The goal of a Rosetta Stone Challenge is to write solutions in as many languages as possible. Show off your programming multilingualism!

The Challenge

When people use the term "average," they generally mean the arithmetic mean, which is the sum of the numbers divided by the number of numbers. There are, however, many more meanings to the word "mean," including the harmonic mean, the geometric mean, the arithmetic mean, the quadratic mean, and the contraharmonic mean.

Your challenge is to write a program which inputs a list of numbers and outputs those 5 different means. Additionally, you are trying to write programs in as many languages as possible. You are allowed to use any sort of standard library function that your language has, since this is mostly a language showcase.


Input will be a list of positive numbers.



Output will be the five means in the order listed above (harmonic, geometric, arithmetic, quadratic, contraharmonic). Conveniently, this is the same as increasing order.


There will be some reasonable leniency in I/O format, but I do want several decimal places of accuracy. Since I want floating-point output, you can assume floating-point input.

The Objective Winning Criterion

As for an objective winning criterion, here it is: Each language is a separate competition as to who can write the shortest entry, but the overall winner would be the person who wins the most of these sub-competitions. This means that a person who answers in many uncommon languages can gain an advantage. Code-golf is mostly a tiebreaker for when there is more than one solution in a language: the person with the shortest program gets credit for that language.

If there is a tie, the winner would be the person with the most second-place submissions (and so on).

Rules, Restrictions, and Notes

Your program can be written in any language that existed prior to September 2th, 2014. I will also have to rely on the community to validate some responses written in some of the more uncommon/esoteric languages, since I am unlikely to be able to test them.

Please keep all of your different submissions contained within a single answer.

Also, no shenanigans with basically the same answer in a slightly different language dialects. I will be the judge as to what submissions are different enough.

Current Leaderboard

This section will be periodically updated to show the number of languages and who is leading in each.

  • Algoid (337) - Beta Decay
  • APL (42) - algorithmshark
  • Awk (78) - Dennis
  • BBC BASIC (155) - Beta Decay
  • C (136) - Dennis
  • C++ (195) - Zeta
  • C# (197) - Martin Büttner
  • CJam (43) - Dennis
  • Clojure (324) - Michael Easter
  • Cobra (132) - Ourous
  • CoffeeScript (155) - Martin Büttner
  • Commodore BASIC (104) - Mark
  • Common Lisp (183) - DLosc
  • Erlang (401) - Mark
  • Fortran (242) - Kyle Kanos
  • Fortran 77 (286) - Beta Decay
  • GNU bc (78) - Dennis
  • GolfScript (83) - Dennis
  • Groovy (157) - Michael Easter
  • Haskell (140) - Zeta
  • J (28) - algorithmshark
  • Java (235) - Michael Easter
  • JavaScript (ES6) (112) - Dennis
  • JRuby (538) - Michael Easter
  • Julia (79) - Martin Büttner
  • Lua (113) - AndoDaan
  • Mathematica (65) - Martin Büttner
  • Matlab (63) - Martin Büttner
  • Octave (68) - Dennis
  • Openscript (849?) - COTO
  • Pascal (172) - Mark
  • Perl (76) - Grimy
  • PHP (135) - Dennis
  • POV-Ray 3.7 (304) - Mark
  • Prolog (235) - DLosc
  • Pyth (52) - Dennis
  • Python 2 (96) - Dennis
  • Python 3 (103) - DLosc
  • Q (53) - algorithmshark
  • Q'Nial (68) - algorithmshark
  • QBasic (96) - DLosc
  • R (91) - plannapus
  • Ruby (118) - Martin Büttner
  • Rust (469) - Vi.
  • Scala (230) - Michael Easter
  • T-SQL (122) - MickyT
  • TI-Basic (85) - Ypnypn
  • TypeScript (393) - rink.attendant.6
  • VBA (Excel) (387) - Stretch Maniac
  • wxMaxima (134) - Kyle Kanos

Current User Rankings

  1. Dennis (10)
  2. Martin Büttner (6)
  3. Michael Easter (5)
  4. Mark, DLosc, algorithmshark (4)
  5. Beta Decay (3)
  6. Zeta, Kyle Kanos (2)
  7. Ourous, AndoDaan, COTO, Grimy, plannapus, Vi., MickyT, Ypnypn, rink.attendant.6, Stretch Maniac (1)

(If I made a mistake in the above rankings, let me know and I'll fix it. Also, the tiebreaker has not been applied yet.)

  • \$\begingroup\$ When you say you're lenient on I/O, does that mean functions are allowed, too, or does everything have to be a program (as far as that notion makes sense in some languages)? \$\endgroup\$ – Martin Ender Sep 2 '14 at 19:26
  • \$\begingroup\$ You missed my favourite mean: the logarithmic mean (a-b)/ln(a/b). I'll admit that only today did I find out how it generalises to a sample set of more than two :-) en.wikipedia.org/wiki/Logarithmic_mean \$\endgroup\$ – Level River St Sep 2 '14 at 20:20
  • 1
    \$\begingroup\$ September 2th, eh? \$\endgroup\$ – amalloy Sep 4 '14 at 18:29
  • 1
    \$\begingroup\$ Also - when it comes to built in commands in Linux, do you consider bc, awk etc to be "languages" or "commands" - so would the different ways to implement this from a shell be counted at different languages? \$\endgroup\$ – Floris Sep 4 '14 at 19:59
  • 2
    \$\begingroup\$ @Floris If in doubt: meta.codegolf.stackexchange.com/a/2073/8478 \$\endgroup\$ – Martin Ender Sep 7 '14 at 13:38

24 Answers 24


Languages: 1

Openscript (many hundreds)

(My favourite obscure and sadly defunct programming language, because I learned to program on it many years ago. ;)

openFile "inputs.txt"
readFile "inputs.txt" to EOF

put it into my input_string

closeFile "inputs.txt"

local inputs[]

fill the inputs with my input_string in [item] order

put 0 into the harmonic_mean
put 0 into the geometric_mean
put 0 into the arithmetic_mean
put 0 into the quadratic_mean

put the length of the inputs into n

step i from 1 to n
    get inputs[i]
    increment the harmonic_mean by 1/it
    increment the geometric_mean by log( it )
    increment the arithmetic_mean by it
    increment the quadratic_mean by it*it

get "outputs.txt"
createFile it

writeFile n/harmonic_mean                & "," to it 
writeFile exp( geometric_mean/n )        & "," to it
writeFile arithmetic_mean/n              & "," to it
writeFile sqrt( quadratic_mean/n )       & "," to it
writeFile quadratic_mean/arithmetic_mean to it

closeFile it
  • 21
    \$\begingroup\$ put the length of the inputs into n? O_O I love this language already. \$\endgroup\$ – DLosc Sep 3 '14 at 1:57
  • 2
    \$\begingroup\$ The syntax reminds me of Chef. \$\endgroup\$ – Comintern Sep 3 '14 at 3:27
  • 2
    \$\begingroup\$ The syntax reminds me of COBOL. \$\endgroup\$ – Amadan Sep 3 '14 at 4:11
  • 3
    \$\begingroup\$ For an even more extreme (and usage specific) "natural" looking language, check out Inform 7. \$\endgroup\$ – Beska Sep 3 '14 at 12:41
  • 3
    \$\begingroup\$ inform 7 is a real language - it's just that the I/O is a text adventure. People have written chess engines in it and Dijkstra's shortest path is at: en.literateprograms.org/Dijkstra's_algorithm_(Inform_7) \$\endgroup\$ – Jerry Jeremiah Sep 7 '14 at 10:41

Languages: 13

I think this list should now contain every programming language that I know sufficiently well to solve at least simple problems in. I'll try to keep this list complete over time as I look into some new languages. (I used to know some Smalltalk and Delphi, but I'd have to look up to much for adding them to feel right.)

