Has someone been defenestrated?

Question

Defenestration is the act of throwing someone or something out of a window.
_—Wikipedia

Input

The input will consist of two parts:

• A floor plan and a person inside the house/building.

  • v><^ represents a person, pointing in the direction signified by the arrow. The input will contain exactly one person.

  • - and | represent walls, and # represents a window. is empty space.

  This portion of the input may be taken as either a single string, or an array/list/etc. of lines. There will never be any trailing or leading spaces, and the input will always be a rectangle.

  Example:

  -----###---
  |         |
  |     ^   |
  -----------
  

• An integer ≥ 1 signifying how far (in characters) the person travels.

Output

The output should be

• 1 if the person ends up "inside" a window (i.e. after moving forwards the distance specified in the input, the person is on top of a #).

• 2 if the person has been defenestrated (come into contact with a # and then continued further on).

• 3 if the person has hit a wall (come into contact with a - or |. Once hitting the wall, the person stops and does not continue through it).

• 0 if none of the above are true (and all the person has done is travel through empty space).

Assumptions

All of the following can be assumed to be true:

• The person will never travel "out of bounds" of the input area.

• After being defenestrated, the person will never come into contact with another # or a -/| (so you don't have to worry about if 2 and 1 or 3 are both true).

Test cases

For the following "floor plan":

-----
|   |
|###|
|   |
| ^ |

In   Out
1    0
2    1
3    2

For this floor plan:

> | # |

In   Out
1    0
2-99 3    * that is, any input 2-99 outputs 3

For this floor plan:

||####|#|#|##|<

In   Out
any  3

Final test case:

|v|
|#|
| |
| |
| |
| |

In   Out
1    1
2-5  2  

Answer 1

JavaScript (ES6), 147 146 bytes

(p,n)=>eval('l=p.search`\n`+1;m=p.match`[<>v^]`;for(r=d=i=0;i++<n&r<3;r-1?0:d=2)r=(c=p[m.index+i*({v:l,"<":-1,">":1}[m]||-l)])>"#"?3:c>" ";+r||d')

Saved 1 byte thanks to @NinjaBearMonkey!

Explanation

Takes a floorplan as a string and the number of moves. Returns a number.

(p,n)=>                               // p = floor plan as string, n = number of moves
  eval(`                              // use eval to enable for loop without {} or return
    l=p.search\`\n\`+1;               // l = line length
    m=p.match\`[<>v^]\`;              // m = the position and orientation of the person
    for(
      r=                              // r = result at the current step
        d=                            // d = 2 if the person has been defenestrated
          i=0;                        // i = current step
      i++<n&r<3;                      // for each step while the person has not hit a wall
      r-1?0:d=2                       // set d to 2 once the person enters the window
    )
      r=(                             // r = 0 if on " ", 1 if on "#" or 3 if on "|" or "-"
        c=p[m.index+i*                // c = character after current step
          ({v:l,"<":-1,">":1}[m]||-l) // get the index offset of each step
        ]
      )>"#"?3:c>" ";
    +r||d                             // return the result of the current step or d
  `)

Test

var solution = (p,n)=>eval('l=p.search`\n`+1;m=p.match`[<>v^]`;for(r=d=i=0;i++<n&r<3;r-1?0:d=2)r=(c=p[m.index+i*({v:l,"<":-1,">":1}[m]||-l)])>"#"?3:c>" ";+r||d')

<textarea id="floorplan" rows="6" cols="30">-----
|   |
|###|
|   |
| ^ |</textarea><br />
Moves = <input type="text" id="moves" value="3" />
<button onclick="result.textContent=solution(floorplan.value,moves.value)">Go</button>
<pre id="result"></pre>