Building spikes

Question

Inspired by this building (United States Air Force Academy Cadet Chapel, Colorado)

Your task is simple, given a positive integer n, output the spiked building to size n

Testcases

1
->
   ^
  /|\
 /.|.\
/..|..\
_______


2
->
   ^  ^
  /|\/|\
 /.|..|.\
/..|..|..\
__________


7
->
   ^  ^  ^  ^  ^  ^  ^
  /|\/|\/|\/|\/|\/|\/|\
 /.|..|..|..|..|..|..|.\
/..|..|..|..|..|..|..|..\
_________________________

Trailing spaces are allowed

You are to output the string with newlines

This is code-golf, so shortest code wins!

What should it look like for 0? Should we just not output anything? — Lecdi, Mar 10 at 7:29
You said "nonnegative integer" in the challenge, which includes 0. Maybe change that to "positive integer" — Lecdi, Mar 10 at 8:21

tsh · Accepted Answer · 2022-03-10 10:51:53Z

10

JavaScript (Node.js), 80 bytes

n=>`   ^ 
  /|\\
 /.|.\\
/..|..\\
___`.replace(/.[_|^]./g,'$&'.repeat(n))+'____'

Try it online!

edited Mar 10 at 10:51

answered Mar 10 at 5:25

tsh

28.6k2 gold badges31 silver badges108 bronze badges

3

\$\begingroup\$ brilliant! this is a really smart solution :D \$\endgroup\$
– DialFrost
Mar 10 at 5:46

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DialFrost · Accepted Answer · 2022-04-12 06:41:55Z

7

Python 3.8 (pre-release), 81 bytes

lambda n:f" {'  ^'*n}\n  "+'/|\\'*n+'\n /'+(d:='.|.'*n)+rf'\
/.{d}.\
_'+'_'*3*-~n

Try it online!

Thanks @UnrelatedString for -3 bytes, by teaching me about the rf string literal. Thanks @AidenChow for -1 byte, by adding another f-string. Thanks @tsh for -1 byte.

Wow, looks like this has become a bit of a community effort.

edited Apr 12 at 6:41

DialFrost

3,0312 gold badges5 silver badges46 bronze badges

answered Mar 10 at 8:04

ophact

2,6591 gold badge2 silver badges22 bronze badges

2

\$\begingroup\$ You, my friend, are a genius of python 3.8! \$\endgroup\$
– DialFrost
Mar 10 at 8:07
\$\begingroup\$ ...this is the first I've ever even thought about this, but looks like raw string literals handle backslash-newline perfectly here \$\endgroup\$
– Unrelated String
Mar 10 at 8:16
1

\$\begingroup\$ @UnrelatedString Wow, I've never seen rf string literals before. You learn something new every day... \$\endgroup\$
– ophact
Mar 10 at 8:20
1

\$\begingroup\$ 82 bytes using another f-string at the beginning. \$\endgroup\$
– Aiden Chow
Mar 10 at 8:29
3

\$\begingroup\$ '+'_'*(3*n+4) could be _'+'_'*3*-~n \$\endgroup\$
– tsh
Mar 10 at 8:47

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emanresu A · Accepted Answer · 2022-03-11 08:34:28Z

Vyxal, 30 bytes

»ε¥»₄τ2?»øƒ≈»₇τẋṀf`|^/\.`τ\_+§

Try it Online!

Modified port of the Jelly answer.

»ε¥»₄τ                         # [2, 14, 19, 3]
      2         Ṁ              # Insert at position 2...
        »øƒ≈»₇τ                # [74, 125, 99]
       ?       ẋ               # Repeated <input> times
                 f             # Flatten the whole thing
                  `|^/\.`τ     # Decompress each from base with the key "|^/\."
                          \_+  # Append an underscore to each
                             § # Transpose, fill and join by newlines.

Old version below because I thought it was quite elegant.

Vyxal `C`, 42 bytes

` ^
/|
.|
.|
__`øM↵*` 
 
/
/.
__`øṀ↵½Zƛ÷$j

Try it Online!

This is quite elegant but somewhat messy approach. I'm unsatisfied with the last bit, vj should work but it doesn't.

