Which Western Zodiac sign is today?

Question

• Task:
  With the minimum amount of bytes, determine today's Zodiac sign using the programming language of your choice.
• Rules:
  This is code golf, the answer with the fewest characters wins. The initialization of getting the current date into a variable (e.g. var now = new Date();) does not add to the count. Leap years must be handled correctly.
• Limitations:
  You cannot use any other library functions for handling dates, nor predefined lists. In particular, participants would have to calculate the ordinal day of the year themselves if needed.
• Input:
  The current date in the proleptic Gregorian calendar with numeric year, month (1–12) and day of the month (1–28…31).
• Output:
  A single Unicode symbol indicating the current one of the twelve Zodiac signs from Western astrology, as used in horoscopes and listed below:

1. ♈︎ Aries: March 21 – April 19
2. ♉︎ Taurus: April 20 – May 20
3. ♊︎ Gemini: May 21 – June 21
4. ♋︎ Cancer: June 22 – July 22
5. ♌︎ Leo: July 23 – August 22
6. ♍︎ Virgo: August 23 – September 22
7. ♎︎ Libra: September 23 – October 22
8. ♏︎ Scorpio: October 23 – November 22
9. ♐︎ Sagittarius: November 23 – December 21
10. ♑︎ Capricorn: December 22 – January 19
11. ♒︎ Aquarius: January 20 – February 18
12. ♓︎ Pisces: February 19 – March 20

The actual dates might differ by one day depending on the year, but for this task the above date ranges are considered accurate for every year.

Example

The sign for today, 28 February 2022, is Pisces, so the correct output would be ♓︎.

Related challenges

• Chinese Zodiac of the year
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• ASCII Art of the Day #4 - Zodiac Signs
• What is your star-sign? – different output

Answer 1

JavaScript (Node.js),  64  62 bytes

Expects (month)(day).

This version builds the UTF-8 encoding of the code point (from 0xE2 0x99 0x88 for Aries to 0xE2 0x99 0x93 for Pisces).

m=>d=>Buffer([226,153,136+(m+=9^d<24+~"1342321"[m%12])%12])+''

Try it online!

ES6, 63 bytes

Using the more straightforward String.fromCharCode() with a direct code point is one byte longer.

m=>d=>String.fromCharCode(9800+(m+=9^d<24+~"1342321"[m%12])%12)

Try it online!

Answer 2

Jelly, 27 bytes

“£f{ẋ’b5⁸ị+19>_@⁸_3%12+⁽#1Ọ

A dyadic Link accepting an integer, month, on the left and an integer, day, on the right that yields a character.

Try it online! Or see a whole year.

How?

“£f{ẋ’b5⁸ị+19>_@⁸_3%12+⁽#1Ọ - Link: M; D
“£f{ẋ’                      - 53343748
      b5                    - to base five -> [1, 0, 2, 1, 2, 3, 4, 4, 4, 4, 4, 3]
        ⁸ị                  - get the item at 1-indexed index M
          +19               - add nineteen to it
             >              - is that greater than D? -> 1 or 0
              _@⁸           - subtract from M -> M-1 or M
                 _3         - subtract three (offset since characters start at March)
                   %12      - modulo twelve
                       ⁽#1  - 9800
                      +     - add
                          Ọ - cast to character

Answer 3

Retina 0.8.2, 112 bytes

T`d`k-m`1.-
T`d`l`.-
T`b-m`c-mb`.-3|[bce]-2|[df]-2[1-9]|[gm]-2[2-9]|[h-l]-2[3-9]|c-19
.(.).+
$1
T`e-mb-d`♈-♓

Try it online! Link includes test cases. Takes input in the format mm-dd. Does not output a Unicode variation selector, but the output looks fine in TIO to me. Explanation:

T`d`k-m`1.-

Change October to December to k to m, which will become Scorpio to Capricorn.

T`d`l`.-

Change January to September to b to j, which will become Aquarius to Libra.

T`b-m`c-mb`.-3|[bce]-2|[df]-2[1-9]|[gm]-2[2-9]|[h-l]-2[3-9]|c-19

Increment the encoded sign if the day is past the cutoff date for the next sign.

.(.).+
$1

Delete everything except the encoded sign.

T`e-mb-d`♈-♓

Decode to a Unicode Zodiac sign.

Answer 4

Charcoal, 31 bytes

Ｎθ℅⁺⁹⁸⁰⁰﹪⁺⁸⁺θ›Ｎ⁺¹⁸Ｉ§”)⊞⌊4\`ζ”θ¹²

Try it online! Link is to verbose version of code. Takes separate month and day as inputs. Explanation:

Ｎθ                           First input as a number
              Ｎ              Second input as a number
             ›               Is greater than
                    ”...”    Compressed string `310212344444`
                   §         Cyclically indexed by
                         θ   Input month
                  Ｉ          Cast to integer
               ⁺             Plus
                ¹⁸           Literal integer `18`
           ⁺                 Plus
            θ                Input month
         ⁺                   Plus
          ⁸                  Literal integer `8`
        ﹪                    Modulo
                          ¹² Literal integer `12`
   ⁺                         Plus
    ⁹⁸⁰⁰                     Literal integer `9800`
  ℅                          Convert to Unicode
                             Implicitly print