Converting to Secret Language [closed]

Question

Write some code in any language that inputs a string such as "Today is a great day" (Note that there is no punctuation) and converts it to the "Secret Language". Here are the rules for the "Secret Language".

• a=c, b=d, c=e and so on (y=a and z=b)
• separate each word by a space
• make sure there is proper capitalization

Example:

Input: "Today is a great day"

Output: "Vqfca ku c itgcv fca"

It is a popularity-contest. Other users should give points by looking for most "to the point" yet "unique" code.

CHALLENGE: I was looking up uncommon programming languages and I found a language called Piet (esolang). I challenge anyone to write it in this language.

Answer 1

C#, 163

Yes, this is not code-golf. I went for shortest anyway (or at least, made a first stab at it)

using System.Linq;class P{static void Main(string[]a){System.Console.WriteLine(string.Concat(a[0].Select(c=>(char)(c==32?c:c<89?c+2:c<91?c-24:c<121?c+2:c-24))));}}

Formatted:

using System.Linq;
class P
{
    static void Main(string[] a)
    {
        System.Console.WriteLine(string.Concat(a[0].Select(c => (char)(c == 32 ? c : c < 89 ? c + 2 : c < 91 ? c - 24 : c < 121 ? c + 2 : c - 24))));
    }
}

Yes, I did have a peek at ufis' answer.

Answer 2

C# 5KB

(381 chars)

391

using System;
namespace WinHelper {
    class P {
        static void Main(string[] args) {
            char[] f =  "abcdefghijklmnopqrstuvwxyz ".ToCharArray();
            char[] g =  "cdefghijklmnopqrstuvwxyzab ".ToCharArray();

            foreach (char c in Console.ReadLine().ToCharArray().ToLower()) 
                Console.Write(g[Array.FindIndex(f, a => a == c)]);
        }
    }
}

Answer 3

Bash, 8 characters

...if you happen to have the bsdgames package installed! Reads from standard input.

caesar 2

Example

echo Today is a great day|caesar 2

Output: Vqfca ku c itgcv fca

Answer 4

C

#include <stdio.h>
char c[100];
int main()
{
gets(c);
char *p=c,x;
while(*p)
{
    x=*p;
    if(x>='a'&&x<='z')
    {
        *p=((*p-'a'+2)%(26)+'a');
    }
    if(x>='A'&&x<='Z')
    {
        *p=((*p-'A'+2)%(26)+'A');
    }

    p++;
}
puts(c);
}

Answer 5

Brainfuck

Must have (at least) 7-bit wrapping cells to work.

+[>,>+++++[<------>-]>[<<++++++++++++++++++++++++++++++.>>>+<]>-[<<<++++++++++++++++++++++++++++++++.[-]]<]

• Infinite input loop +[
• Get input >,
• Make a loop to get number 30 >+++++[<------>-]>
• If the symbol is a space, output the space [<<++++++++++++++++++++++++++++++.>>>+<]>-
• Otherwise, shift the ASCII value by two and output [<<<++++++++++++++++++++++++++++++++.[-]]<
• Get more input ]