Typing, but to the left [closed]

Question

Background

You've been given a task to take notes for a meeting. You start typing on your Google Doc, but you don't have enough time during the meeting to look at your keyboard while you type.

Fortunately for you, you can type without looking at your keyboard. After the meeting, you realize that everything you typed was one key to the left.

The Challenge

For this challenge, you will be using the letters, numbers, and space bar of the QWERTY keyboard layout.

• Given an input of text (from any standard input method), output the resulting text, where every character is moved one to the left on the keyboard.

  • For the majority of letters, just look at the letter and translate it to the letter to the left (c becomes x, t becomes r, etc).

  • For letter q, translate to a literal tab character (\t).

  • For letter a, enable caps lock, so the capitalization of the rest of the string is reversed.

  • For letter z, capitalize the next letter in the string.

  • No translation is required for the space bar.

• Preserve capitalization while translating, and be mindful of caps lock (if caps lock is enabled, make sure the case is the opposite).

• All characters in the input string will be letters, numbers, or a space. No punctuation or other characters can be included.

Test Cases

^{\t is a literal tab character}

Hello world    -> Gwkki qieks
Code Golf      -> Xisw Fikd
Queried apples -> \tyweuws OOKWA

Scoring

Lowest score in bytes wins. Have fun!

Answer 1

JavaScript (V8), 271 bytes

f=(s,k='~!@#$%^&*()_+`1234567890-=\tQWERTYUIOP{}|\tqwertyuiop[]\\ASDFGHJKL:"\n\\asdfghjkl;\'ZXCVBNM<>?zxcvbnm,./')=>s.replace(/[^ ]/g,c=>k[k.indexOf(c)-1]).replace(/\\([^\\]*)\\?/g,(m,c)=>c.replace(/[a-zA-z]/g,l=>l>'Z'?l.toUpperCase():l.toLowerCase())).replace(/[?']/,"")

Try it online! My first JavaScript code golf. It could definitely be shorter, but I think this is a good start.
It basically finds each character in the k string and replaces it with the previous one, then swaps the case of everything between the A or a, and removes all occurences of Z or z (as shift key does nothing on its own).
This should be a normal QWERTY keyboard layout, but let me know if not.

Answer 2

Python 3, 211 bytes

d=' ~!@#$%^&*()`~1!2@3#4$5%6^7&8*9(0)		qQwWeErRtTyYuUiIoOpPaAsSdDfFgGhHjJkKlLzZxXcCvVbBnNmM  '
c=s=0
for i in input():k=d.find(i);print(end=d[k-2+(c*i.isalpha()^s)*(1-k%2*2)][i in'aAzZ':]);c^=i in'aA';s=i in'zZ'

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Uses a lookup string in which the normal character and its shift-modified version are grouped together. For each character in the input, it will retreive the character two places to the left. Changes capitalization by adding 1 (or -1 if the current character is uppercase) to the lookup value when shift XOR caps lock is active. Numbers are not influenced by the caps lock modifier.

Answer 3

PHP, 227 bytes

for(;''<$s=$argn[$i++];)$s!=a&&$s!=A?$s!=z&&$s!=Z?($t=$m[stripos($m='~1!2@3#4$5%6^7&8*9(0	qwertyuiopasdfghjklzxcvbnm',$s)-1])+(print$s>' '?$s<A?!$h?$s-1?$s?$s-1:9:'`':$t:($t>=A&&(($s<a)+$h+$c)%2?$t^' ':$t):$s)+$h=0:$h=1:$c=!$c;

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I have created a mapping string (~1!2@3#4$5%6^7&8*9(0 qwertyuiopasdfghjklzxcvbnm) which for each digit has their SHIFT mode on the left and for each letter has the letter/key to their left.

I loop over input characters and for each character:

• If character is a or A, caps lock flag gets reversed (logical not).
• If character is z or Z, shift flag is set to 1.
• When character is not in aAzZ:
  • Character to the left of current character in the mapping string is stored in $t.
  • If current character is an space, it is printed.
  • If current character is a digit, and if shift flag is 1, $t is printed, else, if digit is 1, ` is printed, if digit is 0, 9 is printed and otherwise, digit-1 is printed.
  • If current character is a letter, based on status of shift flag, caps lock flag and casing of current character (lower/upper), $t in lower or upper case is printed. The only special case here is tab character, which is printed as is.
  • Shift flag is always set back to 0 at the end.

Answer 4

Red, 218 bytes

func[t][c: z: 0 rejoin collect[foreach s t[case[find"Aa"s[c: c xor 32]find"Zz"s[z: 32]on
[keep(select/case"  poiuytrewq^-lkjhgfdsamnbvcxzPOIUYTREWQ^-LKJHGFDSAMNBVCXZ0987654321~"s)xor either s <#"Z"[0][c xor z]z: 0]]]]]

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Currently AaZz don't affect digits.

Answer 5

C (gcc), 276 bytes

i;j;k;h;l;m;n;o;f(char*b){char*c=calloc(m=strlen(b),1),*a=" \tqwertyuiop\aasdfghjkl\nzxcvbnm\tQWERTYUIOP\aASDFGHJKL\nZXCVBNM`1234567890";for(i=k=j=n=0;j<=m;l=a[i=index(a,b[j++])-a-1])k=l^7?k:!k,o=l>64&l<91?a[i-30*k]:l<97?h=i?l^7?l?l^10?l:0:32:0:0:a[i+29*k],o?c[n++]=o:n;b=c;}

Thanks to ceilingcat for -33 bytes.

Try it online!