C, 196 190 171 165 bytes

main(int c,char**v){float n=c-1,x,h,g=1,q,a=h=q=0;for(;c-1;h+=1/x,g*=pow(x,1/n),a+=x/n,q+=x*x/n)sscanf(v[--c],"%f",&x);printf("%f,%f,%f,%f,%f",n/h,g,a,sqrt(q),q/a);}

Reads the input as individual command line arguments and writes a comma-separated list of the means to STDOUT.

Thanks for some improvements to Quentin.

C++, 200 bytes

This is the same as the above C code, plus two includes. I'm including this because it's longer than the winning C++ submission, so I guess no harm is done, and I'd like this post to actually contain every language I know. :)

#include <cmath>
#include <cstdio>
main(int c,char**v){float n=c-1,x,h,g=1,q,a=h=q=0;for(;c-1;h+=1/x,g*=pow(x,1/n),a+=x/n,q+=x*x/n)sscanf(v[--c],"%f",&x);printf("%f,%f,%f,%f,%f",n/h,g,a,sqrt(q),q/a);}

C#, 220 197 bytes

namespace System{using Linq;class F{double[]f(double[]l){double n=l.Length,a=l.Sum()/n,q=l.Sum(x=>x*x)/n;return new[]{n/l.Sum(x=>1/x),l.Aggregate((p,x)=>p*Math.Pow(x,1.0/n)),a,Math.Sqrt(q),q/a};}}}

Defines a function in a class taking a List of doubles and returning an array of doubles with the five means.

Thanks for some improvements to Visual Melon and Bob.

CJam, 52 bytes


Takes the input as command-line arguments and prints a list with the five values to STDOUT.

CoffeeScript, 155 bytes

This is almost the same as the JavaScript solution further down (and initially I didn't count it for that reason), but the OP included it in the scoreboard anyway, so I promoted it to a full submission. They are technically different languages after all.


JavaScript (ES6), 155 153 bytes


Defines a function taking a array of numbers and returning a array with the five means.

Thanks for some improvements to William Barbosa.

Julia, 79 bytes


Defines a function taking a list of numbers and returning a list with the five means.

Lua, 120 bytes

f=function(l)h=0;q=0;a=0;g=1;for i=1,#l do x=l[i]h=h+1/x;a=a+x/#l;g=g*x^(1/#l)q=q+x*x/#l end;return#l/h,g,a,q^.5,q/a end

Defines a function taking a list of numbers and returning 5 separate values for the means.

Mathematica, 73 67 65 bytes


Defines a function taking a list of floating point numbers and returning a list with the five means.

Fun fact: Mathematica has all 5 means built in (and that was my original submission), but three of them can be implemented in fewer characters than their function names.

Matlab, 65 63 bytes


Requests the input as an array of numbers from the user and outputs the five means individually.

Thanks for some improvements to Dennis Jaheruddin.

PHP ≥ 5.4, 152 149 143 bytes

function f($l){$g=1;$n=count($l);foreach($l as$x){$q+=$x*$x/$n;$h+=1/$x;$g*=pow($x,1/$n);}return[$n/$h,$g,$a=array_sum($l)/$n,sqrt($q),$q/$a];}

Same functional implementation as the earlier ones.

Thanks for some improvements to Ismael Miguel.

Python 2, 127 bytes

def f(l):n=len(l);a=sum(l)/n;q=sum(x*x for x in l)/n;return[n/sum(1/x for x in l),reduce(lambda x,y:x*y,l)**(1./n),a,q**.5,q/a]

Same functional implementation as the earlier ones.

Ruby, 129 118 bytes

r=->l{l.reduce :+}

Same functional implementation as the earlier ones.

  • \$\begingroup\$ I realize this is quite after the fact, but you can lose 3 Julia bytes by using norm(l)/n^.5 in place of norm(l)/sqrt(n). \$\endgroup\$ – Alex A. Mar 31 '15 at 18:55

4 languages

J - 32 28 char!

A function taking the list of numbers as its sole argument.


a here is an adverb, which is J's take on second-order functions.

  • +/ % # is a train in J, meaning Sum Divided-by Count, the definition of the arithmetic mean.
  • &.: is a conjunction called Under, where u&.:v(y) is equivalent to vi(u(v(y))) and vi is the functional inverse of v. Yes, J can take functional inverses.
  • Finally, a useful feature of J is that certain functions can automatically loop over lists, because J knows to apply them pointwise if it wouldn't make sense to apply them on the whole argument. So the square of a list is a list of the squares, for instance.

Thus a takes a function on the left, and returns a mean that "adjusts" the values by the function, takes the arithmetic mean, and then reverses the adjustment afterwards.

  • %a is the harmonic mean, because % means Reciprocal, and is its own inverse.
  • ^.a is the geometric mean, because ^. is the natural logarithm and its inverse is the exponential. (Π x)^(1/n) = exp(Σ log(x)/n)
  • [a is the arithmetic mean, because [ is the identity function.
  • *:a is the quadratic mean, because *: is Square, and its inverse is the square root.
  • The contraharmonic gives us a whole host of trouble—mean of the squares divided by mean—so we do a little math to get it: (*:a divided by ([a divided by *:a)). This looks like [a(]%%)*:a. While we're at it, we prepend each of the means, [a(,,]*%~)*:a.

Finally, we use commas to append the rest of the results together. We require no further parens because concatenation is (in this case at least) associative.

In use at the J REPL:

   (%a,^.a,[a(,,]%%)*:a=.+/%#&.:) 1,2,3,4,5   NB. used inline
2.18978 2.60517 3 3.31662 3.66667
   f =: %a,^.a,[a(,,]%%)*:a=.+/%#&.:          NB. named
   f 1.7,17.3,3.14,24,2.718,1.618
3.01183 4.62179 8.41267 12.2341 17.7915
   f 8.6
8.6 8.6 8.6 8.6 8.6
   f 3,123456
5.99985 608.579 61729.5 87296.6 123453
   f 10.1381,29.8481,14.7754,9.3796,44.3052,22.2936,49.5572,4.5940,39.6013,0.9602
5.95799 14.3041 22.5453 27.9395 34.6243
   f 3,4,4,6.2,6.2,6.2
4.5551 4.74682 4.93333 5.10425 5.28108

Q - 53 char

Single argument function. We just make a list of all the means we want.

{s:(a:avg)x*x;(1%a@1%x;exp a log x;a x;sqrt s;s%a x)}

The same thing in other versions of k is below.

  • k4, 51 char: {s:(a:avg)x*x;(%a@%x;exp a log x;a x;sqrt s;s%a x)}
  • k2, 54 char: {s:(a:{(+/x)%#x})x*x;(%a@%x;(*/x)^%#x;a x;s^.5;s%a x)}

APL - 42 char

Function taking list as argument.


Explained by explosion:

{                                         } ⍝ function with argument ⍵
                                   +/÷≢     ⍝ Sum Divide Length, aka mean
                                 M←         ⍝ assign function to M for Mean
                              A←(M     )⍵   ⍝ arithmetic Mean, assign to A
                     (S←M⍵*2)               ⍝ Mean of squares, assign to S
                      S      ÷A             ⍝ S divide A, aka contraharmonic mean
              (S*.5)                        ⍝ sqrt(S), aka quadratic mean/RMS
                    ,                       ⍝ concatenate into a list
             A                              ⍝ prepend A (APL autoprepends to lists)
        *M⍟⍵                                ⍝ exp of Mean of logs, aka geometric
       (    )                               ⍝ prepend (auto)
  ÷M÷⍵                                      ⍝ recip of Mean of recips, aka harmonic
 (    )                                     ⍝ prepend (auto)

Q'Nial - 68 char

You're going to love this one.


