Shortest method to implement the Pythagorean Theorem

Question

Who doesn't love the Pythagorean theorem \$a^2+b^2=c^2\$? Write the shortest method you can in any language that takes in value a and b and prints out The hypotenuse of this right triangle is c. Keep c to only three decimal places.

Answer 1

Jelly, 32 characters

,²S½ær3µ,“¡ÆC⁷⁺ɱSoṿȤç½?⁶Ẏtḍỵŀ»ṚK

Try it online!

There is probably a better string compression that allows me to get around needing to join with spaces but I was having trouble finding it.

Explanation:

,²S½ær3µ,“...»ṚK    Example inputs: 3, 4
,                   Pair the inputs. Result: [3, 4]
 ²                  Square them. Result: [9, 16]
  S                 Sum them. Result: 25
   ½                Get the square root of the sum. Result: 5
    ær3             Round to 3 decimal places. Result: 5
       µ            Take the result of that... Result: 5
         “...»       ...and  the compressed string Result: "The hypotenuse of this right triangle is"
        ,           And put them into a pair. Result: [5, "The hypotenuse of this right triangle is"]
              Ṛ     Reverse that. Result: ["The hypotenuse of this right triangle is", 5]
               k    Join it with spaces. Result: "The hypotenuse of this right triangle is 5.0"
                    Implicit output.

Answer 2

JavaScript, 70 bytes

(a,b)=>'The hypotenuse of the triangle is '+((a*a+b*b)**.5).toFixed(3)

The latter function rounds the number to 3 decimal places.

Answer 3

Javascript, 109

A=1,B=1,s=1e3,console.log("The hypotenuse of this right triangle is " + (Math.round(Math.sqrt(A*A+B*B)*s)/s))

Fiddledee

Answer 4

Scala (95c)

import Math._;val x=sqrt(pow(a,2)+pow(b,2));f"The hypotenuse of this right triangle is $x%1.3g"

Answer 5

Java : 223

   class l {
        public static void main(String[] args) {      
          new l().H(2,4);
        }   
        void H(float a, float b)
    {
        System.out.printf("The hypotenuse of this right triangle is %.3f",Math.hypot(a,b));
    }
    }

Answer 6

Groovy : 78 Characters

a={x,y->printf"The hypotenuse of this right triangle is %.3f",Math.hypot(x,y)}

Assuming the task is just writing a method. If you need to take input parameters:

99 Characters

printf"The hypotenuse of this right triangle is %.3f",Math.hypot(args[0].toLong(),args[1].toLong())

I found two ways to it with the same length:

printf"The hypotenuse of this right triangle is %.3f",Math.sqrt(args.collect{it.toLong()**2}.sum())

Answer 7

newLISP, 103 characters

(let(a 3.1 b 4)(println"The hypotenuse of this right triangle is "(round(pow(add(pow a)(pow b)).5)-3)))

The unspecified input method helps a lot... :)

Answer 8

F#, 78

let f a b=sqrt(a*a+b*b)|>printf"The hypotenuse of this right triangle is %.3f"

Answer 9

Java : 155

class A{A(int x,int y){System.out.printf("The hypotenuse of this right triangle is %.3f",Math.hypot(x,y));}public static void main(String[]s){new A(1,4);}}

Answer 10

Fortran (90)

read(*,*)a,b;print'(a,f9.3)',"The hypotenuse of this right triangle is ",sqrt(a*a+b*b);end

Uses implicit typing so that a,b are single precision reals.

Answer 11

Javascript 98 characters/bytes

This is implemented as a browser alert in a function.

function p(a,b){alert('The hypotenuse of this right triangle is: '+Math.sqrt(a*a+b*b).toFixed(3))};

Answer 12

Ruby 2.1+ (73 characters)

f=->a,b{puts"The hypotenuse of this right triangle is %.3f"%(a+b*1i).abs}

Answer 13

Prolog

h(A,B):-X is A*A+B*B, C is sqrt(X),format('The hypotenuse of this right triangle is ~3f',C).

Answer 14

Bash with bc, 91

No bash script yet?!

read a b
echo -n 'The hypotenuse of this right triangle is '
bc<<<"scale=3;sqrt($a^2+$b^2)"

There is no way this can win.

Answer 15

Haskell, 77 characters

(\x y->print$"The hypotenuse of this right triangle is "++(show$sqrt$x^2+y^2))

Useage:

(\x y->print$"The hypotenuse of this right triangle is "++(show$sqrt$x^2+y^2)) 3.0 4.0
The hypotenuse of this right triangle is 5.0

Answer 16

Fortran 2008 (87 characters)

Based on the Fortran 90 solution, but now in Fortran 2008, HYPOT is an intrinsic function.

read(*,*)a,b;print'(a,f9.3)','The hypotenuse of this right triangle is ',hypot(a,b);end

Answer 17

J, 56 bytes

'The hypotenuse of this right triangle is '&,@":@(+&.*:)

explanation

J's "Under" verb &. is a nice fit here. It applies a transformation, executes a verb, and then applies the reverse transformation to the result. In this case, squaring is the transformation *:, its reverse is taking the square root, and the verb in question is addition. So we do addition "under" the square transformation. The rest is just formatting the number and cat'ing it onto the sentence.

