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You want to send an ASCII letter to someone, but you need an envelope to put it in. Your task is to output an envelope given a size as input.

Rules:

  • Given positive integer input i, your envelope will be i characters tall (not counting the top row), and i*2 characters wide (not counting the side columns). In other words, your envelope will be i+1 characters tall and (i*2)+2 characters wide.
  • Output must be in the form of text, using \, /, _, |, and .
  • The flap of the envelope must be on the row above the bottom row of the envelope unless impossible (as with an envelope of size 1).
  • Trailing whitespace is allowed.

Example input and output:

1
->
 __
|\/|

2
->
 ____
|\__/|
|____|

3
->
 ______
|\    /|
| \__/ |
|______|

4
->
 ________
|\      /|
| \    / |
|  \__/  |
|________|

This is a challenge, so shortest code wins!

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0

9 Answers 9

4
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Python 3, 207 181 180 177 146 130 bytes

lambda i,u="__",b=" ":b+u*i+"".join(f"\n|{b*x}\{(b*(i*2+~x*2),u)[x==i-2]}/{b*x}|"for x in range(i-1))+("\n|\/|",f"\n|{u*i}|")[i>1]

Try it online!

To 181 bytes: Golfed the code even more thanks to @Kevin Cruijssen.

To 180 bytes: -1 bytes thanks again to @Kevin Cruijssen, by replacing the i!=1 with i<2.

To 177 bytes: Moved the whole "nonsense soup" line onto the same line as the for loop, thanks to @des54321's suggestion.

To 146 bytes: Some major byte-saving golfs thanks to @ElPedro.

To 130 bytes: More golfs by @Kevin Cruijssen, including replacing \\ with \.

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14
  • 1
    \$\begingroup\$ 181 bytes with some golfs :) The u,b declaration is a single line to save a byte; the if/else are both single lines with and/or to save byes; and the (i*2)-(x*2)-2 (for which you don't need the parenthesis) is i*2+~x*2 to save some bytes (~x is -x-1 btw). \$\endgroup\$ Mar 24 at 22:20
  • 1
    \$\begingroup\$ One more small golf for -1: s+(i!=1and f"|{u*i*2}|"or"|\\/|") can be s+(i<2and"|\\/|"or f"|{u*i*2}|") \$\endgroup\$ Mar 25 at 7:40
  • 2
    \$\begingroup\$ After @ElPedro golfs everything can be put onto a single line and you can use a lambda for 134 bytes. \$\endgroup\$ Mar 29 at 14:29
  • 2
    \$\begingroup\$ 130 bytes by replacing both \\ with \ (apparently they don't have to be escaped in Python's strings depending on the character behind it). \$\endgroup\$ Mar 29 at 14:33
  • 2
    \$\begingroup\$ @KevinCruijssen - I guessed you'd be back! Thanks for finishing it off for me. Was busy this afternoon :) Didn't know that about the \\ in f-strings. Learned something new today. Thanks. \$\endgroup\$
    – ElPedro
    Mar 29 at 15:23
3
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05AB1E, 41 bytes

i'_„|\‚ë2ÊiÍFðI×'\Nǝ}}„\_Ij¤Iש)'|쮚}º.c

Try it online or verify the first few outputs.

Expanation:

i              # If the (implicit) input is 1:
 '|„|\‚       '#  Push pair of strings ["_","|\"]
ë              # Else:
 2Êi           #  If the (implicit) input is NOT 2:
    ÍF         #   Loop `N` in the range [0,input-2):
      ðI×      #    Push a string with the input amount of spaces
         '\Nǝ '#    Insert a "\" character at index `N`
     }         #   Close the loop
   }           #  Close the inner if-statement
„\_            #  Push string "\_"
   Ij          #  Pad leading spaces until the string is of a length equal to the input
     ¤         #  Push the last character (without popping): "_"
      I×       #  Repeat it the input amount of times as string
        ©      #  Store it in variable `®` (without popping)
)              #  Wrap all values on the stack into a list
 '|ì          '#  Prepend a "|" in front of each string
    ®š         #  Prepend string `®` to the list
}              # Close the outer if-else statement
 º             # Mirror each inner string
  .c           # Join by newlines and centralize
               # (adding a single leading space to the first "_"-string)
               # (after which the result is output implicitly)
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1
  • 13
    \$\begingroup\$ Congrats on reaching 100k! \$\endgroup\$
    – ophact
    Mar 24 at 16:09
3
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Vyxal C, 49 bytes

1=[\_‛|\"|2≠[⇩ʁ(⁰Ifn\\Ȧ¤j)]‛\_⁰r:t⁰ẋ:£W\|vp¥p]vøṀ

Try it Online!

