# String to Binary

This is a code golf challenge. Just like the title says, write a program to covert a string of ascii characters into binary.

For example:

"Hello World!" should turn into 1001000 1100101 1101100 1101100 1101111 100000 1010111 1101111 1110010 1101100 1100100 100001.

Note: I am particularly interested in a pyth implementation.

• We had the reversed asked: codegolf.stackexchange.com/questions/35096/… – chilemagic Jan 23 '15 at 0:57
• I noticed that. There's an anecdote for why I asked this question. I encouraged my friend to learn programming, and he took a java class last summer where each student had to pick a project. He told me he wanted to translate text to binary, which I then did (to his dismay) in python 3 in 1 line (a very long line). I find it incredible that his project idea can be distilled down to 8 bytes. – ericmarkmartin Jan 23 '15 at 4:12
• that's cool, thanks for sharing! I do like easier questions like this because it gives more people a chance to participate and generates lots of content in the form of answers. – chilemagic Jan 23 '15 at 4:22
• Can I take input via a file (as specified at meta.codegolf.stackexchange.com/a/2452/30076)? – bmarks Jan 23 '15 at 16:08
• Does it has to be ASCII? i.e., if a technology is not ASCII compatible, could the results reflect that? – Shaun Bebbers Apr 13 at 11:13

# CJam, 8 bytes

l:i2fbS*


Easy-peasy:

l:i           "Read the input line and convert each character to its ASCII value";
2fb        "Put 2 on stack and use that to convert each ASCII value to base 2";
S*      "Join the binary numbers by space";


Try it here

# Python 3, 41 bytes

print(*[bin(ord(x))[2:]for x in input()])


Like KSFT's answer, but I thought I'd point out that, in addition to raw_input -> input, Python 3 also has an advantage here due to the splat for print.

# Pyth, 10 bytes

jdmjkjCd2z


Python mapping and explanation:

j           # join(                               "Join by space"
d          #      d,                             "this space"
m          #      Pmap(lambda d:                 "Map characters of input string"
j         #                    join(            "Join by empty string"
k        #                        k,           "this empty string"
j       #                        join(        "This is not a join, but a base conversion"
C      #                             Pchr(   "Convert the character to ASCII"
d     #                                  d  "this character"
#                                 ),
2      #                             2       "Convert to base 2"
#                            )
#                        ),
z         #           z)))                      "mapping over the input string"


Input is the string that needs to be converted without the quotes.

Try it here

• Is asdfghjlkl also a valid pyth program? What does it do? – flawr Jan 22 '15 at 22:57
• @flawr any harm in trying ? ;) – Optimizer Jan 22 '15 at 22:57
• @flawr That compiles to the python Psum(d).append(Pfilter(lambda T:gte(head(join(Plen(k),Plen()))))), whee d=' ' and k=''. So no, it is not valid at all. – isaacg Jan 22 '15 at 23:11
• @ericmark26 look around your room or office, and smash everything that you can find into your keyboard and see if it interprets. Figure out what it does, and then repeat with the next object. When you run out, try different rotations. – globby Jan 23 '15 at 5:35
• @ericmark26 I think the best way to get used to Pyth is to take some simple Python programs, and translate them into Pyth. – isaacg Jan 23 '15 at 18:47

# Python - 52

print" ".join([bin(ord(i))[2:]for i in raw_input()])


I'll work on translating this into Pyth. Someone else did a Pyth answer already.

If you don't care about it being a full program or about I/O format and use Python 3, you can do it in 23 bytes like this:

[bin(ord(i))for i in x]


x is the input.

I know this doesn't count because the interpreter wasn't released before the challenge was posted, but here it is in KSFTgolf:

oan


# Python 3 - 43 bytes

print(*map("{:b}".format,input().encode()))


No quite the shortest, but an interesting approach IMO. It has the added advantage that if the number of significant bits varies, E.G. Hi!, padding with zeros is trivial (2 more bytes, as opposed to 9 for .zfill(8)):

print(*map("{:08b}".format,input().encode()))


# Ruby, 3428 24 bytes

$<.bytes{|c|$><<"%b "%c}


Takes input via STDIN. 6 bytes saved thanks for AShelly and another 4 thanks to britishtea.

• trim by 6 with $<.each_byte{|c|$><<"%b "%c} – AShelly Jan 23 '15 at 19:07
• You can shave off some more characters by using String#bytes instead of String#each_byte. The block form is deprecated, but it still works :) – britishtea Jan 23 '15 at 22:16
• @britishtea Oh, nice. thank you! – Martin Ender Jan 23 '15 at 22:55

