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A current internet meme is to type 2spooky4me, with a second person typing 3spooky5me, following the (n)spooky(n+2)me pattern.

Your mission is to implement this pattern in your chosen language. You should write a program or function that takes a value n (from standard input, as a function argument, or closest alternative), and outputs the string (n)spooky(n+2)me (without the parentheses; to standard output, as a return value for a function, or closest alternative).

Your solution should work for all inputs, from 1 up to 2 below your language's maximum representable integer value (2^32-3 for C on a 32-bit machine, for example).

Example implementation in Python:

def spooky(n):
    return "%dspooky%dme"%(n,n+2)

spooky(2) -> "2spooky4me"

This is , so standard loopholes are forbidden, and the shortest answer in bytes wins!

Leaderboard

The Stack Snippet at the bottom of this post generates the leaderboard from the answers a) as a list of shortest solution per language and b) as an overall leaderboard.

To make sure that your answer shows up, please start your answer with a headline, using the following Markdown template:

## Language Name, N bytes

where N is the size of your submission. If you improve your score, you can keep old scores in the headline, by striking them through. For instance:

## Ruby, <s>104</s> <s>101</s> 96 bytes

If there you want to include multiple numbers in your header (e.g. because your score is the sum of two files or you want to list interpreter flag penalties separately), make sure that the actual score is the last number in the header:

## Perl, 43 + 2 (-p flag) = 45 bytes

You can also make the language name a link which will then show up in the snippet:

## [><>](http://esolangs.org/wiki/Fish), 121 bytes

<style>body { text-align: left !important} #answer-list { padding: 10px; width: 290px; float: left; } #language-list { padding: 10px; width: 290px; float: left; } table thead { font-weight: bold; } table td { padding: 5px; }</style><script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="language-list"> <h2>Shortest Solution by Language</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr> </thead> <tbody id="languages"> </tbody> </table> </div> <div id="answer-list"> <h2>Leaderboard</h2> <table class="answer-list"> <thead> <tr><td></td><td>Author</td><td>Language</td><td>Size</td></tr> </thead> <tbody id="answers"> </tbody> </table> </div> <table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{NAME}}</td><td>{{LANGUAGE}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr> </tbody> </table> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr> </tbody> </table><script>var QUESTION_ID = 62350; var ANSWER_FILTER = "!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe"; var COMMENT_FILTER = "!)Q2B_A2kjfAiU78X(md6BoYk"; var OVERRIDE_USER = 45941; var answers = [], answers_hash, answer_ids, answer_page = 1, more_answers = true, comment_page; function answersUrl(index) { return "https://api.stackexchange.com/2.2/questions/" + QUESTION_ID + "/answers?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + ANSWER_FILTER; } function commentUrl(index, answers) { return "https://api.stackexchange.com/2.2/answers/" + answers.join(';') + "/comments?page=" + index + "&pagesize=100&order=desc&sort=creation&site=codegolf&filter=" + COMMENT_FILTER; } function getAnswers() { jQuery.ajax({ url: answersUrl(answer_page++), method: "get", dataType: "jsonp", crossDomain: true, success: function (data) { answers.push.apply(answers, data.items); answers_hash = []; answer_ids = []; data.items.forEach(function(a) { a.comments = []; var id = +a.share_link.match(/\d+/); answer_ids.push(id); answers_hash[id] = a; }); if (!data.has_more) more_answers = false; comment_page = 1; getComments(); } }); } function getComments() { jQuery.ajax({ url: commentUrl(comment_page++, answer_ids), method: "get", dataType: "jsonp", crossDomain: true, success: function (data) { data.items.forEach(function(c) { if (c.owner.user_id === OVERRIDE_USER) answers_hash[c.post_id].comments.push(c); }); if (data.has_more) getComments(); else if (more_answers) getAnswers(); else process(); } }); } getAnswers(); var SCORE_REG = /<h\d>\s*([^\n,<]*(?:<(?:[^\n>]*>[^\n<]*<\/[^\n>]*>)[^\n,<]*)*),.*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/; var OVERRIDE_REG = /^Override\s*header:\s*/i; function getAuthorName(a) { return a.owner.display_name; } function process() { var valid = []; answers.forEach(function(a) { var body = a.body; a.comments.forEach(function(c) { if(OVERRIDE_REG.test(c.body)) body = '<h1>' + c.body.replace(OVERRIDE_REG, '') + '</h1>'; }); var match = body.match(SCORE_REG); if (match) valid.push({ user: getAuthorName(a), size: +match[2], language: match[1], link: a.share_link, }); else console.log(body); }); valid.sort(function (a, b) { var aB = a.size, bB = b.size; return aB - bB }); var languages = {}; var place = 1; var lastSize = null; var lastPlace = 1; valid.forEach(function (a) { if (a.size != lastSize) lastPlace = place; lastSize = a.size; ++place; var answer = jQuery("#answer-template").html(); answer = answer.replace("{{PLACE}}", lastPlace + ".") .replace("{{NAME}}", a.user) .replace("{{LANGUAGE}}", a.language) .replace("{{SIZE}}", a.size) .replace("{{LINK}}", a.link); answer = jQuery(answer); jQuery("#answers").append(answer); var lang = a.language; lang = jQuery('<a>'+lang+'</a>').text(); languages[lang] = languages[lang] || {lang: a.language, lang_raw: lang.toLowerCase(), user: a.user, size: a.size, link: a.link}; }); var langs = []; for (var lang in languages) if (languages.hasOwnProperty(lang)) langs.push(languages[lang]); langs.sort(function (a, b) { if (a.lang_raw > b.lang_raw) return 1; if (a.lang_raw < b.lang_raw) return -1; return 0; }); for (var i = 0; i < langs.length; ++i) { var language = jQuery("#language-template").html(); var lang = langs[i]; language = language.replace("{{LANGUAGE}}", lang.lang) .replace("{{NAME}}", lang.user) .replace("{{SIZE}}", lang.size) .replace("{{LINK}}", lang.link); language = jQuery(language); jQuery("#languages").append(language); } }</script>

