29
\$\begingroup\$

Numbers by Position

Challenge

Print the numbers:

1
22
333
4444
55555
666666
7777777
88888888
999999999

In that order.

I/O

Takes no input. The numbers can have any delimiters desired (or none). That includes lists, cell arrays, .jpeg, etc.... Example outputs:

122333444455555666666777777788888888999999999

[1,22,333,4444,55555,666666,7777777,88888888,999999999]

etc....

Code Example

This is an un-golfed example that may perhaps act as algorithm guide (or maybe not):

Turing Machine Code, 535 bytes

0 * 1 r L
L * _ r 2
2 * 2 r a
a * 2 r M
M * _ r 3
3 * 3 r b
b * 3 r c
c * 3 r N
N * _ r 4
4 * 4 r d
d * 4 r e
e * 4 r f
f * 4 r O
O * _ r 5
5 * 5 r g
g * 5 r h
h * 5 r i 
i * 5 r j
j * 5 r P
P * _ r 6
6 * 6 r k
k * 6 r l
l * 6 r m
m * 6 r n
n * 6 r o
o * 6 r Q
Q * _ r 7
7 * 7 r p
p * 7 r q
q * 7 r r
r * 7 r s
s * 7 r t
t * 7 r u
u * 7 r R
R * _ r 8
8 * 8 r v
v * 8 r w
w * 8 r x
x * 8 r y
y * 8 r z
z * 8 r A
A * 8 r B
B * 8 r S
S * _ r 9
9 * 9 r C
C * 9 r D
D * 9 r E
E * 9 r F
F * 9 r G
G * 9 r H
H * 9 r I
I * 9 r J
J * 9 r halt

Try it online!

This prints out the numbers with a space delimiter:

1 22 333 4444 55555 666666 7777777 88888888 999999999

Challenge Type

, so shortest answer in bytes (by language) wins.

Based on a submission in the sandbox.

\$\endgroup\$
9
  • 2
    \$\begingroup\$ Can the delimeters be numbers? \$\endgroup\$ – Wheat Wizard Mar 17 '20 at 17:16
  • \$\begingroup\$ @AdHocGarfHunter, No. Good catch. Edit: Actually, I think '0' should be acceptable. \$\endgroup\$ – ouflak Mar 17 '20 at 17:17
  • \$\begingroup\$ Could you verify that they "strange delimiters" version of this answer, is valid? It definitely seems cheaty. \$\endgroup\$ – Wheat Wizard Mar 17 '20 at 17:32
  • \$\begingroup\$ Honestly I think it's a clever 'outside-of-the-box' solution. I'd upvote, but I'm out of votes until tomorrow. \$\endgroup\$ – ouflak Mar 17 '20 at 17:35
  • 4
    \$\begingroup\$ @ouflak Thanks for the algorithm guide! How did you know I always write my prototypes with Turing Machines :p \$\endgroup\$ – AviFS Mar 19 '20 at 1:01

83 Answers 83

1
\$\begingroup\$

Deadfish~, 194 bytes

{{i}ddddd}dc{d}{d}iiic{i}{i}ddcc{d}{d}iic{i}{i}dccc{d}{d}ic{i}{i}cccc{d}{d}c{i}{i}iccccc{d}{d}dc{i}{i}iicccccc{d}{d}ddc{i}{i}iiiccccccc{d}{d}dddc{i}{i}iiiicccccccc{d}{d}ddddc{i}{i}iiiiiccccccccc

Try it online!

\$\endgroup\$
26
\$\begingroup\$

Google Sheets, 35 bytes

=ArrayFormula(Rept(Row(1:9),Row(1:9

Sheets will automatically add three trailing parentheses when you exit the cell. Output is one line per row.

results

\$\endgroup\$
2
  • \$\begingroup\$ I've run out of votes. \$\endgroup\$ – ouflak Mar 17 '20 at 12:37
  • \$\begingroup\$ @ouflak Darn... \$\endgroup\$ – S.S. Anne Mar 17 '20 at 13:18
15
\$\begingroup\$

05AB1E, 3 bytes

9L×

Try it online!

9L    Build a list from 1 to 9 {1, 2, 3, 4, 5, 6, 7, 8, 9}
×     copy each number that many times
\$\endgroup\$
0
15
\$\begingroup\$

Bash + Core utilities, 27, 25 bytes

seq -f8d%f*7-v1+2/n 45|dc

Try it online!


Changed seq formatting from %0.f to %f for a 2-byte savings.

Modified to print on one line, with no delimiters, instead of having a newline after each number, just because I like that better. Same number of bytes.


