Write the shortest code that raises a Segmentation Fault (SIGSEGV) in any programming language.
-
52\$\begingroup\$ Wow. Possibly the shortest successful question. \$\endgroup\$– Matthew RohCommented Feb 9, 2017 at 11:42
-
6\$\begingroup\$ @MatthewRoh Out of interest, I made this SEDE query. It looks like there are a few with +10 or higher, but this is the first above +40 \$\endgroup\$– rydwolfCommented Nov 21, 2020 at 20:38
85 Answers
Phooey, Interpreter Bug, 2 bytes
<?
This interpreter is so buggy it is beautiful. I can cause a bad free()
with one byte of code in two ways. But that, unfortunately, is a SIGABRT. 😂
A quick check of the source code will tell you that the interpreter does not support wrapping. However, the bug isn't "lul I read backwards and it crashes", it is a little more in depth.
The Phooey code translates to these function calls:
< tape.left(1) // move left one cell
? debug() // print debug info
So let's step through it:
First, we call tape.left(1)
.
void left(int64_t amount) {
right(-amount);
}
This turns into tape.right(-1)
:
void right(int64_t amount = -1) {
pointer += -1;
Adding -1
to pointer
results it being -1
, since the initial value was zero.
However, let's double check what type pointer
is:
size_t pointer = 0;
size_t furthest = 0;
pointer
is a size_t
, which is an unsigned type, meaning that this -1
turns into a REALLY big number. Specifically, SIZE_MAX
, the largest object size C++ is allowed to handle.
if(pointer > furthest)
furthest = pointer;
We assign pointer
to furthest
, because SIZE_MAX > 0
.
Now, we call debug()
:
void Phooey::debug() {
std::cout << "Tape: " << tape << std::endl;
}
And this calls the operator overload function for std::ostream << Tape
, and here is our bug:
std::ostream& operator<<(std::ostream& stream, Tape& tape) {
for(size_t i = 0; i <= tape.furthest; i++) {
stream << tape[i];
}
}
Let's substitute tape.furthest
, if the bug wasn't clear enough:
for(size_t i = 0; i <= SIZE_MAX; i++) {
stream << tape[i];
}
This loop will keep reading data from the tape
pointer and printing it, until it segfaults. It is actually an infinite loop otherwise: Since tape.furthest
is SIZE_MAX
, it will always be true, as SIZE_MAX + 1 == 0
.
How ironic that the bug occurs in the debug()
function.
A simple way to fix this would be to add wrapping support, making sure that the pointer is always in range. As a matter of fact, almost every bug in this program can be fixed with range checks.
Bonus!
debug()
is the buggiest function in this program. It segfaults even without putting any ?
s in your code!
<3-509
You may be saying, "How are you calling debug()
without ?
?
And the answer is: ROP. 😂
Specifically, on this exact build of Phooey, the tape is stored on the stack, and cells[-3]
contains the return address from call Phooey::run()
, 0x403957
.
509 bytes before that is just after Phooey::debug()
sets up its stack frame. (If I set the pointer to the start of the function, it crashes too early to be interesting since the stack is unaligned). That is why I subtract 509.
It segfaults because it is definitely NOT called how the code expects it to be, and rdi
doesn't have the this
pointer, so it crashes.
This is OBVIOUSLY going to be dependent on the system and binary itself.
J (6)
memf 1
memf
means free memory, 1
is interpreted as a pointer.
-
\$\begingroup\$ Why
1
rather than0
? Is it legal to free a null pointer in J? \$\endgroup\$ Commented Nov 18, 2020 at 18:35
Unix PDP-11 assembly, 18 bytes binary, 7 bytes source
(this is becoming a theme with me, maybe because it's the only language I sort of know that no-one else here does.)
inc(r0)
Increments the single byte addressed by the initial value of r0 [which happens to be 05162 according to the simh debugger] as of program start.
