Running length of the movie in a human readable format

Question

Whenever I search for the running length of a movie in IMDb, it is displayed in minutes. Immediately I would try to convert it into hour(s) and minute(s). It would be better if we could automate this.

Input:

150 min

Output:

2 hours 30 minutes

Input:

90 min

Output:

1 hour 30 minutes

Input:

61 min

Output:

1 hour 1 minute

Input:

60 min

Output:

1 hour 0 minute or 1 hour 0 minutes

Following are the conditions:

1. Input and Output should be in this exact format.

2. Input minutes will between 0 and 240.

3. Your answer can accept command line arguments or read input from the user or a function.

4. Output should not be enclosed within quotes.

5. Output must be printed, not returned.

Leaderboard:

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Result:

Its a tie between CJam and Pyth. Accepting CJam's answer as it was submitted before Pyth's 35 bytes code. However, please continue encouraging new submissions.

Answer 1

Java - 143 141 139 bytes

Since functions are allowed, here is my take

void a(String a){int b=Integer.valueOf(a.split(" ")[0]),c=b/60,d=b%60;System.out.print(c+" hour"+(c>1?"s ":" ")+d+" minute"+(d>1?"s":""));}

---

Ungolfed

void a(String a){
    int b=Integer.valueOf(a.split(" ")[0]),c=b/60,d=b%60;
    System.out.print(
            c+" hour"+(c>1?"s ":" ")+
            d+" minute"+(d>1?"s":"")
            );
}

---

Input

a("59 mins");
a("121 mins");
a("239 mins");

Output

0 hour 59 minutes
2 hours 1 minute
3 hours 59 minutes

Answer 2

Mumps, 81 Bytes

R U S M=+U#60,H=+U\60 W H," hour",$S(H=1:" ",1:"s "),M," minute",$S(M=1:"",1:"s")

Ungolfed:

R U                 ; (R)ead from standard input
S M=+U#60,H=+U\60   ; S(et) M to integer (mod) Minutes and H to integer Hours
W H," hour",$S(H=1:" ",1:"s "),M," minute",$S(M=1:"",1:"s")
                    ; W(rite) H & hour, if H doesn't equal 1 pluralize;
                    ; same for M & minute(s).

Sorry for the initial submission - the formatting on my ungolfed wasn't quite right and I didn't realize at first that hitting 'tab' then 'space' in the editor window equated to "submit." :-)

Answer 3

Prolog, 134 bytes

Code:

p(X):-sub_atom(X,0,_,4,S),atom_number(S,N),divmod(N,60,Q,R),(Q>1->I=s;I=""),(R=1->J="";J=s),writef('%w hour%w %w minute%w',[Q,I,R,J]).

Explanation:

p(X):-sub_atom(X,0,_,4,S),                       % Remove last 4 chars from input
      atom_number(S,N),                          % Convert to integer
      divmod(N,60,Q,R),                          % Split minutes into hours/minutes
      (Q>1->I=s;I=""),(R=1->J="";J=s),           % Check if hours/minutes are plural
      writef('%w hour%w %w minute%w',[Q,I,R,J]). % Print

Example:

p('150 min').
2 hours 30 minutes

Answer 4

Pyth, 35 bytes

jds.b,N+WtNY\s.Ds-zG60c"hour minute

Try it online: Demonstration or Test Suite

Explanation:

jds.b,N+WtNY\s.Ds-zG60c"hour minute  implicit: z = input string
                 -zG                 remove all letters from the string
                s                    and convert it (gives us the number)
              .D    60               gives [quotient, remainder] (division by 60)
                      c"hour minute  split "hour minute"
   .b                                map each pair (number N, string Y) to:
     ,                                  the pair
      N                                 [ N, 
       +WtNY\s                               Y + "s" if N-1 ]
  s                                  join the two pairs
jd                                   join strings by spaces

Answer 5

awk, 72 bytes

{printf"%d hour%s %d minute%s\n",h=$1/60,h~/^1/?_:"s",m=$1%60,1~m?_:"s"}

Basically just a printf, taking advantage of awks ability to compare numbers using regexp.

input/output examples

0 min
0 hours 0 minutes
1 min
0 hours 1 minute
60 min
1 hour 0 minutes
61 min
1 hour 1 minute
121 min
2 hours 1 minute
122 min
2 hours 2 minutes

Answer 6

Python, 152 bytes

Sorry, fixed the code so it handles the input/output the way the insturctions say.

 def t(p):
  import math
  print(str(math.floor(p/60))+" hour" + ("s " if math.floor(p/60>1) else " ") +str(p%60)+" minute" + ("s " if p%60>1 else ""))

Edit: Why is the still -1 with the edited code? It works exactly how the OP asks.