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2
  • \$\begingroup\$ Doesn't work, draws backslashes instead of slashes \$\endgroup\$
    – allxy
    Apr 30 at 22:43
  • \$\begingroup\$ @allxy Fixed and shavead off a couple more bytes. \$\endgroup\$
    – Steffan
    May 1 at 0:44
2
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Charcoal, 28 bytes

Nθ←×_θ↑θ→P×_θ↓¿⊖θ«↘⊖θ←¶_»\‖M

Try it online! Link is to verbose version of code. Explanation:

Nθ

Input i.

←×_θ

Draw half of the bottom row of _s.

↑θ

Draw the left column of |s.

→P×_θ↓

Draw the top row of _s.

¿⊖θ«

If i is not 1, then...

↘⊖θ←¶_

... draw the i-1 \s on the left and one of the two middle _s, ...

»\

... otherwise overwrite the bottom _ with a \.

‖M

Reflect to complete the envelope.

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2
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Javascript, 181 177 174 Bytes

Code is split into newlines for readability, see link for 174 byte string.

c=n=>{
r=(d,n)=>d.repeat(n);
z='\n|';
b=r('_',n*2);
o=' '+b;
for(e=0;e<n-1;e++)y=r(' ',e),o+=z+y+'\\'+r(e!=n-2?' ':'_',n*2-2*(e+1))+'/'+y+'|';
o+=(n==1?z+'\\/|':z+b+'|');
return o;}

Try me online.

  • Saved 4 bytes pulling \n| into a variable z
  • Saved 3 bytes pulling r(' ',e) into y every loop

I'm not too happy with my performance here, especially the implicit check I had to do to get the i=1 output working, but oh well.

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1
  • \$\begingroup\$ Just so you know, readability doesn't matter in this case, so you can make it as unreadable as you like ;-)! The goal is to have it as golfed as possible. \$\endgroup\$ Apr 23 at 23:58
2
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Vyxal o, 37 bytes

\_*:£ðpm,ċ[ɽ‹\\꘍ṫ\_+J↲¥J\|vpvøṀ⁋|‛|\m

Try it Online!

\_*                                   # <input> copies of _
   :£                                 # Duplicate and set gregister
     ðpm,                             # Prepend a space and print mirrored
         ċ[                     |‛|\m # If it's 1, print `|\/|`, else:
           ɽ‹                         # 0...n-1
             \\꘍                      # For each, prepend that many spaces to an underscore
                ṫ   J                 # To the last...
                 \_+                  # Append an underscore
                     ↲                # Pad all of that to length n
                      ¥J              # Append the underscores that we stored in the register earlier
                        \|vp          # Prepend a | to each
                            vøṀ⁋      # Mirror and print
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2
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Python 3.8 (pre-release), 107 bytes

lambda n:[' '+(a:="__"*n)]+['|%s|'%[a," "*i+f'\{"_ "[i<n-2]*2*(n+~i)}/'+" "*i][i<n-(n>2)]for i in range(n)]

Try it online!

-20 by @emanresuA

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1
  • \$\begingroup\$ You can save a bunch by outputting as a list of lines, which opens up a whole host of golfing oppurtunities - 107 bytes. \$\endgroup\$
    – emanresu A
    May 1 at 10:04
1
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Perl 5 + -M5.10.0 -a, 98 bytes

say$".__ x$_,map{'
|',/@F/*($#a=$_-1)?__ x$_.'|':"@a\\".($_<"@F"-1?'  ':__)x("@F"-$_)."/@a|"}1..$_

Try it online!

Currently on mobile (in a rainy field!) so I'll add an explanation later!

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1
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05AB1E, 68 bytes

ð'_IиJJÂJUX,I<F'|ðNи'\N>I<Qi'_ëð}IN-<·и'/ðNи'|JJ,}I2‹i"|\/|"ëXð'|:},

Try it online!

Explanation:

ð              Push space
'_Iи           Push I underscores (I = input)
JJÂJ           Push reverse of that
UX,            Put that in X and print it
I<F            Loop from 1 to N-1 (N = index)
  '|           Push '|' (pipe)
  ðNи          Push N spaces
  '\           Push '\' (backslash)
  N>I<Qi'_     If N+1 == I-1, push _ (underscore)
    ëð}        Otherwise push space
  IN-<·и       Pop and repeat that by (I-N-1)*2
  '/           Push '/' (slash)
  ðNи          Push N spaces
  '|           Push '|' (pipe)
  JJ,          Join and print
}      
I2‹i"|\/|"     If I == 1, push '|\/|'
  ëXð'|:}      Otherwise, push X with spaces replaced with pipes
,              Print
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