0000000 000407 000002 000000 000000 000000 000000 000000 000000
0000020 005210 000000
And, as always, the extraneous bytes at the end can be removed with strip.
I made a few attempts to get the source shorter, but always ended up getting either a syntax error or SIGBUS.
x86 and x86_64 machine language, 3 bytes
0: 50 push %eax
1: eb fd jmp 0
This pushes the value of the EAX (or RAX in long mode) register to the stack in a loop until the stack overflows.
To try this, compile and run the following C program.
const char main[]="\x50\xeb\xfd";
To try it on Windows, prepend the following to mark main
as executable.
#pragma section("foo", execute)
__declspec(allocate("foo"))
-
\$\begingroup\$ Main is not loaded in at address 0. As such, that jmp alone is causing the segfault. (I'm pretty certain,at least) \$\endgroup\$ Commented Mar 6, 2018 at 19:25
-
1\$\begingroup\$ @moonheart08 it isn't jumping to absolute address
0
, it's jumping to thepush %eax
. Jumping to absolute address0
would require something likexor %eax, %eax; jmp *%eax
\$\endgroup\$ Commented Mar 6, 2018 at 20:42 -
\$\begingroup\$ A long time later, i learned that the hard way (bugggssss!) Thanks. \$\endgroup\$ Commented Sep 5, 2018 at 15:15
Squire commit 93d3bf1
, 6 bytes
" "*-1
A quite intriguing blunder.
My initial attempt was to allocateth \$\text{II}^\text{LXIV}-\text{I}\$ bytes of memory, but alas, Squire thwarteth me by limiting string lengths to \$\text{XXXII}\$-bit integers, and even my peasant computer with a mere \$\text{VIII}\$ gigabytes of RAM was impervious to said attacks, but lo! Even if malloc
rewardeth null
, Squire containeth a defense stronger than steel:
void *xmalloc(size_t length) {
void *ptr = malloc(length);
if (ptr == NULL) {
fprintf(stderr, "error allocating %zu bytes of memory\n", length);
// Alas, thwarted again with SIGABRT!
abort();
}
return ptr;
}
Instead, I ventured into value.c
and spied this:
case SQ_TSTRING: {
sq_number amnt = sq_value_to_number(rhs);
struct sq_string *result = sq_string_alloc(AS_STRING(lhs)->length * amnt + 1);
// ...
}
As with most strings in C, Squire terminateth all strings with \N
, so Sampersand addeth \$I\$ whilst calculating the length.
Intriguingly, \$\text{I} \times -{\text{I}} + \text{I} == \text{N}\$. Therefore, this rewardeth &sq_string_empty
.
struct sq_string *sq_string_alloc(unsigned length) {
if (length == 0)
return &sq_string_empty;
// ...
}
To be more swift, Squire containeth some "static" strings for common values like "false"
or ""
.
struct sq_string {
char *ptr;
int refcount;
unsigned length;
bool borrowed;
};
struct sq_string sq_string_empty = {
.ptr = "",
.length = 0,
.refcount = -1,
.borrowed = false,
};
Curiously, we have a string literal treateth as char *
, which, despite its mutable appearances, is actually a member of the evil .rodata
clan. These sneaky impostors are indistinguishable from normal strings, unless one encanteth -Wwrite-strings
.
Returning to value.c
, the next line triggers the .rodata
impostor:
// Lo! Sampersand hath summoned nasal demons!
*result->ptr = '\0';
In order to make thine computer repent from nasal demons, thy great and powerful Linux exorcises Squire with a SIGSEGV
.
-
2\$\begingroup\$ I thoroughly enjoyed reading this \$\endgroup\$ Commented Jun 17, 2021 at 2:05
Ruby 3.x, 10 bytes
->x=(1in^x
Ruby doesn't like a circular pin reference in proc argument for some reason, this results in a null pointer dereference. Since this is a parser bug the program doesn't even have to be syntactically valid.
