227
\$\begingroup\$

Using your language of choice, golf a quine.

A quine is a non-empty computer program which takes no input and produces a copy of its own source code as its only output.

No cheating -- that means that you can't just read the source file and print it. Also, in many languages, an empty file is also a quine: that isn't considered a legit quine either.

No error quines -- there is already a separate challenge for error quines.

Points for:

  • Smallest code (in bytes)
  • Most obfuscated/obscure solution
  • Using esoteric/obscure languages
  • Successfully using languages that are difficult to golf in

The following Stack Snippet can be used to get a quick view of the current score in each language, and thus to know which languages have existing answers and what sort of target you have to beat:

var QUESTION_ID=69;
var OVERRIDE_USER=98;

var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe";var COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk";var answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;function answersUrl(index){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+index+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}
function commentUrl(index,answers){return"https://api.stackexchange.com/2.2/answers/"+answers.join(';')+"/comments?page="+index+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}
function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(data){answers.push.apply(answers,data.items);answers_hash=[];answer_ids=[];data.items.forEach(function(a){a.comments=[];var id=+a.share_link.match(/\d+/);answer_ids.push(id);answers_hash[id]=a});if(!data.has_more)more_answers=!1;comment_page=1;getComments()}})}
function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(data){data.items.forEach(function(c){if(c.owner.user_id===OVERRIDE_USER)
answers_hash[c.post_id].comments.push(c)});if(data.has_more)getComments();else if(more_answers)getAnswers();else process()}})}
getAnswers();var SCORE_REG=(function(){var headerTag=String.raw `h\d`
var score=String.raw `\-?\d+\.?\d*`
var normalText=String.raw `[^\n<>]*`
var strikethrough=String.raw `<s>${normalText}</s>|<strike>${normalText}</strike>|<del>${normalText}</del>`
var noDigitText=String.raw `[^\n\d<>]*`
var htmlTag=String.raw `<[^\n<>]+>`
return new RegExp(String.raw `<${headerTag}>`+String.raw `\s*([^\n,]*[^\s,]),.*?`+String.raw `(${score})`+String.raw `(?=`+String.raw `${noDigitText}`+String.raw `(?:(?:${strikethrough}|${htmlTag})${noDigitText})*`+String.raw `</${headerTag}>`+String.raw `)`)})();var OVERRIDE_REG=/^Override\s*header:\s*/i;function getAuthorName(a){return a.owner.display_name}
function process(){var valid=[];answers.forEach(function(a){var body=a.body;a.comments.forEach(function(c){if(OVERRIDE_REG.test(c.body))
body='<h1>'+c.body.replace(OVERRIDE_REG,'')+'</h1>'});var match=body.match(SCORE_REG);if(match)
valid.push({user:getAuthorName(a),size:+match[2],language:match[1],link:a.share_link,})});valid.sort(function(a,b){var aB=a.size,bB=b.size;return aB-bB});var languages={};var place=1;var lastSize=null;var lastPlace=1;valid.forEach(function(a){if(a.size!=lastSize)
lastPlace=place;lastSize=a.size;++place;var answer=jQuery("#answer-template").html();answer=answer.replace("{{PLACE}}",lastPlace+".").replace("{{NAME}}",a.user).replace("{{LANGUAGE}}",a.language).replace("{{SIZE}}",a.size).replace("{{LINK}}",a.link);answer=jQuery(answer);jQuery("#answers").append(answer);var lang=a.language;lang=jQuery('<i>'+a.language+'</i>').text().toLowerCase();languages[lang]=languages[lang]||{lang:a.language,user:a.user,size:a.size,link:a.link,uniq:lang}});var langs=[];for(var lang in languages)
if(languages.hasOwnProperty(lang))
langs.push(languages[lang]);langs.sort(function(a,b){if(a.uniq>b.uniq)return 1;if(a.uniq<b.uniq)return-1;return 0});for(var i=0;i<langs.length;++i)
{var language=jQuery("#language-template").html();var lang=langs[i];language=language.replace("{{LANGUAGE}}",lang.lang).replace("{{NAME}}",lang.user).replace("{{SIZE}}",lang.size).replace("{{LINK}}",lang.link);language=jQuery(language);jQuery("#languages").append(language)}}
body{text-align:left!important}#answer-list{padding:10px;float:left}#language-list{padding:10px;float:left}table thead{font-weight:700}table td{padding:5px}
 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="https://cdn.sstatic.net/Sites/codegolf/primary.css?v=f52df912b654"> <div id="language-list"> <h2>Winners by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td><a href="{{LINK}}">{{SIZE}}</a></td></tr></tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td><a href="{{LINK}}">{{SIZE}}</a></td></tr></tbody> </table> 

