7,¯1)
:Line(¯5,1,20,1)
:Line(¯5,¯1,¯20,¯1)
:Line(¯7,¯1,¯7,¯9)
:Line(¯5,¯1,¯5,¯9)
:Line(¯7,1,¯7,9)
:Line(¯5,1,¯5,9)

Golfed:

:18→Xmax:¯18→Xmin:10→Ymin:¯10→Ymin:AxesOff:Line(¯15,9,¯8,9:Line(¯8,9,¯8,2:Line(¯8,2,¯15,2:Line(¯15,2,¯15,9:Line(¯15,¯9,¯8,¯9:Line(¯8,¯9,¯8,¯2:Line(¯8,¯2,¯15,¯2:Line(¯15,¯2,¯15,¯9:Line(¯4,9,10,9:Line(¯4,2,10,2:Line(¯4,9,¯4,2:Line(10,9,19,2:Line(¯4,¯9,10,¯9:Line(¯4,¯2,10,¯2:Line(¯4,¯9,¯4,¯2:Line(10,¯9,19,¯2:Line(¯15,1,¯7,1:Line(¯15,¯1,¯7,¯1:Line(¯5,1,20,1:Line(¯5,¯1,¯20,¯1:Line(¯7,¯1,¯7,¯9:Line(¯5,¯1,¯5,¯9:Line(¯7,1,¯7,9:Line(¯5,1,¯5,9

Yes, the lack of ) is intentional.

Size:

Line( and all commands like that take up 1 byte, each number takes a byte. That's 323 bytes.

That was absolutely tedious. I'll get this on an emulator hopefully (I have to manually enter everything) but it's literally just lines in the shape of the flag.

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  • 1
    \$\begingroup\$ @Random832 Oddly enough, yes! Check the token size here: tibasicdev.wikidot.com/line I'm not sure what the byte is exactly. However I do know that on the calculator, it is treated essentially as a char. \$\endgroup\$ – charredgrass Jul 11 '16 at 13:38
  • 1
    \$\begingroup\$ @Random832 The byte for Line( is 0x9C. You can see a table of one-byte tokens here: tibasicdev.wikidot.com/one-byte-tokens \$\endgroup\$ – f'' Jul 11 '16 at 14:12
  • 1
    \$\begingroup\$ Couldn't you graph using regions (using < and >) instead of lines to get greyscale shading? \$\endgroup\$ – mbomb007 Jul 11 '16 at 16:51
  • 7
    \$\begingroup\$ Why is this non-competing? \$\endgroup\$ – Mego Jul 11 '16 at 22:55
  • 1
    \$\begingroup\$ Note that there is now a color TI-84, so you could probably run it on there with only minor modifications. \$\endgroup\$ – Moshe Katz Jul 13 '16 at 7:10
6
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C#, 384 346 317 292 291 289 Bytes

Simple solution with Windows Forms and GDI

Func<int,int,Point>p=(x,y)=>new Point(x*10,y*10);var b=new Bitmap(250,180);var g=Graphics.FromImage(b);g.Clear(Color.Blue);g.DrawLines(new Pen(Color.White,40),new[]{p(0,9),p(50,9),p(9,-20),p(9,18)});g.DrawLines(new Pen(Color.Red,20),new[]{p(0,9),p(50,9),p(9,-20),p(9,18)});b.Save("b.png");

Usage

Start a new console-project and put the code above in the main-method, add System.Drawing-Namespace.

How it works

The code creates a new image and draws some lines on it. It saves the image to disk. Some of the ending points of the lines are outside the visible area.

enter image description here

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  • \$\begingroup\$ Welcome to PPCG ! Great first codegolf, but it looks like you could improve it. First, I think you can removes some spaces here and there (b = new=>b=new, using () => using(), don't use spaces after ;s. If you want, you can read our Tips for golfing in C# to find some advices. \$\endgroup\$ – Katenkyo Jul 13 '16 at 14:37
  • \$\begingroup\$ Thanks, spaces are removed and I delete the using statement, too. I also use anonymous variables now. \$\endgroup\$ – soema Jul 13 '16 at 14:42
  • \$\begingroup\$ Sure you need Process.Start(f);? As I understand, that is similar to cmd start. As you can choose to save or display the image and you already saved it, that step seems pointless. In which case maybe you can avoid declaring variable f too. \$\endgroup\$ – manatwork Jul 13 '16 at 14:49
  • \$\begingroup\$ Yes! Just save now and no opening more ... \$\endgroup\$ – soema Jul 13 '16 at 14:59
  • \$\begingroup\$ You should count the bytes for the namespace usings as well as for a method declaration or program boilerplate. This is all part of what's needed (the task gives you the choice of a function or a program, but not the choice of just a bunch of statements). \$\endgroup\$ – Joey Jul 15 '16 at 10:06
5
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Perl, 134 bytes

Note: \x1b is actually the ASCII escape character and counts as 1 byte

($b,$w,$r)=map"\x1b[48;5;${_}m",18,15,1;print@l=("$b "x7,"$w $r  $w $b",$"x14,$/)x7,@m=("$w "x8,"$r  ","$w "x15,$/),("$r "x25,$/)x2,@m,@l

Usage

Save as iceland-flag.pl and run via:

perl iceland-flag.pl

Squished flag

Uses ANSI escape sequences and assumes a Linux terminal to display the flag. Looks a bit weird using the measurements provided.