Q'Nial is another array-oriented language, an implementation of Nial, which is based on an obscure Array Theory in the sam way Haskell is based on category theory. (Get it here.) It's very different from any of the other three—it parses left-to-right, first of all!—but it is still more related to them than to any other languages.

  • \$\begingroup\$ I knew there was a better way to do this in APL. So I can deference a variable I defined at its right; wouldn't have thought of that myself... -- That J code is impressive! Every time I see one of your answers, I say to myself You have to learn that language., but then I start reading some documentation/tutorial and I suddenly don't know if I'm in English class or at a train station... :P \$\endgroup\$ – Dennis Sep 7 '14 at 18:45
  • \$\begingroup\$ @Dennis Yeah, APL/J/K assignments return values (most of the time!). And thanks. :) When learning J, it can start to get confusing as to what corresponds to what parts of your home language, so Iverson essentially banned the F-word (function) when writing the docs to try to force you to start fresh. Rolling with it and coming up with your own analogy later is the easiest way to do it. \$\endgroup\$ – algorithmshark Sep 7 '14 at 20:29
  • \$\begingroup\$ I still maintain APL is by far the most readable array language. So much for "write-only" snarks! Too bad GNU APL does not support any of the modern syntax (nested D-funs, lexical scoping, conditional return, hooks and trains… hell, it chokes on /⍨) It was probably meant for porting really old code. What do you use? Dyalog? NARS2000? I think it's really unfortunate that J took the ASCII noise approach. That language's implementation is otherwise a work of genius. But I can't be bothered to mentally parse ]a(,,]*%~)*:a \$\endgroup\$ – Tobia Jan 18 '15 at 10:19
  • \$\begingroup\$ @Tobia I briefly used Dyalog, but I actually barely know enough APL to get by. I'm a J/K fanboy mostly because ASCII is portable, and the rank models make more sense than APL's. ([0.5]? Ew.) With practice, you get used to tacit J, though. It gets far worse than this. \$\endgroup\$ – algorithmshark Jan 18 '15 at 16:56

12 languages

CJam, 45 44 43 bytes


Reads an array of floats (e.g., [1.0 2.0 3.0 4.0 5.0]) from STDIN. Try it online.

APL, 67 61 53 52 50 bytes


Try it online.

Pyth, 55 52 bytes

JyzKlJ=YcsJK=Zcsm^d2JK(cKsmc1kJ ^u*GHJc1K Y ^Z.5 cZY

Reads space-separated numbers (e.g., 1 2 3 4 5) from STDIN.

Octave, 68 bytes

#!/usr/bin/octave -qf
[mean(I=input(''),"h") mean(I,"g") a=mean(I) q=mean(I.*I)**.5 q*q/a]

Not counting the shebang. Reads an array (e.g., [1 2 3 4 5]) from STDIN.

GNU bc, 78 bytes

#!/usr/bin/bc -l

Counting the shebang as 1 byte (-l switch). Reads whitespace separated floats from STDIN, followed by a zero.

Awk, 78 bytes

#!/usr/bin/awk -f
{h+=1/$0;g+=log($0);a+=$0;q+=$0^2;n++}END{print n/h,exp(g/n),a/n,(q/n)^.5,q/a}

Not counting the shebang. Reads one number per line from STDIN.

GolfScript, 86 83 bytes


GolfScript has no built-in support for floats, so the code is parsing them. Therefore, the input format is rather restrictive: you must input 1.0 and 0.1 rather than 1, 1. or .1.

Reads floats (as explained above) one by line, from STDIN. Try it online.

Perl, 90 85 bytes

#!/usr/bin/perl -n

Counting the shebang as 1 byte (-n switch). Reads one number per line from STDIN.

Python 2, 102 96 bytes

for i in input():h+=1/i;g*=i;a+=i;q+=i*i;n+=1
print n/h,g**n**-1,a/n,(q/n)**.5,q/a

Not counting the shebang. Reads a list of floats (e.g., 1.0,2.0,3.0,4.0,5.0) from STDIN.

ECMAScript 6 (JavaScript), 114 112 bytes


Not counting the LF. Expects an array (e.g., [1,2,3,4,5]) as argument.

PHP, 135 (or 108?) bytes


Not counting shebang or LF. Reads floats as command-line arguments.

I have a shorter solution, but I don't know how to count the bytes:

php -R '$i=$argn;$h+=1/$i;$g+=log($i);$a+=$argn;$q+=$i^2;$n++;' \
-E 'print_r([$n/$h,exp($g/$n),$a/$n,sqrt($q/$n),$q/$a]);'

Counting the bytes in each code string and adding two for -R and -E, this approach would score 108.

C, 172 140 139 137 136 bytes

float i,h,g=1,a,q,n;main(){for(;scanf("%f",&i)+1;n++)h+=1/i,g*=i,a+=i,q+=i*i;
printf("%f %f %f %f %f",n/h,pow(g,1/n),a/n,sqrt(q/n),q/a);}

Not counting the LF. Compile with gcc -lm. Reads whitespace separated floats from STDIN.

  • \$\begingroup\$ You can save one byte in C: while(cond)...,n++; vs for(;cond;n++)...; \$\endgroup\$ – Zeta Sep 3 '14 at 17:42
  • \$\begingroup\$ Do we really need to include shebang lines in our counts? \$\endgroup\$ – OregonTrail Sep 4 '14 at 8:42
  • \$\begingroup\$ @OregonTrail: I've included the shebangs in the code since it's easier than explaining run this as interpreter switches script for every submission. Convention is that shebang lines are not counted, unless the contain non-default switches. As stated in my answer, I've counted #!/usr/bin/awk -f as zero bytes (-f means read program from file), but #!/usr/bin/perl -n as one byte (-n means iterate over input lines). \$\endgroup\$ – Dennis Sep 4 '14 at 13:23
  • \$\begingroup\$ Shouldn't you count -q for Octave and -lm for C? \$\endgroup\$ – nyuszika7h Sep 16 '14 at 11:53
  • \$\begingroup\$ -q is just to quiet output. -lm is needed by GCC. Other compilers may noy require it. \$\endgroup\$ – Dennis Sep 16 '14 at 13:21

J (50):

This is the sort of thing J is good at:


As always: an explosion in the smiley factory. However, some of the smileys were left intact this time around: :) and :*: (that's a guy with four eyes and a gem embeded in his face) My interactive session that was used to create this: http://pastebin.com/gk0ksn2b

In action:

   f 1,2,3,4,5
2.18978 2.60517 3 3.31662 3.66667
   f 1.7,17.3,3.14,24,2.718,1.618
3.01183 4.62179 8.41267 12.2341 17.7915
   f 8.6
8.6 8.6 8.6 8.6 8.6
   f 3,123456
5.99985 608.579 61729.5 87296.6 123453
   f 10.1381,29.8481,14.7754,9.3796,44.3052,22.2936,49.5572,4.5940,39.6013,0.9602
5.95799 14.3041 22.5453 27.9395 34.6243
   f 3,4,4,6.2,6.2,6.2
4.5551 4.74682 4.93333 5.10425 5.28108


As you might expect, there are actually 5 functions that are bundled into a list with a train of forks and hooks. (Don't worry about it, it's just a convenient way of making multiple functions output to a single list).