\$\endgroup\$
3
  • 4
    \$\begingroup\$ Do you not mean, "Golf you a quine for greater good!"? \$\endgroup\$ May 3 '11 at 2:49
  • 59
    \$\begingroup\$ @muntoo it's a play on "Learn you a Haskell for Great Good". \$\endgroup\$ May 3 '11 at 2:52
  • 12
    \$\begingroup\$ Did anybody notice that this is question 69? \$\endgroup\$
    – aidan0626
    Oct 24 '20 at 22:47

406 Answers 406

1
\$\begingroup\$

Aubergine, 16 bytes

-a1+a1=oA:bA=iB

Try it online!

The program has a trailing null byte. Works similarly to my hello world.

\$\endgroup\$
1
\$\begingroup\$

Perl 6, 36

printf |(q<printf |(q<%s>xx 2)>xx 2)

Based on the Perl 5 quine.

\$\endgroup\$
0
1
\$\begingroup\$

Brachylog v2, 12 bytes

"~k;?w₁";?w₁

Try it online!

Full program. Essentially a translation of Fatalize's (non-builtin) Brachylog v1 answer, although it also uses different SWI-Prolog formatting sequences, or rather, a single different one, which saves about 20 bytes (both [34:s, both :34]s, and both ~cs). It seems to have existed back in 2016, but it was probably bugged or something. The last two bytes saved come from using the implicit input, which Brachylog being Brachylog is useful even when the program receives no input, because it's a variable (so instead of explicitly unifying the string with S, we just let it be implicitly unified with ?).

          w     Print
"~k;?w₁"        "~k;?w₁"
                which is the input
           ₁    formatted with
        ;?      the input.
 ~k             (so that the ~k is replaced with the input's canonical representation, i.e. in quotes)

We don't actually need to use implicit input--"~kgjw₁"gjw₁ works just as well (and might even translate back to v1)--but doing so regardless manages to both more closely mirror the structure of the original and feel cleverer.

\$\endgroup\$
1
\$\begingroup\$

C (gcc), 85 bytes

#define q(k)main(){puts(#k"\nq("#k")");}
q(#define q(k)main(){puts(#k"\nq("#k")");})

Try it online!

The q() macro expands into a program that prints out its argument on the first line, and prints out the argument called by q() itself in the second line. So:

#define q(k)main(){puts(#k"\nq("#k")");}
q(foo)

would expand into:

main(){puts("foo""\nq(""foo"")");}

and after string literal concatenation, becomes:

main(){puts("foo\nq(foo)");}

And executing and running the program would produce:

foo
q(foo)

Replacing foo with the macro definition itself results in the quine.

\$\endgroup\$
1
\$\begingroup\$

C, 353 bytes

char q[]={125,59,109,97,105,110,40,41,123,112,114,105,110,116,102,40,34,99,104,97,114,32,113,91,93,61,123,34,41,59,99,104,97,114,42,112,61,113,59,119,104,105,108,101,40,42,112,41,112,114,105,110,116,102,40,34,37,100,44,34,44,42,112,43,43,41,59,112,117,116,115,40,113,41,59,125,};main(){printf("char q[]={");char*p=q;while(*p)printf("%d,",*p++);puts(q);}
\$\endgroup\$
18
  • 1
    \$\begingroup\$ With some golfing, including changing it from hexadecimal to decimal, this can be 354 bytes \$\endgroup\$
    – Jo King
    Aug 2 '19 at 2:04
  • 1
    \$\begingroup\$ The link itself is a gcc compiler and it works fine. Are you sure they aren't just warnings? \$\endgroup\$
    – Jo King
    Aug 2 '19 at 2:51
  • 1
    \$\begingroup\$ If only the output is erroring, then what is the difference between the two programs? What version of gcc are you using? \$\endgroup\$
    – Jo King
    Aug 2 '19 at 3:15
  • 1
    \$\begingroup\$ ... What is the difference between the code of the two programs, not their behaviour. I already know that the second one fails. The version TIO uses is 8.3, and that works fine. \$\endgroup\$
    – Jo King
    Aug 2 '19 at 3:32
  • 1
    \$\begingroup\$ I don't care about the output of the second generation quine. I would like to know the output of the first program, the one that didn't fail and produced something that did. I don't want to know about the errors that you have commented about several times already. I would like to know the difference between the program I have given you and its output. You can put the program in an online compiler like I have and link it in a comment below. \$\endgroup\$
    – Jo King
    Aug 2 '19 at 3:49
1
\$\begingroup\$