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  • 3
    \$\begingroup\$ For bonus points: Input %dspooky%dme, validate and return next in series. \$\endgroup\$
    – clapp
    Commented Oct 31, 2015 at 6:13
  • 27
    \$\begingroup\$ True, but Dennis would still win \$\endgroup\$
    – clapp
    Commented Oct 31, 2015 at 6:19
  • 10
    \$\begingroup\$ Who is Dennis? :O \$\endgroup\$
    – NuWin
    Commented Feb 15, 2016 at 20:39
  • 17
    \$\begingroup\$ @NuWin Dennis is the way. Dennis is the light. \$\endgroup\$
    – Alex A.
    Commented Feb 15, 2016 at 23:02
  • 2
    \$\begingroup\$ @NuWin Dennis is love, Dennis is life \$\endgroup\$
    – user63571
    Commented Jan 25, 2017 at 19:40

120 Answers 120

1 2 3
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O, 20 characters

Q"spooky"Q2+"me"+++p

Sample run:

bash-4.3$ o.sh 'Q"spooky"Q2+"me"+++p' <<< 42
42spooky44me
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0
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Fourier, 32 bytes

I~zo115a-3avaa-4a121az+2o109a-8a

Still using @isaacg's golfing algorithm ;)

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Haskell, 38 bytes

a n=show(n)++"spooky"++show(n+2)++"me"

Defines a function named a that takes a Num n. Returns <n>spooky<n+2>me.

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  • \$\begingroup\$ You can save a byte by writing show n instead of show(n). \$\endgroup\$ Commented Feb 22, 2016 at 16:28
0
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Clojure, 26 bytes

#(str %"spooky"(+ 2%)"me")

First post. It's a function, as required. I think I took as many liberties with the tokenizer as possible, but I don't know. Here it is in action in the REPL:

user=> #(str %"spooky"(+ 2%)"me")
#<user$eval1176$fn__1177 user$eval1176$fn__1177@2d2d2f69>
user=> (*1 55)
"55spooky57me"
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Dart, 27 Bytes

t(n)=>'${n}spooky${n+2}me';

Unremarkable but competitive.