Try it online!

Answer 18

Perl 5, 69 bytes

printf"The hypotenuse of this right triangle is %.3f",sqrt<>**2+<>**2

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Answer 19

Tcl, 80 bytes

puts "The hypotenuse of this right triangle is [expr int(hypot($a,$b)*1e3)/1e3]"

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Answer 20

Jq 1.5, 80 bytes

"The hypotenuse of this right triangle is \(1e3*pow(map(.*.)|add;.5)|floor/1e3)"

Assumes input is [a,b]

Try it online at tio.run or jqplay.org

Answer 21

Axiom, 92 bytes

g(a,b)=="The hypotenuse of this right triangle is "((round((a^2+b^2)^.5*1.e3)/1.e3)::String)

test

(4) -> g(12, 19)
   (4)  "The hypotenuse of this right triangle is 22.472"
                                                             Type: String

Answer 22

05AB1E, 53 characters

"The hypotenuse of this right triangle is "|nOt₄*ï₄/«

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I could not figure out how to compress 05AB1E strings. :(

Explanation:

"..."|nOt₄*ï₄/«

     |             Push array of inputs.
      n            Square them.
       O           Get the sum.
        t          Get the square root.
         ₄*        Multiply by 1000
           ï       Convert to integer. This rounds it.
            ₄/     Divide by 1000
"..."         «    Append it to the string.
                   Implicit print.

Answer 23

Petit Computer BASIC, 66 bytes

INPUT A,B?"The hypotenuse of this right triangle is ";SQR(A*A+B*B)

PTC only displays the first 3 decimal places when printing.

Answer 24

Stax, 24 bytes

╬Z.-êû$P¿[▐Ä√#╙δdr▼▀Ö☺┐ç

Run and debug it

Unpacked, ungolfed, and commented, it looks like this.

`1/yyH\fBXNR&X+{.SC`p   print "The hypotenuse of this right triangle is "
:J+                     square and add the inputs
|Q                      square root
3j                      round to 3 places
p                       print

Run this one

Answer 25

APL (Dyalog), 51 bytes

'The hypotenuse of this right triangle is',3⍕|0j1⊥⎕

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0j1⊥⎕: Convert the input into base i. e.g a b -> b+ai

|: Magnitude

3⍕: Round to 3 decimal places

Answer 26

Japt, 37 bytes

`T hypÇQ«e  È ght â0Ø8  `+Nx²¬x3

Try it

Answer 27

JavaScript (Node.js), 76 bytes

a=>b=>'The hypotenuse of this right triangle is '+Math.hypot(a,b).toFixed(3)

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Explanation

a => b => // the two arguments (curry method)
    `The hypotenuse of this right triangle is // write the text required
    ${Math.hypot(a,b)}` // and use JS Math.hypot function to calculate the hypotenuse. 

Alternately, if the you spare me the pain of writing this text.

f=Math.hypot // is also a valid answer

Answer 28

Husk, 41 bytes

+¨ΣŸṗ¤μe₀fı≤ṙ↔ẏ«G¹∫¨J"."msλ‰⁰i*⁰)1000√¤+□

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With rounding being involved, I sure didn't pick the right language for the task...

+                              The concatenation of
 ¨...¨                         the compressed prefix for the output
          ms                   with the stringified elements of
            λ‰⁰   )1000        the divmod by 1000 of
                       √       the square root of 
                         +     the sum of
                        ¤ □    the squares of the two arguments
                *⁰             times 1000
               i               converted to an integer
      J"."                     with a period inserted between them.

Computing the actual length of the hypotenuse only takes four bytes, rounding to three decimal places takes seventeen bytes, and adding on The hypotenuse of this right triangle is to the output takes twenty bytes. 90.244% of this answer is just formatting!

Answer 29

Pyth, 51 bytes

+." y¢ó³-.n?ãÜPŽýD'9¹i¾5ŠÁ«£¿9WhI‚".R@s^RJ2QJ3

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---

The actual math only takes up 8 bytes.

Despite having built-in string compression capabilities, Pyth is pretty bad at compressing strings.

Answer 30

Javascript, 110 bytes

function h(a,b){return a/1==a&&b/1==b?'The hypotenuse of this right triangle is '+(a*a+b*b||0).toFixed(3):!1;}

It's a monster!!!

But it can handle NaN and invalid numbers, like text, objects, 0/0 and other invalid numbers.