This uses the formula $$\left\lfloor\frac{\big\lfloor\sqrt{8n-7}\big\rfloor+1}2\right\rfloor$$

for the \$n^{th}\$ digit, where \$n\$ goes from 1 to 45.

\$\endgroup\$
0
10
\$\begingroup\$

Python 2, 28 bytes

i=1;exec"print`i`*i;i+=1;"*9

Try it online!

\$\endgroup\$
0
9
\$\begingroup\$

R, 18 bytes

a=1:9;(10^a-1)/9*a

Try it online!

Use the formula \$\frac{10^n-1}{9}\times n\$ for the \$n\$th number.

\$\endgroup\$
5
  • \$\begingroup\$ Hmm, I may be out of date but isn't the usual ruling that it needs cat() or equivalent to print the output? \$\endgroup\$ – user2390246 Mar 17 '20 at 16:44
  • 1
    \$\begingroup\$ @user2390246 yeah, the consensus was changed...a while ago? Late 2017 by my quick search of meta. This is probably what you're aware of but taking that approach with this meta post on compiler flags basically means all R answers are just "R invoked with source(...,echo=TRUE)" \$\endgroup\$ – Giuseppe Mar 17 '20 at 18:44
  • \$\begingroup\$ @Giuseppe thanks for the clarification, I've not been around for a while! Seems like the trend for cat()-type answers ended up being quite a short phase then. \$\endgroup\$ – user2390246 Mar 17 '20 at 19:33
  • \$\begingroup\$ Beat you with a string-only approach! :-) \$\endgroup\$ – Giuseppe Mar 18 '20 at 19:07
  • \$\begingroup\$ @Giuseppe Ooh, nice! \$\endgroup\$ – Robin Ryder Mar 18 '20 at 19:16
8
\$\begingroup\$

Kotlin, 30 bytes

{(1..9).map{"$it".repeat(it)}}

Try it online!

\$\endgroup\$
7
\$\begingroup\$

APL (dzaima/APL), 6 bytes

Full program, requiring ⎕IO←0.

⍋⍛⌿⍨⎕D

Try it online!

⎕D on the string "0123456789",

⍛⌿⍨ replicate the characters by

 their grade (0, 1, 2, …, 9)

\$\endgroup\$
2
  • \$\begingroup\$ Isn't \⍨⍳9 at 4 bytes sufficient? I've added it as my own answer, though it doesn't seem to be gaining any traction. Would love feedback! \$\endgroup\$ – AviFS Mar 19 '20 at 0:58
  • \$\begingroup\$ @AviF.S. It wasn't clear that this was a permitted format, but now that OP has clarified, you have my upvote. \$\endgroup\$ – Adám Mar 19 '20 at 6:52
6
\$\begingroup\$

brainfuck, 56 bytes

+++++++[>+++++++<-]+++++++++[<+[>>.<<-<+>]<[>+<-]>>>+<-]

Try it online!

+++++++[>+++++++<-]     49 (ASCII "1")
+++++++++[              do 9 times
  <+                    add 1 to output counter
  [                     do that many times
    >>.<<               print character
    -<+>                move value of output counter to temp
  ]
  <[>+<-]               move value of temp back to output counter
  >>>+                  increment character
  <-                    decrement loop counter
]
\$\endgroup\$
2
  • 1
    \$\begingroup\$ 50 bytes \$\endgroup\$ – Jo King Mar 17 '20 at 9:22
  • 1
    \$\begingroup\$ Thank you. Your code is so different from mine, you should post it as a separate answer. \$\endgroup\$ – Dorian Mar 17 '20 at 13:27
6
\$\begingroup\$

Retina, 12 bytes


9*

$.`*$.`

Try it online! Outputs a leading _ to each number, which appears to be acceptable (would cost 2 bytes to fix if not). Explanation:


9*

Insert 9 _s.


$.`*$.`

Around each _, insert its position repeated appropriately.

\$\endgroup\$
1
  • \$\begingroup\$ The leading _ is absolutely acceptable. \$\endgroup\$ – ouflak Mar 17 '20 at 11:31
6
\$\begingroup\$

APL (Dyalog Unicode), 4 bytes

\⍨⍳9

Try it online!