Answer 7

PHP, 110 100 96 bytes

$t=$argv[1];$h=intval($t/60);$m=$t-$h*60;echo"$h hour".($h>1?"s":"")." $m minute".($m>1?"s":"");

You can run it using php -r

GET parameters are no longer allowed(meta.codegolf.stackexchange.com/a/7591/14732 and meta.codegolf.stackexchange.com/q/7575/14732)

Answer 8

Go, 168 132 127 120 121 120 115 bytes

Try it here!

Even with minification, I'm still being beaten by Java ): finally beating Java!

note: there's nothing in the spec about plurals nor excluding 0 minutes, so my program ignores such cases.

integer math in Go always returns an integer, thus this is straightforward.

package main
import(."fmt"."strconv")
func main(){a:=""
Scanln(&a)
x,_:=Atoi(a)
Printf((x/60),"hrs",(x%60),"mins")}

Ungolfed

package main

import (
    . "fmt"
    . "strconv"
)

func main() {
    a := ""
    Scanln(&a)
    x, _ := Atoi(a)
    Println((x / 60), "hrs", (x % 60), "mins")
}

Answer 9

Thunno 2 Ṡ, 29 bytes

OhN60ḋDð‘ƝḢ Ạẋ‘O+ZıẸs1>'s×+;Z

Try it online!

Explanation

O          # Split on spaces
 hN        # Take the first item and convert to integer
   60ḋ     # Divmod by 60
      Dð   # Duplicate and push a space
‘ƝḢ Ạẋ‘    # Push compressed string "hour minute"
       O   # Split it on spaces
        +  # And prepend the space to each one
Z          # Zip it with the divmod list
 ı         # And map over this list of pairs:
  Ẹ        #  Dump onto the stack
   s       #  Swap so the number is on top
    1>     #  Is it greater than 1?
's        '#  Push the character "s"
  ×        #  Multiply by our boolean value
   +       #  Add to the string
    ;Z     # After the map, zip with the divmod list
           # Implicit output, joined by spaces

Answer 10

Julia, 110 99 93 bytes

x->((h,m)=divrem(parse(x[1:end-4]),60);print("$h hour$(h>1?"s":"") $m minute$(m>1?"s":"")"))

This is an anonymous function that accepts a string and prints to STDOUT.

Ungolfed:

function f(x::AbstractString)
    # Parse the number of minutes out of the input
    y = parse(x[1:end-4])

    # Get the number of hours and minutes
    h, m = divrem(y, 60)

    # Construct the output using string interpolation
    print("$h hour$(h>1?"s":"") $m minute$(m>1?"s":"")")
end

Answer 11

C++, 175 bytes

#include<iostream>
using namespace std;main(int argc,char**argv){int a=stoi(argv[1]);cout<<a/60<<" hour";if(a/60!=1)cout<<"s";cout<<" "<<a%60<<" minute";if(a%60!=1)cout<<"s";}

Ungolfed:

#include <iostream>
using namespace std;
main(int argc, char **argv)
{
   int a = stoi(argv[1]);
   cout << a / 60 << " hour";
   if(a / 60 != 1) cout << "s";
   cout << " " << a % 60 << " minute";
   if(a % 60 != 1) cout << "s";
}

Probably the only time that std::stoi truncating non-number characters will ever be useful, but it's enough to put C++ ahead of C, I think.

Answer 12

VBA, 175 bytes

Sub e(f)
f = Val(f)
h = Int(f / 60)
m = f - h * 60
MsgBox IIf(h > 0, h & " hour" & IIf(h > 1, "s", ""), "") & " " & IIf(m > 0, m & " minute" & IIf(m > 1, "s", ""), "")
End Sub

Answer 13

Java, 107 192 160 149 129 172 162 129 bytes

So, here's my solution:

void b(String[]a){int a=Integer.valueOf(a[0]);System.out.print(a/60>1?a/60+" hrs ":a/60+" hr "+a%60>1?a%60+" mins":a%60+" min");}

It uses command-line input, and works like this:

Java command example: javac MovieTime 108 minutes

Input: 108 minutes

Output: 1 hr 48 mins

Changes:

• Changed the code to full class, adding 85 bytes
• Got rid of unnecessary whitespaces, subtracting 32 bytes
• Made variable/class names shorter, subtracting 11 bytes
• Made Integer.valueOf(args[0]) into a variable and changed println into print, subtracting 20 bytes
• Added system for changing plurals of times, adding 43 bytes
• Made times shorter, subtracting 10 bytes
• Code is now a function instead of a class, subtracting 33 bytes

Any ideas as to how I can shorten it would be greatly appreciated, as this is my first golf submission.

