The goal of this challenge is the write the shortest function/program to take input text, encrypt it using the method below, and return the result.
As an example, I will use the string hello world
.
First, get the input text.
hello world
Second, convert the string into ternary (base 3). Use this key:
a = 000
b = 001
c = 002
d = 010
e = 011
f = 012
g = 020
...
w = 211
x = 212
y = 220
z = 221
[space] = 222
With this key, hello world
becomes 021011102102112222211112122102010
, as seen below.
h e l l o w o r l d
021 011 102 102 112 222 211 112 122 102 010
Third, move the first digit to the end.
021011102102112222211112122102010
becomes
210111021021122222111121221020100
Fourth, convert the number back into a string using the same key.
210 111 021 021 122 222 111 121 221 020 100
v n h h r n q z g j
Lastly, return the encrypted text.
vnhhr nqzgj
Here are some sample text and their output:
the turtle ==> dvo fh ego
python ==> uudwqn
code golf ==> hpjoytqgp
As this is code golf, the shortest entry in bytes wins. Errors are allowed if some of the characters are not lowercase letters or space. This is my first challenge, so any suggestions would be more than helpful.
Good luck!
Leaderboard:
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uint64
) using increasing powers of27
. The displacement by one digit would then be equivalent to multiplying this large integer by3
, and the introduction of the first digit on the other end would simply be an addition. But there are complications, such as discarding the last "carry" (perhaps via amod
operation), and I couldn't get it to work with few bytes \$\endgroup\$