The lines that I used to make J generate this answer might be a bit clearer:

   f=:harmonic , Geometric , arithmatic , rms , contraharmonic
harmonic , Geometric , arithmatic , rms , contraharmonic
   f f.
(# % +/@:%) , (# %: */) , (+/ % #) , %:@(%@# * +/@:*:) , +/ %~ +/@:*:

Let's look at them separately.


(# % +/@:%)
  • # - Length (of the array)
  • % - Divided by
  • +/@:% - The sum (+/, or fold + in the array (+/1 2 3 4 == 1+2+3+4)) atop divide, but this time in the monadic case. What this means here, is that J automatically "guesses" that 1 would be the most useful value.


(# %: */)
  • # - Length (of the array)
  • %: - Root (4 %: 7 would mean 'the fourth (or tesseract) root of seven)
  • */ - Product (*/ is similar in meaning to +/, see the previous function for this)


(+/ % #)
  • +/ - sum, should be familiar now
  • % - divided by
  • # - Lenght

Root mean square

%:@(%@# * +/@:*:)

Ehm, yeah...

  • %: - The root of
    • %@# - The inverse of the lenght
    • * - Times
    • +/@:*: - The sum of the squares (*: is squared, even though *~ is as well.)


+/@:*: % +/
  • +/@:*: - The sum of the squares
  • % - divided by
  • +/ - the sum.

I actually found out that my function was one byte two bytes too long by explaining this, so that's good!

If J were just this good at processing strings, we'd be winning a lot more golfing competitions...

  • \$\begingroup\$ Is that RegEx?? :P \$\endgroup\$ – Little Child Sep 2 '14 at 20:01
  • \$\begingroup\$ @LittleChild Nope. It's J. (jsoftware.com) \$\endgroup\$ – ɐɔıʇǝɥʇuʎs Sep 2 '14 at 20:03
  • 5
    \$\begingroup\$ @LittleChild: Be glad it's not APL \$\endgroup\$ – slebetman Sep 3 '14 at 1:10
  • \$\begingroup\$ J certainly does a great job in both terseness and in the smiley department -- I also found %) and :@( ... \$\endgroup\$ – Desty Sep 9 '14 at 16:01

Languages: 5

POV-Ray 3.7 Scene Description Language: 304 bytes

#fopen I"i"read#declare S=0;#declare N=0;#declare Q=0;#declare P=1;#declare R=0;#while(defined(I))#read(I,V)#declare S=S+V;#declare N=N+1;#declare Q = Q+V*V;#declare P=P*V;#declare R=R+1/V;#end#warning concat(str(N/R,0,5),",",str(pow(P,1/N),0,5),",",str(S/N,0,5),",",str(sqrt(Q/N),0,5),",",str(Q/S,0,5))

(POV-Ray SDL doesn't have console input functions, so I've substituted file input. Output is to the console, but is surrounded by a good deal of program status output.)

Commodore BASIC: 111 104 bytes

1 P=1:O┐1,0
2 I/#1 V:IF V=0T|G┌4
3 S=S+V:N=N+1:Q=Q+V*V:P=P*V:R=R+1/V:G┌2
4 ?N/R,P↑(1/N),S/N,(Q/N)↑.5,Q/S

(Not all of the characters in this program can be represented in Unicode. | is used to represent SHIFT+H, represents SHIFT+O, represents SHIFT+P, / represents SHIFT+N. Because of the limitations in Commodore Basic I/O, the input is entered one number at a time, with an input of -1 to indicate the end of input. Output is tab-delimited.)

QBasic: 96 bytes

P=1:INPUT V:WHILE V:S=S+V:N=N+1:Q=Q+V*V:P=P*V:R=R+1/V:INPUT V:WEND:?N/R;P^(1/N);S/N;(Q/N)^.5;Q/S

Uses the same I/O scheme as DLosc's entry; I golfed 15 bytes off by using the fact that INPUT V returns 0 (which evaluates to false) when an empty line is input (at least in MS-DOS QBasic 1.1 -- I don't know if it also works in QB64).

Pascal (FPC compiler): 172 bytes

program M;uses math;var v,p,s,n,q,r:real; begin p:=1;while not eoln do begin read(v);s:=s+v;n:=n+1;q:=q+v*v;p:=p*v;r:=r+1/v end;write(n/r,p**(1/n),s/n,(q/n)**0.5,q/s);end.

The input is separated by spaces, not commas, and is newline terminated. Output is space-separated.

Erlang: 401 bytes


means(S,N,Q,P,R,[]) -> io:fwrite("~f,~f,~f,~f,~f~n", [N/R,math:pow(P,(1/N)),S/N,math:sqrt(Q/N),Q/S]);
means(S,N,Q,P,R,[V|T]) -> means(S+V,N+1,Q+V*V,P*V,R+1/V,T).

means:means(0,0,0,1,0,lists:map(fun({F,R}) -> F end, lists:map(fun(X) -> string:to_float(X) end, string:tokens(io:get_line(""), ",\n")))).

String handling in Erlang is a royal pain. Consequently, all floating-point numbers must be entered with at least one digit after the decimal point -- string:to_float/1 will not convert 1, but will convert 1.0.

(More to come, especially if I figure out how to do this in RoboTalk, a language with neither floating-point operations nor I/O)

  • \$\begingroup\$ I loved my Commodore 64 \$\endgroup\$ – AquaAlex Sep 3 '14 at 7:33
  • \$\begingroup\$ Ditto ... and the amiga \$\endgroup\$ – MickyT Sep 4 '14 at 9:01
  • \$\begingroup\$ A fellow QBasic fan! I independently came up with the same thing after realizing that we didn't have to handle 0 as a valid input. ;) I see you've used (Q/N)^.5 to my SQR(q/n), but that doesn't affect the length. Maybe we could share the lead? (I make the byte count 96, not including the trailing newline.) \$\endgroup\$ – DLosc Sep 5 '14 at 0:21
  • \$\begingroup\$ @DLosc, My byte counter (wc) includes the trailing newline, which I suppose gives us both the lead -- at least until I figure out how to get rid of that duplicate INPUT V. \$\endgroup\$ – Mark Sep 5 '14 at 5:51
  • \$\begingroup\$ Good luck. :^) I tried some fancy stuff with GOTOs instead of the loop, but couldn't get any further reduction. \$\endgroup\$ – DLosc Sep 5 '14 at 19:35

Languages: 3

Unless noted otherwise, numbers need to be seperated by space.

C: 181 163

Takes numbers till end of input.

main(){double h=0,g=1,a=0,q=0,k,n=0;for(;scanf("%lf",&k);++n)h+=1/k,g*=k,a+=k,q+=k*k;printf("%f %f %f %f %f\n",n/h,pow(g,1/n),a/n,sqrt(q/n),q/a);}

(ISO) C++: 195

Takes numbers till end of input.

int main(){double h=0,g=1,a=0,q=0,k,n=0;for(;std::cin>>k;++n)h+=1/k,g*=k,a+=k,q+=k*k;std::cout<<n/h<<" "<<pow(g,1/n)<<" "<<a/n<<" "<<sqrt(q/n)<<" "<<q/a<<"\n";}

Haskell: 185 180 164 159 149 140

Takes arbitrarily many lists of numbers seperated by newline.


f x=let{s=sum;n=s$m(\_->1)x;t=s$m(^2)x}in[n/s(m(1/)x),product x**(1/n),s x/n,sqrt$t/n,t/s x]
main=getLine>>=print.f.m read.words>>main

50 41 (thanks shiona) bytes are just for IO :/.


