I wrote a code that separates the numbers from 1 to 9999 by comma
void p(n){printf("%d,",n);if(n<9999){p(n+1);}}main(){p(1);}
Is there a way to make this short code without using a repeat statement?
\$\begingroup\$
\$\endgroup\$
1
-
21\$\begingroup\$ Welcome to Code Golf! Just a word of caution: we'll do anything we can on this site to save a single byte, which usually leads to terrible code that should not be actually used for anything serious. \$\endgroup\$– ArnauldOct 24 at 10:17
Add a comment
|
7 Answers
\$\begingroup\$
\$\endgroup\$
7
C (gcc), 40 bytes by Sisyphus, exit by stack overflow
i;main(){main(dprintf(i++<9999,"%d,"));}
C (gcc), 41 bytes by dingledooper
i;main(){++i<1e4&&main(printf("%d,",i));}
C (gcc), 42 bytes, original
main(i){i<1e4&&main(i+1,printf("%d,",i));}
main can be used to recurse
-
4\$\begingroup\$ 41:
n;main(){++n<1e4&&main(printf("%d,",n));}\$\endgroup\$ Oct 24 at 6:33 -
3\$\begingroup\$ 39;
main(i){for(;i<1e4;)printf("%d,",i++);}\$\endgroup\$ Oct 24 at 19:10 -
1\$\begingroup\$ @HudsonGraeme I follow rule
without using a repeat statement?\$\endgroup\$– l4m2Oct 25 at 0:29 -
1\$\begingroup\$ 40:
i;main(){main(dprintf(i++<9999,"%d,"));}\$\endgroup\$– SisyphusOct 25 at 6:25 -
2\$\begingroup\$ "exit by stack overflow" That phrase just embodies everything I love about this site so well. \$\endgroup\$ Oct 27 at 1:02
\$\begingroup\$
\$\endgroup\$
5
-
-
1\$\begingroup\$ That's what I started with, then for some reason, I thought it needed a space after the commas. \$\endgroup\$– AShellyOct 24 at 20:47
-
-
-
\$\begingroup\$ OpenBSD and supposedly NetBSD have a seq command also, and it supports the s option. \$\endgroup\$ Oct 25 at 8:08
\$\begingroup\$
\$\endgroup\$
7
Python 3, 30 bytes by Karl Knechtel
print(*range(1,10000),sep=',')
Python 3, 36 bytes by onetoinfinity
print(str(list(range(10000)))[4:-1])
Python 3, 39 bytes by UndoneStudios
i=0
while i<1e5:print(end='%d,'%i);i+=1
Python 3, 40 bytes by Lemon
print(",".join(map(str,range(1,10000))))
-
-
\$\begingroup\$ range end is exclusive so you need 10000 or it will only print up to 9998 \$\endgroup\$– rbntdOct 26 at 7:41
-
-
-
1
\$\begingroup\$
\$\endgroup\$
1
C# 71 bytes
Console.WriteLine(string.Join(",",Enumerable.Range(1, 999).ToList()));
Saved 14 bytes thanks to Jupotters comment
Console.Write(string.Join(",",Enumerable.Range(1,9999)));
-
1\$\begingroup\$ 57:
Console.Write(string.Join(",",Enumerable.Range(1,9999)));\$\endgroup\$– JupotterOct 25 at 14:11
\$\begingroup\$
\$\endgroup\$
\$\begingroup\$
Haskell,
\$\endgroup\$
Haskell, 36 35 bytes
main=putStr.init.tail$show[1..9999]
Old version
main=putStr.init.tail.show$[1..9999]
\$\begingroup\$
\$\endgroup\$
Wolfram Language (Mathematica), 27 bytes
Range@9999~StringRiffle~","
Range@9999 (10 bytes) almost does it...
