Draw the Heart Shape [closed]

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Challenge

Draw a Heart shape

enter image description here

...as ASCII art!

Your art doesn't have to look exactly like mine, but it has to look like a Heart Shape.

The inside of of the heart has to contain the words "Love" at least 20 times

Rules

The program must write the art to the console.
Shortest code (in bytes, any language) wins.

The winner will be chosen on February 14th on Valentines Day

In order to be a fair code-golf I think you should give a more restrictive definition of the output. — Howard, Jan 22, 2014 at 18:16
I'm waiting for someone to submit a biologically accurate looking heart. Whoever does that immediately gets a +1 from me. — Joe, Jan 23, 2014 at 16:05

VisioN · Accepted Answer · 2014-01-22 19:05:59Z

52

JavaScript [160 bytes]

The following code seems to be 160 bytes unformatted.

   ('l2v2l6v2'+  'e1l1v3l2'+
 'v3e1v7e1v7e1v7e1l2v6e1l4v5'+
'e1l6v4e1l8v3e1l7l3v2e1l9l3v1')
 .replace(/[lve]\d/g,function
   (c){return Array(-~c[1]).
      join({l:' ',v:'Love'
         ,e:'\n'}[c[0
             ]])})

_{Simply run this in the browser console (e.g. in Firebug or Chrome Dev Tools).}

answered Jan 22, 2014 at 19:05

VisioN

4,4802 gold badges19 silver badges27 bronze badges

2

\$\begingroup\$ Changing /[lve]\d/ to /../ and using array ['','Love','\n'] instead of object will save another 10 bytes leading to 150 bytes in total, but the source heart won't be that well shaped anymore :) \$\endgroup\$
– VisioN
Jan 23, 2014 at 11:57
3

\$\begingroup\$ !!!Awesome job!!! \$\endgroup\$
– SpYk3HH
Jan 23, 2014 at 15:04
1

\$\begingroup\$ Using fat arrow function will save a lot of bytes. Replace function(c){return by c=> and remove }. You should post a shorter version! \$\endgroup\$
– Florent
Jan 23, 2014 at 15:19
2

\$\begingroup\$ No. EcmaScript 6. \$\endgroup\$
– Florent
Jan 23, 2014 at 15:21
1

\$\begingroup\$ @Florent Ah! As far as I know ECMAScript 6 is still experimental and unfortunately it is still very hard to test how it works. Lets assume my code is ECMAScript 5 compatible :) But thank you for pointing out! I hope soon JavaScript will compete with Perl and Python in golfing matters and everyone will be able to try that out. \$\endgroup\$
– VisioN
Jan 23, 2014 at 15:27

| Show 4 more comments

Ben Reich · Accepted Answer · 2014-01-24 19:33:12Z

GolfScript: 62 57 54 characters

4 1.5\.5,+{.5\-\2*\0.}/]4/{[32'LOVE']2*]zip{(*}%''+}%~

Output:

    LOVE    LOVE
  LOVELOVELOVELOVE
LOVELOVELOVELOVELOVE
  LOVELOVELOVELOVE
    LOVELOVELOVE
      LOVELOVE
        LOVE

Or, for some added love, and the obligatory abuse of whitespace insignificance (for 84 characters):

    5 1       .8\
  .)...5   ,{.5\-\3
 *\0.}/]4 /{[32[9829
  :x.'LOVE'\]''+]2
    *[@;]zip{(*}%
     ''+}%~' '15
        *x[]+
          +

Output:

     ♥LOVE♥        ♥LOVE♥
  ♥LOVE♥♥LOVE♥  ♥LOVE♥♥LOVE♥
♥LOVE♥♥LOVE♥♥LOVE♥♥LOVE♥♥LOVE♥
   ♥LOVE♥♥LOVE♥♥LOVE♥♥LOVE♥
      ♥LOVE♥♥LOVE♥♥LOVE♥
         ♥LOVE♥♥LOVE♥
            ♥LOVE♥
               ♥

Community · Accepted Answer · 2020-06-17 09:04:33Z

16

C - 183 bytes

Not a winner, but a whole lotta love. Can you figure out how it works?

