32
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Challenge

Given that Christmas is:

  • December
  • Month 12
  • Day 25

Every year, determine today's date, and whether or not today is Christmas. If it is Christmas, you must print "It's Christmas". If it is not Christmas, you must somehow wait until Christmas and then print "It's Christmas".

Example

From this Stack Overflow Question

import time
while time.strftime("%b, %d", time.localtime()) != "Dec, 25":
    time.sleep(60)
print "It's Christmas"

Python in 115 Characters

Rules

Here are the rules:

  • Assume that the computer's clock is always right.
  • Your code must be able to be started at any time.
  • Your code must print "It's Christmas" on Christmas.
  • Looping is certainly not necessary, but once started your code should not stop until it has printed.
  • Shortest code wins.
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  • \$\begingroup\$ I thought the input is in Julian date before I read this post \$\endgroup\$ – Ming-Tang Dec 21 '11 at 9:51

36 Answers 36

18
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Perl + Unix, 40 chars

1until`date`=~/c 25/;say"It's Christmas"

This is the same as J B's Perl solution, except that I save a few chars by using the external date command instead of Perl's localtime.

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143
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Bash, 39

For those who just can't wait:

sudo date 12250000
echo It\'s Christmas

This follows all of the rules, especially the first one.

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  • 11
    \$\begingroup\$ Clever. Not what I meant, but damned clever. \$\endgroup\$ – Patrick Perini Dec 5 '11 at 21:56
  • 8
    \$\begingroup\$ “...and if the computer's clock isn't always right enough, make it.” Good show! \$\endgroup\$ – J B Dec 6 '11 at 8:49
  • 13
    \$\begingroup\$ You can save 5 characters if you're root. :D \$\endgroup\$ – Wug Oct 8 '12 at 21:11
29
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Unix, 39 bytes

echo{,} "It\'s christmas"|at -t12252359

With help from Dennis, thanks for that.

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  • \$\begingroup\$ This violates »Looping is certainly not necessary, but once started your code should not stop until it has printed.«, though. \$\endgroup\$ – Joey Dec 7 '13 at 17:59
  • \$\begingroup\$ I don't understand your critique. Do you claim this is looping? That it stops before printing? \$\endgroup\$ – user unknown Dec 7 '13 at 19:30
  • 2
    \$\begingroup\$ Using echo{,} "It\'s Christmas"|at -t12252359, this is shorter than the accepted answer. (The backslash is required by the way.) \$\endgroup\$ – Dennis Jun 6 '15 at 5:18
  • 1
    \$\begingroup\$ @Dennis: Nice use of brace expansion. \$\endgroup\$ – Joey Adams Jun 9 '15 at 12:45
18
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PowerShell, 45 46 chars

for(;(date).date-ne'12/25'){}"It's Christmas"

It's certainly not very power-efficient, so a laptop battery might die before Christmas (reason to wish for a new one, maybe). But not sleeping is definitely shorter.

This is also locale-agnostic. And thanks to Jaykul for a nice trick in reducing this further.

Abusing the rules a bit, 45 chars

for(){"It's Christmas"*((date)-like'12/25*')}

This will print empty lines until it's Christmas, upon which it will print “It's Christmas”.

It ...

  • ... can be started at any time.
  • ... prints “It's Christmas” on Christmas. Several times. The whole day long. (The rules didn't say anything about how often it may be printed.)
  • ... does not print “It's Christmas” on not-Christmas (although it prints an empty line in that case; can be rectified by sacrificing another character, but then this gains nothing over the more sane solution above).
  • ... does not ever stop (not even after it has printed “It's Christmas” but definitely not before).
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  • 2
    \$\begingroup\$ for(;(date).date-ne"12/25"){}"It's Christmas" # 45 chars \$\endgroup\$ – Jaykul Dec 6 '11 at 6:32
  • \$\begingroup\$ Jaykul: Thanks ... that's something I never would have thought to be working. \$\endgroup\$ – Joey Dec 6 '11 at 9:54
  • \$\begingroup\$ The "abusive" script could also use -match, and do without the wildcard, for no gain/loss in characters. \$\endgroup\$ – Iszi Dec 7 '13 at 7:38
  • \$\begingroup\$ You can remove the abuse now, it's unneeded. \$\endgroup\$ – Erik the Outgolfer Sep 11 '16 at 13:55
  • \$\begingroup\$ @EriktheGolfer: How so? It still offers an interesting alternative approach, even though it's not shorter. \$\endgroup\$ – Joey Sep 11 '16 at 14:35
13
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Python (36 chars)

