Write a program or function that listens for incoming TCP traffic on port N. It offers a simple service: it calculates sum of IP address fields of incoming connection and returns.

Program or function reads integer N from arguments or stdin. It listens to incoming TCP connections on port N. When someone connects to that port, the program calculates sum of its IP address fields and sends it back to the client with trailing newline and closes connection.

  • Port number N is a valid port, and 210 < N < 215
  • Trailing newline can be either \nor \r\n
  • You can use either IPv4 or IPv6. Since IPv6 addresses are written in hexadecimal form, you must also provide result in same format, for example 2001:0db8:0000:0042:0000:8a2e:0370:7334 => 12ecd.

This is . Standard rules and loopholes apply.


You run your server with ./server 1234. The server is now running and waiting for connections on port 1234. Then a client from connects to your server. Your server performs a simple calculation: 127+0+0+1 => 128 and sends the result to the client (with trailing newline): 128\n. Then server closes connection and waits for next client.


var QUESTION_ID=76379,OVERRIDE_USER=20569;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

  • 1
    \$\begingroup\$ Is it allowed to use inetd/xinetd or similar? \$\endgroup\$ Commented Mar 28, 2016 at 18:17
  • 94
    \$\begingroup\$ I like this, since it's a golfing challenge that golfing languages are unlikely to be very good at. \$\endgroup\$
    – isaacg
    Commented Mar 28, 2016 at 18:54
  • 9
    \$\begingroup\$ Not only is it amazing that a TCP server is apparently a very easy program to write, I am thoroughly floored at the fact that it's getting golfed for fun. I'll just go back to struggling with FizzBuzz like an imbecile. \$\endgroup\$
    – MonkeyZeus
    Commented Mar 29, 2016 at 19:50
  • 18
    \$\begingroup\$ @isaacg It's only time before someone finds the TCP server built-in in Mathematica \$\endgroup\$
    – Downgoat
    Commented Mar 29, 2016 at 22:19
  • 3
    \$\begingroup\$ @MonkeyZeus To be fair, you will not see any good TCP server here. Making a reliable, scalable TCP server that handles all the intricacies of TCP (and your application protocol) well is a bit harder :D Though it certainly helps that the protocol is exceedingly simple - you don't even need to read the stream, something that I've seen broken in too many TCP servers to count :D \$\endgroup\$
    – Luaan
    Commented Mar 30, 2016 at 9:11

40 Answers 40


Bash + netcat + ss + …, 65 60 characters

nc -lp$1 -c'ss src :'$1'|awk \$0=\$5|tr .: +#|bc'
exec $0 $1

Not a serious solution, was just curious about this possibility.

Thanks to:

  • ninjalj for suggesting the awk based filtering (-5 characters)

Sample run:

(terminal 1)

bash-4.3$ ./ip-reduce.sh 8080

(terminal 2)

bash-4.3$ nc localhost 8080

bash-4.3$ telnet localhost 8080
Connected to localhost.
Escape character is '^]'.
Connection closed by foreign host.

On Ubuntu you can get nc from netcat-traditional (no, netcat-openbsd is not good) and ss from iproute2.

  • 24
    \$\begingroup\$ Why do you say it isn't a serious solution? As long as it works as expected I see no reason why it shouldn't be considered serious. It's also the shortest by a pretty significant margin at the moment. \$\endgroup\$
    – Alex A.
    Commented Mar 28, 2016 at 16:43
  • \$\begingroup\$ The biggest concern against it appeared during discussion with @JesseSielaff when I learned that on systems with configured IPv6, socket related information may be formatted differently. Have no such system to test it. For which I'm thinking whether would be more correct to turn it into CW. \$\endgroup\$
    – manatwork
    Commented Mar 28, 2016 at 17:02
  • 3
    \$\begingroup\$ My understanding of the spec is that you have to support IPv4 or IPv6, not both. So as long as it works for IPv4, not supporting IPv6 shouldn't matter, I would think. \$\endgroup\$
    – Alex A.
    Commented Mar 29, 2016 at 4:11
  • 1
    \$\begingroup\$ @AlexA. At least I think my question says so. Should I clarify it? \$\endgroup\$ Commented Mar 29, 2016 at 15:30
  • \$\begingroup\$ @HannesKarppila, your question is clear. The possible issue is that my solution may require the operating system to be configured in a particular way to be able to run. So I'm worry because it may fail if IPv6 is configured, regardless whether I handle it or not. Someone who has IPv6 configured could tell it for sure… \$\endgroup\$
    – manatwork
    Commented Mar 29, 2016 at 15:55

Linux ELF/x86, 146 bytes

00000000  7f 45 4c 46 01 00 00 00  5a 0e 00 00 5a 5e eb 10  |.ELF....Z...Z^..|
00000010  02 00 03 00 0c 50 eb 10  0c 50 eb 10 04 00 00 00  |.....P...P......|
00000020  5e 53 43 53 52 89 e1 b0  66 3d 20 00 01 00 cd 80  |^SCSR...f= .....|
00000030  97 55 6b ed 0a 01 c5 ac  2c 30 79 f6 43 0f cd 01  |.Uk.....,0y.C...|
00000040  dd 55 89 e1 6a 10 51 6a  10 51 57 89 e1 b0 66 cd  |.U..j.Qj.QW...f.|
00000050  80 43 43 b0 66 cd 80 01  64 24 08 89 e1 43 b0 66  |.CC.f...d$...C.f|
00000060  cd 80 89 c1 93 8d 74 24  1b 99 fd ac 01 c2 e2 fb  |......t$........|
00000070  89 f7 b0 0a aa 91 92 f6  f1 86 c4 04 30 aa 42 c1  |............0.B.|
00000080  e8 08 75 f3 42 89 f9 41  b0 04 cd 80 b0 06 cd 80  |..u.B..A........|
00000090  eb c9                                             |..|

Includes a 52-byte ELF header, a 32-byte program header, 111 bytes of program code + 3 bytes of code for skipping around inside the headers.

Information on how to create tiny ELF executables can be found at breadbox's "A Whirlwind Tutorial on Creating Really Teensy ELF Executables for Linux".

Linux/i386 uses the socketcall(2) multiplex system call, which takes in ebx the specific socket call (the SYS_* macros from /usr/include/linux/net.h), and in ecx a pointer to the argument area of the original library call.

Some things done to keep the executable small:

  • It assumes registers are zeroed on entry, which Linux does, but is not required by the ELF standard (the only requirement is that on entry EDX points to a finalization funtion (useful for executables loaded by the dynamic linker) or is NULL).
  • It assumes on launch (typically by a shell) the only open file descriptors are 0, 1, and 2. Which means that the listening socket will be fd 3, and the accepted socket will be fd 4.
  • It assumes there are exactly 2 arguments (including argv[0]).
  • The same stack space is reused for the calls to bind(2), listen(2) and accept(2).
  • To skip over the phentsize and phnum fields, a byte is prepended, turning into a CMP operation which takes the phentsize and phnum fields as an immediate (trick shamelessly stolen from breadbox's solution to 123 in anarchy golf).
  • x86 string operations LODS (load into accumulator and increment/decrement source index) and STOS (store from accumulator and increment/decrement destination index) are nice for short code.
  • XCHG EAX, reg is 1-byte, compared to MOV EAX, reg, which takes 2 bytes.
  • CDQ/CLTD (sign-extend EAX into EDX:EAX) can be used as a 1-byte way to zero the EDX register.
  • BSWAP is useful for implementing htons().