JavaScript Shell, 7 bytes
clear()
Clears absolutely everything, not just the current scope which obviously causes lots of borks which result in JS blowing up and segfaulting
-
\$\begingroup\$ According to MDN (document.clear), this should only do something in really old versions of Mozilla, and even then, what really segfaults in your experience? \$\endgroup\$ Commented Dec 16, 2016 at 19:55
-
\$\begingroup\$ @tomsmeding this is window.clear, FF directly doesn't reveal it, it's a spidermonkey built-in \$\endgroup\$– DowngoatCommented Dec 16, 2016 at 19:56
Java (OpenJDK 9), 311 227 223 bytes
import sun.misc.*;import java.lang.reflect.*;class M{public static void main(String[]args) throws Exception{Constructor<Unsafe> c=Unsafe.class.getDeclaredConstructor();c.setAccessible(true);c.newInstance().getAddress(0);}}
Ungolfed:
import sun.misc.Unsafe;
import java.lang.reflect.Constructor;
public class SegFault {
public static void main(String[] args) throws Exception {
Constructor<Unsafe> unsafeConstructor = Unsafe.class.getDeclaredConstructor();
unsafeConstructor.setAccessible(true);
Unsafe unsafe = unsafeConstructor.newInstance();
System.out.println(unsafe.getAddress(0));
}
}
Saved 84 Bytes thanks to Mistah Figg
-
\$\begingroup\$ It does the same as the Dyvil Answer below \$\endgroup\$ Commented Feb 9, 2017 at 14:51
-
\$\begingroup\$ Ask the OP. After searching, I think Access Violation and SegFault are maybe two names for the same thing. \$\endgroup\$– mbomb007Commented Feb 9, 2017 at 14:58
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\$\begingroup\$ TIO throws a SIGSEGV on OpenJDK, so I think its Possible that Oracle and OpenJDK throws same things but under different names. \$\endgroup\$ Commented Feb 9, 2017 at 15:07
-
2\$\begingroup\$ Why the long names and
import x.y.asdf;
instead ofimport x.y.*;
? \$\endgroup\$ Commented Feb 14, 2017 at 4:36 -
1\$\begingroup\$ Using
java.lang.reflect.Constructor
instead of importing it saves 9 bytes \$\endgroup\$– PokeCommented May 1, 2017 at 17:16
Befunge-98 (FBBI), 1 byte
=
Try it online! (expand the Debug section to view the segfault)
This only works in the FBBI implementation of Befunge, exploiting a bug in its string handling code. Any attempt to read a string from an empty stack will result in a null pointer dereference. You can achieve the same result with the i
(Input File) and o
(Output File) instructions, which also expect a string on the stack.
Note that this error wouldn't occur if the stack was simply full of zeros, which in Befunge should be semantically equivalent to an empty stack. For it to crash the stack must be genuinely empty, as is the case on startup.
Ruby, 15 bytes
eval a='eval a'
Segfaults (Ruby 2.3 on Ubuntu xenial)
Lua (luajit
), 52 48 bytes
function f()c=coroutine;c.resume(c.create(f))end
An attempt to compete for the bounty that was recently set on an answer in Lua. This is a function submission (basically because I had to define a function anyway, so not including the code to run it saves bytes). Now with 4 bytes saved due to a suggestion by @ceilingcat to avoid repeating the word coroutine
.
The program works by creating infinitely many coroutines, suspending each in turn to create and start the next. The most commonly used Lua interpreter, lua
, thought of this case and starts causing coroutine creation to fail after a while. luajit
, however, segfaults. (Valgrind reports the issue as a failure to grow the OS-defined stack; this is believable, seeing as one common coroutine implementation gives them each separate parts of the stack.)
Lua 5.3.2 PUC-RIO (the "official") interpreter - 57 bytes
local t={}t.__newindex=t local y=setmetatable({},t)y[1]=1
Note: does not work on all machines, and was fixed in Lua 5.3.3.