The first bit produces the string

 ^ 
/|\
.|.
.|.
___

Then repeats each row of that by the input.

Then, it creates



/\
/..\
____

by mirroring half of each line, and inserts the previous into that. Finally, the whole thing is centered.

Jonathan Allan · Accepted Answer · 2022-03-11 00:16:03Z

Jelly, 30 bytes

“\ɓ^‘ẋ“£×“Œ¥‘jṃ“|/.\^””_;Ɱz⁶ṚY

Try it online!

How?

“\ɓ^‘ẋ“£×“Œ¥‘jṃ“|/.\^””_;Ɱz⁶ṚY - Main Link: integer, N
“\ɓ^‘                          - Code-page indices = [92, 155, 94]
     ẋ                         - repeat N times
      “£×“Œ¥‘                  - Code-page indices = [[2, 17], [19, 4]]
             j                 - join -> [2, 17, 92, 155, 94, ..., 92, 155, 94, 19, 4]
               “|/.\^”         - list of characters = "|/.\^"
              ṃ                - convert to base 5 using "|/.\^" in place of the digits 12340
                         Ɱ     - map across these lists of characters with:
                      ”_;      -   concatenate to an '_' character
                          z⁶   - transpose with space characters as filler
                            Ṛ  - reverse
                             Y - join with newlines
                               - implicit print

Neil · Accepted Answer · 2022-03-10 08:54:09Z

3

Charcoal, 30 bytes

_/¶_./¶×“ ∧σ¿⊘=8G℅H«⊙”Ｎ_.\¶_\⟲

Try it online! Link is to verbose version of code. Explanation:

_/¶_./¶

Print the first two columns.

×“ ∧σ¿⊘=8G℅H«⊙”Ｎ

Print the middle columns repeated the appropriate number of times.

_.\¶_\

Print the last two columns.

⟲

Rotate to orient the output correctly.

answered Mar 10 at 8:54

Neil

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sinvec · Accepted Answer · 2022-03-10 10:17:22Z

3

Python 3, ^{124 91 90} 88 bytes

lambda n:[print(('   /_  /._'+' /.._^|||_ \.._'*n+'  \._   \_')[i::5])for i in range(5)]

Try it online!

edited Mar 10 at 10:17

answered Mar 10 at 6:12

sinvec

1,5552 silver badges26 bronze badges

1

\$\begingroup\$ 91: lambda n:[print((' /_ /._'+' /.._^|||_ \\.._'*n+' \\._ \\_')[i::5])for i in range(5)] \$\endgroup\$
– tsh
Mar 10 at 6:25
1

\$\begingroup\$ Save one more byte with an r-string \$\endgroup\$
– emanresu A
Mar 10 at 8:19

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Graham · Accepted Answer · 2022-03-10 15:09:47Z

3

APL+WIN, 88 73 bytes

Prompts for spikes.

Original

l←5 2⍴¯10↑'//.__'⋄c←5 3⍴' ^ /|\.|..|.___'⋄r←5 2⍴¯10↑'\ .\__'⋄⊃⊂[2]⍎'l,',((2×⎕)⍴'c,'),'r'

A simpler iindexing solution

m←5 7⍴'   ^     /|\   /.|.\ /..|..\_______'⋄m[;⍳2],m[;(3×⎕)⍴2+⍳3],m[;6 7]

Try it online! Thanks to Dyalog APL Classic

edited Mar 10 at 15:09

answered Mar 10 at 8:56

Graham

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AZTECCO · Accepted Answer · 2022-03-10 21:50:55Z

3

Ruby, 69 bytes

->n{'   ^ 
  /|\
 /.|.\
/..|..\
_______'.lines.each{|l|l[2,3]*=n}*''}

Try it online!

Lambda tacking n that multiplies inner substring n times for each line of the spike.

edited Mar 10 at 21:50

answered Mar 10 at 21:31

AZTECCO

9,4261 gold badge11 silver badges52 bronze badges

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Kevin Cruijssen · Accepted Answer · 2022-03-11 07:50:42Z

05AB1E, 42 41 35 bytes

Y17•₅œ •₅вIи19Y·)˜"^|/.\"Åв'_δšζRJ»

-6 bytes porting @JonathanAllan's Jelly answer

Try it online or verify the first 10 test cases.