Nasm source:

BITS 32                                         ;
                                                ;   ELF HEADER    --   PROGRAM HEADER
; ELF HEADER                                    ; +-------------+
DB 0x7f,'E','L','F'                             ; | magic       |    +--------------------+
                                                ; |             |    |                    |
; PROGRAM HEADERS                               ; |             |    |                    |
DD 1                                            ; |*class   32b | -- | type: PT_LOAD      |
                                                ; |*data   none |    |                    |
                                                ; |*version   0 |    |                    |
                                                ; |*ABI    SysV |    |                    |
DD 0xe5a        ; offset = vaddr & (PAGE_SIZE-1); |*ABI vers    | -- | offset             |
                                                ; |             |    |                    |
entry:  pop     edx     ; edx = 2 (argc)        ; |*PADx7       | -- | vaddr = 0x10eb5e5a |
        pop     esi     ; discard argv[0]       ; |             |    |                    |
        jmp     short skip                      ; |             |    |                    |
DW 2                                            ; | ET_EXEC     | -- |*paddr LO           |
DW 3                                            ; | EM_386      | -- |*paddr HI           |
DD 0x10eb500c                                   ; |*version     | -- | filesz             |
DD 0x10eb500c                                   ; | entry point | -- | memsz              |
DD 4                                            ; | ph offset   | -- | flags: RX          |
                                                ; |             |    |                    |
skip:   pop     esi     ; esi = argv[1]         ; |*sh offset   | -- |*align              |
socket: push    ebx     ; default protocol (0)  ; |             |    |                    |
        inc     ebx                             ; |             |    |                    |
        push    ebx     ; SOCK_STREAM (1)       ; |             |    |                    |
        push    edx     ; AF_INET (2)           ; |*flags       |    +--------------------+
        mov     ecx, esp                        ; |             |
        mov     al, 0x66                        ; |*ehsize      |
DB 0x3d         ; cmp eax,0x10020               ; |             |
DW 32                                           ; | phentsize   |
DW 1                                            ; | phnum       |
                                                ; |             |
        int     0x80    ; socket(2, 1, 0)       ; |*shentsize   |
        xchg    edi, eax; edi = sockfd, eax = 0 ; |*shnum       |
        push    ebp     ; INADDR_ANY            ; |             |
                                                ; |             |
mult:   imul    ebp, 10 ; \_                    ; |*shstrndx    |
        add     ebp, eax; >                     ; |             |
        lodsb           ; >                     ; +-------------+
        sub     al,'0'  ; >
        jns     mult    ; / ebp = atoi(argv[1])                 ;       bind stack frame
                                                                ;    +-----------------------+
endmul: inc     ebx             ; SYS_BIND (2)                  ;    |        INADDR_ANY     |
                                                                ; +->| AF_INET | htons(port) |
        bswap   ebp                                             ; |  +-----------------------+
        add     ebp, ebx        ; AF_INET (2), htons(port)      ; |  |           16          |
        push    ebp                                             ; |  +-----------------------+
                                                                ; |  |         dummy         |
        mov     ecx, esp                                        ; |  +-----------------------+
        push    16              ; addrlen                       ; |  |           16          |
        push    ecx             ; dummy value                   ; |  +-----------------------+
        push    16              ; addrlen                       ; +--|          addr         |
        push    ecx             ; addr                          ;    +-----------------------+
        push    edi             ; sock                          ;    |         sockfd        |
        mov     ecx, esp                                        ;    +-----------------------+
        mov     al, 0x66
        int     0x80            ; bind(sockfd, addr, addrlen)
                                                                ;       accept stack frame
                                                                ;    +-----------------------+
listen: ;mov    byte [esp+8],1                                  ;    |        INADDR_ANY     |
        inc     ebx                                             ; +->| AF_INET | htons(port) |
        inc     ebx             ; SYS_LISTEN (4)                ; |  +-----------------------+
        mov     al, 0x66                                        ; |+>|           16          |
        int     0x80            ; listen(sockfd, backlog)       ; || +-----------------------+
                                                                ; || |         dummy         |
        add     [esp+8], esp                                    ; || +-----------------------+
accept: mov     ecx, esp                                        ; |+-|        &addrlen       |
        inc     ebx             ; SYS_ACCEPT (5)                ; |  +-----------------------+
        mov     al, 0x66                                        ; +--|          addr         |
        int     0x80            ; accept(sockfd, addr, &addrlen);    +-----------------------+
                                                                ;    |         sockfd        |
        mov     ecx, eax        ; ecx = 4                       ;    +-----------------------+
        xchg    ebx, eax        ; ebx = acceptfd, eax = 000000xx

        lea     esi, [esp+27]   ; point to the IP part of struct sockaddr_in

        std                     ; reverse direction for string operations
addip:  lodsb                   ; \_
        add     edx, eax        ; > edx = sum of 4 IP bytes
        loop    addip           ; /

        mov     edi, esi        ; reuse struct sockaddr_in as scratch buffer
        mov     al, 10          ; '\n'
        xchg    ecx, eax        ; ecx = 10
        xchg    eax, edx        ; edx = 0, eax = sum

divide: div     cl              ; \_
        xchg    al, ah          ; >
        add     al,0x30         ; >
        stosb                   ; > sprintf(scratch, "%d", sum)
        inc     edx             ; >
        shr     eax, 8          ; >
        jnz     divide          ; /

write:  inc     edx             ; ndigits + 1 ('\n')
        mov     ecx, edi
        inc     ecx
        mov     al,4
        int     0x80            ; write(acceptfd, scratch, scratchlen) 
close:  mov     al, 6
        int     0x80            ; close(acceptfd)
        jmp     accept
  • 4
    \$\begingroup\$ This answer is way underappreciated. \$\endgroup\$
    – cat
    Commented Jul 7, 2016 at 18:14

C#, 284 283 282 278 274 254 bytes

class A{static int Main(string[]a){var b=new System.Net.Sockets.TcpListener(int.Parse(a[0]));b.Start();for(;;){var c=b.AcceptTcpClient();var d=c.Client.LocalEndPoint.Serialize();new System.IO.StreamWriter(c.GetStream()).WriteLine(d[4]+d[5]+d[6]+d[7]);}}}

Classic example of a basic C# TCP server. Testing:

Terminal 1:

$ ./Q76379.exe 1029

Terminal 2:

$ telnet localhost 1029
Connected to localhost.
Escape character is '^]'.
Connection closed by foreign host.