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1
  • \$\begingroup\$ Welcome to Programming Puzzles & Code Golf! \$\endgroup\$
    – Dennis
    Commented Nov 2, 2015 at 20:44
0
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Factor, 79 bytes

: f ( x -- ) dup 2 + [ number>string ] bi@ "spooky" swap "me" 4array concat . ;

First stab at it, just did it the obvious way.

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0
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Lua, 41 Bytes

There's this other lua answer, but it doesn't work anymore since lua 5.3. It will now print 2spooky4.0me Here comes a code working under all versions of lua, and who's still in 41 Bytes:

print(("%dspooky%dme"):format(...,...+2))
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0
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,,,, 18 bytes

:↓2+"spooky"↓↓"me"
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0
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Acc!!, 99 bytes

N
Write _
Write 115
Write 112
Write 111
Write 111
Write 107
Write 121
Write _+2
Write 109
Write 101

Try it online!

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0
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Implicit, 20 17 16 bytes

ì¯spooky]ì..ìme"

Try it online!

ì¯spooky]ì..ìme"
ì                 « implicit integer input, convert to string     »;
 ¯                « copy input to memory                          »;
  spooky          « push the ASCII character codes for each letter in `spooky` individually »;
        ]         « copy memory to stack                          »;
         ì        « convert string to integer                     »;
          ..      « increment twice                               »;
            ì     « and back to string                            »;
             me   « push character codes for `me`                 »;
               "  « stringify the entire stack                    »;
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0
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Python ≥ 3.6, 28 bytes

lambda x:f'{x}spooky{x+2}me'

Try it online!

Makes use of formatted string literals, a feature that was introduced in Python 3.6.

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SmileBASIC, 26 bytes

INPUT N?N;"spooky";N+2;"me
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T-SQL, 40 bytes

SELECT CONCAT(n,'spooky',n+2,'me')FROM t

Input taken via a pre-existing table t with integer column n, per our input standards.

CONCAT does an implicit type conversion, otherwise I'd have to do something like CONVERT(n,varchar(9)).

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OCL, 52 46 bytes

Function a b Print b+"spooky"+(b + 2)+"me" End

This one is pretty straight forward, I just wanted to show off an obscure language.

Edit: I found out you can omit the spaces between the pluses when doing concatenation, but not addition. Weird.

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Pip, 23 bytes

(a:q)."spooky".a+2."me"

Try it online!

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Stax, 14 bytes

ü╫2┐╚╘Wö»§W╟╛╨

Run and debug it at staxlang.xyz!

Unpacked (16 bytes)

.me;2+`tNCrf`,Wp
.me                 Literal "me"
   ;2+              Peek from input stack, push to stack, and add 2
      `tNCrf`       Literal "spooky"
             ,      Pop from input stack; push to stack
              Wp    Pop and print everything from the stack with no additional newlines
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0
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Excel, 22 bytes

=A1&"spooky"&A1+2&"me"
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0
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Runic Enchantments, 18 bytes

i:2+"me"S9´334E{@

Try it online!

Saves 1 byte by using 9´334E to pull "spooky" out of the word dictionary. 8b*E for "me" is the same length.

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0
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Japt, 14 bytes

`èï`ri@°+T°

Try it

Japt, 13 bytes

+`spooky{+2}´

Try it

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0
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AWK, 21 bytes

$0=$0"spooky"$0+2"me"

Try it online!

Substitutes the input for (input)spooky(input+2)me. As the new value of $0 is not zero nor null, prints $0.

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Lua, 39 bytes

w=io.write w(...)w'spooky'w(...+2)w'me'

Test

> lua -v & echo -------- & lua ./spooky.lua 2
Lua 5.4.0  Copyright (C) 1994-2020 Lua.org, PUC-Rio
--------
2spooky4me
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0
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JAVA, 60 bytes

class p {String main(int n) {return n+"spooky"+(n+2)+"me";}}

Works fine on blueJ but not on TIO idk why?