See the previous revision for the original 42 and 41 bytes approaches.

Explanation:

Y              # Push 2
17             # Push 17
•₅œ •          # Push compressed 6021919
     ₅в        # Convert it to base-255 as list: [92,155,94]
       Iи      # Repeat this list the input amount of times
19             # Push 19
Y·             # Push 4 (2 doubled)
 )             # Wrap the stack into a list
  ˜            # Flatten
   "^|/.\"Åв  "# Convert it to custom base-"^|/.\"
               # (basically base-length, and then index into the string)
  δ            # Map over each inner list:
'_ š          '#  Prepend a "_" to each
    ζ          # Zip/transpose; swapping rows/columns, with a space " " as
               # default filler
     R         # Reverse the list of lists
      J        # Join each inner list together to a string
       »       # Join by newlines
               # (after which the result is output implicitly)

See this 05AB1E tip of mine (section How to compress large integers? and How to compress integer lists?) to understand why •₅œ • is 6021919 and •₅œ •₅в is [92,155,94].

Neil · Accepted Answer · 2022-03-11 01:17:42Z

2

Retina, 64 63 bytes

.+
 $&*$(  ^)¶  $&*$(/|\)¶ /$&*$(.|.)\¶/.$&*$(.|.).\¶__$&*3*___

Try it online! Link includes test cases. Explanation: Just an application of Retina 1's string repetition operator. Note that repetition has higher precedence than concatenation so the string to be repeated has to be grouped (except in the case of repeating three _s which is achieved via a second repetition).

edited Mar 11 at 1:17

answered Mar 10 at 8:58

Neil

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DLosc · Accepted Answer · 2022-03-11 20:48:38Z

2

Regenerate, 61 bytes

  ( ^ ){$~1}
  (/\|\\){$~1}
 /((.\|.){$~1})\\
/.$3.\\
_{#3+4}

Attempt This Online!

Explanation

$~1 is the input number, and {$~1} repeats something that many times. So:

  ( ^ ){$~1}

Two spaces, followed by ^ N times.

  (/\|\\){$~1}

Two spaces, followed by /|\ N times.

 /((.\|.){$~1})\\

/, followed by .|. N times (and capture that result as group 3), followed by \.

/.$3.\\

/., followed by the contents of group 3 again, followed by .\.

_{#3+4}

_ repeated len(group 3) + 4 times.

edited Mar 11 at 20:48

answered Mar 11 at 18:18

DLosc

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\$\begingroup\$ I think it's meant to be _ at the end? \$\endgroup\$
– emanresu A
Mar 11 at 20:11
\$\begingroup\$ @emanresuA Fixed, thanks. \$\endgroup\$
– DLosc
Mar 11 at 20:49

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coltim · Accepted Answer · 2022-03-10 15:14:19Z

1

K (ngn/k), 76 66 bytes

{`0:+?[4 4#"   /  /.  \\.   \\";2;,/(x,3 4)#" /..^||| \\.."],'"_"}

Try it online!

?[a;2;b] use splice to insert b into a at position 2
- 4 4#" / /. \\. \\" the initial array, representing the "sides" of the spiked building
- ,/(x,3 4)#" /..^||| \\.." x copies of the spikes
?[;;],"_" append a "_" to each slice
`0:+ transpose the above, and print to stdout

edited Mar 10 at 15:14

answered Mar 10 at 14:20

coltim

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DLosc · Accepted Answer · 2022-03-11 20:50:42Z

Pip, 46 bytes

FlRsX,4.:"/\"J'|WR'.X,3PE'^AE'_X7{(l2,5)X:aPl}

Attempt This Online!