In the spirit of abusing the rules:

  • Definitely prints "It's Christmas" on Christmas

  • If it is not Christmas, pass the time by printing "It's Christmas"

    while True:
        print "It's Christmas"
    
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  • 2
    \$\begingroup\$ 29 bytes: while 1:print"It's Christmas". \$\endgroup\$ – Erik the Outgolfer Sep 11 '16 at 13:56
11
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PostScript, 90

(%Calendar%)currentdevparams begin{Month 12 eq Day 25 eq and{exit}if}loop(It's Christmas)=

Don't run on a printer, it doesn't print a page, and it will only DoS your printer until Christmas day. Then again, getting your printer back would be a nice present.

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  • 4
    \$\begingroup\$ Don't forget to tape a sign to the printer saying: DO NOT KILL JOB UNTIL CHRISTMAS! \$\endgroup\$ – Joey Adams Dec 6 '11 at 16:58
  • \$\begingroup\$ I guess most printers won't even have a working hardware clock as that's an optional feature. Very nice, though :) \$\endgroup\$ – Joey Dec 7 '11 at 9:38
7
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Mathematica, 47

While[Date[][[2;;3]]!={12,25}];"It's Christmas"
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5
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Perl, 44 45

perl -E'1until localtime=~/c 25/;say"It's Christmas"'

Wouldn't GMT time be sufficient? (3 characters off ;-)

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  • \$\begingroup\$ 1until localtime=~/c 25/; would save you one char. :) \$\endgroup\$ – Ilmari Karonen Dec 5 '11 at 15:33
  • \$\begingroup\$ I thought I'd already tried that and it failed, but it turns out I actually forgot -E at the time. Thanks! \$\endgroup\$ – J B Dec 5 '11 at 15:49
  • \$\begingroup\$ No problem. (Ps. I just posted a version of your solution using backticks instead of localtime below. Feel free to steal it if you like, but I felt the extra dependency justified a separate answer.) \$\endgroup\$ – Ilmari Karonen Dec 5 '11 at 15:59
  • \$\begingroup\$ Naaaw, shame's on me for not thinking of it again. The separate answer is perfectly justified IMO (and upvoted). \$\endgroup\$ – J B Dec 6 '11 at 8:54
5
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Perl, 45

{localtime=~/c 25/&&die"It's Christmas";redo}

Perl, 44

using ternary operator (Thanks to Ilmari Karonen).

{localtime=~/c 25/?say"It's Christmas":redo}
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  • \$\begingroup\$ ? : instead of && ; would save you one char too. (And I'd use say instead of die for prettier output.) \$\endgroup\$ – Ilmari Karonen Dec 5 '11 at 15:35
  • \$\begingroup\$ @Ilmari Karonen: thanks. But by using say instead of die, the script never finish. \$\endgroup\$ – Toto Dec 5 '11 at 15:43
  • \$\begingroup\$ It will, if you use the ternary operator. \$\endgroup\$ – Ilmari Karonen Dec 5 '11 at 15:49
  • \$\begingroup\$ @Ilmari Karonen: yes, of course. May be i'm too tired !!! \$\endgroup\$ – Toto Dec 5 '11 at 16:01
5
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Javascript, 51 chars

It's a CPU killer:

while(!/c 25/.test(Date()));alert("It's Christmas")
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4
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I wanted to do this without parsing strings. Subsequently, there's a lot of magic numbers in my code.

I did some approximation to account for leap years. No one said that it had to print it out right on 00:00:00, Dec. 25!

Perl, 80 69 57 characters

{(time-30931200)%31557600<86399?die"It's Christmas":redo}

Edited for more concise looping!