(Powershell's echo aka Write-Output prints every parameter on a single line)

PS> echo "1 2 3 4 5" "1.7 17.3 3.14 24 2.718 1.618" | runhaskell SO.hs
  • \$\begingroup\$ you should be able to inline some of the definitions in the haskell answer. for example, instead of writing ;c=t/a in the let clause, write [h,g,a/z,r,t/a] after the in. \$\endgroup\$ – proud haskeller Sep 7 '14 at 13:29
  • \$\begingroup\$ @proudhaskeller: Good point, thanks! \$\endgroup\$ – Zeta Sep 7 '14 at 13:35
  • \$\begingroup\$ also, writing s$m(1/)x is shorter than s.m(1/)$x, as is s$m(^2)x. \$\endgroup\$ – proud haskeller Sep 7 '14 at 13:40
  • \$\begingroup\$ @proudhaskeller: Again thanks. One can probably tell that the code gradually evolved from a non-golfed version. Also replaced fromIntegral.length$x with foldr(\_ x->x+1)0x. \$\endgroup\$ – Zeta Sep 7 '14 at 13:47
  • \$\begingroup\$ nice trick! but now that you made me look at it, i found this: s$m(const 1)x. \$\endgroup\$ – proud haskeller Sep 7 '14 at 13:54

Languages - 4

I always love an excuse to pull out good old

QBasic, 112 96 bytes

g=1:INPUT x:WHILE x:h=h+1/x:g=g*x:a=a+x:q=q+x^2:n=n+1:INPUT x:WEND:?n/h;g^(1/n);a/n;SQR(q/n);q/a

QBasic isn't good with variable numbers of inputs, so the program requires one number per line, terminated with 0 or an empty line. Output is separated with spaces.

(Shortened once I realized that 0 isn't a valid number and can be used for input termination.)

Tested using QB64:

Testing the QBasic means program

Common Lisp, 183 bytes

(defun m(l)(let((a(apply #'+ l))(q(apply #'+(map'list #'(lambda(x)(* x x))l)))(n(length l)))(list(/ n(apply #'+(map'list #'/ l)))(expt(apply #'* l)(/ n))(/ a n)(sqrt(/ q n))(/ q a))))

For some reason I expected this to be shorter. I'm not any kind of Lisp expert, so tips are appreciated. Ungolfed version:

(defun means (l)
  (let ((a (apply #'+ l))                                    ; sum of numbers
        (q (apply #'+ (map 'list #'(lambda (x) (* x x)) l))) ; sum of squares
        (n (length l)))
    (list                                 ; Return a list containing:
      (/ n (apply #'+ (map 'list #'/ l))) ; n over sum of inverses
      (expt (apply #'* l) (/ n))          ; product to the power of 1/n
      (/ a n)                             ; a/n
      (sqrt (/ q n))                      ; square root of q/n
      (/ q a)                             ; q/a

Probably the best way to test is by pasting the function into the clisp REPL, like so:

$ clisp -q
[1]> (defun m(l)(let((a(apply #'+ l))(q(apply #'+(map'list #'(lambda(x)(* x x))l)))(n(length l)))(list(/ n(apply #'+(map'list #'/ l)))(expt(apply #'* l)(/ n))(/ a n)(sqrt(/ q n))(/ q a))))
[2]> (m '(1 2 3 4 5))
(300/137 2.6051712 3 3.3166249 11/3)
[3]> (m '(8.6))
(8.6 8.6 8.6 8.6 8.6)
[4]> (m '(3 123456))
(246912/41153 608.5787 123459/2 87296.58 5080461315/41153)

I love how Lisp uses exact fractions instead of floats when dividing two integers.

Prolog, 235 bytes

Prolog isn't great at math, but we're gonna use it anyway. Tested with SWI-Prolog. I think the sumlist predicate may not be standard Prolog, but whatever, I'm using it.

m(L,H,G,A,Q,C):-length(L,N),h(L,I),H is N/I,p(L,P),G is P^(1/N),sumlist(L,S),A is S/N,q(L,R),Q is sqrt(R/N),C is R/S.
p([H|T],R):-p(T,P),R is H*P.
q([H|T],R):-q(T,P),R is H*H+P.
h([H|T],R):-h(T,P),R is 1/H+P.


m(L, H, G, A, Q, C) :-
        length(L, N),   % stores the length into N
        h(L, I),        % stores the sum of inverses into I
        H is N/I,
        p(L, P),        % stores the product into P
        G is P^(1/N),
        sumlist(L, S),  % stores the sum into S
        A is S/N,
        q(L, R),        % stores the sum of squares into R
        Q is sqrt(R/N),
        C is R/S.

% Helper predicates:

% p calculates the product of a list
p([H|T], R) :-
        p(T, P),     % recursively get the product of the tail
        R is H*P.    % multiply that by the head
p([], 1).            % product of empty list is 1

% q calculates the sum of squares of a list
q([H|T], R) :-
        q(T, P),     % recursively get the sum of squares of the tail
        R is H*H+P.  % add that to the square of the head
q([], 0).            % sum of empty list is 0

% h calculates the sum of inverses of a list
h([H|T], R) :-
        h(T, P),     % recursively get the sum of inverses of the tail
        R is 1/H+P.  % add that to the inverse of the head
h([], 0).            % sum of empty list is 0

On Linux, with the code in a file called means.pro, test like this:

$ swipl -qs means.pro
?-  m([1,2,3,4,5],H,G,A,Q,C).
H = 2.18978102189781,
G = 2.605171084697352,
A = 3,
Q = 3.3166247903554,
C = 3.6666666666666665.

Gives a correct but rather amusing result when there's only one number:

 ?- m([8.6],H,G,A,Q,C).
 H = G, G = A, A = Q, Q = C, C = 8.6.

Python 3, 103 bytes

for x in eval(input()):h+=1/x;g*=x;a+=x;q+=x*x;n+=1

Same strategy as Dennis's Python 2 version. Takes a comma-separated list of numbers; handles both ints and floats. A single-number input must be wrapped in square braces (and a list of numbers always may be); a fix would cost 4 bytes.


8 Languages

Fortran 77 - 286

      DO 10 i=1,l


FOR i=1 TO l


9.7914836236097695 26.600000000000001 45.596052460711988 78.15789473684211  

C++ - 292

#include <iostream>
#include <cmath>
using namespace std;int main(){cout << "Length of sequence?: ";cin >> l;int b=0;int d=1;int e=0;int f=0;int j;int seq[l];for(int i=0;i<l;i++){cin >> j;b+=1/j;d*=j;e+=j;f+=pow(j,2);}
    h=l/b;g=pow(d,(1/l));a=e/l;q=pow((f/l),0.5);c=f/e;cout << h,g,a,q,c;}

Python 3 - 151

for i in s:i=float(i);b+=1/i;d*=i;e+=i;f+=i**2


5,100,12,15,1       # Input
3.6764705882352944 9.7914836236097695 26.600000000000001 45.596052460711988 78.15789473684211

Java - 421

class Sequences {
    public static void main( String[] args){
        System.out.println("Length of sequence?: ");Scanner reader = new Scanner(System.in);l=reader.nextInt();int b=0;int d=1;int e=0;int f=0;int j;int seq[l];
        for(int i=0;i<l;i++){j=reader.nextInt();b+=1/j;d*=j;e+=j;f+=Math.pow(j,2);}
        h=l/b;g=Math.pow(d,(1/l));a=e/l;q=Math.sqrt(f/l);c=f/e;System.out.println(h+' '+g +' '+ a+' '+q+' '+c);}}

Javascript - 231

I'm not a Javascripter so any tips would be greatly appreciated

console.log("Length of sequence?: ");
var l=readline(),b=0,d=1,e=0,f=0;
for(var i = 0;i<l;i++) {var j=readline();b+=1/j;d*=j;e+=j;f+=pow(j,2);}
console.log(h+' '+g+' '+a+' '+q+' '+c);

Algoid - 337

Look it up on the Google Play Store or the Raspberry Pi Store

set l=text.inputNumber("Length of sequence?: ");set b=0;set d=1;set e=0;set f=0;set seq=array{};
for(set i=1; i<=l; i++){set j=text.inputNumber(i..": ");b+=1/j;d*=j;e+=j;f+=math.pow(j,2);}
set h=l/b;set g=math.pow(d,(1/l));set a=e/l;set q=math.sqrt(f/l);set c=f/l;set str=h.." "..g.." "..a.." "..q.." "..c;text.output(str);

var'aQ - 376

This is syntactically correct and all, but all current interpreters just don't work...

