74
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Our task is to, for each letter of the (English) alphabet, write a program that prints the alphabet, in a language whose name starts with that letter.

Input: none

Output:

abcdefghijklmnopqrstuvwxyz

uppercase and trailing newline optional

Rules:

  • The scoring metric is the length of the programming language name, plus the length of the code. Hence, C will be assessed a "penalty" of 1, while GolfScript will be assessed a penalty of 10.
  • One language/implementation per answer. Multiple answers are encouraged.
  • If a programming language name's first letter is not an English letter, it should not be coerced into one. It will be treated as a separate letter (meaning less competition).
  • No answer will be accepted until every English letter has a solution.

Current rankings:

Tell me if I'm missing anybody.

Automatic leaderboard (experimental)

var QUESTION_ID=2078;function answersUrl(e){return"https://api.stackexchange.com/2.2/questions/"+QUESTION_ID+"/answers?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+ANSWER_FILTER}function commentUrl(e,s){return"https://api.stackexchange.com/2.2/answers/"+s.join(";")+"/comments?page="+e+"&pagesize=100&order=desc&sort=creation&site=codegolf&filter="+COMMENT_FILTER}function getAnswers(){jQuery.ajax({url:answersUrl(answer_page++),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){answers.push.apply(answers,e.items),answers_hash=[],answer_ids=[],e.items.forEach(function(e){e.comments=[];var s=+e.share_link.match(/\d+/);answer_ids.push(s),answers_hash[s]=e}),e.has_more||(more_answers=!1),comment_page=1,getComments()}})}function getComments(){jQuery.ajax({url:commentUrl(comment_page++,answer_ids),method:"get",dataType:"jsonp",crossDomain:!0,success:function(e){e.items.forEach(function(e){answers_hash[e.post_id].comments.push(e)}),e.has_more?getComments():more_answers?getAnswers():process()}})}function getAuthorName(e){return e.owner.display_name}function process(){var e=[];answers.forEach(function(s){var r=s.body;s.comments.forEach(function(e){OVERRIDE_REG.test(e.body)&&(r="<h1>"+e.body.replace(OVERRIDE_REG,"")+"</h1>")});var a=r.match(SCORE_REG);a&&r.indexOf('non-competing')===-1&&e.push({user:getAuthorName(s),size:+a[2],language:a[1],lang:/<a/.test(a[1])?jQuery(a[1]).text():a[1],link:s.share_link})}),e.sort(function(e,s){var d=e.lang[0].toLowerCase(),a=s.lang[0].toLowerCase();return(d>a)-(d<a)||e.size-s.size});var s={},a=null,n="A";e.forEach(function(e){n=e.lang[0].toUpperCase(),a=e.size;var t=jQuery("#answer-template").html();t=t.replace("{{PLACE}}",n+" is for").replace("{{NAME}}",e.user).replace("{{LANGUAGE}}",e.language).replace("{{SIZE}}",e.size).replace("{{LINK}}",e.link),t=jQuery(t),jQuery("#answers").append(t);var o=e.lang,p=o[0].toUpperCase();s[p]=s[p]||{language:e.language,lang:e.lang,letter:p,user:e.user,size:e.size,link:e.link}});var t=[];for(var o in s)s.hasOwnProperty(o)&&t.push(s[o]);t.sort(function(e,s){return(e.letter>s.letter)-(e.letter<s.letter)});for(var c=0;c<t.length;++c){var i=jQuery("#language-template").html(),o=t[c];i=i.replace("{{LANGUAGE}}",o.language).replace("{{NAME}}",o.user).replace("{{SIZE}}",o.size).replace("{{LINK}}",o.link),jQuery("#languages").append(jQuery(i))}}var ANSWER_FILTER="!t)IWYnsLAZle2tQ3KqrVveCRJfxcRLe",COMMENT_FILTER="!)Q2B_A2kjfAiU78X(md6BoYk",answers=[],answers_hash,answer_ids,answer_page=1,more_answers=!0,comment_page;getAnswers();var SCORE_REG=/<h\d>\s*(?:<[^>]+>)?(?:[^]+?for )?((?:<a[^>]*?>)?(?:(?! [(=→-])[^\n,:])*[^\s,:])(?:[,:]| [(=→-]).*?(\d+)(?=[^\n\d<>]*(?:<(?:s>[^\n<>]*<\/s>|[^\n<>]+>)[^\n\d<>]*)*<\/h\d>)/,OVERRIDE_REG=/^Override\s*header:\s*/i;
body{text-align:left!important}#answer-list,#language-list{padding:10px;width:290px;float:left}table thead{font-weight:700}table td{padding:5px} /* font fix */ body {font-family: Arial,"Helvetica Neue",Helvetica,sans-serif;} /* #language-list x-pos fix */ #answer-list {margin-right: 200px;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <link rel="stylesheet" type="text/css" href="//cdn.sstatic.net/codegolf/all.css?v=83c949450c8b"> <div id="answer-list"> <h2>Winners by Letter</h2> <table class="language-list"> <thead> <tr><td>Language</td><td>User</td><td>Score</td></tr></thead> <tbody id="languages"> </tbody> </table> </div><table style="display: none"> <tbody id="answer-template"> <tr><td>{{PLACE}}</td><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table> <h2>Everything</h2> <table class="answer-list"> <thead> <tr><td></td><td>Language</td><td>Author</td><td>Size</td></tr></thead> <tbody id="answers"> </tbody> </table> </div><div id="language-list"> <table style="display: none"> <tbody id="language-template"> <tr><td>{{LANGUAGE}}</td><td>{{NAME}}</td><td>{{SIZE}}</td><td><a href="{{LINK}}">Link</a></td></tr></tbody> </table>