  • 7
    \$\begingroup\$ You can save 1 Byte by using int Main instead of void Main. As the program never returns the compiler doesn't require a return statement. \$\endgroup\$
    – raznagul
    Commented Mar 29, 2016 at 9:45
  • \$\begingroup\$ And no, it doesn't leak. It's actually pretty deterministic about releasing resources as well. Also, the argument to Start is optional, saving another character. \$\endgroup\$
    – Luaan
    Commented Mar 30, 2016 at 8:53
  • \$\begingroup\$ @Luaan Yeah, that was left over from debugging. \$\endgroup\$ Commented Mar 30, 2016 at 10:17
  • \$\begingroup\$ Also, you could use using on the TcpClient, which will save you three more characters (use the {} from the for), and doing the same with the StreamWriter should save one more. \$\endgroup\$
    – Luaan
    Commented Mar 30, 2016 at 11:13
  • \$\begingroup\$ @Luaan I need to explicitly Flush the StreamWriter to make it work properly. \$\endgroup\$ Commented Mar 30, 2016 at 11:16

NodeJS, 146 134 127 bytes


I finally get to post a NodeJS answer! IPv4 only right now.

Sample execution: node script.js 1024. From another terminal:

$ curl
  • 2
    \$\begingroup\$ I count 127 bytes right now, although you can get it down to 126 by swapping out '\n' with a template string containing a literal newline. \$\endgroup\$
    – Mwr247
    Commented Mar 30, 2016 at 0:08
  • \$\begingroup\$ Wouldn't this fail the requirements because your creating a HTTP server , I mean, it's technically a TCP server, but couldn't you just use the TCP module and save yourself a character? \$\endgroup\$
    – bren
    Commented Apr 2, 2016 at 19:07

Tcl, 92

  • 1 byte saved thanks to @DonalFellows.
proc s {c a p} {puts $c [expr [string map .\ + $a]]
close $c}
socket -server s $argv
vwait f

Fairly self-explanatory:

socket -server s $argv creates a listening socket on the port specified in the arguments.

Every time a new connection arrives, the proc s is called, with channel, source-address and source-port as parameters. string map substitutes . for + in the source address, and expr arithmetically evaluates the result, which is then puts back to the connection channel c.

vwait runs an event loop to catch the incoming connection events.

Credit to @DonalFellows for the following:

Here's a version that handles IPv6 (requires Tcl 8.6; most of the extra length is due to producing a hex response):

Tcl, 109

proc s {c a p} {puts $c [format %x [expr 0x[string map :\ +0x0 $a]]]
close $c}
socket -server s $argv
vwait f
  • 1
    \$\begingroup\$ Using apply doesn't seem to save anything. Nor can you use tcl::mathop::+ {*}[split $a .] as that's slightly longer. Nor can you shave anything from option names. But supporting IPv6 is pretty trivial to add, and only costs a few bytes of code more (and then a regsub-based approach is just as long). \$\endgroup\$ Commented Mar 30, 2016 at 23:06
  • \$\begingroup\$ ahhh, Tcl / Tcl-DP ... amazing bunch of tools. (in the '90s a professor showed us we could write a network-distributed Excel (with a grid, and including formulas evaluation!) shared among several persons with (iirc) 4 (short) lines for the server and 5 for the clients... \$\endgroup\$ Commented Mar 31, 2016 at 17:22
  • \$\begingroup\$ proc s {c a p} do you really need all that whitespace? \$\endgroup\$
    – cat
    Commented Apr 8, 2016 at 13:41

Groovy 133, 125, 93, 89

new ServerSocket(args[0]as int).accept{it<<(it.inetAddress.address as int[]).sum()+"\n"}

IPv4 only, probably.


new ServerSocket(args[0]as int).accept{
    it << (it.inetAddress.address as int[]).sum()+"\n"


$ telnet localhost 9000
Connected to localhost.
Escape character is '^]'.
Connection closed by foreign host.
  • 1
    \$\begingroup\$ .toInteger()as int and s.inetAddress.address*.toInteger()(s.inetAddress.address as int[]). And there is an extra space after .with. \$\endgroup\$
    – manatwork
    Commented Mar 28, 2016 at 17:33
  • \$\begingroup\$ @manatwork thx! Updated. \$\endgroup\$
    – Will Lp
    Commented Mar 28, 2016 at 18:13

Python 3, 170 166 147 bytes

from socket import*
while 1:

Takes port on stdin, IPv4 only. Works on GNU/Linux (and, I assume, most other unices), which automatically expands "" to "", not sure about Windows though.

  • 2
    \$\begingroup\$ You could save several bytes. Firstly, spaces in import * and , SOCK_STREAM are unnecessary. Also, the send line could be written more efficiently as c.send(b"%d\n"%eval(a[0].replace(".","+"))). \$\endgroup\$ Commented Mar 28, 2016 at 12:35
  • 2
    \$\begingroup\$ @HannesKarppila oh, thanks. forgot about the spaces, the eval hack is pretty cool though. \$\endgroup\$
    – sammko
    Commented Mar 28, 2016 at 12:40
  • 2
    \$\begingroup\$ AF_INET and SOCK_STREAM are just constants; AF_INET is 2 and SOCK_STREAM is 1. Also, as mentioned, SOCK_STREAM is unnecessary; so you can shorten that by instead using s=socket(2). \$\endgroup\$
    – Skyler
    Commented Mar 28, 2016 at 17:49
  • 1
    \$\begingroup\$ can't you just do socket() and therefore save another byte? \$\endgroup\$
    – Foon
    Commented Mar 28, 2016 at 18:42
  • 1
    \$\begingroup\$ You can save 10 characters by using Python 2. Then, int(input()) becomes input() and the send part becomes c.send(`eval(a[0].replace(".","+"))`) \$\endgroup\$
    – Blender
    Commented Mar 29, 2016 at 23:40

Java, 371 368 350 344 333 310 295 282 bytes


import java.net.*;class A{public static void main(String[]n)throws Exception{ServerSocket s=new ServerSocket(Integer.decode(n[0]));for(;;){try(Socket a=s.accept()){byte[]c=a.getInetAddress().getAddress();new java.io.PrintStream(a.getOutputStream()).println(c[0]+c[1]+c[2]+c[3]);}}}}


import java.net.*;

class A {
    public static void main(String[] n) throws Exception {
        ServerSocket s = new ServerSocket(Integer.decode(n[0]));
        for (;;) {
            try (Socket a = s.accept()) {
                byte[] c = a.getInetAddress().getAddress();
                new java.io.PrintStream(a.getOutputStream()).println(c[0] + c[1] + c[2] + c[3]);


mallard@steamroller:~$ telnet localhost 8888
Connected to localhost.
Escape character is '^]'.
Connection closed by foreign host.
  • 1
    \$\begingroup\$ Remove the int k= and replace the k with all the c things in Integer.toString(k). To save a few bytes. \$\endgroup\$
    – GiantTree
    Commented Mar 28, 2016 at 13:40
  • 1
    \$\begingroup\$ Javas byte pretty sure messes up the return value for or similar adresses with a byte above 127. \$\endgroup\$
    – AlexR
    Commented Mar 28, 2016 at 17:06
  • 1
    \$\begingroup\$ Change interface to class should gain few more byte \$\endgroup\$
    – ortis
    Commented Mar 29, 2016 at 8:37
  • 2
    \$\begingroup\$ Use a.getOutputStream().write((c[0] + c[1] + c[2] + c[3]+"\n").getBytes()); instead of new DataOutputStream(a.getOutputStream()).writeBytes(c[0] + c[1] + c[2] + c[3] + "\n") \$\endgroup\$
    – ortis
    Commented Mar 29, 2016 at 9:17
  • 3
    \$\begingroup\$ Isn't try(Socket a=...){} shorter than a.close();? Requires Java 7, but can gain bytes. \$\endgroup\$ Commented Mar 29, 2016 at 14:53