0 ~ b cher
1 ~ d cher
0 ~ e cher
0 ~ f cher
'Ij mI'moH ~ l cher
l {
    'Ij mI'moH ~ j cher
    b 1 j wav boq ~ b cher
    d j boq'egh ~ d cher
    e j boq ~ e cher
    f j boqHa'qa boq ~ f cher
} vangqa'
l b boqHa''egh ~ h cher
d 1 l boqHa''egh boqHa'qa  ~ g cher
e l boqHa''egh ~ a cher
f l boqHa''egh loS'ar ~ q cher
f e boqHa''egh c cher
h cha'
g cha'
a cha'
q cha'
c cha'
  • 1
    \$\begingroup\$ You can save 1 character using sqrt(b4/l) instead of (b4/l)**0.5 and many more by using a,b,c,d instead of b1-4. You're also making me cry by using 77 instead of the more-modern F90+. \$\endgroup\$ – Kyle Kanos Sep 3 '14 at 14:01
  • \$\begingroup\$ @Kyle Haha, I'll start learning F99 then \$\endgroup\$ – Beta Decay Sep 3 '14 at 14:23
  • \$\begingroup\$ I'm more impressed by the fact that even after seeing the programming train that is Martin, you still decide to go for 6 (more?) languages... Nah, just kidding. I'm most impress by people knowing more than a couple of languages. \$\endgroup\$ – AndoDaan Sep 3 '14 at 14:53
  • 1
    \$\begingroup\$ In JS, you can use comma operator to avoid repeating var: var l=readline(),b=0,d=1,e=0,f=0;. Not sure what readline function is, though. \$\endgroup\$ – Oriol Sep 4 '14 at 0:45
  • 1
    \$\begingroup\$ You should be able to save some bytes by omitting Length of sequence? or at least making it shorter. \$\endgroup\$ – nyuszika7h Sep 16 '14 at 11:55

Languages: 3

CJam, 58


TI-Basic, 85

Input L1:{dim(L1)/sum(1/(L1),dim(L1)√prod(L1),mean(L1),√(mean(L1²)),mean(L1²)/mean(L1

Java, 457

import java.util.*;class C{public static void main(String[]s){List r=new ArrayList();double[]d=Arrays.stream(new Scanner(System.in).nextLine().split(",")).mapToDouble(Double::new).toArray();double x=0,y,z;for(double D:d){x+=1/D;}r.add(d.length/x);x=1;for(double D:d){x*=D;}r.add(Math.pow(x,1./d.length));r.add(y=Arrays.stream(d).average().getAsDouble());x=1;for(double D:d){x+=D*D;}r.add(Math.sqrt(z=x/d.length));r.add(z/y);r.forEach(System.out::println);}}
  • \$\begingroup\$ Can you add the sample output for Java? How many decimal places of accuracy does it give compared to the output in OP? \$\endgroup\$ – Michael Easter Sep 3 '14 at 9:21
  • \$\begingroup\$ Trivially shorter for TI-BASIC is {dim(Ans)/sum(Ansֿ¹),dim(Ans)√(prod(Ans)),mean(Ans),√(mean(Ans²)),mean(Ans²)/mean(Ans \$\endgroup\$ – lirtosiast Jun 8 '15 at 1:56

Languages - 2

Cobra - 132

def f(l as number[])
    for i in l,a,b,c,d=a+1/i,b*i,c+i,d+i**2
    print (e=l.length)/a,b**(1/e),c/e,(d/e)**0.5,d/c

Python - 129

def f(l):a,b,c=len(l),sum(i*i for i in l),sum(l);print(a/sum(1/i for i in l),eval('*'.join(map(str,l)))**(1/a),c/a,(b/a)**.5,b/c)
  • \$\begingroup\$ The Python version works in both Python 2 and 3, but note that the output format isn't exactly the same. \$\endgroup\$ – nyuszika7h Sep 16 '14 at 12:42

1 language

R, 92 91


Takes a vector of value and output a vector of means.

  • \$\begingroup\$ You can save a character if you use d=s(x^2) and replace the latter two uses of s(x^2) with d. \$\endgroup\$ – Kyle Kanos Sep 3 '14 at 14:27
  • \$\begingroup\$ Indeed, thanks! \$\endgroup\$ – plannapus Sep 3 '14 at 14:39

1 Language

Golfscript, 162


Yes, it's huge. And it can definitely be made smaller. Which I will do sometime later. Try it out here.

It expects the input to be newline separated. If that is not allowed, I'll fix it (+2 chars). It outputs the list newline separated.

Here's a slightly more readable version:

  • \$\begingroup\$ Looks like more Ruby than GolfScript. :P \$\endgroup\$ – Dennis Sep 3 '14 at 3:22
  • \$\begingroup\$ @Dennis It is. ;-) \$\endgroup\$ – Justin Sep 3 '14 at 3:36
  • \$\begingroup\$ Why are you sorting the means? \$\endgroup\$ – Dennis Sep 3 '14 at 4:25
  • \$\begingroup\$ @Dennis I don't need to? "Conveniently, the results will be in increasing order." \$\endgroup\$ – Justin Sep 3 '14 at 4:40
  • 4
    \$\begingroup\$ That's a comment, not a requirement. The harmonic mean is less or equal to the geometric mean, which is less or equal to the arithmetic mean, etc. By the way, you have a bug in your contraharmonic mean. The result should be l*l times higher, where l is the number of floats. \$\endgroup\$ – Dennis Sep 3 '14 at 4:41

Languages 2

Fortran: 242

I've ungolfed it for clarity, but the golfed version is what is counted. you first need to input the number of values to be added, then the values.

program g
   function m(x) result(p)

wxMaxima 134

Copy this into the editor, ctrl+enter and then call via m([1,2,3,4,5]),numer to get floating point output (otherwise you get symbolic output).

m(x):=block([n:length(x),d:0,c:mean(x)],for i:1 thru n do(g:x[i],d:d+g*g),return([1/mean(1/x),apply("*",x)^(1/n),c,sqrt(d/n),d/n/c]));
  • 1
    \$\begingroup\$ Maybe you could additionally include the golfed version, so people could check the count? \$\endgroup\$ – Paŭlo Ebermann Sep 5 '14 at 20:53

Perl, 86 76


Input: one number per line.

EDIT: this is one character longer, but since apparently shebang lines aren’t counted toward the total, it ends up being better:

#!perl -pl
  • \$\begingroup\$ It's customary to count a shebang containing two non-default switches as two bytes. That being said, very impressive solution! \$\endgroup\$ – Dennis Sep 6 '14 at 4:24

T-SQL, 136 122

With the number lists stored in table S with I (integer) identifying the list and V (float) the value.