# PowerShell, 6359 46 bytes

-13 bytes thanks to @mazzy

"$($args|% t*y|%{[Convert]::ToString(+$_,2)})"  Try it online! • – mazzy Apr 13 at 20:47 # Matlab This is an anonymous function f=@(x) dec2bin(char(x))  usage is f('Hello World'). Alternatively, if x is defined as the string Hello World! in the workspace, then just dec2bin(char(x)) will work. • I'm not sure about how to score this because I'm not sure how I can get the input. Any comments? – David Jan 23 '15 at 0:12 • Why char? I think you mean dec2bin(x)-'0' – Luis Mendo Jan 23 '15 at 16:09 • Because I'm not that clever! – David Jan 24 '15 at 4:34 • My point is: char(x), when x is already a string, does nothing. So you can remove it to save some space. On the other hand, the result of dec2bin is a string, and I think the output should be numbers – Luis Mendo Jan 24 '15 at 11:24 • I understand, and you are right, of course. Matlab makes it easy to forget about data types sometimes. – David Jan 26 '15 at 5:12 # J - 9 1":#:3&u:  No idea how to make this in a row without doubling the length of the code, I need J gurus to tell me :) 1":#:3&u:'Hello world!' 1001000 1100101 1101100 1101100 1101111 0100000 1110111 1101111 1110010 1101100 1100100 0100001  • You can add ". to the beginning. It evaluates your result so it will be in one line and separated by spaces. Even shorter is to create base10 numbers with the base2 digits: 10#.#:3&u:. – randomra Jan 23 '15 at 11:53 # Java - 148 Bytes public class sToB{public static void main(String[] a){for(int i=0;i<a[0].length();i++){System.out.print(Integer.toString(a[0].charAt(i) ,2)+" ");}}}  Edited to include full file • I think OP wants a full program, not just a snippet. Plus, it can be golfed a lot more, methinks. – Rodolfo Dias Jan 23 '15 at 11:47 • that is the full program, if you put that in a main class, it will run. as for better golfing, probably but i could not spot how. – Bryan Devaney Jan 23 '15 at 13:10 • The full program includes the main class, too. – Rodolfo Dias Jan 23 '15 at 13:19 • could be shorter using for(char c:a[0].toCharArray()){ or even for(byte b:a[0].getBytes()){ since the input is ascii, assuming a non-utf-16 machine locale – njzk2 Jan 23 '15 at 15:00 • You can get rid of the public and shorten the program name to a single char to win more bytes. Plus, (String[]a)is perfectly accepted by the compiler, earning you another byte. – Rodolfo Dias Jan 23 '15 at 15:33 # JavaScript ES6, 63 65 bytes alert([for(c of prompt())c.charCodeAt().toString(2)].join(' '))  This is rather long, thanks to JavaScript's long function names. The Stack Snippet below is the rough ES5 equivalent, so it can be run in any browser. Thanks to edc65 for the golfing improvements. alert(prompt().split('').map(function(e){return e.charCodeAt().toString(2)}).join(' ')) • [for of] is slightly shorter than [...].map to enumerate charactes in strings: alert([for(c of prompt())c.charCodeAt().toString(2)].join(' ')) – edc65 Jan 23 '15 at 14:03 • You can golf off two bytes by replacing .join(' ') with .join  . You can golf off a lot of bytes by using a function instead of prompt/alert – RamenChef Nov 1 '17 at 15:44 # Scala - 59 - 55 Bytes readLine().map(x=>print(x.toByte.toInt.toBinaryString))  Normally, one should use foreach and not map. # 8088 machine code, IBM PC DOS, 33 31 bytes* Listing: D1 EE SHR SI, 1 ; point SI to DOS PSP (80H) AD LODSW ; load input string length into AL, SI to 82H 8A C8 MOV CL, AL ; set up loop counter 49 DEC CX ; remove leading space/slash from char count LOOP_CHAR: B3 08 MOV BL, 8 ; loop 8 bits AC LODSB ; load next char LOOP_BIT: D0 C0 ROL AL, 1 ; high-order bit into low-order bit B4 0E MOV AH, 0EH ; BIOS display character function 50 PUSH AX ; save AH/AL 24 01 AND AL, 1 ; mask all but low-order bit 04 30 ADD AL, '0' ; convert to ASCII CD 10 INT 10H ; write char to display 58 POP AX ; restore AH/AL 4B DEC BX ; decrement bit counter 75 F1 JNZ LOOP_BIT ; loop next bit B0 20 MOV AL, ' ' ; display a space CD 10 INT 10H ; write space to display E2 E8 LOOP LOOP_CHAR ; loop next char C3 RET ; return to DOS  Complete PC DOS executable COM file, input is via command line. With leading zeros: Download and test ASCBIN.COM. Or 39 bytes without leading zeros: Download and test ASCBIN2.COM. *Since it wasn't explicitly clear to me whether or not leading zeros are allowed, am posting versions both ways. # Haskell, 65 m s=tail$do c<-s;' ':do j<-[6,5..0];show$mod(fromEnum cdiv2^j)2  heavy use of the list monad. it couldn't be converted to list comprehentions because the last statements weren't a return. # C++ - 119 bytes Freeing memory? What's that? #include<cstdio> #include<cstdlib> int main(int c,char**v){for(*v=new char[9];c=*(v[1]++);printf("%s ",itoa(c,*v,2)));}  (MSVC compiles the code with warning) # Jelly, 3 bytes OBK  Try it online! # Tcl, 52 bytes proc B s {binary s$s B* b;regsub -all .{8} $b {& }}  Try it online! # APL (Dyalog), 12 bytes 10⊥2⊥⍣¯1⎕UCS  Try it online! Thanks to Adám for help with this solution. # Python 3.6, 39 bytes print(*[f'{ord(c):b}'for c in input()])  Try it online! # Commodore VIC-20/C64/128 and TheC64Mini, 101 tokenized BASIC bytes Here is the obfuscated listing using Commodore BASIC keyword abbreviations:  0dEfnb(x)=sG(xaNb):inputa$:fOi=1tolen(a$):b=64:c$=mI(a$,i,1):fOj=0to6 1?rI(str$(fnb(aS(c$))),1);:b=b/2:nEj:?" ";:nE  Here for explanation purposes is the non-obfuscated symbolic listing:  0 def fn b(x)=sgn(x and b) 1 input a$
2 for i=1 to len(a$) 3 let b=64 4 let c$=mid$(a$,i,1)
5 for j=0 to 6
6 print right$(str$(fn b(asc(c$))),1); 7 let b=b/2 8 next j 9 print " "; 10 next i  The function fn b declared on line zero accepts a numeric parameter of x which is ANDed with the value of b; SGN is then used to convert x and b to 1 or 0. Line one accept a string input to the variable a$, and the loop starts (denoted with i) to the length of that input. b represents each bit from the 6th to 0th bit. c$ takes each character of the string at position i. line 5 starts the loop to test each bit position; right$ is used in line 6 to remove a auto-formatting issue when Commodore BASIC displays a number, converting the output of fn b to a string; asc(c$) converts the current character to its ascii code as a decimal value. Line 7 represents the next bit value. The loop j is ended before printing a space, then the last loop i is ended. # JavaScript ES6, 71 bytes alert(prompt().split('').map(c=>c.charCodeAt(0).toString(2))).join(' ')  • Welcome to PPCG! You need .split('') to split at the empty string; .split() turns "abc" into ["abc"]. – Dennis Apr 13 at 1:55 # Forth (gforth), 45 bytes : f 0 do dup i + c@ 2 base ! . decimal loop ;  Try it online! ### Code Explanation : f \ start a new word definition 0 do \ start a loop from 0 to string length - 1 dup i + \ duplicate the address and add the loop index to get addr of current character c@ \ get the character at that address 2 base ! \ set the base to binary . \ print the ascii value (in binary) decimal \ set the base back to decimal loop \ end the loop ; \ end the word definition  # Ruby, 24 bytes I was hoping to beat Martin Ender, but I only managed to tie him. Takes input on STDIN; +1 bytes for -p flag. gsub(/./){"%b "%$&.ord}


