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Your input will be a integer between 1970 and 2090 (inclusive), representing a year. Your program should output the next year on which New Years Day falls on the same day of the week as the input year.

Test Cases:

Below are the sample inputs and outputs

2001 => 2007
2047 => 2058
2014 => 2020
1970 => 1976
1971 => 1982
1977 => 1983
2006 => 2012

20% Bonus: Output the day of the week of New Years Day

2001 => 2007 (Mon)
2047 => 2058 (Tue)
2014 => 2020 (Wed)
1970 => 1976 (Thu)
1971 => 1982 (Fri)
1977 => 1983 (Sat)
2006 => 2012 (Sun)

30% Bonus: Output Advance Happy New Year, <year>

2010 => Advance Happy New Year, 2016

50% Bonus: Do both above bonuses

2010 => Advance Happy New Year, 2016 (Fri)

Write a program which reads input from STDIN or accepts command line arguments, or a function which takes an argument.

Note: Please add a link to test your code if possible.

Leaderboard:

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  • 6
    \$\begingroup\$ I feel like every single dates challenge requires doing the leap years calculation as a subproblem, and it's getting stale. \$\endgroup\$
    – xnor
    Dec 15 '15 at 10:35
  • \$\begingroup\$ Related: this question. \$\endgroup\$ Dec 15 '15 at 11:09
  • \$\begingroup\$ @xnor If that wasn't the case, it would have been just a +7. I.e. "too broad" \$\endgroup\$ Sep 11 '16 at 1:08
  • \$\begingroup\$ @EriktheGolfer No. When I wrote that comment, my answer was the accepted one. \$\endgroup\$
    – Dennis
    Sep 11 '16 at 1:37

32 Answers 32

1
2
0
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Python 2, 32 bytes

x=input()
print[5,6,6,11][x%4]+x

Uses the 5 6 6 11 trick.

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0
\$\begingroup\$

𝔼𝕊𝕄𝕚𝕟 2, 12 chars / 18 bytes (non-competitive)

ï+⟨566ḋ[ï%4]

Try it here (Firefox only).

Explanation

ï+⟨566ḋ[ï%4] // implicit: ï = input, ḋ = 11
ï+           // add ï to:
  ⟨566ḋ      // [5,6,6,11]
       [ï%4] // get index at input mod 4
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1
2

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