Saved 14 thanks to Alchymist

  • 1
    \$\begingroup\$ Beat me to it on the SQL solution. You can save quite a few characters on the last 2 with sqrt(sum(vv)/count()) and sum(v*v)/sum(v) Also, in Oracle SQL, you can save another character as the function is ln rather than log. \$\endgroup\$ – Alchymist Sep 4 '14 at 8:05
  • \$\begingroup\$ @Alchymist Thanks a lot. Face palm :) \$\endgroup\$ – MickyT Sep 4 '14 at 8:45

Languages: 5

Some entries strive to avoid rounding errors (to 4 decimal places), using Java's BigDecimal instead of float/double, and accept IO rules per OP.

Newer entries relax both IO rules and BigDecimal.

Groovy - 409 400 164 157 chars

float i=0,j=1,k=0,l,n=0,m=0,p;args.each{x=it as float;i+=1/x;j*=x;k+=x;m+=x*x;n++};l=k/n;p=m/n;println "${n/i},${Math.pow(j,1f/n)},$l,${Math.sqrt p},${p/l}"

sample run:

bash$ groovy F.groovy 10.1381 29.8481 14.7754 9.3796 44.3052 22.2936 49.5572 4.5940 39.6013 0.9602

Java - 900 235 chars

class F{public static void main(String[]a){float i=0,j=1,k=0,l,n=0,m=0,p;for(String s:a){float x=Float.valueOf(s);i+=1/x;j*=x;k+=x;m+=x*x;n++;}l=k/n;p=m/n;System.out.println(n/i+","+Math.pow(j,1f/n)+","+l+","+Math.sqrt(p)+","+p/l);}}

sample run:

bash$ java F 10.1381 29.8481 14.7754 9.3796 44.3052 22.2936 49.5572 4.5940 39.6013 0.9602

Clojure - 524 324 chars

(defn r[x](/ (reduce + 0.0 x)(count x)))
(defn s[x](reduce #(+ %1 (* %2 %2)) 0.0 x))
(defn f[x](let[n (* 1.0 (count x))][(/ n(reduce #(+ %1 (/ 1.0 %2)) 0.0 x))(Math/pow(reduce * x)(/ 1.0 n))(r x)(Math/sqrt(/(s x) n))(/(/(s x) n)(r x))]))
(doseq [x(f(map #(Float/valueOf %) *command-line-args*))](print(str x ",")))

sample run (it does have a trailing comma at the end):

bash$ java -jar clojure-1.6.0.jar m2.clj 10.1381,29.8481,14.7754,9.3796,44.3052,22.2936,49.5572,4.5940,39.6013,0.9602

Scala - 841 663 230 chars

import java.math._
object F{def main(a:Array[String]){
var i,j,k,l,m,p=0f;var n=0
a.foreach{y=>var x=y.toFloat;i+=1/x;j*=x;k+=x;m+=x*x;n+=1}

sample run:

bash$ scala F.scala 10.1381 29.8481 14.7754 9.3796 44.3052 22.2936 49.5572 4.5940 39.6013 0.9602

JRuby - 538 chars

It is unclear if JRuby differs from Ruby: this must run on the JVM. Yet it is Ruby syntax. Either way, I'm including it in the spirit of a Rosetta Stone.

require 'java'
java_import 'java.math.BigDecimal'
def b(s) java.math.BigDecimal.new s end
def p(x,y) java.lang.Math::pow(x.doubleValue,y.doubleValue) end
def d(x,y) x.divide y,5,BigDecimal::ROUND_UP end
def r(x,n) d(x.inject(b(0)){|a,v|a.add v},n) end
def s(x) x.inject(b(0)){|a,v|a.add(v.multiply v)} end
n=b x.size
puts "#{d n,x.inject(z){|a,v|a.add(d o,v)}},#{p x.inject(o){|a,v|a.multiply v},d(o,n)},#{r(x,n)},#{p d(s(x),n),b("0.5")},#{d d(s(x),n),r(x,n)}"

sample run (does print a warning to stderr):

bash$ jruby Mean.rb 10.1381,29.8481,14.7754,9.3796,44.3052,22.2936,49.5572,4.5940,39.6013,0.9602

Languages 1

lua - 113

e=arg s=#e h,g,a,r=0,1,0,0 for i=1,s do x=e[i]h=h+1/x g=g*x a=a+x/s r=r+x^2/s end print(s/h,g^(1/s),a,r^.5,r/a)

Languages - 1


def input = [1.7,17.3,3.14,24,2.718,1.618];
def arithmeticMean
def harmonicMean
def geometricMean
def quadraticMean
def contraharmonicMean

def sum = 0
def product = 1
// Arithmetic Mean
for(each in input){
    sum += each
arithmeticMean = sum / input.size()

// Harmonic Mean
sum = 0
for(each in input){
    sum += (1/each)
harmonicMean = input.size() / sum

// Geometric Mean
for(each in input){
    product *= each
geometricMean = Math.pow(product,1/input.size());

// Quadratic Mean
sum = 0
for(each in input){
    sum += (each*each)
quadraticMean = Math.pow(sum/input.size() ,(1/2))

// Contraharmonic Mean
sum = 0
def sum2 = 0
for( each in input ){
    sum += each
    sum2 += (each * each)
contraharmonicMean = (sum2/input.size()) / (sum/input.size())

println "Arithmetic Mean: $arithmeticMean"
println "Harmonic Mean: $harmonicMean"
println "Geometric Mean: $geometricMean"
println "Quadratic Mean: $quadraticMean"
println "Contraharmoic Mean: $contraharmonicMean"
  • 5
    \$\begingroup\$ The aim is to write the shortest possible code for each language, so you probably want to use single-character identifiers and omit whitespace where possible. \$\endgroup\$ – Peter Taylor Sep 2 '14 at 22:06
  • 1
    \$\begingroup\$ @PeterTaylor Oh, okay! Didn't know that. New here. \$\endgroup\$ – Little Child Sep 3 '14 at 7:21
  • \$\begingroup\$ @LittleChild Feel free to edit your code to be as short as possible. Don't forget to write the number of characters you used at the top of your post. \$\endgroup\$ – mbomb007 Jan 21 '15 at 19:33

2 Languages

Java - 243 bytes

class M{public static void main(String[]a){float h=0,l=a.length,p=1,s=0,q=0;for(int i=0;i<l;i++){float v=Float.valueOf(a[i]);q+=v*v;s+=v;h+=1/v;p*=v;}System.out.println(l/h+"\n"+Math.pow(p,1.0/l)+"\n"+s/l+"\n"+Math.sqrt((1.0/l)*q)+"\n"+q/s);}}


class Means {
    public static void main(String[] a) {
        float h = 0, l = a.length, p = 1, s = 0, q = 0;
        for (int i = 0; i < l; i++) {
            float v = Float.valueOf(a[i]);
            q += v * v;
            s += v;
            h += 1 / v;
            p *= v;
        System.out.println(l / h + "\n" + Math.pow(p, 1.0 / l) + "\n" + s / l
                + "\n" + Math.sqrt((1.0 / l) * q) + "\n" + q / s);

vba - excel, 387 bytes

Fill in values in the first column, then press the button (that triggers this code) and it outputs the values in the second column.