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4
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R (47)

while(!grepl("c 25",date())){};"It's Christmas"
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3
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Python, 66 68

import time
while'c 25'not in time.ctime():1
print"It's Christmas"
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  • \$\begingroup\$ That 1 at the end of the second line looks quite suspicious to me. :P \$\endgroup\$ – cjfaure Jan 7 '14 at 15:10
  • \$\begingroup\$ @Trimsty: The 1 provides a body for the while-loop. It's basically a busy wait until December 25. It has the similar effect to while 1:if'c 25'in time.asctime():break. \$\endgroup\$ – Steven Rumbalski Jan 7 '14 at 15:39
  • \$\begingroup\$ Ah, okay, thanks for clearing that up. \$\endgroup\$ – cjfaure Jan 8 '14 at 8:02
  • \$\begingroup\$ I think time.ctime() would do. \$\endgroup\$ – gnibbler Feb 12 '14 at 6:14
  • \$\begingroup\$ @gnibbler: Indeed it would. Nice catch. \$\endgroup\$ – Steven Rumbalski Feb 12 '14 at 15:41
3
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TI-BASIC, 42 38

Repeat 769=sum(getDate²,2
End
"It's Christmas

Expects the date format to be YYYY/MM/DD.

getDate creates a three-element list {year,month,day}; only on Christmas is month^2 + day^2 equal to 769.

23 bytes are used for the string because lowercase letters are two bytes each, except for i which is displayed as the imaginary unit token.

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2
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Batch file, 68 chars

:l
@date/t|findstr/c:"-12-25">nul&&echo It's Christmas&&exit
@goto l

Not usable interactively, as it kills the session. Solving that would require 5 more characters.

Also locale-sensitive. This works on my locale which uses ISO 8601 date format.

But hey, it's a batch file (by most not even regarded as a programming language). And shorter than Javascript (and on par with Python).

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2
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Groovy, 55

while(!new Date()==~/.*c 25.*/);
println"It's Christmas"

Think it works, but still waiting for output.

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  • \$\begingroup\$ If Groovy's regexps are anything like in most other languages, those .* are entirely unnecessary. (Ps. You can test it by waiting for Dec 5 instead of 25.) \$\endgroup\$ – Ilmari Karonen Dec 5 '11 at 18:54
  • 1
    \$\begingroup\$ Ilmari, Groovy is a JVM language and Java's regexes are anchored by default. \$\endgroup\$ – Joey Dec 5 '11 at 19:19
  • 1
    \$\begingroup\$ Ilmari, I'd check but my program is still running \$\endgroup\$ – Armand Dec 6 '11 at 16:56
2
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(pdf)eTeX - 180 chars only December 1-25.

\lccode`m`~\let\e\expandafter\def~{\ifdim900pt<\pdfelapsedtime
sp\pdfresettimer\else\e~\fi}\lowercase\e{\e\scantokens\e
{\romannumeral\numexpr (25 - \day)*96000}}It's Christmas!\bye

TeX only has a way to access the date when the program starts, and the time elapsed since the start, capped at 32768 seconds, so I need to compute the number of seconds to wait, and for each second do a loop which waits for the elapsed time to reach 1s and reset the time. (Precisely, I'm doing blocks of 900 seconds.)

Working for any month requires more work: 355 chars.

\lccode`m=`~\let\o\or\let\y\year\let\n\numexpr\let\e\expandafter
\def\b#1{\ifnum#1=\n(#1/4)*4\relax+1\fi}\def~{\ifdim
900pt<\pdfelapsedtime sp\pdfresettimer\else\e~\fi}\lowercase
\e{\e\scantokens\e{\romannumeral\n(25-\day+\ifcase\month\o334\b\y
\o303\b\y\o275\o244\o214\o183\o153\o122\o91\o61\o30\o0\ifnum25<\day
365\b{\n\y+1}\fi\fi)*96000}}It's Christmas!\bye
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2
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MySQL, 180 chars

Because what are you using your database engine for, anyway?

DELIMITER $$
CREATE FUNCTION c() RETURNS CHAR(14) BEGIN a: LOOP IF DAY(NOW())=25 && MONTH(NOW())=12 THEN RETURN 'It\'s Christmas'; END IF; END LOOP a; END$$
DELIMITER ;
SELECT c();

Not very competitive lengthwise, but hey, it's doable!

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  • \$\begingroup\$ Try DELIMITER /, RETURNS TEXT and CURDATE()LIKE'%12-25'; and try to remove some whitespace. \$\endgroup\$ – Titus Apr 16 '17 at 23:24
2
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Ruby, 53

until Time.now.to_s=~/c 25/
end
puts"It's Christmas!"
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2
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PHP, 40 bytes

<?while(date(dm)-1225);?>It´s Christmas;

Loop until 25th of December; then exit to plain mode and print.

Run with default settings (don´t display notices).