#include <stdio.h>
#define C(a) ((a)*(a)*(a))
int main(){int x,y;for(y=9;y>-6;y--){for(x=-8;x<9;x++)putchar(C(x*x+y*y-25)<25*x*x*y*y*y?"LOVE"[(x+10)%4]:'-');putchar('\n');}return 0;}

Output:

-----------------
--LOVE-----OVEL--
-ELOVEL---LOVELO-
-ELOVELO-ELOVELO-
-ELOVELO-ELOVELO-
-ELOVELOVELOVELO-
--LOVELOVELOVEL--
--LOVELOVELOVEL--
---OVELOVELOVE---
----VELOVELOV----
----VELOVELOV----
------LOVEL------
-------OVE-------
--------V--------
-----------------

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Jan 22, 2014 at 18:26

user15259

6

\$\begingroup\$ Nice job putting V at the bottom. \$\endgroup\$
– luser droog
Jan 22, 2014 at 20:16
1

\$\begingroup\$ Nice use of the heart curve! You can still save a couple of characters and get down to 153 (I also changed the output slightly at the cost of one added byte): ideone.com/ELnkEE \$\endgroup\$
– reima
Jan 23, 2014 at 1:09
\$\begingroup\$ Very cool. I've never been great at REALLY squeezing bytes. You should post it as your own C! The heart curve is public domain :) \$\endgroup\$
– user15259
Jan 23, 2014 at 18:35

Add a comment |

KChaloux · Accepted Answer · 2014-01-23 17:36:50Z

Scala - 273 Characters

Well, I certainly don't expect to win for brevity, but I wanted to see if I could do it in Scala. A smarter golfer could probably shave several bytes off, but here's what I got:

type D=Double;def w(x:D,y:D,a:D)={val(i,j)=(x-a,y-8);Math.sqrt(i*i+j*j)< 8};val l:Stream[Char]="love".toStream#:::l;val c=l.toIterator;def p(b:Boolean)=print(if(b)c.next else' ');for(y<-0 to 24){for(x<-0 to 32){if(y>7)p((16-x).abs< 24-y)else p(w(x,y,8)|w(x,y,24))};println}

Or, if you prefer (still valid code!)

  type D=      Double 
def w(x:D,    y:D,a:D)=
{val(i,j)=   (x-a,y -8);
Math.sqrt(i* i+j*j)< 8};
val l : Stream [Char] =
"love".toStream#:::l;val
 c= l .toIterator;def p
  (b:Boolean) =print(if
   (b)c.next else' ');
    for (y <-0 to 24) 
     { for (x<- 0 to
      32){if(y >7)
        p((16-x).
          abs < 
          24-y)
         else
        p(w
       (x,
       y,
      8
      )
      |
      w(
       x,
         y,
           24)
              )}
                 println}

Prints out two semicircles and a triangle to the screen, making a pretty decent facsimile of a heart. Picture of heart.scala output

Needs to be run with the scala interpreter (compiling would require adding some extra cruft for object Main { def main(args: Array[String]) = { ... } } and I'm just havin' none of that.

@epidemian I probably could've made it look more like a normal heart, but I misjudged the size of the code and was too lazy. So I made a tail instead. I like to pretend that it's a balloon :p — KChaloux, Feb 14, 2014 at 18:05

ProgramFOX · Accepted Answer · 2014-01-22 18:50:08Z

14

Python, 210 characters

Of course, this won't win because it is a code golf, but I wanted to be creative and I have not used the word Love in my source code:

import gzip
print(gzip.decompress(b'\x1f\x8b\x08\x00\x95\x10\xe0R\x02\xffSPP\xf0\xc9/KU\x80\x03\x10\x8f\x0bB\xa1c.l\x82dJ\xe0\xb0\x01\xe6\x02\x0cATa.T\xf7\x02\x00\xd9\x91g\x05\xc5\x00\x00\x00').decode('ascii'))