Tcl, 60 bytes
set a a;while {[incr i]<999999999} {set a [list $a]};puts $a
Not short, but crashes with a segfault.
This builds a deeply nested list (each with only one element), and when trying to serialize it, Tcl will crash with a stack overflow.
Clean, 19 12 bytes
Start=code{}
Every function always returns something in Clean, including Start
. Because we haven't specified the type of Start
, the compiler assumes (and it can only assume when you inline ABC) that it takes no arguments. Since it takes no arguments, there's nothing on either stack when the function resolves, and so the runtime tries to evaluate the first node in the spine of a graph with... Zero nodes.
-
1\$\begingroup\$ Nice, but the explanation is not entirely correct. The compiler knows the arity by the number of arguments of
Start
; there is no way to write a function in ABC that takes a number of arguments other than the number of arguments of the Clean function. On startup, aStart
node is created. When it is evaluated, it is overwritten by_cycle_in_spine
. The ABC code is supposed to push a new node on the stack, with which the_cycle_in_spine
is then filled. But because it doesn't, thefill_a
instruction then attempts to fill an uninitialised node above_cycle_in_spine
. \$\endgroup\$– user42682Commented Jan 8, 2019 at 10:51 -
\$\begingroup\$ @Keelan I learn something new every time you comment :). I'll edit that in once I'm back at my computer. \$\endgroup\$– ΟurousCommented Jan 8, 2019 at 16:03
Malbolge, 3046 bytes
Behold, an answer in Malbolge that you can embed inside an answer!
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Rust, 38 33 bytes
unsafe{*(std::ptr::null_mut())=0}
Full program is fn main(){...}
. Segfaults as setting a null pointer to a type is undefined behavior (hence the unsafe block that is required).
Old version:
unsafe{std::ptr::null::<u8>().read();}
-
1\$\begingroup\$ There is something slightly poetic about a segfault in Rust \$\endgroup\$– rydwolfCommented Nov 21, 2020 at 20:45
Jelly, 2 bytes
ßß
oh
Since ß
isn't actually coded as a recursive function call in the underlying Python, it isn't affected by the recursion limit. I don't actually know how Jelly's quicks work under the hood, but this appears to just create a nested structure that grows until it can't anymore. Any atom or atom-like quick works after the first ß
.
NASM, 3 characters.
any of the following:
ret
nop
cbw
cwd
cdq
clc
cld
cli
cmc
aaa
aas
aad
aam
stc
std
sti
ret
causes stack underflow. cli
and sti
trigger SIGSEGV because they are privileged instructions. All the other opcodes trigger a SIGSEGV simply because there's no exit point.
-
1\$\begingroup\$ Under Linux,
cli
andsti
will segfault all by themselves, because they're privileged, not because of the lack of exit point. You could addhlt
to the list for the same reason. \$\endgroup\$ Commented Dec 9, 2020 at 19:33 -
\$\begingroup\$ @NateEldredge Isn't
hlt
the opcode for "halt"?hlt
causes the program to segfault, and does not halt the processor, even though the NASM manual (posix.nl/linuxassembly/nasmdochtml/nasmdoca.html#section-A.74) says it does. \$\endgroup\$ Commented Dec 9, 2020 at 23:42 -
2\$\begingroup\$ Yes,
hlt
will halt the processor if executed at privilege level 0, but if not then it raises a general protection fault. See for instance felixcloutier.com/x86/hlt. Linux userspace programs are at privilege level 3, and the kernel handles the GPF by delivering SIGSEGV to the process.cli
andsti
are in a similar boat, though the privilege requirements are more complicated. \$\endgroup\$ Commented Dec 9, 2020 at 23:49 -
\$\begingroup\$ @NateEldredge Ok, I've updated this answer. \$\endgroup\$ Commented Dec 10, 2020 at 0:02
C++ (clang), compiler crash, 36 28 bytes
class{operator*(...){*this*1
Unlike the other compiler crash which I found on my own, I totally didn't look this one up on bugs.llvm.org..