How it works

⍳9        ⍝ Integers 1..9
   ⍨      ⍝ Duplicate argument on each side
     \    ⍝ Replicate each element *n* times

Examples

Index Generator:    ⍳5          =  1 2 3 4 5
Expand:             2 3 \ 1 4   =  1 1 4 4 4
Commute:            +⍨4         =  4 + 4 = 8
\$\endgroup\$
1
  • \$\begingroup\$ Feedback: I'd use /⍨⍳9 as it is simpler. / is really "replicate" while \ is the more complex "expand". \$\endgroup\$ – Adám Mar 19 '20 at 6:53
5
\$\begingroup\$

Haskell, 30 29 bytes

(<$)<*>g<$>g '9'
g c=['1'..c]

Try it online!

\$\endgroup\$
5
\$\begingroup\$

Brain-Flak, 90 82 bytes

([(()()())({}){}]){((({})()<([{}]((((()()()){}){}){}){})>)<{({}()<(({}))>)}{}>)}{}

Try it online!

Explanation:


Compare this with the output of JoKing's autogolfer

Brain-Flak, 142 bytes

(((((((((((((((((((((((((((((((((((((((((((((((((()()()){}){}){}){}())()))())))()))))())))))()))))))())))))))()))))))))()))))))))){({}<>)<>}<>

Try it online!


Strange delimiters, 78 bytes

([(()()())({}){}]){((({})()<([{}]((((()()()){}){}){}){})>)<{({}()<(({}))>)}>)}

Try it online!

If we decide to play around with our delimiters a bit, we can shave off 4 bytes. This version outputs the correct stuff but with two leading null bytes and null bytes between the chunks:

This is a tiny bit cheaty but it meets the specs of the challenge.


And for posterity here is the old super cheaty version that has been made obsolete by my golfs.

\$\endgroup\$
4
\$\begingroup\$

APL (Dyalog Unicode), 7 bytesSBCS

⎕D/⍨⍳10

Try it online!

Uses ⎕IO←0.

How it works

⎕D/⍨⍳10
⎕D       ⍝ The string '0123456789'
  /⍨     ⍝ Replicate each of them the following times...
    ⍳10  ⍝ 0..9
\$\endgroup\$
4
\$\begingroup\$

Perl 5, 18 bytes

map{say$_ x$_}1..9

Try it online!

\$\endgroup\$
4
\$\begingroup\$

R, 15 bytes

strrep(1:9,1:9)

Try it online!

\$\endgroup\$
1
  • \$\begingroup\$ Just rep(1:9,1:9) is shorter (and gives exactly the output of the first example)? \$\endgroup\$ – Dominic van Essen Jun 24 '20 at 22:50
4
\$\begingroup\$

Java 11 (JDK), 60 59 bytes

Not sure if thats the shortest approach but couldn`t make it shorter even without System.out.print. Output is without delimiters.

-1 byte thanks to Kevin Cruijssen

v->{for(int i=0;i++<9;System.out.print((i+"").repeat(i)));}

Try it online!

\$\endgroup\$
4
  • 1
    \$\begingroup\$ You can save 1 byte changing the ()-> to v->, by taking an empty unused (Void null) argument, which is allowed when it's completely unused. \$\endgroup\$ – Kevin Cruijssen Mar 18 '20 at 10:04
  • \$\begingroup\$ @Kevin Cruijssen Thanks for the suggestion, didn't know about that. I now use an Object as parameter and pass null, is this the intended way or can you actually do it with Void? \$\endgroup\$ – greinet Mar 18 '20 at 10:26
  • \$\begingroup\$ Object null is fine as well. As long as the argument isn't used in any way, not even for static calls, it's ok. That's why I personally use Void, since it has no available static calls anyway. :) \$\endgroup\$ – Kevin Cruijssen Mar 18 '20 at 10:27
  • \$\begingroup\$ Well thats awkward, could've sworn that it just didn't compile with type Void, changed it again and now it works, thanks. \$\endgroup\$ – greinet Mar 18 '20 at 10:32
3
\$\begingroup\$

PowerShell, 15 bytes

1..9|%{"$_"*$_}

Try it online!

\$\endgroup\$
3
\$\begingroup\$

Icon, 27 bytes

write(1(i:=1to 9,1to i))&\z

Try it online!

\$\endgroup\$
3
\$\begingroup\$

T-SQL, 69 bytes

SELECT top 9replicate(1+number,1+number)FROM spt_values WHERE'p'=type

Try it online

\$\endgroup\$
2
  • \$\begingroup\$ Nice code. Sometimes I wonder how well T-SQL would do in these challenges if we had a built-in number table or some equivalent to PostgreSQL's generate-series() function. \$\endgroup\$ – BradC May 26 '20 at 15:48
  • 1
    \$\begingroup\$ @BradC normally SQL will not win in these golfing questions even with improved features. When we use a command like replicate(a,b), some of the other languages can solve problem with fewer characters than the 14 characters(minimum) it takes to call that function. The best we can do it solve the problems using a language which usually isn't optimal, and hope some people are impressed enough to up-vote those solutions. \$\endgroup\$ – t-clausen.dk May 27 '20 at 11:29
3
\$\begingroup\$

Jelly, 5 bytes

9ẋ`€Ḍ

Try it online!

