# Bob the Bowman

      o
/( )\                                         This is Bob.
L L                                          Bob wants to be an archer.
#############

.
/ \          <--- bow                          So he bought himself a
(c -)->       <--- arrow                        nice longbow and is about
( )/          <--- highly focused Bob           shoot at a target.
L L
#############

___________________________________________________________________________________________
sky

Bob is a smart guy. He already knows what angle and
velocity his arrow has / will have. But only YOU know
the distance to the target, so Bob doesn't know if he
will hit or miss. This is where you have to help him.

.                                                                                  +-+
/ \                                                                                 | |
(c -)->                                                                              | |
( )/                                                                                 +++
L L                                                                                   |
###########################################################################################


Your task is to render an ASCII art picture of Bob hitting or missing the target. For the calculation:

• Your program will receive arrow_x,angle,velocity,distance as comma-separated input in any order you wish.
• One ASCII character equals 1m.
• The first character in the last line has the coordinates (0,0), so the ground (rendered as #) is at y=0.
• Bob always stands on the ground, his y position does not change.
• There is no max y. However, the arrows apex should fit within the rendered picture.
• All input is provided as decimal integer.
• During calculation, assume the arrow is a point.
• The arrow origin is the arrow head > of a shooting Bob (see above). So given arrow_x, you have to calculate arrow_y. The left foot of Bob in the output has to match the x coord. of the shooting Bob.
• distance is the x coordinate of the target's foot. (ie. the middle of the target).
• All measurements are supplied in meters and degrees respectively.
• Attention: The shooting Bob is never rendered, only used for calculations! See below for the two valid output-Bobs
• Hitting the target means the arrows path crosses either one of the two leftmost target walls (|) (That is either (distance-1,3) or (distance-1,4). If at some point the arrow is within those 2m², place the X instead of the wall it hits. The target is always the same height and only its x position can change.). Corner hits or an arrow falling from the sky onto the target does not count.
• Standard earth g applies (9.81 m/s^2).
• distance+1 is the end of the field, after that, everything is a miss and no arrow should be rendered.
• If the arrow hits the target in any other way (distance-1 etc.), no arrow should be rendered.

## Miss

This is an example rendering of Bob missing (arrow enters ground at 34m, angle is 45°, time in air is 10s, velocity is ~50 - but there are a lot more possible inputs to cause this output. Just show your program uses the usual formulas to calculate physically "accurate" results.):

                                                                                        +-+
| |
c\                                                                                    | |
/( )                              v                                                     +++
L L                              |                                                      |
###########################################################################################


## Hit

This is an example rendering of Bob scoring (arrow enters target (= crosses its path)):

                                                                                        +-+
>--X |
\c/                                                                                    | |
( )                                                                                    +++
L L                                                                                     |
###########################################################################################


## Example

• arrow_x is 7. arrow_y is always 3.
• angle is 30° or 0.523598776 radians.
• velocity is 13m/s.
• distance is 20.

So in order to hit the target, the arrow has to cross (19,3) or (19,4). Everything else will be a miss. In this case, the arrow will enter the ground (means y will be <1.0) at 12.9358m = ~13m after 1.149s.

## Limits & Scoring

• This is , so the shortest solution wins. There are no bonuses.
• Your program (as in not function) must accept input in the format described above, additional input is not permitted.
• You don't have to handle wrong/pointless/impossible inputs.
• Print to whatever is the shortest reasonable output for your language (std, file, ...).
• I don't care about trailing whitespace.
• Tip: Width of output is distance+2. The height is apex+1.
• Can you add the input used to generate the output given please?
– Blue
Sep 20 '15 at 13:29
• Why can't you post a function? Sep 20 '15 at 13:52
• @Mhmd You have to draw him, as stated in the task. The left foot of Bob in the output has to match the x coord. of the shooting Bob. and See below for the two valid output-Bobs
– user42643
Sep 20 '15 at 17:56
• And for those of us who haven't taken physics further than GCSE (or have just forgotten?)
– Blue
Sep 20 '15 at 19:11
• @muddyfish Just google for the trajectory equations.
– user42643
Sep 20 '15 at 19:25

# Ruby, 482

include Math
def f s,e,l
[s,' '*(l-s.size-e.size),e].join
end
alias p puts
X,o,V,d=$*[0].split(?,).map &:to_i o*=PI/180 L=X+d B='| |' S='' G=' L L' p f S,'+-+',L d.times{|x|y=3+x*tan(o)-(9.81*x**2)/(2*(V*cos(o))**2) if x==d-1&&(3..5)===y s='>--X |' m=(3..4)===y p f S,m ?B: s,L p f ' \c/',m ?s: B,L p f ' ( )',?+*3,L p f G,'| ',L elsif y<=1 || x==d-1 p f S,B,L p f ' c\\',B,L print f '/( )', y<1? 'V':' ',x p f S,?+*3,L-x print f G, y<1? '|':' ',x p f S,'| ',L-x break end} p ?#*L  ## Ungolfed include Math def fill s,e,l [s,' '*(l-s.size-e.size),e].join end arrow_x,angle,velocity,distance =$*[0].split(',').map(&:to_i)
angle *= PI/180
length=arrow_x+distance
loss = '| |'
puts fill '','+-+',length
distance.times { |x|
y = 3 + x*tan(angle) - (9.81*x**2)/(2*(velocity*cos(angle))**2)
if x == distance-1 && (3..5)===y
puts fill '',(3..4)===y ? '| |':'>--X |',length
puts fill ' \c/',(3..4)===y ? '>--X |':'| |',length
puts fill ' ( )','+++',length
puts fill ' L L','| ',length
elsif y<=1 || x==distance-1
puts fill '',loss,length
puts fill '  c\\',loss,length
print fill '/( )', y<1? 'v': ' ', x
puts fill '','+++',length-x
print fill ' L L', y<1? '|': ' ', x
puts fill '',' | ',length-x
break
end
}
puts ?#*length


### Method

The main equation here is:

Note: image taken from https://en.wikipedia.org/wiki/Trajectory_of_a_projectile

Where,

y0: initial height (of arrow)
Ө: the angle
x: the position of the arrow
g: gravity (9.81)
v: velocity


What I'm doing is to loop through numbers from 0 to (distance -1) and in every iteration check to see if the arrow hits the ground (or the target)