Remove each integer from a string and multiply them all! [closed]

Question

Goal:

• Get every integer from the string (not a number, but integer)
• Multiply them
• Output the result
  
  
  

Input:

5 kilograms of food eaten, 10 liters of water drank, 20 plates dirty, 40 mugs dirty, and only 3 people acted!

Output:

120000

How:

Result was 5 * 10 * 20 * 40 * 3

What do we count as an integer:

General:

• If integer has a symbol BEFORE of AFTER the int, only take the number without symbols. -335 or 335+ are 335 anyways.

• If integer has a symbol like this: 35:3, don't take it. 35 : 3 is available though, and considered as 2 integers.
  
  

  Detailed:

• 35/3 aren't two integers, skip this

• 35.3 is not an integer, skip this
• 35:3, 35*3, 3e3, etc. aren't ints, skip them as well
• 353 is an integer
• 35 3 are two integers
• 353. is an integer
• 353?, 353!, etc. are integers
• -353 is an integer, but you only claim 353 and skip "-".

• +353 is the same case as upper
  
  
  

  Requirements:

• Select any language you want

• The program should contain as little bytes as possible
• You should tell us the language (if it's, like, exotic, link it like this)
• Please, upload the code to Try It Online services like this
• Count the bytes using special services like this
• It would be fine if you'd explain your code!
  
  
  

Scoring:

Less bytes program wins! The end is 20th of June, you guys have a week

Answer 1

perl -pl, 64 bytes

s!\D+|\d+(?:[.:^e/]\d+)+|(\d+)!$1?"*".(0+$1):""!aeg;$_=eval"1$_"

Try it online!

Ignores anything which isn't a digit, or multiple sequences of digits separated by /, ., e, :, or ^. Sequences of digits are replaced by themselves, prepended with *. The result, we eval, after predending 1. There's a tiny bit of hackery going to deal with numbers starting with 0s -- we don't want them be interpreted as octal numbers.

Reads lines from STDIN, writes the result to STDOUT.

Answer 2

Red, 109 bytes

func[s][p: 1 d: charset"0123456789"parse s[any[to d copy t[any d ahead[" "|"!"|"?"]](p: p * to p t)| skip]]p]

Try it online!