Javascript (REPL), 23 22 21 bytes

someone else posted this first

(_=x=>`(_=${_})()`)()

paste into chrome console or equivalent to test

JavaScript (V8), 49 48 47 bytes

@NieDzejkob saved 1 byte on both versions

console.log((_=x=>`console.log((_=${_})())`)())

Try it online!

\$\endgroup\$
2
1
\$\begingroup\$

Wren, 287 bytes

var a="[118,97,114,32,97,61,34].each{|m|System.write(String.fromCodePoint(m))}
System.write(a+String.fromCodePoint(34)+String.fromCodePoint(10)+a)"
[118,97,114,32,97,61,34].each{|m|System.write(String.fromCodePoint(m))}
System.write(a+String.fromCodePoint(34)+String.fromCodePoint(10)+a)

Try it online!

Explanation

var a=                                                                         // Define the variable a
      "[118,97,114,32,97,61,34].each{|m|System.write(String.fromCodePoint(m))}
System.write(a+String.fromCodePoint(34)+String.fromCodePoint(10)+a)"           // As the string that processes the variable

                                                                               // A literal newline is inserted and can be decoded literally.

[118,97,114,32,97,61,34].each{|m|System.write(String.fromCodePoint(m))}        // Output the string "var a=" to the console
System.write(                                                                  // Output without a newline:
             a                                                                 // The string a
              +String.fromCodePoint(34)                                        // Plus a quote
                                       +String.fromCodePoint(10)               // Plus a newline
                                                                +a)            // Plus the string again
```
\$\endgroup\$
2
  • \$\begingroup\$ Why doesn't fromByte work in place of fromCodePoint? \$\endgroup\$
    – Jo King
    Oct 29 '19 at 23:28
  • \$\begingroup\$ I have absolutely no idea. \$\endgroup\$
    – user85052
    Oct 30 '19 at 3:57
1
\$\begingroup\$

Keg, 8 6 4 bytes

`④`④

Try it online!

Answer History

8 bytes

`:.,`:.,

Try it online!

Why did it take me so long to figure out how to write a quine in Keg? I really should have picked up on this sooner.

Basically, it pushes the string :.,, duplicates it, prints the string repr'd and then prints it nicely.

\$\endgroup\$
1
\$\begingroup\$

W, 13 bytes

Print the data string & prepend quote.

p34CS+"p34CS+
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1
\$\begingroup\$

tq, 8 bytes

New high-level language! (Technically inspired by Jo King's Symbolic Raku quine.)

etq'etq'

Explanation

   'etq' # Define the second item of the list
         # As a string
  q      # Surround the string with quotes
 t       # For the first item of the list,
         # Access the last (tail) item in the list,
e        # and un-quote the accessed value.

# The list becomes etq, 'etq' (comma is for readability)
# , which then becomes foreach-printed without any separator.
```
\$\endgroup\$
1
\$\begingroup\$

Common Lisp, 58 bytes

Lisp is perfect for quines because of using code as data, but terseness is not its strong suit.

(FORMAT T "(~{~S ~}~:*'~S)" '(FORMAT T "(~{~S ~}~:*'~S)"))

Excellent expert explanation.

(FORMAT T  -- print
"(      )" -- between parentheses
" ~{  }~ " -- looping over the list argument
" ~S_    " -- each item followed by a space
"   ~:*  " -- use the FORMAT sublanguage's *very* fancy
             -- "~*" directive (skip argument) with the ":"
             -- modifier to back up and reuse the argument
"    '~S " -- print the argument again with a quote before it
    '(FO.. -- the argument is the same thing but with a quote
             -- in front to show that it is data

Ideone it!

Alternative 9 bytes, that only works in the REPL

(prin1 -)

(use print for a trailing newline)

This prints the value of '-', which is the current expression being evaluated. You can try it here.

