Scream very loudly

Question

Write a script that outputs A to stdout infinitely.

There should be no newlines or separators between the characters.

Standard loopholes apply.

This is code-golf. The shortest solution in each language wins.

Answer 1

Scala, 20 bytes

while(print('A')!=0)

Answer 2

CJam, 7 bytes

'A{_o}h

CJam loops are surprisingly expensive as there are no markers, and since there's no infinite loop function, we need to make sure there's always a spare truthy A on the stack for our do-while loop.

Try it online

Explanation:

'A        Push 'A' to the stack
  {  }h   Loop while top of stack is true
   _      Duplicate the A
    o     Pop and output the A w/ no newline

Answer 3

Oak, 29 Bytes

fn main(){while(1){prc!(65)}}

This may have to be changed to fn main(){while(1){prc!('A')}} once num and char are no longer interchangable, but for now it works.

Answer 4

Perl 6, 16 bytes

loop {print "A"}

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Answer 5

Neim, 5 bytes

ͻ    # Infinite loop
 (   # Decompress base 255
  A  # A
 )   #
   B # Compress number to base 255

Runs only 6 times

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Answer 6

StupidStackLanguage, 11 bytes

avqviiimtfu

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Explanation

a - push 0 to stack
v - add 5
q - duplicate
viii - add 8 (making 13)
m - multiply top 2 items (13x5 = 65)
t - start bf style loop
f - print character
u - end bf style loop

Answer 7

Husk, 3 bytes

∞'A

Try it online! Creates an infinite list of 'A characters and prints it.

Answer 8

C#, 62 bytes

class P{static void Main(){for(;;)System.Console.Write('A');}}

Answer 9

Deadfish~, 4014 bytes:

{iiiiii}iiiii{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{c}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}}

Sets the accumulator to 65, then prints as character 10²⁰⁰⁰ times = far beyond the lifespan of the universe.

There's no way to do anything infinitely in Deadfish~, so 10²⁰⁰⁰ times should be enough.

Answer 10

VBScript, 31 bytes

Do 
WScript.StdOut.Write("A")
Loop

Answer 11

C# 9, 33

for(;;)System.Console.Write('A');

Answer 12

Barrel, 9 bytes (or 8 with newer instruction)

^A¤p←1

Explanation:

^A     // Sets the accumulator to the ASCII codepoint of 'A'.
  ¤ ←1 // Creates a jump target and jumps back to it.
   p   // Prints the accumulator as a character value.

Since the ← command will implicitly push the current location onto the location pointer stack, this program will use lots of system memory. In fact, on my system it used about one megabyte of RAM per second. To overcome this, I've since implemented the ↰ operator, which jumps without pushing (and therefore removes the possibility of RAM overflow). It makes the command look like this: ^A¤p↰1

This could be 8 bytes now that I have implemented the infinite loop that I'd thought about implementing: ^65#∞p In this case, the #∞p would define a loop which would print the character value infinitely. However, since the infinity command may have been inspired by this (I actually forget) and the command is newer than the answer anyway, I'll refrain from changing my answer.

Answer 13

Nim, 26, 25 bytes (Credits to @hyper-neutrino)

while 1>0:stdout.write'A'

Try it online!

Not great, but not too shabby.

Answer 14

Rattle, 7 bytes

65|[,]0

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If you run this on the online interpreter, you'll get an error message saying the code timed out with no output. That's only due to how this online interpreter is set up* - if you run this locally, it will never stop printing AAAAAAAAAAAAAAAAAAAAAAAA.... Online CPU-seconds are expensive!

*it's supposed to still give output even if an error gets thrown because it is an interpreted language, but I don't know how to set that up properly on the website. So as of right now, output in the online version only gets printed if the program exits successfully...

Rattle prints the top of the stack implicitly upon exit. However, this code will never exit. If you run this on the online interpreter with a finite loop (change the 0 to 100 or something), you'll notice that 65 gets printed at the end. Of course, the end of infinity doesn't exist, so this code is still valid.

Explanation

65|             hard-coded input (Rattle's equivalent to a variable declaration)
   [...]0       infinite loop
     ,          prints the ASCII character of the value on top of the stack (A = ASCII 65)

Answer 15

Daoyu, 13 instructions, 7 bytes

There's two! Each instruction is a hex, so two instructions fit in a byte.

$$$(([]!)/(/[]!)):><
OPLEV 0:
$$$                   Allocate 8 bits of memory to the bit tape
   (([]!)/(/[]!))     Set the bit tape to 01000001
                 :><  Print the bit tape, and loop to the beginning
OPLEV 1:
...                   NOP
   ((().)/(/().))     Moves around the bit tape with no effect
                 :><  Print the bit tape, and loop to the beginning

This one is simpler, but it's 20 instructions and an extra byte. The first time the program loops, the operation level is 0, and it runs the first program, which allocates memory, sets the bit tape to 'A', and prints. Every other time it loops it just prints the bit tape.

