Shortest Solution in Python 3 for Caught Speeding - CodingBat

Question

I am trying to find the shortest code in python 3, to solve this problem:

You are driving a little too fast, and a police officer stops you.

Write code to take two integer inputs, first one corresponds to speed, seconds one is either 1 or 0, corresponding to True and False respectively to indicate whether it is birthday. Then compute the result, encoded as an int value:

0=no ticket,

1=small ticket,

2=big ticket.

If speed is 60 or less, the result is 0. If speed is between 61 and 80 inclusive, the result is 1. If speed is 81 or more, the result is 2. Unless it is your birthday -- on that day, your speed can be 5 higher in all cases.

input:
60
0
Output:
0

input:
65
0
Output:
1

input:
65
1
output:
0

Here's my shortest solution (57 chars). Is there any way I can make it shorter in Python?

print(min(2,max(0,(int(input())-5*int(input())-41)//20)))

Reference: Problem inspired from this

Answer 1

Python 3, 32 bytes

lambda a,b:(a-b*5>60)+(a-b*5>80)

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---

Python 3, ⁵⁰ 49 bytes

If io must be done with stdin and stdout

a,b=map(int,open(0));print((a-b*5>60)+(a-b*5>80))

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-1 byte thanks to @dingledooper

Answer 2

Python 3, 51 45 bytes

lambda a,b:min(2,max(0,(a//1-5*b//1-41)//20))

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I was able to shave 6 bytes from your approach by using everyone's favourite python golfing keyword: lambda.

This turns your program into an anonymous function, which then can be called in the footer of a program.

Edit: I know that this question is way old, but I only just recently thought of using //1 to convert things to an integer instead of using int(...).