Perl, 141 bytes

This version looks a bit closer to the genuine dimensions...

($b,$w,$r)=map"\x1b[48;5;${_}m",18,15,1;print@l=("$b "x14,"$w  $r    $w  $b",$"x28,$/)x7,@m=("$w "x16,"$r "x4,"$w "x30,$/),("$r "x50,$/)x2,@m,@l

Less squished flag

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  • 1
    \$\begingroup\$ The weirdness comes from the fact that characters are taller than their width. \$\endgroup\$ – Erik the Outgolfer Jul 13 '16 at 9:22
  • \$\begingroup\$ @EʀɪᴋᴛʜᴇGᴏʟғᴇʀ Indeed, I did wonder if there were square fixed-width fonts, but I don't imagine they'd look particularly good! I might update that second version to look even closer (it shouldn't take any more bytes than it currently is, but time...) \$\endgroup\$ – Dom Hastings Jul 13 '16 at 9:36
  • \$\begingroup\$ On a TTY, you cannot wonder such a thing, the font is THE FONT! You can't change it just because you don't like it. \$\endgroup\$ – Erik the Outgolfer Jul 13 '16 at 9:42
5
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SpecaBAS - 150 bytes

1 a=15,b=250,c=180: FOR i=1 TO 5: READ k,x,y,w,h: RECTANGLE INK k;x,y,w,h FILL: NEXT i
2 DATA 1,0,0,b,c,a,71,0,40,c,a,0,71,b,40,2,81,0,20,c,2,0,81,b,20

Reads the ink colour, x,y, width and height and draws a rectangle with those coordinates/dimensions.

enter image description here

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  • \$\begingroup\$ Do you need spaces after each :? Oh, and it's 151 bytes. \$\endgroup\$ – Erik the Outgolfer Jul 13 '16 at 13:16
5
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Python IDLE, 191 172 156 bytes

IDLE is Python's standard IDE. Unless it has a custom theme, STDOUT is blue, STDERR is red, and the background is white. So, the following code:

from sys import*
x=[1]*7;y=[0]*7;z=[0,2,2,0]
f=[x+z+x*2]*4+[y+z+y*2,[2]*25]
for s in f+f[::-1]:[[stderr,stdout][-x].write(' █'[x>0]*2)for x in s];print()

Produces this output:

enter image description here

As printed characters as not square, this is slightly off, but if we take 1 unit to be 2 chars across and 1 char tall, then the proportions are exact.

This could be golfed, by halfing the width dimension, and using an ASCII character for the blocks such as '#', but it doesn't exactly have the same effect.


Explanation

The code itself seems quite sloppy at the moment, and can definitely be golfed, but the basic idea is:

  • Construct a matrix where 0 represents whitespace, 1 represents a blue block, and 2 represents a red block.
    • The first half is constructed (mainly through list slicing / multiplication), and added to the reverse of itself to generate the full flag.
  • Loop through the matrix, printing each value as either whitespace or a block to STDERR/STDOUT accordingly. Print a newline after each row.
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5
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PICO-8/Lua, 108 100 92 bytes (non-competing)

rectfill(0,0,24,17,12)
rect(0,7,24,10,7)
rect(7,0,10,17,7)
rect(0,8,24,9,8)
rect(8,0,9,17,8)

output

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  • 2
    \$\begingroup\$ Why is this marked "Non-competing"? Usually, that is reserved for using a language that's newer than the challenge. \$\endgroup\$ – DJMcMayhem Jul 12 '16 at 20:18
  • \$\begingroup\$ Because the blue is brighter than the flag's blue. \$\endgroup\$ – acrolith Jul 12 '16 at 20:24
  • \$\begingroup\$ I don't know much about Pico8/lua, but is it possible to make the colors match? Otherwise, this answer is incorrect, which means it should be deleted. \$\endgroup\$ – DJMcMayhem Jul 12 '16 at 20:25
  • 4
    \$\begingroup\$ @daHugLenny Since the contest allows for ANSI colors if necessary, I'm sure this would be fine. \$\endgroup\$ – MCMastery Jul 12 '16 at 20:26
  • \$\begingroup\$ @DrGreenEggsandIronMan Nope, the PICO-8 has a fixed 16-color palette. :< The only two shades of blue in the palette are too dark and too bright, respectively. \$\endgroup\$ – Lynn Jul 30 '16 at 19:07

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