\$\endgroup\$
1
\$\begingroup\$

33, 24 bytes

"34cke12ketp"34cke12ketp

Try it online!

Explanation:

"34cke12ketp"               Push the string 34c0ke13ketp to the source string
             34c            Put 34 in the accumulator
                k           Push a " to the destination string
                 e          Append the source string to the destination string
                  12k       Push a " to the end of the destination string
                     e      Append the source string to the destination string
                      t     Swap the source and the destination string
                       p    And print the source string
\$\endgroup\$
1
\$\begingroup\$

4, 3101 bytes

3.611102101111601492000010000000160111200001000000016010020000100000001601002000010000000160139200001000000016019520000100000001601842000010000000160199200001000000016019920000100000001601092000010000000160190200001000000016010920000100000001601912000010000000160111200001000000016019920000100000001601992000010000000160121200001000000016011020000100000001601092000010000000160193200001000000016010020000100000001601892000010000000160101200001000000016011020000100000001601102000010000000160130200001000000016013020000100000001601002000010000000160100200001000000016019920000100000001601002000010000000160100200001000000016010920000100000001601202000010000000160100200001000000016010220000100000001601312000010000000160199200001000000016019920000100000001601282000010000000160199200001000000016019920000100000001601902000010000000160111200001000000016019920000100000001601992000010000000160127200001000000016019920000100000001601992000010000000160191200001000000016011120000100000001601892000010000000160179200001000000016012120000100000001601192000010000000160198200001000000016019320000100000001601992000010000000160110200001000000016019920000100000001601102000010000000160119200001000000016019920000100000001601922000010000000160101200001000000016011020000100000001601992000010000000160131200001000000016010820000100000001601042000010000000160100200001000000016011020000100000001601092000010000000160190200001000000016013020000100000001601302000010000000160160200001000000016019920000100000001601602000010000000160110200001000000016013020000100000001601302000010000000160151200001000000016010320000100000001601032000010000000160105200001000000016011020000100000001601302000010000000160130200001000000016010220000100000001601822000010000000160103200001000000016010120000100000001601182000010000000160129200001000000016012220000100000001601312000010000000160152200001000000016018220000100000001601252000010000000160110200001000000016012520000100000001601222000010000000160151200001000000016015120000100000001601022000010000000160120200001000000016011320000100000001601152000010000000160112200001000000016011120000100000001601012000010000000160131200001000000016012920000100000001601452000010000000160194200001000000016015920000100000001601452000010000000160194200001000000016015820000100000001601452000010000000160194200001000000016015020000100000001601552000010000000160184200001000000016015920000100000001601452000010000000160194200001000000016015920000100000001601452000010000000160145200001000000016015120000100000001601052000010000000160115200001000000016015420000100000001601542000010000000160156200001000000016011520000100000001601152000010000000160160200001000000016015020000100000001601562000010000000160194200001000000016019420000100000001601682000010000000160148200001000000016014620000100000001648486494965050651516545455150155454954954954855054954854954954954921310112151310220151522520152282513229281103028200303015030301503030106990603030990010040801399011029999101990199398991129798111999997299991109999982999913200002900000990000030301011098003990011299991119900990999948599300001194

Try it online!

Explanation

3.           Required boilerplate
6 11 10      Set cell 11 to 10
2 10 11 11   Set cell 10 to cell 11*cell 11 (10*10=100)

-- Data Section --
Every pair of digits in the program are represented by
6 01 49      Set cell 01 to the two digits joined together
2 00 00 10   Multiply cell 00 by 100
0 00 00 01   Add cell 01 to 00

This essentially makes cell 00 the rest of the program after the data section

6 48 48      Set each of the cells 48,49,50,51,54 to their respective values
6 49 49
6 50 50
6 51 51
6 54 54

551501554549549549548550549548549549549549  Print the initial section ('3.611102101111')

2 13 10 11   Initialise various powers of 10
2 15 13 10
2 20 15 15
2 25 20 15
2 28 25 13
2 29 28 11

0 30 28 20   Create the number '1000000010000200106', which is each data part backwards
0 30 30 15
0 30 30 15
0 30 30 10
6 99 06
0 30 30 99