Answer 14

Python 2, 102 bytes

a=int(raw_input().split()[0]);h=a/60;m=a%60;l="s\0";print"%s hour%s %s minute%s"%(h,l[h==1],m,l[m==1])

Answer 15

Python 2: 56 bytes

Golfed code

m=int(raw_input()[:3]);print m/60,'hours',m%60,'minutes'

Readable code

# get input from STDIN
string_input = raw_input()
# parse number of minutes in the first three characters
minutes_input = string_input[:3]
# compute number of hours and remaining minutes
hours = minutes_input / 60
minutes = minutes_input % 60
# display result
print hours, 'hours', minutes, 'minutes'

Try it online

https://ideone.com/HdTKRt

---

Python 2: 80 bytes (with plurals handling)

Golfed code

_,m='\0s',int(raw_input()[:3]);print m/60,'hour'+_[m>60],m%60,'minute'+_[m%60>1]

Try it online

https://ideone.com/GuDCq0

Answer 16

JavaScript 96

m=parseInt(prompt()),h=m/60|0,m%=60
alert(h+" hour"+(h!=1?"s ":" ")+m+" minute"+(m!=1?"s ":" "))

Answer 17

Pyth, 41 bytes

A.Ds<4z60s[G" hour"?tG\skdH>4z"ute"?tH\s"

explanation

A                                          -Assign two values, first to `G` then to `H`
 .Ds   60                                  -DivMod on integer by 60
    <4z                                    -slice everything but the last 4 chars of input
         s[                                -print all following statements on one line
           G                               -hour
            " hour"                        -string literal
                   ?tG\sk                  -ternary, if hour is 1, 's' literal, else nothing
                         d                 -space
                          H                -minute
                           >4z             -get the last 4 chars of input (" min") (so sneaky)
                              "ute"        -string literal
                                   ?tH\s"  -ternary, as before but with minutes

Answer 18

Milky Way 1.2.1, 63 bytes

'" "\=^A60m>?{1b_" "_"s "}" hour";+<?{1b_""_"s"}" minute";++++!

The program is too long to explain in detail here, but you can see the docs for an in-depth look.

---

Usage

python3 milkyway.py <path-to-code> -i <input>

Answer 19

Gema, 64 bytes

<N>=@p{@div{$1;60} hour} @p{@mod{$1;60} minute}
*=
p:1 *=$0;*=*s

Sample run:

bash-4.3$ gema '<N>=@p{@div{$1;60} hour} @p{@mod{$1;60} minute};*=;p:1 *=$0;*=*s' <<< '90 min'
1 hour 30 minutes

Gema, 65 bytes

<N> min=@p{@div{$1;60} hour} @p{@mod{$1;60} minute}
p:1 *=$0;*=*s

This one replaces all “\d+ min” occurrences in the input string.

Sample run:

bash-4.3$ gema '<N> min=@p{@div{$1;60} hour} @p{@mod{$1;60} minute};p:1 *=$0;*=*s' <<< $'150 min\n90 min\n61 min\n60 min'
2 hours 30 minutes
1 hour 30 minutes
1 hour 1 minute
1 hour 0 minutes

Answer 20

Factor, 95 88 bytes

[ readln " " split first 10 >base [ 60 / floor ] [ 60 mod ] bi "%s hrs %s mins" printf ]

Like my Go answer, doesn't handle plurals because it doesn't have to.

Answer 21

Pyke, 31 bytes, noncompeting

dchE60.D]~U1 3:],FDJRh1N\s*+)_J

Try it here!

Explanation:

dchE                            -     eval(input().split(" ")[0])
    60.D]                       -    [divmod(^, 60)]
               ],               -   zip(*[^,V])
         ~U1 3:                 -    ["minute", "hour"]
                 F          )   -  for _ in ^:
                     h1N        -     _[0] != 1
                        \s*     -    "s"*^
                           +    -    V+^
                   J            -     " ".join(_)
                             _J - " ".join(^[::-1])