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Your input will be a integer between 1970 and 2090 (inclusive), representing a year. Your program should output the next year on which New Years Day falls on the same day of the week as the input year.

Test Cases:

Below are the sample inputs and outputs

2001 => 2007
2047 => 2058
2014 => 2020
1970 => 1976
1971 => 1982
1977 => 1983
2006 => 2012

20% Bonus: Output the day of the week of New Years Day

2001 => 2007 (Mon)
2047 => 2058 (Tue)
2014 => 2020 (Wed)
1970 => 1976 (Thu)
1971 => 1982 (Fri)
1977 => 1983 (Sat)
2006 => 2012 (Sun)

30% Bonus: Output Advance Happy New Year, <year>

2010 => Advance Happy New Year, 2016

50% Bonus: Do both above bonuses

2010 => Advance Happy New Year, 2016 (Fri)

Write a program which reads input from STDIN or accepts command line arguments, or a function which takes an argument.

Note: Please add a link to test your code if possible.

Leaderboard:

    var QUESTION_ID=66656,OVERRIDE_USER=16196;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/66656/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){e.owner.user_id===OVERRIDE_USER&&answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],link:s.share_link})}),e.sort(function(e,s){var r=e.size,a=s.size;return r-a});var s={},r=1,a=null,n=1;e.forEach(function(e){e.size!=a&&(n=r),a=e.size,++r;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+".").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.language;/<a/.test(o)&&(o=jQuery(o).text()),s[o]=s[o]||{lang:e.language,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return e.lang>s.lang?1:e.lang<s.lang?-1:0});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.lang).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),i=jQuery(i),jQuery("#languages").append(i)}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*([^\n,]*[^\s,]),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
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  • 7
    \$\begingroup\$ I feel like every single dates challenge requires doing the leap years calculation as a subproblem, and it's getting stale. \$\endgroup\$
    – xnor
    Commented Dec 15, 2015 at 10:35
  • \$\begingroup\$ Related: this question. \$\endgroup\$ Commented Dec 15, 2015 at 11:09
  • \$\begingroup\$ @xnor If that wasn't the case, it would have been just a +7. I.e. "too broad" \$\endgroup\$ Commented Sep 11, 2016 at 1:08
  • \$\begingroup\$ @EriktheGolfer No. When I wrote that comment, my answer was the accepted one. \$\endgroup\$
    – Dennis
    Commented Sep 11, 2016 at 1:37

34 Answers 34

1
2
1
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Vyxal, 9 bytes

4%3e7%+5+

Try it Online!

Port of lirtosiast's Jelly answer.

-2 thanks to @lyxal

Explanation

4%3e7%+5+  # Implicit input
4%         # Input mod 4
  3e       # Cubed
    7%     # Mod 7
      +5+  # Plus 5 plus input
           # Implicit output

Old:

4%»&ṗ»12τi+  # Implicit input
4%           # Input mod 4
         i   # Indexed into
  »&ṗ»12τ    # The list [5,6,6,11]
          +  # Added to the input
             # Implicit output
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2
  • \$\begingroup\$ Try it Online! for 9 bytes porting Jelly. Smh making long answers like this. \$\endgroup\$
    – lyxal
    Commented Aug 25, 2023 at 4:41
  • \$\begingroup\$ @lyxαl thanks. And we were talking the other day about how you don't have a monograph for "cube" lol \$\endgroup\$
    – The Thonnu
    Commented Aug 25, 2023 at 6:41
1
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Thunno 2, 8 bytes

4%³7%+5+

Try it online!

Port of lirtosiast's Jelly answer.

Explanation

4%³7%+5+  # Implicit input
4%        # Input mod 4
  ³       # Cubed
   7%     # Mod 7
     +5+  # Plus 5 plus input
          # Implicit output

Old:

4%¿çƑ{ç¿i+  # Implicit input
4%          # Input mod 4
        i   # Indexed into
  ¿çƑ{ç¿    # The list [5,6,6,11]
         +  # Added to the input
            # Implicit output
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0
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Python 2, 32 bytes

x=input()
print[5,6,6,11][x%4]+x

Uses the 5 6 6 11 trick.

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0
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𝔼𝕊𝕄𝕚𝕟 2, 12 chars / 18 bytes (non-competitive)

ï+⟨566ḋ[ï%4]

Try it here (Firefox only).

Explanation

ï+⟨566ḋ[ï%4] // implicit: ï = input, ḋ = 11
ï+           // add ï to:
  ⟨566ḋ      // [5,6,6,11]
       [ï%4] // get index at input mod 4
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