0 01 00 40   Copy cell 00 to cell 01

8 01         Loop while cell 01 is not zero

  3 99 01 10    Integer divide cell 01 by 100 and store in cell 99
  2 99 99 10    Multiply cell 99 by 100
  1 99 01 99    Subtract cell 99 from cell 01 to get cell 01 modulo 100

  3 98 99 11
  2 97 98 11
  1 99 99 97
  2 99 99 11
  0 99 99 98    Swap the two digits of the modulo result
  2 99 99 13    Multiply it by 1000

  2 00 00 29    Multiply cell 00 by 10**19
  0 00 00 30    And append a copy of a data part
  0 00 00 99    And insert the modulo result in the correct place
  
  3 01 01 10    And divide cell 01 by 100
9            End loop

Now we print the number in cell 00 in reverse

8 00         Loop while cell 00 is non-zero
  3 99 00 11    Get the last digit of cell 00
  2 99 99 11
  1 99 00 99

  0 99 99 48    Add the digit to '0'
  5 99          And print

  3 00 00 11    Divide cell 00 by 10
9            End loop
\$\endgroup\$
3
  • \$\begingroup\$ I should write a SEDE query to see how many of the 362 quines you've written. \$\endgroup\$
    – Razetime
    Sep 19 '20 at 17:00
  • \$\begingroup\$ @Razetime A search for inquestion:69 user:76162 currently puts it at 32 \$\endgroup\$
    – Jo King
    Sep 19 '20 at 21:44
  • \$\begingroup\$ 8% of all the answers. I'm waiting for the day 50% comes. \$\endgroup\$
    – Razetime
    Sep 20 '20 at 3:35
1
\$\begingroup\$

JavaScript (ES6), 11 bytes

a=_=>'a='+a

Try it online!

\$\endgroup\$
1
\$\begingroup\$

Groovy, 90 bytes

`s='s=\\\';s[0..1]+s[3]+s[0..1]+s[2]*6+s[3..-1]*2';s[0..1]+s[3]+s[0..1]+s[2]*6+s[3..-1]*`2

Edit

Works in GroovyConsole

\$\endgroup\$
1
\$\begingroup\$

AWK, 56 bytes

BEGIN{printf a="BEGIN{printf a=%c%s%c,34,a,34}",34,a,34}

Try it online!

Outgolfed these two.

\$\endgroup\$
1
\$\begingroup\$

05AB1E, 13 bytes

"34çì«"34çì«

Try it online!

"..."34çì«  # trimmed program
"..."       # push literal...
        ì   # prepended with...
       ç    # character with codepoint...
     34     # literal...
         «  # concatenated with...
            # (implicit) itself
            # implicit output
\$\endgroup\$
1
\$\begingroup\$

Agony, 243 bytes

<[.<]>[{(<(<){*}*{(>)}~)<(<){-.+(*}*<{)>(>)>}]${(@]@){,{.{[{*{]{)+*<}>[>*+)+]{@$${<{<<$+(@[{({.{({,>]@(>]+[>){,{({.+(@[+({,+(@(+({]+({)+({.<$@[<${-+({<@[+[>]{.>]{->]{.+(>){,+[{,{-{({]{[+({.>){->){.+]+[{.>]{-+({,+[{,+({.>){->){-+(@(>]@[>){]@(>)

Try it online!

This looks like a bit of a mess, but this language is actually a brainfuck derivative, similar to SMBF. The self-modifying part is not used to read the executed code though (especially as each instruction is not mapped to one character). Agony splits up each brainfuck cell into 4 bits each (with two cells being a "character"), with special instructions to manipulate individual cells.

Explanation:

The code is split up into three sections; Code, the printable list of characters (offset by one to avoid the zero cell in @) and the data section (which is the printable version of the other two sections backwards).

Code

<[.<]      Print out the data section printing the code and the list of chars
>[         Loop over each 4 bits of the data section
  {(         While the current cell is not zero
    <(<){      Go to the start of the character list
    *}*{       Move it over one cell to make the next character the new start
    (>)}~      Go back to the current cell and decrement it
  )
  <(<){      Go to the start of the character list
  -.+        Print it offset by one (`@` is 0010 0000, so we store it as 0010 0001)
  (*}*<{)    Move over all the other characters by one to restore the list
  >(>)>}     Move to the next cell in the data section
]$         End the loop and halt

This section is modified or read (except the $, which separates it from the character list section).