Try it online!

# MITS Altair 8800, 0 bytes

Input string is at memory address #0000H (allowed). Output in binary via front panel I/O lights D7-D0.

Example, do RESET, then EXAMINE to see the first byte, followed by repeating EXAMINE NEXT to see the rest.

"H" = 01 001 000:

"e" = 01 100 101:

"l" = 01 101 100:

Try it online!

Non-competing, of course. :)

## STATA 158

I used a different approach than most. Read in via the display _request() prompt (shortened to di _r(r)). Write the string to a file called b in text mode. Open b in binary mode and read each character as a byte and convert to binary. Technically the b file should be closed at the end, but it is a valid program and runs successfully without it.

di _r(r)
file open a using "b",w
file w a "$r" file close a file open a using "b",b r file r a %1bu t while r(eof)==0 { loc q=t inbase 2 q' file r a %1bu t }  # Golang - 68 I'm new to Go and I'm not sure on the rules for counting characters in this language on here either. Imports (11 bytes): import"fmt"  Function (55 bytes): func c(s string){for _,r:=range s{fmt.Printf("%b ",r)}}  You can run it here. Never will C# win these kinds of questions but here's a try, completely without encoding. :) # C# - 84 Console.Write(String.Join(" ",Console.ReadLine().Select(x=>Convert.ToString(x,2))));  • This could be made much shorter by using a lambda function, ie: x=>String.Join(" ",x.Select(y=>Convert.ToString(y,2))); However note that, due to using .Select(), both this shorter answer, and your original answer, need to include the 18 bytes for using System.Linq; unless you specify that it's using the Visual C# Interactive Compiler, which imports System.Linq by default – Skidsdev Apr 15 at 15:09 • Here's the lambda function solution using Interactive Compiler, total of 55 bytes – Skidsdev Apr 15 at 15:10 # Cobra - 64 As a Lambda: do(s='')=(for c as int in s get Convert.toString(c,2)).join(' ')  # Postscript, 17 bytes (13 byte program + 4 character command line switch) s { 2 7 string cvrs = } forall  Which is 31 bytes in tokenized form: (backticks denote literal characters, everything else is hexidecimal) s{2 7 92A5 9230 =} 9249  Run using Ghostscript as: gs -ss="Hello World!" string-to-binary.ps  # JavaScript 78 alert(eval('""'+prompt().replace(/./g,"+' '+'$&'.charCodeAt().toString(2)")))
`