PowerShell v2+, 303 268 257 227 bytes

nal n new-object;($l=n Net.Sockets.TcpListener($args[0])).Start()
for(){($w=n IO.StreamWriter(($c=$l.AcceptTcpClient()).GetStream())).Write((([Net.IPEndPoint]$c.Client.RemoteEndPoint).Address-replace"\.",'+'|iex))

Saved 35 bytes thanks to Matt ... Saved another 11 bytes by aliasing New-Object and minor tweaks ... Saved 30 more bytes by implicitly using localhost rather than any IP address and corrected to account for continual usage as originally specified and I missed

Really similar to the C# answer, since it's .NET underlying both. We save a few bytes here over the C# answer by being able to leverage the returning functionality of PowerShell (surrounding our declaration/assignment in parens, and then immediately calling the . methods), but we lose an awful lot by needing to formulate the summation. The fact that we've got slightly shorter class names/calls is really why this answer is beating C#.


We first create a New-Alias (with the nal alias) to save on re-typing New-Object later. The rest of the first line is setting up a TCP Listener. We pass the command-line $args[0] as the input for creating a new System.Net.Sockets.TcpListener, stored as $l. That object is encapsulated in parens and immediately called with .Start() to have it actively open the socket.

Entering an infinite for loop, we then set our listener $l to blocking with AcceptTcpClient() which will wait for a connection. A reference to that connection (once it's made) is stored in $c, encapsulated in parens, and immediately called GetStream() to get the datastream. That datastream is passed to a new System.IO.StreamWriter constructor, $w, so we can manipulate it. That constructor is itself encapsulated in parens and immediately called Write(...).

Inside the Write(...) call, we take our client handle $c and obtain the client's RemoteEndPoint property. This is the only way (that I've found so far) to get the remote IP address. Next we need to re-cast that as a [System.Net.IPEndPoint] object so it's formatted correctly, encapsulate that in parens, and pull just the .Address property. We then -replace the literal periods with plus signs, then pipe it to Invoke-Expression (similar to eval) to obtain our summation.

After the IO write, we need to call .Dispose() to ensure the datastream is flushed to the client and closed. The TCP server drops the client connection without warning, so depending upon the client used it may hang for a while at this point. It then continues through the for loop without properly closing connections. This also means that it leaks memory and system handles like crazy, but we don't care about that, right? You may need to use Task Manager to kill the process when you're done running the server, though. :D

Also IPv4 only, as the summation barfs spectacularly trying to handle an IPv6 address, since : isn't a valid algebraic operator for iex to parse.

  • 2
    \$\begingroup\$ "Leaks memory and system handles like crazy" What, do you have to free() them after? delete[], maybe? :P \$\endgroup\$
    – cat
    Commented Mar 28, 2016 at 15:25
  • 8
    \$\begingroup\$ @tac Yeah, there's a whole slew of .close() and .dispose() methods we're not calling here that would cause people on Code Review to have a fit. \$\endgroup\$ Commented Mar 28, 2016 at 15:27
  • \$\begingroup\$ Oh, isn't PS GC'd? Or does the GC do refcounting and not scope-analysis? \$\endgroup\$
    – cat
    Commented Mar 28, 2016 at 15:28
  • \$\begingroup\$ @tac Yes, PowerShell does have garbage collection thanks to the underlying .NET system. But, depending on how you're calling or leveraging this script, you can run into bugs like this one leaking memory in the pipeline. The above code also isn't thread-safe, and so can run into GC issues with that, since we're not explicitly closing the socket. \$\endgroup\$ Commented Mar 28, 2016 at 15:40
  • 1
    \$\begingroup\$ In testing I could not get this to work, likely due to firewall issues that I don't feel like fixing so I cannot be sure but..... I think you can drop "System" from most if not all the type casts you have there ie: [Net.ipaddress]::Any works. \$\endgroup\$
    – Matt
    Commented Mar 28, 2016 at 16:21

PHP, 161 (56?)

This is my first post in here. I hope this goes right :)

<?php $s=socket_create_listen($argv[1]);while($c=socket_accept($s)){socket_getpeername($c,$r);socket_write($c,array_sum(explode('.',$r))."\n");socket_close($c);}


    $s = socket_create_listen($argv[1]); //Create socket
    while( $c = socket_accept($s) ) { // Loop accepting new connections
        socket_getpeername($c, $r); // Get IP address in $r
        socket_write($c, array_sum(explode('.', $r))."\n"); //Calculate sum
        socket_close($c); //Close connection and wait for next one


$ php test.php 8080 &
$ telnet localhost 8080
Connected to localhost.
Escape character is '^]'.
Connection closed by foreign host.

This only works for IPV4

Edit: I just noticed that php supports basic server:
I decided stick to original character count unless somebody confirms if following is allowed :)

test2.php: (possible 56-byte solution)


And then start service with:

php -S localhost:8080 test2.php

Chrome as client screenshot

Edit 2: wget as client

$ wget -qO- localhost:8080
  • \$\begingroup\$ I know rules say: "Program or function reads integer N from arguments or stdin", but is it ok if program in this case is php itself? Or is using builtin server in php considered loophole? \$\endgroup\$
    – Mikael
    Commented Mar 29, 2016 at 20:36
  • \$\begingroup\$ Welcome to Programming Puzzles & Code Golf! Your 161-byte solution looks great. Is the 56-byte solution you mentioned the one under test2.php? If so, I think you'd have to ask the OP whether they'd consider that kind of built-in acceptable for this challenge. It isn't a loophole though. \$\endgroup\$
    – Alex A.
    Commented Mar 30, 2016 at 5:13
  • \$\begingroup\$ I would say, using a builtin TCP server would be acceptable, but in this case we talk about a builtin HTTP server. So the 56 byte solution 1) does nothing if the client only connects and sends nothing; 2) sends back only “[Wed Mar 30 10:15:02 2016] Invalid request (Malformed HTTP request)” without running test2.php in case the client sends for example “foo”; 3) sends full set of HTTP response headers before the actual required response in case the client sends valid HTTP request. \$\endgroup\$
    – manatwork
    Commented Mar 30, 2016 at 7:19
  • \$\begingroup\$ @Alex A. Thank you and yes, 56-byte solution is under test2.php :) \$\endgroup\$
    – Mikael
    Commented Mar 30, 2016 at 14:48
  • \$\begingroup\$ @manatwork You are correct but I was thinking that client is not clearly specified in this task. So is it ok to use browser or even more simplier something like "wget -qO- localhost:8080" as client? \$\endgroup\$
    – Mikael
    Commented Mar 30, 2016 at 14:48

Go, 359 311

This is my first program in Go - It allowed to let me discover one thing : This is definitively not a good golfing language!