%!)))):((((><
%!             Acts as NOP, encodes 'A'
  ))))         Moves data reader to '%!'/'A'
      :((((><  Prints, resets position, and loops to beginning

This one reads its own source code, and is a few bytes smaller. The operation level does change, but it doesn't really affect any of the program. When attempting to MERGE ()) while selecting the entire but tape, which is the original state of the program, the data reader moves to the parent bit tape, which is the program's source code. The program navigates to the %!, prints it as 'A', and loops.

Answer 16

Deorst, 6 bytes

oA
#EO

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Explanation:

oA   # Push 'A'
#    # Forever:
 EO  #   Print without newline

Answer 17

WedgeScript, 4 bytes

'A|o

Explanation:

'A    Pushes the character literal A to the stack\
|     Loop the rest of the code infinitely\
o     Output

Yes, Wedgescript is a custom language made by me, here is the repo with interpreter install instructions: https://github.com/WedgeScript/WedgeScript

Answer 18

JavaScript (Node.js), 33 32 bytes

-1 byte thanks to @Luke_

for(;;)process.stdout.write('A')

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Answer 19

Japt, 10 bytes

{Oo'A}g1/0

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Explanation

{Oo'A}a
{          // Function
 Oo'A      //    Output 'A'
     }     // End Function
      g1/0 // Call infinite times
           // (Japt's O.o() method returns undefined)

---

Japt, 7 bytes

As pointed out by @Shaggy due to how a is implemented this will print A only 1e8 times

{Oo'A}a

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Explanation

{Oo'A}a
{       // Function
 Oo'A   //    Output 'A'
     }  // End Function
      a // Call repeatedly until it returns a truthy value
        // (Japt's O.o() method returns undefined)

Answer 20

Arduino, 63 bytes

void setup(){Serial.begin(300);}void loop(){Serial.write('A');}

Not sure how much explaining I need to do here. Arduino has an infinite loop built-in, so just write one 'A' to the Serial output inside of it. Equally valid would be Serial.print('A'); and Serial.print("A");, and I think Serial.write("A"); should work as well. It's all just a matter of preference.

Answer 21

Vyxal, 4 bytes

The try it link has the 5 flag to prevent it from freezing up forever.

{\A₴

Explanation

{    - While loop
 \A  - Push "A"
   ₴ - Print without newline

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Answer 22

INTERCAL (C-INTERCAL), 61 bytes

DO,1<-#9DO,1SUB#1<-#126DOCOMEFROM#9PLEASEREADOUT,1(9)DO,1<-#9

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Answer 23

CLC-INTERCAL, 48 bytes.

DO;1<-#1DO;1SUB#1<-#20DOCOMEFROM#9(9)DOREADOUT;1

(Don't) Copy and paste to try it online! It is very recommend to replace COME with NEXT, as output suppression may be weak.

Answer 24

ErrLess, 3 bytes

'A?

Explanation

'A { Push 'A' to the stack }
?  { Output the top element of the stack as a character }

The Instruction pointer loops when it reaches the end of the program.

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Answer 25

Python 3, 23 bytes

while[print(end="A")]:0

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Answer 26

Lexurgy, 17 bytes

a propagate:
*=>A

Forever replaces an empty string with A.

Answer 27

Desmos with actions, 44 bytes

Code in ticker:

s_{tdout}\to join(s_{tdout},65)

Code in list (the actual area where you can enter equations):

s_{tdout}=[]

It outputs the ascii code for A

Link: https://www.desmos.com/calculator/u1fynzwbuf

Answer 28

Underload, 10 bytes

((A)S:^):^

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Explained:

(    :^):^ While true...
    S      Print
 (A)       The string "A"

Answer 29

rusty_deque, 19 bytes

'A'~{dup~ow~}~loop~

Pretty much a duplicate of my "Shortest code to produce infinite output" answer.

Answer 30

x86 machine code - 14 bytes

So, yeah I'm using write() system call to print A characters without \n

     6                                  scream:
     7 00000000 6A41                      push 0x41
     8 00000002 31DB                      xor ebx, ebx
     9 00000004 89E1                      mov ecx, esp 
    10 00000006 B201                      mov dl, 0x1 
    11 00000008 B004                      mov al, 0x4 
    12 0000000A CD80                      int 0x80
    13 0000000C EBF2                      jmp scream

This is output using strace :

write(0, "A", 1A)                        = 1
write(0, "A", 1A)                        = 1
write(0, "A", 1A)                        = 1
write(0, "A", 1A)                        = 1
<repeat> ..