Character list

The character list is the section between the $ and the $$

{( @] @) {, {. {[ {* {] {) +* <} >[ >* +) +] {@
$  }  {  >  <  @  ~  +  -  .  ,  (  )  [  ]  *

Each pair of characters represents 8 bits each, which is the ordered list of the 15 instructions in Agony (offset by one).

Data section

Similar to the character section, each pair of characters in this part represent a single character in the code section. You can have it more efficient by just duplicating the code section entirely (thus being one to one), which is actually how the reference quine works. However, I think that even golfed, this would still take more code to handle duplicating the data section than it would save (but I'm not too sure about that, so feel free to prove me wrong).

\$\endgroup\$
1
\$\begingroup\$

ALGOL 68 (Genie), 70 bytes

STRINGa="STRINGa="";print(a[..9]*2+a[9..]*2)";print(a[..9]*2+a[9..]*2)

Try it online!

It's fascinating how modern feeling the syntax of this language (or at least the parts I've used), despite being over 50 years old. I wrote this without looking at any documentation, simply guessing at the features like string indexing (with ranges even!) and string multiplying.

Explanation:

STRINGa="STRINGa="";print(a[..9]*2+a[9..]*2)";  # Assign this string to `a` #
                                                # This escapes the " by doubling it #
print(a[..9]*2             # Print STRINGa=" twice #
     +a[9..]*2)            # Followed by ";print(a[..9]*2+a[9..]*2) twice #
\$\endgroup\$
1
\$\begingroup\$

OCaml, 66 bytes

(fun x->Printf.printf"%s%S"x x)"(fun x->Printf.printf\"%s%S\"x x)"

Try it online!

\$\endgroup\$
1
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JsonLogic, 631

{"reduce":[[1],{"cat":[{"reduce":[{"var":"accumulator"},{"cat":[{"var":"accumulator"},{"substr":["\\\",:[]1abcdelmnorstuv{}",{"var":"current"},1]}]}]},{"var":"accumulator"},"]]}"]},[21,1,16,11,10,19,9,11,1,3,4,4,6,5,2,21,1,9,7,18,1,3,4,21,1,16,11,10,19,9,11,1,3,4,21,1,20,7,16,1,3,1,7,9,9,19,13,19,12,7,18,15,16,1,22,2,21,1,9,7,18,1,3,4,21,1,20,7,16,1,3,1,7,9,9,19,13,19,12,7,18,15,16,1,22,2,21,1,17,19,8,17,18,16,1,3,4,1,0,0,0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,1,2,21,1,20,7,16,1,3,1,9,19,16,16,11,14,18,1,22,2,6,5,22,5,22,5,22,2,21,1,20,7,16,1,3,1,7,9,9,19,13,19,12,7,18,15,16,1,22,2,1,5,5,22,1,5,22,2,4]]}

Try it online by pasting it under "Rule" here. (Note: the "Output" section is JSON-encoded. The raw unquoted string is logged in the console which can be viewed with F12)

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1
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OIL, 77 bytes

Quines are one of the things that aren't that hard in OIL, because of the whole "unified memory" thing. The quine exists since a long time, but I hadn't posted it here yet.

The following code needs to be stripped of the comments to work:

0  # do nothing, these two fields are just placeholders
0
1  # copy the line above to itself
1
1
4  # output line 1
1
11 # and a newline
4  # and output line 1 again
1
11 # and a newline (now we printed 0 and 0)
1  # copy line 2 to line 2
2  # *
2
1  # copy
12 # line 12 (the one marked with the star)
18 # to line 18 (marked with $)
10 # ^, if the next line (currently 2) is equal to the line afterwards (1)
18 # $
1
32 # jump to line 32 (essentially quitting, because it's out of bounds)
22 # otherwise to the next line:
1  # copy from 18 ($) to 26 (&)
18
26
4  # output from the cell with the number in the next line
26 # &
8  # increment line 18 ($)
18
11 # newline
6  # jump to line 17 (^, beginning of the loop)
17
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0
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Ada, 274 258 257 Characters

with Text_IO;use Text_IO;procedure Q is M:Character:='"';T:String:="with Text_IO;use Text_IO;procedure Q is M:Character:=';T:String:=;begin Put_Line(T(1..54)&M&T(54..65)&M&T&M&T(66..126));end Q;";begin Put_Line(T(1..54)&M&T(54..65)&M&T&M&T(66..126));end Q;

pretty printed:

with Text_IO;
use Text_IO;
procedure Quine is
   M : Character := '"';
   T : String := "with Text_IO;use Text_IO;" &
     "procedure Q is M:Character:=';T:String:=;" &
     "begin Put_Line(T(1..54)&M&T(54..65)&M&T&M&T(66..126));end Q;";
begin
   Put_Line(T(1..54)&M&T(54..65)&M&T&M&T(66..126));
end Quine;

this program actually produces the short version (output can be redirected to q.adb).