(Kudos to @steve who did most of the golfing !)

package main
func main(){l,_:=n.Listen("tcp",":"+os.Args[1])
for{c,_:=l.Accept();var s int
for _,i:=range t.Split(x.MustCompile(":[0-9]+$").ReplaceAllLiteralString(c.RemoteAddr().String(),""),"."){
  • 2
    \$\begingroup\$ But it sure is a nice language for making a tcp server! \$\endgroup\$
    – Numeri
    Commented Mar 29, 2016 at 20:52
  • 1
    \$\begingroup\$ Odd, am getting the result 360 when I connect from, rather than 427. \$\endgroup\$
    – steve
    Commented Mar 29, 2016 at 21:43
  • 3
    \$\begingroup\$ You could name the strings+strconv packages to save a few bytes. e.g. "strings" becomes s "strings" so that the later strings.Split becomes just s.Split. \$\endgroup\$
    – steve
    Commented Mar 29, 2016 at 21:49
  • 1
    \$\begingroup\$ Few more bytes shaved off pastebin.com/HY84sazE - starting to look a bit more "golfed" now \$\endgroup\$
    – steve
    Commented Mar 30, 2016 at 20:32
  • 2
    \$\begingroup\$ If you use import(."pkgname") all functions will be imported to the current namespace, you can then drop the prefix. eg. import ."fmt"; Println("foo") If you use Sscanf from the fmt package to parse the address instead of regex it'll save you another few bytes, giving you the nice bonus of having Fprintln for returning the total instead of importing strconv. \$\endgroup\$ Commented Mar 31, 2016 at 12:10

Common Lisp, 110 bytes

(use-package'usocket)(lambda(p)(socket-server"localhost"p(lambda(u)(format u"~D~%"(reduce'+ *remote-host*)))))


(use-package 'usocket)

(lambda (port)

  ;; create server with event-loop
  (socket-server "localhost"

                 ;; tcp-handler
                 (lambda (stream)
                   ;; format to stream to client
                   (format stream
                           ;; add all elements of the host,
                           ;; a vector of 4 integers
                           (reduce #'+ *remote-host*))

                   ;; client connection is closed automatically
                   ;; when exiting this function                     
  • 2
    \$\begingroup\$ Yay for Common Lithp! \$\endgroup\$
    – cat
    Commented Apr 8, 2016 at 13:43

q, 88 bytes

system raze"p ",1_.z.x;.z.pg:{(string sum"i"$0x0 vs .z.a),"\n"};.z.ph:{.h.hy[`;.z.pg[]]}
  • system raze"p ",1_.z.x: Takes the second command-line argument (the first "-" is for telling q not to interpret N as a script/file) and opens a port ("p ") with it.
    • Note: Calling q -p N sets the port as N automatically, but since the question seems to suggest that N should be an argument to the program rather than the executable itself, I've gone the longer way.
  • Inside the .z.pg function that handles incoming requests, .z.a holds the IP address as a 32-bit integer.
    • "i"$0x0 vs splits it into its integer 'constituents', and sum does the summation.
    • Last, string the numeric result and append "\n" to it to return to the client.
  • .z.ph is another function for HTTP GET requests, with extra handling to convert the string output into a valid HTTP response.

Demo - Server:

c:\q\w32>q - 1234
KDB+ 3.3 2015.11.03 Copyright (C) 1993-2015 Kx Systems
w32/ 4()core ... NONEXPIRE

Welcome to kdb+ 32bit edition
q)system raze"p ",1_.z.x;.z.pg:{(string sum"i"$0x0 vs .z.a),"\n"};.z.ph:{.h.hy[`;.z.pg[]]}

Demo - Client (from another q session running on

q)(hopen `::1234)""

Demo - Client (from curl):

$ curl localhost:1234


8086 machine code (16-bit DOS), 163 156 148 148 142 bytes

00000000  31 c0 bb 0a 00 31 c9 be  81 00 bf 80 00 8a 0d 01  |1....1..........|
00000010  cf 46 8a 0c 80 e9 30 f7  e3 00 c8 39 fe 72 f2 89  |.F....0....9.r..|
00000020  c3 89 c1 b8 01 10 ba ff  ff 31 f6 31 ff cd 61 53  |.........1.1..aS|
00000030  b8 00 12 bf 80 00 b9 01  00 ba ff ff cd 61 b8 00  |.............a..|
00000040  14 cd 61 31 c0 bb 0a 00  83 c7 06 8d 4d 04 26 02  |..a1........M.&.|
00000050  05 80 d4 00 47 39 cf 72  f5 bf 84 00 b9 80 00 bb  |....G9.r........|
00000060  0a 00 4f 31 d2 f7 f3 80  c2 30 88 15 39 cf 77 f2  |..O1.....0..9.w.|
00000070  1e 07 b8 0e 13 5b bf 80  00 b9 04 00 ba ff ff cd  |.....[..........|
00000080  61 b8 00 11 ba 01 00 cd  61 b8 00 4c cd 21        |a.......a..L.!|

Equivalent assembly code:

org 0x100
tcp equ 0x61    ; NTCPDRV interrupt

    xor ax,ax
    mov bx,10
    xor cx,cx
    mov si,0x81     ; [ds:81]-[ds:FF] = command line args
    mov di,0x80     ; [ds:80] = strlen(args)
    mov cl,[di]
    add di,cx

@@: inc si
    mov cl,[si]     ; get character
    sub cl,'0'      ; convert char to int
    mul bx          ; ax *= 10
    add al,cl
    cmp si,di
    jb @b
    ; now ax = port number

    mov bx,ax       ; source port (leaving this 0 doesn't work?)
    mov cx,ax       ; dest port
    mov ax,0x1001   ; open TCP socket for listening
    mov dx,-1       ; infinite timeout
    xor si,si       ; any dest IP
    xor di,di
    int tcp
    ; ^ I think this call should block until a connection is established, but apparently it doesn't.

    push bx         ; bx = socket handle, save it for later

    mov ax,0x1200   ; read from socket
    mov di,0x80     ; es:di = buffer (just reuse argument area to save space)
    mov cx,1        ; one byte
    mov dx,-1
    int tcp         ; this will block until a client connects and sends one byte

    mov ax,0x1400   ; get TCP session status, bx=handle
    int tcp
    ; now es:di points to a struct containing the source/dest IP addresses and ports
    ; the docs say it's two dwords for each IP address, then two bytes for "ip_prot" and "active" (whatever that means)
    ; ...but actually each IP address is followed by the port number (one word)

    xor ax,ax
    mov bx,10
    add di,6        ; [es:di+6] = client IP
    lea cx,[di+4]
@@: add al,[es:di]  ; add all bytes together
    adc ah,0
    inc di
    cmp di,cx
    jb @b
    ; now ax contains the IP address sum

    mov di,0x84     ; recycle arguments area again
    mov cx,0x80
    mov bx,10
@@: dec di
    xor dx,dx
    div bx          ; dl = ax mod 10
    add dl,'0'      ; convert int to char
    mov [di],dl
    cmp di,cx
    ja @b
    ; now [ds:80]-[ds:83] contains an ascii representation of the IP address sum

    push ds
    pop es
    mov ax,0x130e   ; send data with newline, wait for ack
    pop bx          ; socket handle
    mov di,0x80     ; es:di = data
    mov cx,4        ; sizeof data
    mov dx,-1
    int tcp

    mov ax,0x1100   ; close TCP socket
    mov dx,1
    int tcp

    mov ax,0x4c00
    int 0x21

This assumes ntcpdrv is loaded at INT 0x61 (and any suitable packet driver at 0x60). Compile with fasm tcpserv.asm.