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9
  • 1
    \$\begingroup\$ Are we allowed to print junk to stderr? \$\endgroup\$ Apr 18, 2011 at 22:02
  • \$\begingroup\$ @Peter Taylor: Go nuts. To answer your question, yes, printing junk to stderr is fine (as long as stdout is correct). \$\endgroup\$
    – Joey Adams
    Apr 18, 2011 at 22:05
  • \$\begingroup\$ Is it OK to print the alphabet IN BIG LETTERS? \$\endgroup\$
    – SE is dead
    Jun 21, 2016 at 18:25
  • \$\begingroup\$ Funge is distinct from Befunge. Surely my pedanticism will be rewarded on a site dedicated to feats of it! \$\endgroup\$
    – tngreene
    Mar 23, 2017 at 19:53
  • 7
    \$\begingroup\$ Is *0*5AB1E the same as *o*sabie :P? \$\endgroup\$ Jun 6, 2019 at 14:58

156 Answers 156

0
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vimscript

What does output mean?

Assuming output to the current vim buffer is ok:

:norm aabcdefghijklmnopqrstuvwxyz

Otherwise, output to stdout:

:!echo abcdefghijklmnopqrstuvwxyz
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0
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AWK,33+3(Penalty)

END{for(;i<26;)printf"%c",97+i++}
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0
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T is for TI-BASIC, 27 + 8 = 35

"ABCDEFGHIJKLMNOPQRSTUVWXYZ

Can be run from command line, as a standalone program, or called as a function.

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0
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S is for Scala, Score: 40

print("abcdefghijklmnopqrstuvwxyz")
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0
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B is for Bash, 25 bytes

echo {a..z}|tr -d ' '

(21 bytes of code plus 4 for the language name)

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0
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R is for REXX, 15 characters → Score: 19

say xrange(a,z)
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0
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U is for uBASIC, 36 bytes → Score: 42

1 PRINT "abcdefghijklmnopqrstuvwxyz"

Try it online!

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0
0
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V is for VBA, 28 + 3 = 31

Anonymous VBE immediate window function that takes no input and outputs abcdefghijklmnopqrstuvwxyz to the VBE immediate window.

The two solutions below are of equal length and produce the same output

For i=97To 122:?Chr(i);:Next

Or

?"abcdefghijklmnopqrstuvwxyz
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0
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U is for uBASIC, 30 + 6 = 36

Anonymous function that takes no input and outputs abcdefghijklmnopqrstuvwxyz

0?"abcdefghijklmnopqrstuvwxyz"

Try it online!

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0
0
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S is for SmileBASIC, 27 bytes + 10 = 37

FOR I=65TO 90?CHR$(I);
NEXT

Prints the alphabet in uppercase. (I'm not sure whether this is allowed, but other people are doing it so...)