Private Sub a_Click()
Dim d,s,q,h,p As Double
Dim y As Integer
While Not IsEmpty(Cells(y,1))
End Sub

1 language

Rust - 469

(rustc 0.11.0-pre (3851d68 2014-06-13 22:46:35 +0000))

use std::io;use std::from_str::from_str;use std::num;fn main(){loop{let a:Vec<f64>=io::stdin().read_line().ok().expect("").as_slice().split(',').map(|x|std::from_str::from_str(x.trim_chars('\n')).expect("")).collect();let n:f64=num::from_uint(a.len()).expect("");let s=a.iter().fold(0.0,|a,b|a+*b);let q=a.iter().fold(0.0,|a,b|a+*b* *b);println!("{},{},{},{},{}",n / a.iter().fold(0.0,|a,b|a+1.0/ *b),(a.iter().fold(1.0,|a,b|a**b)).powf(1.0/n),s/n,(q/n).sqrt(),q/s,);}}

Ungolfed version:

use std::io;
use std::from_str::from_str;
use std::num;

fn main() {
    loop {
        let a : Vec<f64>  = io::stdin().read_line().ok().expect("").as_slice().split(',')
        let n : f64 = num::from_uint(a.len()).expect("");
        let s = a.iter().fold(0.0, |a, b| a + *b);
        let q = a.iter().fold(0.0, |a, b| a + *b * *b);
                 n / a.iter().fold(0.0, |a, b| a + 1.0 / *b),
                 (a.iter().fold(1.0, |a, b| a * *b)).powf(1.0/n),
                 s / n,
                 (q / n).sqrt(),
                 q / s,

Compacted 430-byte version without loop or input, for testing in playrust:

use std::from_str::from_str;use std::num;fn main(){let a:Vec<f64>="1,2,3,4".as_slice().split(',').map(|x|std::from_str::from_str(x.trim_chars('\n')).expect("")).collect();let n:f64=num::from_uint(a.len()).expect("");let s=a.iter().fold(0.0,|a,b|a+*b);let q=a.iter().fold(0.0,|a,b|a+*b**b);println!("{},{},{},{},{}",n / a.iter().fold(0.0, |a, b| a + 1.0 / *b),(a.iter().fold(1.0, |a, b| a * *b)).powf(1.0/n),s/n,(q/n).sqrt(),q/s);}

Updated for newer Rust:


use std::io;                 
fn main(){
    let mut s=String::new();
    io::stdin().read_line(&mut s);
    let a:Vec<f64>=s
    let n:f64=a.len() as f64;
    let s=a.iter().fold(0.0,|a,b|a+*b);
    let q=a.iter().fold(0.0,|a,b|a+*b**b);
        n / a.iter().fold(0.0, |a, b| a + 1.0 / *b),
        (a.iter().fold(1.0, |a, b| a * *b)).powf(1.0/n),s/n,

Golfed (402 bytes):

use std::io;fn main(){ let mut s=String::new(); io::stdin().read_line(&mut s); let a:Vec<f64>=s .split(',') .map(|x|x.trim().parse().expect("")) .collect(); let n:f64=a.len() as f64; let s=a.iter().fold(0.0,|a,b|a+*b); let q=a.iter().fold(0.0,|a,b|a+*b**b); println!("{},{},{},{},{}", n / a.iter().fold(0.0, |a, b| a + 1.0 / *b), (a.iter().fold(1.0, |a, b| a * *b)).powf(1.0/n),s/n, (q/n).sqrt(),q/s);}

Languages: 4

CoffeeScript, 193

Takes a comma-separated string of input:

m=(q)->m=Math;q.r=q.reduce;q=q.split(',').map Number;l=q.length;x=q.r ((p,v)->(p+v)),0;y=q.r ((p,v)->(p+v*v)),0;[l/q.r(((p,v)->(p+1/v)),0),m.pow(q.r(((p,v)->(p*v)),1),1/l),x/l,m.sqrt(y/l),y/x];

JavaScript (ES5), 256

Again, takes a comma-separated string of input:

function m(q){m=Math,q=q.split(',').map(Number),q.r=q.reduce,l=q.length,x=q.r(function(p, v){return p+v;},0),y=q.r(function(p,v){return p+v*v},0);return[l/q.r(function(p,v){return p+1/v},0),m.pow(q.r(function(p,v){return p*v},1),1/l),x/l,m.sqrt(y /l),y/x]}

PHP, 252

Same concept:

<?function m($q){$r=array_reduce;$q=explode(',',$q);$l=count($q);$x=array_sum($q);$y=$r($q,function($p,$v){return $p+$v*$v;});return[$l/$r($q,function($p,$v){return $p+1/$v;}),pow($r($q,function($p,$v){return $p*$v;},1),1/$l),$x/$l,sqrt($y/$l),$y/$x];}

TypeScript, 393*

Since TypeScript is a superset of JavaScript, I could have just submitted the same code but that wouldn't really be fair now. Here's a minified TypeScript code with all functions, variables, and parameters fully typed:

function m(q:String):number[]{var a:number[]=q.split(',').map(Number),l:number=a.length,x:number=a.reduce(function(p:number,v:number):number{return p+v},0),y:number=a.reduce(function(p:number,v:number):number{return p+v*v},0);return[l/a.reduce(function(p:number,v:number):number{return p+1/v},0),Math.pow(a.reduce(function(p:number,v:number):number{return p*v},1),1/l),x/l,Math.sqrt(y/l),y/x]}

Could have cheated and used the type any as well... but, you know.


Excel - 120

Not sure if this counts as a "programming" language, but thought people may actually use a spreadsheet for this type of thing

With the numbers in A2:J2

L2 (harmonic) =HARMEAN(A2:J2)
M2 (geometric) =GEOMEAN(A2:J2)
N2 (arithmetic) =AVERAGE(A2:J2)
O2 (quadratic) =SQRT(SUMSQ(A2:J2)/COUNT(A2:J2))
P2 (contraharmonic) =(SUMSQ(A2:J2)/COUNT(A2:J2))/AVERAGE(A2:J2)
  • 1
    \$\begingroup\$ I don't have Excel, but I think you can use the range A:A to target the entire column A. \$\endgroup\$ – Dennis Sep 6 '14 at 4:21

VBA (Excel) - 105

a=1:for each n in i:a=a*n:b=b+1/n:c=c+n:d=d+n*n:next:x=ubound(i)+1:?x/b","a^(1/x)","c/x","(d/x)^0.5","d/c

Ungolfed :

a=1:               set a variable to 1 (for the geometric mean)
for each n in i:   loop through the list
    a=a*n:            product of the list
    b=b+1/n:          sum of inverses of the list
    c=c+n:            sum of the list
    d=d+n*n:          sum of squares of the list
next:              end loop
x=ubound(i)+1:     get the number of elements in the list
?                  prepare to print
 x/b","               harmonic = count / sum(inverses)
 a^(1/x)","           geometric = product^(1/count)
 c/x","               arithmetic = sum / count
 (d/x)^0.5","         quadratic = square root of ( sum of squares / count )
 d/c                  contraharmonic = sum of squares / sum

This code has to be run in the immediate window, and the array must be called i. Since there is no error collection, no cleaning, no variable dropping/releasing, if you want to test this code you can use the following piece of code (just paste in the immediate window and run the lines in order) :

b=0:c=0:d=0:set i = nothing:i= array(1,2,3,4,5)
a=1:for each n in i:a=a*n:b=b+1/n:c=c+n:d=d+n*n:next:x=ubound(i)+1:?x/b","a^(1/x)","c/x","(d/x)^0.5","d/c

Nothing very special, just the choice to use the immediate window with : to replace line breaks, which saves a few bytes vs setting up a sub or function and closing it; using ? to print rather than debug.print (only in the immediate window); and relying on how vba determines implicit values (adding a value to an un-set variable returns the value) and implicit operations (anything involving a string is implicitly concatenation).


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.