It has some issues though:

  • It doesn't check if the argument is a valid port number, or if it's even a number at all.
  • The client must send at least one byte, since I can't seem to find any other way to tell if a client has connected.
  • It only works once, and hangs on a second attempt. Works again after a reboot.
  • The returned value is left-padded with zeroes.
  • This is my very first code golf entry, and also my very first 8086 asm program. I'm sure there are ways to improve this further.
  • 1
    \$\begingroup\$ You can just post a hexdump of the compiled output for 148 bytes \$\endgroup\$
    – cat
    Commented Apr 8, 2016 at 13:37
  • 1
    \$\begingroup\$ Alright, I've changed the entry to machine code. Also shaved a few more bytes off by using xor r,r instead of mov r,0. \$\endgroup\$ Commented Apr 8, 2016 at 20:17
  • 1
    \$\begingroup\$ I wrote it on a dos machine where newlines are CR LF, so I just went with that. Either way it's kinda pointless to count the asm size now, might as well clean it up a bit and add some comments. \$\endgroup\$ Commented Apr 9, 2016 at 15:54
  • 1
    \$\begingroup\$ source port (leaving this 0 doesn't work?) On UNIX, giving a port of 0 lets the kernel randomly assign a port, then returns the new port number. I guess DOS doesn't have that functionality \$\endgroup\$
    – cat
    Commented Apr 9, 2016 at 16:24
  • 2
    \$\begingroup\$ That's supposed to happen here too, and it does work; int 0x61 returns a random local port in ax. But it also changes the listening IP to some garbage number ( iirc) \$\endgroup\$ Commented Apr 9, 2016 at 16:39

LiveScript, 107 105 bytes

(require \http)createServer(->&1.end((.reduce (+))<|it.connection.remoteAddress/\.))listen process.argv.0

Nothing much to add, it's just basic NodeJS stuff. Style points for &1 (second argument), <| (F# piping, akin to $ in Haskell) and biop: (+) in LS is like operator sections in Haskell: a curried binary function (that adds its operands). Also a bit dirty: /, if given a literal string on its right, will do split.


Perl, 141 132 + 1 = 133 bytes


$s=new IO::Socket::INET LocalPort=><>,Listen=>5,Reuse=>1;{$c=$s->accept;$_=$c->peerhost;y/./+/;$c->send(eval.$/);shutdown $c,1;redo}


# listen on tcp port obtained from stdin
$s=new IO::Socket::INET(LocalPort=> <>,
                        Listen   => 5,
                        Reuse    => 1);

    # accept connection
    # get the ip address

    # replace dots with plus

    # send the evaluated version back, with a newline
    $c->send(eval . $/);

    # close



$ echo 7777|perl -MIO::Socket::INET -e'$s=new IO::Socket::INET LocalPort=><>,Listen=>5,Reuse=>1;{$c=$s->accept;$_=$c->peerhost;y/./+/;$c->send(eval.$/);shutdown $c,1;redo}'

$ telnet 7777
Connected to
Escape character is '^]'.
Connection closed by foreign host.
  • \$\begingroup\$ Are you sure this is correct? I get the sum printed in the server's terminal, not the client's. Anyway, you can remove all parenthesis and change s/\./+/gy/./+/. \$\endgroup\$
    – manatwork
    Commented Mar 28, 2016 at 18:08
  • \$\begingroup\$ Ahh, misread..will revise accordingly and incorporate your good y/ suggestion. \$\endgroup\$
    – steve
    Commented Mar 28, 2016 at 18:22
  • 1
    \$\begingroup\$ while(1){…}{…;redo} according to user130144's great tip. And excepting the ->send() call, all other parenthesis are unnecessary. \$\endgroup\$
    – manatwork
    Commented Mar 29, 2016 at 12:36

Python 2, 180 bytes

from SocketServer import*
TCPServer(('',input()),type('',(BaseRequestHandler,set),{'handle':lambda s:s.request.send(`eval(s.client_address[0].replace('.','+'))`)})).serve_forever()

Takes the port over stdin.


NodeJS (ES6), 129 118 107 bytes


Works for IPv4. Run as node server.js <port>

  • \$\begingroup\$ Actually doesn't work if the server's using IPv6 (as, for instance, mine does automatically), since c.remoteAddress would then be ::ffff: (I tested on Node v5.9.1). \$\endgroup\$
    – Frxstrem
    Commented Mar 29, 2016 at 23:36
  • \$\begingroup\$ Also, you don't have a trailing newline, which should increase your score by 2 bytes. \$\endgroup\$
    – Frxstrem
    Commented Mar 29, 2016 at 23:40
  • \$\begingroup\$ @Frxstrem Whoops, forgot that newline. Only adds 1 byte though thanks to template strings. Regarding IP family: .listen() used to default to IPv4 first, but it seems either by bug or design that this has changed. The submission will still function properly on newer versions of node when IPv6 is disabled on the host machine. \$\endgroup\$
    – Mwr247
    Commented Mar 30, 2016 at 0:05

Go, 211 bytes

package main
func main(){s,_:=Listen("tcp4",":"+os.Args[1])
var a,b,d,e int

Can probably be golfed further, I'm not entirely satisfied with the way I have to parse the IP adress for instance, it looks like a horrible hack.

Listens on IPv4 on the port given as argument.


PowerShell, 208 206 192 152 bytes


version information:

Name                           Value
----                           -----
PSVersion                      4.0
WSManStackVersion              3.0
CLRVersion                     4.0.30319.34209
BuildVersion                   6.3.9600.17400
PSCompatibleVersions           {1.0, 2.0, 3.0, 4.0}
PSRemotingProtocolVersion      2.2

Thanks to TimmyD for saving me 14 bytes!

Massive thanks to TessellatingHeckler for saving me 40 bytes

  • \$\begingroup\$ @TimmyD ah oops I missed that that was necessary... fixed now \$\endgroup\$
    – Nacht
    Commented Mar 30, 2016 at 21:27
  • \$\begingroup\$ One of the ways programs are allowed to take input is from stdin. i suppose this particular question doesn't specify that as allowed but it's a general code-golf thing that i think should count for PowerShell. It's unfortunately different from bash in that it doesn't wait for input on stdin if none has been provided. \$\endgroup\$
    – Nacht
    Commented Mar 31, 2016 at 12:27
  • \$\begingroup\$ fair enough. fixed again \$\endgroup\$
    – Nacht
    Commented Mar 31, 2016 at 13:29
  • \$\begingroup\$ Alrighty, now for some golfs -- try the following at 192 -- ($t=new-object net.sockets.tcplistener($args[0])).start();for(){($z=$t.acceptsocket()).send(($x=[byte[]][char[]](""+($z.remoteendpoint.address-replace"\.","+"|iex))+32),$x.count,0);$z.close()} \$\endgroup\$ Commented Mar 31, 2016 at 13:46
  • 1
    \$\begingroup\$ I think you can knock this down to 152 - drop new-object and cast directly, skip the byte array conversion and do a string cast differently, don't store $x at all and drop the remaining parameters to send(), and it becomes ($t=[net.sockets.tcplistener]$args[0]).start();for(){($z=$t.acceptsocket()).send([char[]]"$($z.remoteendpoint.address-replace"\.","+"|iex)");$z.close()} - which I've only tested quickly with netcat connecting, but it seems to work the same - connecting from localhost anyway. \$\endgroup\$ Commented Apr 8, 2016 at 0:06

C, 535 bytes

Well, someone had to do this.