This is the output:

   Love          Love
  LoveLoveLoveLoveLove
LoveLoveLoveLoveLoveLove
LoveLoveLoveLoveLoveLove
LoveLoveLoveLoveLoveLove
  LoveLoveLoveLoveLove
    LoveLoveLoveLove
      LoveLoveLove
          Love

answered Jan 22, 2014 at 18:50

ProgramFOX

8,3717 gold badges44 silver badges70 bronze badges

\$\begingroup\$ I like your approach ^_^ \$\endgroup\$
– Navin
Jan 29, 2014 at 1:52
2

\$\begingroup\$ Using gzip is not really creative... \$\endgroup\$
– Alexia Luna
Feb 13, 2015 at 18:38

Add a comment |

mbomb007 · Accepted Answer · 2016-06-17 20:09:40Z

12

Python 2, 117

prints exactly 20 loves horizontally.

x="love";print"   x    x\nx xx x\nx   x   x".replace("x",x)
for i in range(5):print" "*i+x+" "*(9-i*2),x
print" "*6,x

output:

   love    love
love lovelove love
love   love   love
love          love
 love        love
  love      love
   love    love
    love  love
       love

edited Jun 17, 2016 at 20:09

mbomb007

23.4k7 gold badges62 silver badges134 bronze badges

answered Jan 22, 2014 at 19:12

Wasi

1,7702 gold badges15 silver badges24 bronze badges

\$\begingroup\$ Spare some characters by: use a single letter placeholder in the 2nd line's string then replace() them; in the 3rd line's print change one + to , and 10 with 9; in the last line use variable x's value. pastebin.com/i1TSEZfE \$\endgroup\$
– manatwork
Jan 22, 2014 at 19:28
\$\begingroup\$ @manatwork Thank you. Edited the body now down to 121 chars :-) \$\endgroup\$
– Wasi
Jan 22, 2014 at 19:36
\$\begingroup\$ Are you counting the three vertical loves on the right side that you got by staggering the horizontal loves? \$\endgroup\$
– Joshua Taylor
Jan 29, 2014 at 20:42
\$\begingroup\$ @JoshuaTaylor Thanks, I didn't notice those vertical loves. Including those the love count will be 23 :D \$\endgroup\$
– Wasi
Jan 30, 2014 at 10:30

Add a comment |

Community · Accepted Answer · 2017-04-13 12:39:16Z

Perl - 36 bytes

  open    0;s
/\S.?/Lo.ve
  /ge,print
    , , for
        <0>

Output:

  LoveLove    LoveLove
LoveLoveLoveLoveLoveLove
  LoveLoveLoveLoveLove
    LoveLoveLoveLove
        LoveLove

This is a bit of a cheat; it will print Love once for every two non-white space characters in the source code. With the required whitespace to make the heart shape, the code is 61 bytes in length: flattened it is only 36 bytes:

open 0;s/\S.?/Lo.ve/ge,print,,for<0>

Perl - 60 bytes

print$"x(15&ord),Love,$/x/\D/for'3h112a05e0n1l2j4f6b9'=~/./g

Outputs the following:

   Love        Love
 Love Love  Love Love
Love     Love     Love
Love              Love
 Love            Love
  Love          Love
    Love      Love
      Love  Love
         Love

Exactly 20 Love.