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2
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8086 machine code, 33 bytes

00000000  b4 2a cd 21 81 fa 19 0c  75 f6 b4 09 ba 12 01 cd  |.*.!....u.......|
00000010  21 c3 49 74 27 73 20 43  68 72 69 73 74 6d 61 73  |!.It's Christmas|
00000020  24                                                |$|
00000021
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1
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Javascript, 93 89 78 77 chars

function x(){Date().match("c 25")?alert("It's Christmas"):setTimeout(x,1)}x()

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  • \$\begingroup\$ @Joey Thanks! I forgot about that. \$\endgroup\$ – JiminP Dec 5 '11 at 9:52
  • 2
    \$\begingroup\$ Another non-blocking version: setInterval('/c 25/.test(Date())&&alert("It\'s Christmas")',9) at 61 chars ... the only drawback is that it will alert() all day on Christmas. \$\endgroup\$ – David Murdoch Dec 6 '11 at 3:14
  • \$\begingroup\$ Why setInterval to 1? setInveral to 1000*60*60*24 and it both won't make the process suffer and will notify only once on christmas. \$\endgroup\$ – George Mauer Feb 12 '14 at 20:24
1
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D, 130

import std.datetime,std.stdio;
main(){
do{
auto t = Clock.currTime();
}while(t.month!=12||t.day!=25);
writeln("It's Christmas");
}
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  • \$\begingroup\$ You can probably save two characters in the assignment. And a few more by reducing the number of lines. \$\endgroup\$ – Joey Dec 5 '11 at 16:28
  • \$\begingroup\$ I can also save some by using t.month^12|t.day^25 (if I get my priorities right) \$\endgroup\$ – ratchet freak Dec 5 '11 at 18:38
1
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Q, 63 chars

system"t 1000";.z.ts:{$["12.25"~-5#-3!.z.d;1"It's Christmas";]}

will work for christmas day on every year

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1
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SQL*Plus + PL/SQL - 100

EXEC LOOP EXIT WHEN TO_CHAR(SYSDATE,'DDMM')='2512';END LOOP;DBMS_OUTPUT.put_line('It''s Christmas');
  • Assuming SERVEROUTPUT ON
  • Shorter then the MySql solution (eat that, MySql!)
  • Too late for last year, but in time for this year
  • Tried DBMS_OUTPUT.put instead of DBMS_OUTPUT.put_line but that doesn't print anything.
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1
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C# (126)

using System;class P{static void Main(){while(DateTime.Now.Date.ToString("Md")!="1225");Console.WriteLine("It's Christmas");}}

Nicer for your battery:

C# (163)

using s=System;class P{static void Main(){s.Threading.Thread.Sleep(s.DateTime.ParseExact("1225","Md",null)-s.DateTime.Now);s.Console.WriteLine("It's Christmas");}}

edit

The second ("nicer for your battery") version does have a bit of an issue dec. 26th to dec. 31st I just thought of :P

Both versions can probably be shortened a bit more.

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1
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Japt, 27 bytes (non-competing)

Ks f"c 25" ?`It's CËItµs`:P

To test against today's date : Replace c 25 with this month's last letter (shorthand) + space + day of the month. Feb 02 == b 02

Try it online! Non-competing because Japt is far newer than this challenge.

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1
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VBA, 58 Bytes

Anonymous VBE immediates window function that takes no input and runs until it's Christmas day, at which time it outputs It's Christmas to the VBE immediates window.

While Left(Now,5)<>"12/25":DoEvents:Wend:?"It's Christmas"
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0
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bash-n-date: 69 chars:

sleep $(($(date -d"12/25" +%s)-$(date +%s))) && echo "It's X-Ray    "

But it will fail on Dec. 26th to Dec. 31th.

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0
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Q (60)

 system"t 1000";.z.ts:{if[.z.d~2012.12.25;1"It’s Christmas"]}
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  • \$\begingroup\$ > If it is not Christmas, you must somehow wait until Christmas and then print "It's Christmas". \$\endgroup\$ – skeevey Mar 7 '12 at 13:55
  • \$\begingroup\$ My apologies, corrected to check every second if it's Christmas...so this will print "It's Christmas" 86,400 times every 25th December. Obviously you can alter this by increasing the timer, which is in milliseconds. \$\endgroup\$ – sinedcm Mar 7 '12 at 14:20

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