I added a single line break so the posted code actually has 536 characters.

#include <stdio.h>
#include <netdb.h>
#include <netinet/in.h>
#include <string.h>
int main(int c,char**v){int f,l;char b[99];struct sockaddr_in d,e;f=socket(AF_INET,SOCK_STREAM,0);bzero(&d,sizeof(d));d.sin_family=AF_INET;d.sin_addr.s_addr=INADDR_ANY;d.sin_port=htons(atoi(v[1]));bind(f,&d, sizeof(d));listen(f,5);l=sizeof(e);
f=accept(f,&e,&l);bzero(b,99);int p,q,r,s;char g[INET_ADDRSTRLEN];inet_ntop(AF_INET,&(e.sin_addr),g,INET_ADDRSTRLEN);sscanf(g,"%d.%d.%d.%d",&p,&q,&r,&s);sprintf(b,"%d\n",p+q+r+s);write(f,b,strlen(b));return 0;}

compile with gcc [file_name] -o server

run with ./server [port]

connect with telnet localhost [port]

  • 3
    \$\begingroup\$ Nice answer! As mentioned before, you could save a few bytes by using actual values for some constants, such as AF_INET and SOCK_STREAM. \$\endgroup\$ Commented Apr 1, 2016 at 10:15

Haskell, 216 bytes

Using the "network-simple" package (cabal install network-simple). Needs a couple of language extensions (-XOverloadedStrings -XNoMonomorphismRestriction) to work.

import Network.Simple.TCP(serve)
import Network.Socket
import Data.Bits
main=getLine>>= \n->serve"*"n p
p(s,(SockAddrInet _ h))=()<$(send s$(show$sum$w h 24)++"\n")
w h 0=[h.&.m]
w h n=h`shiftR`n.&.m:(w h$n-8)

There are a couple of possible simplifications, including changing the w function to return the sum directly rather than a list, and using a function rather than a program so that the port number can be specified as an argument. I don't imagine this would reduce the size very much, though. 20 bytes perhaps?

  • \$\begingroup\$ Nice! Pretty sure you can still shave a few bytes off by renaming w to #, so w h n becomes h#n for a savings of 2 bytes per usage. \$\endgroup\$
    – fmt
    Commented Apr 6, 2016 at 0:10

Mumps, 114 115 Bytes


R P F{S J=0,I="|TCP|1" O I:(:P) U I R K F K=1:1:4{S J=J+$P(##class(%SYSTEM.TCPDevice).PeerAddr(),".",K)} W J,! C I}


R P             ; Read Port # from STDIN ;
  F{            ; Loop over everything;
  S J=0,        ; Initial IP segment total
  I="|TCP|1"    ; TCP device
  O I:(:P)      ; Open the TCP device, port from input {and sticking a tongue out! :-) }
  U I           ; Use the TCP device
  R K           ; Read from STDIN (anything)
  F K=1:1:4{    ; Iterate 1->4 in variable K
    S J=J+      ; Accumulate the following segments of the IP in var. J
    $P(##class(%SYSTEM.TCPDevice).PeerAddr(),".",K) ; Grab each piece of IPv4.
            }   ; close the loop.
  W J,!         ; Write the total w/newline out the TCP port 
  C I           ; close the TCP port to send.
}               ; end final loop

This is the InterSystems Caché version of Mumps - if there's a version out there that can acquire the TCP address shorter than ##class(%SYSTEM.TCPDevice).PeerAddr() (as it's almost a 1/3 of the entire program) it might have a better chance against some of the other languages posted already... ;-)

Edit: Thanks to @TimmyD - I missed the reading of the port from STDIN or arguments instead of being hardcoded. Edited; it added 1 byte to the program.

  • \$\begingroup\$ @TimmyD - Ah, you're correct. Missed that on reading through the requirements. Will edit posthaste. \$\endgroup\$
    – zmerch
    Commented Apr 4, 2016 at 21:43

C, 243 188 bytes (or perhaps 217 162 bytes)

V2: see below for the explanations.

188 bytes:

s;main(g,v)char**v;{short S[8]={2,htons(atoi(v[1]))};char C[g=16];bind(s=socket(2,1,0),&S,g);for(listen(s,8);g=fdopen(accept(s,&C,&g),"w");fclose(g))fprintf(g,"%d\n",C[4]+C[5]+C[6]+C[7]);}

Slightly circumspect 162 bytes:

s;main(g){short S[8]={2,g};char C[g=16];bind(s=socket(2,1,0),&S,g);for(listen(s,8);g=fdopen(accept(s,&C,&g),"w");fclose(g))fprintf(g,"%d\n",C[4]+C[5]+C[6]+C[7]);}

Probably more golfing possible tomorrow morning. I'll tidy this post up after those updates.


This one was really quite fun to golf.

s,c,q;main(g,v)char**v;{struct sockaddr_in S={2,htons(atoi(v[1]))},C;bind(s=socket(2,1,0),&S,g=16);for(listen(s,8);c=accept(s,&C,&g);q=fclose(g)){for(g=4;g;q+=C.sin_addr.s_addr>>8*--g&255);fprintf(g=fdopen(c,"w"),"%d\n",q);}}

It works for IPv4. Mostly it's a straightforward implementation. The three main components are

Creating the socket:

struct sockaddr_in S={2,htons(atoi(v[1]))},C;bind(s=socket(2,1,0),&S,g=16);

We use the various explicit forms of the constants AF_INET etc, and make use of the fact that when a struct is initialised in C in this way the non-specified elements are set to zero.

Listen for clients, accept them, and close their connections:


Finally to send each client the data:


The IP is stored in C.sin_addr.s_addr as a 32 bit integer where each octet is represented by one of the four bytes. We sum these bytes with the for loop and then print them to the stream using fprintf.