Explanation

First, we generate this list

["   ^"
 "  /|\"
 " /.|.\"
 "/..|..\"
 "_______"]

as follows:

RsX,4.:"/\"J'|WR'.X,3PE'^AE'_X7
                   ,3            ; Range(3): [0;1;2]
                '.X              ; Repeat . that many times: ["";".";".."]
            '|WR                 ; Wrap | in each of those strings: ["|";".|.";"..|.."]
       "/\"J                     ; Insert each of those strings between / and \:
                                 ; ["/|\";"/.|.\";"/..|..\"]
                     PE'^        ; Prepend "^" to the front of that list
                         AE'_X7  ; and append "_______" to the end:
                                 ; ["^";"/|\";"/.|.\";"/..|..\";"_______"]
   ,4                            ; Range(4): [0;1;2;3]
 sX                              ; Repeat space that many times: ["";" ";"  ";"   "]
R                                ; Reverse: ["   ";"  ";" ";""]
     .:                          ; Concatenate those two lists itemwise:
                                 ; ["   ^";"  /|\";" /.|.\";"/..|..\";"_______"]

Then we loop over each line, repeat the center section, and print the result:

Fl...{(l2,5)X:aPl}
Fl   {           }  ; For each line l
  ...               ; in the above list:
      (l   )        ;   The section of l
        2,5         ;   at indices range(2,5) i.e. [2;3;4] (modular 0-based indexing)
            X:      ;   string-repeat in place
              a     ;   (program argument) times
               Pl   ;   Print (the modified version of) l with a trailing newline

twentysix · Accepted Answer · 2022-03-17 17:08:07Z

1

Lua, 92 bytes

print(([[   ^ 
  /|\
 /.|.\
/..|..\
]]):gsub(".[_|^].",("%1"):rep(...))..('_'):rep(4+3*...))

Attempt This Online! I feel like it can go a bit lower but don't want to play with it right now. Basically? a port of tsh's answer but with the underscores outside the initial string.

answered Mar 17 at 17:08

twentysix

4091 silver badge4 bronze badges

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Neil · Accepted Answer · 2022-03-11 01:16:23Z

0

Retina 0.8.2, 70 bytes

.+
 $&$*1¶  $&$*2¶ /$&$*3\¶/.$&$*3.\¶__$&$*4__
1
  ^
2
/|\
3
.|.
4
___

Try it online! Link includes test cases. Explanation: Since Retina 0.8.2 can only repeat characters, placeholder digits are used for the four different building parts which are then substituted in afterwards.

answered Mar 11 at 1:16

Neil

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Ethan Chapman · Accepted Answer · 2022-03-11 03:38:12Z

CJam, 66 bytes

ri:R;SSSa"^  "R*NSS"/|\\"R*NS'/".|.":QR*'\N"/."QR*".\\"N'_"___"R)*

Try it online! I haven't golfed for a while, and longer since CJam, so this probably has significant optimizations available, but I was in the mood to try something. It basically just constructs the result line by line, with a couple minor optimizations by saving the size as a variable, saving the ".|." construction as a variable since we re-use it, and using 3(n+1)+1 instead of 3n+4 to construct the bottom row.

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Building spikes

Testcases

16 Answers 16

JavaScript (Node.js), 80 bytes

Python 3.8 (pre-release), 81 bytes

Vyxal, 30 bytes

Vyxal `C`, 42 bytes

Jelly, 30 bytes

How?

Charcoal, 30 bytes

Python 3, ^{124 91 90} 88 bytes

APL+WIN, 88 73 bytes

Ruby, 69 bytes

05AB1E, 42 41 35 bytes

Retina, 64 63 bytes

Regenerate, 61 bytes

Explanation

K (ngn/k), 76 66 bytes

Pip, 46 bytes

Explanation

Lua, 92 bytes

Retina 0.8.2, 70 bytes

CJam, 66 bytes

Your Answer

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Building spikes

Testcases

16 Answers 16

JavaScript (Node.js), 80 bytes

Python 3.8 (pre-release), 81 bytes

Vyxal, 30 bytes

Vyxal C, 42 bytes

Jelly, 30 bytes

How?

Charcoal, 30 bytes

Python 3, 124 91 90 88 bytes

APL+WIN, 88 73 bytes

Ruby, 69 bytes

05AB1E, 42 41 35 bytes

Retina, 64 63 bytes

Regenerate, 61 bytes

Explanation

K (ngn/k), 76 66 bytes

Pip, 46 bytes

Explanation

Lua, 92 bytes

Retina 0.8.2, 70 bytes

CJam, 66 bytes

Your Answer

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Vyxal `C`, 42 bytes

Python 3, ^{124 91 90} 88 bytes