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  • \$\begingroup\$ It might be because your main function does not seem standard, it should be public static void main(String[] args) { ... } and parse args[] accordingly before calculating : int n = Integer.parseInt(args[0]);. You could lose the spaces before the opening braces and save some bytes \$\endgroup\$
    – Riptide
    Commented Nov 1, 2021 at 17:57
  • \$\begingroup\$ ARE JVM for blueJ and TIO different? \$\endgroup\$
    – Ha'Penny
    Commented Nov 1, 2021 at 23:39
0
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tinylisp, 72 bytes

(load library
(q((N)(strcat(string N)(join2(q spooky)(q me)(string(a N 2

Anonymous function that takes a number and returns a name (tinylisp's equivalent of a string). Try it online!

Ungolfed/explanation

(load library)         ; Needed for strcat, join2, and ungolfed aliases

(lambda (N)            ; Anonymous function with one argument
  (strcat              ; Concatenate these two names as a single string:
    (string N)         ; Convert the input number to a string, and
    (join2             ; Join these strings together:
      (q spooky)       ;   "spooky" and
      (q me)           ;   "me", with the following separator:
      (string          ;   Convert to a string
        (add2 N 2))))) ;   the input number plus 2
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0
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Python, 39 bytes

x=int(input());print(f"{x}spooky{x+2}me)

Don't remove the int(). That will cause an error. Tested on Python 3.10.1 (v3.10.1:2cd268a3a9, Dec 6 2021, 14:28:59) [Clang 13.0.0 (clang-1300.0.29.3)] on darwin

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1
  • \$\begingroup\$ You are missing a quote mark before the last closing bracket. \$\endgroup\$ Commented Oct 13, 2023 at 10:48
0
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BQN, 30 28 bytes

•Fmt∾"spooky"∾"me"∾˜·•Fmt+⟜2

Anonymous tacit function. Try it at BQN online

Explanation

Reading right-to-left:

  • +⟜2 adds 2 to the argument
  • •Fmt converts that number to a string
  • · helps with parsing
  • "me"∾˜ concatenates me to the end of the string
  • "spooky"∾ concatenates spooky to the beginning of the string
  • •Fmt∾ concatenates the argument, stringified, to the beginning of the string
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0
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J, 24 bytes

'me',~":,'spooky',":@+&2

Attempt This Online!

If you've seen the BQN or APL golfs then you've seen this one.

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MathGolf, 11 bytes

k╕o3╣Rk⌠ûme

Try it online.

Explanation:

k           # Push the input-integer
 ╕o3        # Push compressed string "spoo"
    ╣R      # Push compressed string "ky"
      k     # Push the input-integer again
       ⌠    # Increase it by 2
        ûme # Push string "me"
            # (after which the entire stack joined together is output implicitly)

k...k⌠ could alternatively have been └)...@ for the same byte-count: try it online.

└           # Increase the (implicit) input-integer by 1 without popping
 )          # Pop and increase it by 1 again
       @    # Reverse triple-swap the top three values on the stack
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0
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MATL, 18 bytes

'spooky'yUQQV'me'v

Try it on MATL Online

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0
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Vyxal , 12 bytes

:⇧‛me«½↵*←«∇

Try it Online!

2spooky4joe

Explained

:⇧‛me«½↵*←«∇
:⇧             # Without popping, push input + 2 - this leaves the stack as [input, input + 2]
  ‛me          # push the string "me"
     «½↵*←«    # and the string "spooky"
           ∇   # rotate the top three items and output the sum of the stack
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1
  • \$\begingroup\$ I don't think this code works anymore (maybe it worked on previous versions?), but replacing the ~ with a : fixes it: Try it Online! \$\endgroup\$
    – The Thonnu
    Commented Jan 15, 2023 at 16:37
0
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><> (Fish), 26 bytes

:n'ykoops'oooooo2+n'em'oo;

Try it

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