A niladic link returning a list of integers. If a program printing the numbers is preferred, subsitute Y for .

Explanation

9     | Literal 9
 ẋ`€  | Repeat each that many times
    Ḍ | Convert from decimal digits to integer
\$\endgroup\$
1
  • \$\begingroup\$ You can drop the trailing , based on the comments below the challenge description between xnor and OP. \$\endgroup\$ – Kevin Cruijssen Mar 18 '20 at 15:37
3
\$\begingroup\$

Charcoal, 5 bytes

⭆χ⭆ιι

Try it online! Link is to verbose version of code. Outputs without separators. The first StringMap could be changed into a for statement for the same byte count. Explanation:

 χ       Predefined variable 10
⭆        Map over implicit range and join
   ι     Current index
  ⭆      Map over implicit range and join
    ι    Outer index
         Implicitly print
\$\endgroup\$
3
\$\begingroup\$

C (gcc), 54 53 bytes

i;j;f(){for(i=0;9/++i;)for(j=0;j++<i;)putchar(48+i);}

Try it online!

No delimiters between the numbers.

\$\endgroup\$
1
3
\$\begingroup\$

Perl 6, 13 bytes

{1..9 Zx^9+1}

Try it online!

Anonymous code block that returns a list of strings by zip string multiplying the range 1 to 9 with itself.

\$\endgroup\$
3
\$\begingroup\$

W 5 4 3 bytes

@π┐

Uncompressed:

$*9N

Repeat 1..9 N times.

Explanation

     M % Map in the range
9      % From 1 to 9
  a$   % Stringify the current counter
 a  *  % Repeat that string by the current counter
\$\endgroup\$
5
  • \$\begingroup\$ Just curious, why do you have the meta link to the command line flags answer? Is that related to your implementation? \$\endgroup\$ – ouflak Mar 17 '20 at 11:29
  • \$\begingroup\$ @ouflak No,that's was part of the copy-pasted template. \$\endgroup\$ – user92069 Mar 17 '20 at 11:30
  • \$\begingroup\$ @ouflak Why is this accepted? The 05AB1E solution is posted before this answer. You should accept that instead. \$\endgroup\$ – user92069 Mar 24 '20 at 12:10
  • \$\begingroup\$ Both were 3 bytes. I just flipped a coin. I can swap them.... \$\endgroup\$ – ouflak Mar 24 '20 at 12:41
  • \$\begingroup\$ @ouflak The general consensus is that you shouldn‘t accept an answer anyway. (Appreciate I‘m a few months late, and that you can do as you please, just spreading the consensus view) \$\endgroup\$ – ChartZ Belatedly Jun 23 '20 at 23:47
3
\$\begingroup\$

Erlang (escript), 49 bytes

f()->[X*(math:pow(10,X)-1)/9||X<-lists:seq(1,9)].

Try it online!

\$\endgroup\$
3
\$\begingroup\$

C (gcc), 50 bytes

n;f(i){for(i=0;i++<9;)for(n=i;n--;)putchar(48+i);}

Try it online!

\$\endgroup\$
3
\$\begingroup\$

Haskell, 21 bytes

[c<$[1..c]|c<-[1..9]]

Try it online!

A list of lists of numbers.

23 bytes

replicate<*>id=<<[1..9]

Try it online!

A flat list of nubers.

\$\endgroup\$
2
  • \$\begingroup\$ I think that the delimiter has to be in between differing digits (e.g. 1 and 2 as opposed to 8 and another 8). \$\endgroup\$ – Wheat Wizard Mar 17 '20 at 18:06
  • \$\begingroup\$ @AdHocGarfHunter Looking again at the challenge, I'm not clear on this so I asked. I think it would be unfortunate if the flat list in the second version were invalid too. \$\endgroup\$ – xnor Mar 17 '20 at 18:14
3
\$\begingroup\$

Japt, 4 bytes

AÇîZ

Try it

NaN
\$\endgroup\$
3
\$\begingroup\$

This is my dumbest code golf submission ever, but here it goes

SQLite, 53 bytes

SELECT'122333444455555666666777777788888888999999999'

Try it online!

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.