Just 1 character shorter than the (even more) boring answer:

?"abcdefghijklmnopqrstuvwxyz
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0
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F is for FALSE, 15 bytes +5 = 20

97[$'{-][$,1+]#

Doesn't use any letters!

Explanation:

97 {push 97 (ASCII for 'a')}
  [ {function start}
   $'{- {subtract '{' from the current letter}
       ] {function end}
        [ {function start}
         $, {print the current letter}
           1+ {add 1}
             ] {function end}
              # {while loop. Run the second function while the first doesn't return 0}
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0
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JavaScript, 34 + 10 = 44

alert('abcdefghijklmnopqrstuvwxyz')
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1
  • \$\begingroup\$ alert(8337503854730415241050377135811259267835n.toString(36)) ;) \$\endgroup\$ Oct 7, 2019 at 19:21
0
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PHP, 26 + 3 = 29

<?=implode('',range(a,z));
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0
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Racket, 46 bytes (score 52)

(for((i 26))(display(integer->char(+ i 97))))
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0
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I is for ICI, 37+3 bytes → 40

printf("abcdefghijklmnopqrstuvwxyz");
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0
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I is for Io, 35+2 bytes → 37

"abcdefghijklmnopqrstuvwxyz"println
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0
0
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C is for Common Lisp, Score 35 + 11 => 46

(princ"abcdefghijklmnopqrstuvwxyz")

Try it online!

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0
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H is for HTML -> 4+31

<HTML/>abcdefghijklmnopqrstuvwxyz

ps: browser will interpret the missing end tag

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1
  • 2
    \$\begingroup\$ ABCDEFGHIJKLMNOPQRSTUVWXYZ is far better at 30. \$\endgroup\$ Aug 3, 2016 at 9:52
0
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P is for PowerShell, 15 bytes+10 = 25

-join('a'..'z')

Try it online!

Uses the character range feature added in 6.0 to improve upon past answers.

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0
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Canvas, 1 byte, score: 7

Try it online!

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0
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CJam, 7 bytes, score: 11

Learnt this language just for solving this problem.

'{,'a,-

Try it online!

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0
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Stax, 2 bytes, score: 6

Also, Stax has a built-in.

Va

Try it online!

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0
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Gaia, 2 bytes, score: 6

₵a

Try it online!

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0
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MathGolf, 1 byte, score: 9

Try it online!

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0
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Japt, 2 bytes, score: 6

;C

Try it online!

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0
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05AB1E, 1 byte, score: 7

A

Try it online!

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0
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Jsonnet (with -S), 37 characters, score: 44

std.repeat("%c",26)%std.range(97,122)

Sample run:

bash-5.0$ jsonnet -Se 'std.repeat("%c",26)%std.range(97,122)'
abcdefghijklmnopqrstuvwxyz
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0
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C is for C, 34 bytes + 1 = 35

c(i){for(i=26;i;)putchar(91-i--);}
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1
  • \$\begingroup\$ 33 bytes \$\endgroup\$
    – jdt
    Sep 24, 2021 at 14:49
0
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X is for XJam, 6 + 4 = 10

'[,65>

What is XJam, you may ask? It's a language I started creating earlier this year and gave up before doing anything really interesting. It technically does fulfill its design criteria though, which is to be a version of CJam which adapts to the informal specification in the xkcd comic X. It accomplishes this by using a custom charset where Unicode characters representing variations on the letter X fill the top 32 slots in what's otherwise standard 7-bit ASCII. Those characters are then the only ones which can be used as variables. It also happens to be perfect for this challenge, beating the previous x answer by two. (Sorry Peter Cordes, that x86 answer was great!)

Credit where it's due, the code is taken from Lynn's answer on a different question here. It doesn't use variables so it ports over perfectly.

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0
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Eso2D, 15 bytes + 5 = 20

2v
,>#1~5
@#,5<

Eso2D is a language starting with E that has a relatively short name and an instruction set very good for string construction that I found on the esolang wiki. This could probably be improved further, but it's more than enough for a new best E.

Explanation:

2v        Increment the accumulator by 97 and move down to the second row
,>#1~5    Loop (from wrapping): print num to char, add 50, check if > 170, decrement by 49 otherwise.
@#,5<     Once it hits 171, decrement by 49 and print one last time before stopping.
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