Assembly (as, x64, Linux), 17 10 bytes
Unfortunately, this was not a segfault, but an assertion. Leaving it up with another compiler segfault as a bonus.
I wrote code that raises a SIGSEGV in assembler.
Literally. 😏
Replace \0
with a literal 0x00
byte.
"\0.asciz "
Found this bug when golfing the assembly here
Note that this bug seems to have been fixed as of v2.34.
Rust, 17 bytes
fn main(){main()}
Well... This just calls itself.
It may be the only way to do it without unsafe
.
-
\$\begingroup\$ It looks like Rust actually detects the stack overflow and aborts.. What version are you running? 🤔 \$\endgroup\$– EasyasPiCommented Feb 11, 2021 at 1:24
-
\$\begingroup\$ But, it also is doing segfault, before aborting... as I found with
strace
\$\endgroup\$ Commented Feb 11, 2021 at 1:27 -
\$\begingroup\$ Oh, I guess you're right. My bad. Good find, then! \$\endgroup\$– EasyasPiCommented Feb 11, 2021 at 1:44
Lua (LuaJIT), 47 43 bytes
f=require"ffi"f.cdef"int puts()"f.C.puts()
Uses FFI in LuaJIT to call puts()
with no (valid) argument.
Perl 6, 22
shell "kill -11 $*PID"
Just shelling to whatever shell you have.
-
1\$\begingroup\$ Why not do it directly in bash (11 chars):
kill -11 $$
... \$\endgroup\$– ElistCommented Feb 18, 2017 at 20:55
Dyvil, 42 bytes
dyvil.reflect.ReflectUtils.UNSAFE.getInt 0
Explanation:
dyvil.reflect.ReflectUtils // qualified type name
.UNSAFE // accesses the static field UNSAFE in class
// dyvil.reflect.ReflectUtils, of type sun.misc.Unsafe
.getInt 0 // calls the method sun.misc.Unsafe.getInt(long),
// which tries to read a 4-byte integer from
// the memory address 0
-
2
-
\$\begingroup\$ I don't know about you, but I just get a SIGKILL. \$\endgroup\$ Commented Dec 25, 2020 at 20:15
Common Lisp (SBCL), 79 bytes.
SBCL captures pretty much every exception and signal, but we can cause an "Unhandled memory exception" which is the result of a SIGSEGV. We must tell SBCL to not consider type safety and just add a fixnum to a float, which ends up disastrous.
(defun f(x)(declare (optimize (safety 0))(fixnum x))(the fixnum (1+ x)))(f 0.0)
My SBCL image errors with:
Unhandled memory fault at #x14.
[Condition of type SB-SYS:MEMORY-FAULT-ERROR]
Evaluating (f '(1 5))
returned a garbage object, then (gc)
threw Lisp into the low-level debugger after it tried to GC that object presumably. I don't see the difference in results since it is possible to jump back into Lisp from this state, and I imagine this is 100% platform dependent behavior.
x86 .COM, 2 Bytes
66 61 POPAD
x86 .COM, 5 3 Bytes
A3 FF FF
Write to the segment border
x86 machine code - 1 byte
08048060 <_start>:
8048060: 5c pop esp
This is change value of address esp
into value 0x1
, and then raises a SIGSEGV
.
(gdb) disassemble _start Dump of assembler code for function _start: 0x08048060 : pop esp End of assembler dump. (gdb) b *0x08048060 Breakpoint 1 at 0x8048060 (gdb) r Starting program: /home/user/programming/assembly/pop Breakpoint 1, 0x08048060 in _start () (gdb) i r $esp esp 0xbfffed40 0xbfffed40 (gdb) c Continuing. Program received signal SIGSEGV, Segmentation fault. 0x08048061 in ?? () (gdb) i r $esp esp 0x1 0x1 (gdb)