I have a shorter 217 byte solution but I'm not entirely sure it doesn't violate the standard loopholes since it requires that the port is given in unary in network byte order as command line arguments. That is, to run the server on port 12345 one would need to call

$ ./tcp 1 1 1 1 ... 1 1 1

where the total number of 1s is 14640. To say the least it's a little... cumbersome. But here it is anyway:

s,c,q;main(g){struct sockaddr_in S={2,g},C;bind(s=socket(2,1,0),&S,g=16);for(listen(s,8);c=accept(s,&C,&g);q=fclose(g)){for(g=4;g;q+=C.sin_addr.s_addr>>8*--g&255);fprintf(g=fdopen(c,"w"),"%d\n",q);}}

Java, 210 bytes


p->{java.net.ServerSocket x=new java.net.ServerSocket(p);for(;;){try(java.net.Socket s=x.accept()){byte[]b=s.getInetAddress().getAddress();s.getOutputStream().write((0+b[0]+b[1]+b[2]+b[3]+"\n").getBytes());}}};


@FunctionalInterface interface Consumer { // Define an interface that allows a function that throws an exception.
  void accept(int port) throws Exception;

Consumer consumer = (port) -> {
  java.net.ServerSocket serverSocket = new java.net.ServerSocket(port);
    for (;;) {
      try (java.net.Socket socket = serverSocket.accept()) {
        byte[] bytes = socket.getInetAddress().getAddress();
        socket.getOutputStream().write((0 + b[0] + b[1] + b[2] + b[3] + "\n").getBytes());

This a gathering of all the tips I gave in other Java answers, plus the writing as a function instead of a full program, which gains roughly 70 bytes compared to the program.


Haskell, 326 bytes

import Data.Bits
import Network.Socket
import System.IO
f n=withSocketsDo$do
 s<-socket AF_INET Stream defaultProtocol
 bind s$SockAddrInet n iNADDR_ANY
 listen s 1
 g s
g s=do
 (z,SockAddrInet _ a)<-accept s
 h<-socketToHandle z WriteMode
 hPutStrLn h$show$b a
 hClose h
 g s
b 0=0
b x=x.&.0xFF+b(x`shiftR`8)

Sadly I had to use Network.Socket to get access to the remote IP address as an integer rather than a string. It would have saved dozens of characters if I could just do s <- listenOn (PortNumber n), rather than having to explicitly call socket, bind and listen individually. But, sadly, Network.accept gives me a host string, not an IP address integer, so I had to resort to Network.Socket.accept and friends.

The function f takes a port number as argument, and creates a server socket (s) listening on that port. It then calls the function g with the server socket. g loops forever, accepting connections. The function b takes an actual IPv4 address and computes the sum of its digits.

I'm sure somebody somewhere can do this better than me. I wanted to show off just how damned easy socket stuff is in Haskell... but then failed miserably, because I need access to the IP address, which isn't usually easy to get.

  • \$\begingroup\$ The "network-simple" package provides a much nicer interface which passes the SockAddr to a function you give it, which makes things easier. See my solution which I'm about to post... \$\endgroup\$
    – Jules
    Commented Mar 31, 2016 at 15:49
  • \$\begingroup\$ A few simplifications are apparent: (1) I believe withSocketsDo is only necessary on Windows, so if running on Linux it can be ignored; (2) 0xFF is a character longer than 255; (3) converting the socket to a handle and using regular IO is a lot longer than using Network.Socket.send. Yes, send is deprecated, but the reason is not relevant to this scenario (it only relates to non-ASCII text or binary data), so it seems reasonable to use it. \$\endgroup\$
    – Jules
    Commented Mar 31, 2016 at 16:04
  • \$\begingroup\$ Network.accept gives me a host string, not an IP address integer Can't you just split the IP string on the ".", map Haskell's string-to-number function over the split string and sum the results? \$\endgroup\$
    – cat
    Commented May 2, 2016 at 2:21

Lua, 169 162 160 153 151 148 138 129 bytes

Golfed version

m=require"socket".bind(0,...)::l::c=m:accept()f=0 for n in c:getpeername():gmatch"%d+"do f=f+n end c:send(f.."\n")c:close()goto l

It requires Luasocket to be installed and an interpreter that supports labels. I've tested it with Luajit and I can also confirm that the code does not work with Lua 5.1.

Ungolfed version


for n in c:getpeername():gmatch"%d+" do

goto l

Edit 1:

Changed i=({c:getpeername()})[1] to just i=c:getpeername()

Edit 2:

Removed braces from the require statement.

Edit 3:

Removed the braces around the vararg, decreased the byte count a little bit.

Edit 4:

Removed the parenthesis around "%d+", shorter by 2 bytes.

Edit 5:

Removed the unnecessary variable i.

Edit 6:

Changed the ip from "" to 0. (Thanks to xyzzy on #lua)

Edit 7:

Removed the function call to tonumber since strings are cast to numbers automatically (Thanks to Trebuchette for the suggestion, I did not know this)

  • 1
    \$\begingroup\$ Only Lua 5.2 and up support labels, if you're curious \$\endgroup\$ Commented Mar 31, 2016 at 3:25
  • 1
    \$\begingroup\$ Also, Lua automatically casts strings to numbers with the + operator, so you can take out tonumber. \$\endgroup\$ Commented Mar 31, 2016 at 3:32

Haskell, 185 (+ 19 = 204)? bytes

import Network.Simple.TCP(serve)
import Network.Socket
import Data.List.Split
main=getLine>>=flip(serve"*4")(\(a,b)->()<$(send a$(++"\n")$show$sum.map read.take 4.sepByOneOf":."$show b)

Takes port number as one line on stdin; requires network-simple from Cabal.

As usual with Haskell answers that don't constrain themselves to pure functions, the imports take up far too many bytes. The trailing newline is also worth 9 bytes...

Somewhat similar to @Jules's answer, but I use string manipulation instead of byte operations. I stole used the -XOverloadedStrings extension as well, which is probably worth 19 bytes extra.


Racket, 265 bytes

#lang racket(define l(tcp-listen(string->number(read-line))))(let e()(define-values(i o)(tcp-accept l))(thread(λ()(define-values(a b)(tcp-addresses o))(write(~a(foldl + 0(map string->number(string-split a".")))o))(newline o)(close-output-port o)))(e)))


#lang racket
(define listener (tcp-listen (string->number (read-line))))
(define (mk-server)
  (let echo-server ()
    (define-values (in out) (tcp-accept listener))
       (define-values (a b) (tcp-addresses out))
       (write (number->string (foldl + 0(map string->number(string-split a "."))) out))
       (write "\n" out)
       (close-output-port out)))

Factor, 155 146 131 206 190 bytes

Well, I just learned a lot about low-level socket programming. I don't think I ever wanna do that again, because my thrhead hurts.

[ utf8 <threaded-server> readln 10 base> >>insecure [ remote-address get host>> "." split [ 10 base> ] map sum 10 >base print flush ] >>handler [ start-server ] in-thread start-server drop ]

Oh yeah, threaded, and doesn't return, right.

  • \$\begingroup\$ Can you use 10 base> instead of string>number? \$\endgroup\$
    – fede s.
    Commented Apr 9, 2016 at 18:24
  • \$\begingroup\$ @fedes. Wow, I never knew that existed. I think that will allow me to shorten a lot of my Factor answers! \$\endgroup\$
    – cat
    Commented Apr 9, 2016 at 18:30
  • \$\begingroup\$ And 10 >base for number>string, also. \$\endgroup\$
    – fede s.
    Commented Apr 9, 2016 at 18:30
  • 1
    \$\begingroup\$ @fedes. Those deserve an answer here :D \$\endgroup\$
    – cat
    Commented Apr 9, 2016 at 18:32

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