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0
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Pretty certain you can't get shorter than this with Common Lisp. The first one I managed to figure out myself; all credit to http://rosettacode.org/wiki/Quine#Common_Lisp for the second one.

Common Lisp - 9 (With REPL)

(write -)

In Common Lisp, - is a special variable that holds the expression currently being evaluated but only during a read-eval-print loop. If you're running from a script or you've disabled the REPL though...

Common Lisp - 25 (No REPL)

#1=(write '#1# :circle t)

This references itself and then prints itself out. :circle t makes it detect the infinite recursion cycle and exit early.

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0
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CJam, 1 byte

Note: CJam was made after this challenge was posted, I am posting this answer as documentation as opposed to a serious entry.

0

Pushes a 0 to the stack, and CJam automatically outputs the stack after program execution.

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3
  • \$\begingroup\$ Don't forget newlines. \$\endgroup\$ May 28 '17 at 1:39
  • 2
    \$\begingroup\$ One part of the program does not encode another, so this program is invalid \$\endgroup\$
    – MilkyWay90
    Feb 5 '19 at 18:04
  • \$\begingroup\$ @MilkyWay90 Am I missing something about the definition of a quine? The challenge simply states "A quine is a non-empty computer program which takes no input and produces a copy of its own source code as its only output." This seems to do that. \$\endgroup\$ Mar 31 '21 at 18:15
0
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ForceLang with this module, 87 bytes

Noncompeting, language postdates the challenge

set j require njs
j var f=function(){print("set j require njs\nj var f="+f+";f()")};f()
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0
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Idris, 88 bytes

q:String;main:IO();main=putStr$q++show q;q="q:String;main:IO();main=putStr$q++show q;q="

It’s like Haskell with more enforced top-level type signatures. I had to put q’s type first, because Idris’s type checker is a little weird? I dunno.

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0
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Forth (gforth), 21 bytes

: x
latest name-see ;

This prints the decompiled source of the latest word, thus only works if x is the latest defined word.

Test:

x 
: x  
latest name-see ; ok

This one works without that condition, but replaces the constant definition with it's value (since that's the only thing that actually gets saved to memory)

: x
[ latest ] literal name-see ;

Test:

x 
: x  
  140121195205104 name-see ; ok
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3
  • 1
    \$\begingroup\$ If it prints with a newline in the middle, but the original doesn't have it, it's not a quine. \$\endgroup\$
    – Pavel
    Dec 29 '16 at 5:07
  • \$\begingroup\$ Fixed. It's because there's no way to tell where spaces/newlines are as it's only compiled code \$\endgroup\$
    – 2xsaiko
    Dec 29 '16 at 13:39
  • \$\begingroup\$ It's not a proper quine anyway, because it reads its own source. \$\endgroup\$
    – mbomb007
    May 10 '17 at 14:02
0
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Pyke, 14 bytes

"34.Cp\D\Es"DE

Try it here!

"34.Cp\D\Es"   - "34.Cp\D\Es"
            DE - eval(^, stack=^)

 34.C          -   '"'
     p         -  print(^)
      \D\Es    - sum("34.Cp\D\Es", ^, "D", "E")
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0
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SimpleTemplate, 56 bytes

This is a template engine language I've made for fun.

It was written in PHP and run by compiling the weird syntax to PHP.

This answer is a translation of Aurel Bílý's amazing PHP answer!

{@setF"{@setF%c%s%c}{@printF,34,F,34}"}{@printF,34,F,34}

Weird, right?

This works with the commit d1d3e2c43bd98da2bd38f884ee5ac7b39cb8c579 on my Github and you can try it on http://sandbox.onlinephpfunctions.com/code/cca9ed3b9c87abad61159725f159285e5daf9bb9.

In there, you will have the existing code on that commit, plus showing the result and the generated PHP.

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