Brief Explaination
by request

for'3h112a05e0n1l2j4f6b9'=~/./g
This modifies the print statement, and iterates over each character. The regex /./ obviously matches a single character, and in a list context /./g will return a list of all characters in the string. A more common, but slightly longer way to write this would be for split//,'3h112a05e0n1l2j4f6b9'.
print$"x(15&ord),Love,$/x/\D/
The special variable $" defaults to a space. The ordinal value of each character mod 16 stores the number spaces needed between each Love via string repetition (x). Finally, if the character is not a digit (/\D/), the value of $/, which defaults to "\n" is tacked on to the end.

your second program throws an error: "syntax error at -e line 1, near "/\D/for3h112a05e0n1l2j4f6b9" (tried to invoke from command line using -e) — Tomas, Jan 31, 2014 at 17:40
From command line, you will need to replace $" with ' ': perl -e "print' 'x(15&ord),Love,$/x/\D/for'3h112a05e0n1l2j4f6b9'=~/./g" — primo, Jan 31, 2014 at 17:46
The 36 byte version doesn't actually print the required output — Tobia, Feb 1, 2014 at 13:20

swish · Accepted Answer · 2014-01-30 12:45:06Z

6

Wolfram Language (Mathematica) - 111

i=0;MatrixForm@Table[If[(x^2+y^2-200)^3+10x^2y^3<0,{"L","O","V","E"}[[i++~Mod~4+1]],""],{y,-20,20},{x,-20,20}]

enter image description here

answered Jan 30, 2014 at 12:45

swish

7,7443 gold badges22 silver badges29 bronze badges

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tigrou · Accepted Answer · 2014-01-29 15:53:50Z

5

Javascript - 147 141 137 133 characters

with(Math){s="";for(k=800;k--;)
x=abs(1.25-k%40/16),y=k/320-1.25,
s+=.75>x+abs(y)|.5>sqrt(x*x-x+y*y-y+.5)
?"Love"[k%4]:39==k%40?"\n":" "}s

Note : I posted another answer, but this one use different approach and heart has a different shape.

How it works :

enter image description here

First, I render a diamond (equation is |x|+|y|) then, I combine two circles on the top. x values are mirrored (so only one circle is needed).

edited Jan 29, 2014 at 15:53

answered Jan 23, 2014 at 18:51

tigrou

2,3671 gold badge13 silver badges12 bronze badges

1

\$\begingroup\$ You could shorten your code by removing the 0 before floating numbers and assigning Math.abs to a variable. \$\endgroup\$
– Florent
Jan 24, 2014 at 9:48
\$\begingroup\$ Also you may want to remove two useless semicolons from the end to save another couple of bytes. \$\endgroup\$
– VisioN
Jan 29, 2014 at 8:11

Add a comment |

Doorknob · Accepted Answer · 2014-01-22 22:13:26Z

4

Ruby, 47, or Golfscript, 41

Boring answer.

puts" Love  Love
"+"LoveLoveLove
"*6+"    Love"

Golfscript version:

" Love  Love
""LoveLoveLove
"6*"    Love"

Output:

 Love  Love
LoveLoveLove
LoveLoveLove
LoveLoveLove
LoveLoveLove
LoveLoveLove
LoveLoveLove
    Love

edited Jan 22, 2014 at 22:13

answered Jan 22, 2014 at 16:51

Doorknob

71.5k20 gold badges142 silver badges383 bronze badges

33

\$\begingroup\$ Lol, what an ugly heart! :D \$\endgroup\$
– Abbas
Jan 22, 2014 at 18:48

Add a comment |

FireFly · Accepted Answer · 2014-01-24 20:15:24Z

4

Sclipting — 28 chars / 56 bytes

겤뙡늆굚넰밌各긂밀❷거雙復냄뭖끐❸갰右거雙復겠⓸걠右復終

Output:

    LOVE    LOVE
  LOVELOVELOVELOVE
LOVELOVELOVELOVELOVE
  LOVELOVELOVELOVE
    LOVELOVELOVE
      LOVELOVE
        LOVE

edited Jan 24, 2014 at 20:15

FireFly

7,27829 silver badges41 bronze badges

answered Jan 23, 2014 at 18:08

Timwi

12.9k3 gold badges45 silver badges66 bronze badges

\$\begingroup\$ (Or in 24 characters: 긢꼙겱딧꽔밂各감啃갰啃긂밀⓶復냄뭖끐⓷復겠⓸復終 — but this uses the 啃 instruction, which I added after this challenge was posted, so it doesn’t count.) \$\endgroup\$
– Timwi
Jan 23, 2014 at 19:28
\$\begingroup\$ This is 84 bytes. \$\endgroup\$
– tobyink
Jan 23, 2014 at 21:08
\$\begingroup\$ No, it’s 56 bytes as UTF-16. \$\endgroup\$
– Timwi
Jan 23, 2014 at 21:13
\$\begingroup\$ @Timwi for me it measures 58 bytes. Odd. \$\endgroup\$
– primo
Jan 28, 2014 at 23:54
\$\begingroup\$ @primo: It’s 56 bytes. If you saved it as “Unicode” in Windows Notepad, you get a 58 byte file that consists of the UTF-16 BOM (2 bytes) plus the 56-byte program. \$\endgroup\$
– Timwi
Jan 30, 2014 at 14:03

| Show 1 more comment

tigrou · Accepted Answer · 2014-01-29 16:11:39Z

4

JavaScript - 136 121 115 113 characters

s="";for(k=800;k--;)
x=1.25-k%40/16,y=k/320-1.25,
s+=Math.pow(x*x+y*y-1,3)<x*x*y*y*y
?"Love"[k%4]:39==k%40?"\n":" ";s

To run : copy paste into browser console (eg : Chrome or Firefox)

edited Jan 29, 2014 at 16:11

answered Jan 23, 2014 at 11:45

tigrou

2,3671 gold badge13 silver badges12 bronze badges

\$\begingroup\$ ["L","o","v","e"] => "Love" will save 11 bytes. \$\endgroup\$
– VisioN
Jan 23, 2014 at 11:49
\$\begingroup\$ Fixed :). Thanks for suggestion. \$\endgroup\$
– tigrou
Jan 23, 2014 at 12:04

Add a comment |

FireFly · Accepted Answer · 2014-01-22 18:32:19Z

3

C, 116 chars

(I don't know if this is heart-shaped enough... fills the inside of three circles to produce the output.)

i = 192, x, y;
main(t) {
  for (; i--; putchar(i % 16? y : 10))
    y = i / 16 - 8,
    x = i % 16 - 8,
    t = x*x + y*y,
    y = " Levo"[ (t < 64 & y < 0 | t < 8*abs(x)) * (i % 4 + 1) ];
}

Output:

 veLov   veLov 
oveLove oveLove
oveLove oveLove
oveLove oveLove
oveLoveLoveLove
oveLoveLoveLove
oveLoveLoveLove
 veLoveLoveLov 
 veLoveLoveLov 
  eLoveLoveLo  
    oveLove

Earlier in the golfing process, before replacing constant expressions (change M to adjust size):

#define M 4

i = 3*M * 4*M, x, y;
main(t) {
  for (; i--; putchar(i % (4*M)? x : '\n')) {
    y = i / (4*M) - 2*M, x = i % (4*M) - 2*M,
    t = x*x + y*y, x = " Levo"[ (t < 4*M*M & y < 0 | t < abs(2*M*x)) * (1 + i % 4) ];
  }
}

I also felt compelled to do this. :P

#define F for
#define M main

 /*##     ####
####*/i  =192,x
,y;M(t) {F(;i--
;putchar(i %16?
y:10))y=i/16-8,
x=i%16-8,t=x*x+
y*y,y=" Levo"[(
 t<64&y<0|t<8*
  abs(x))*(i%
    4+1)];}

edited Jan 22, 2014 at 18:32

answered Jan 22, 2014 at 18:02

FireFly

7,27829 silver badges41 bronze badges

\$\begingroup\$ What kind of mystic options/compiler should you use to compile it ? All variables in C are typed en.wikibooks.org/wiki/C_Programming/Variables \$\endgroup\$
– Micka
Jan 24, 2014 at 19:07
1

\$\begingroup\$ @Micka global variables are implicitly declared as int, a legacy feature borrowed from pre-ANSI-C. It compiles just fine for me with clang foo.c or gcc -std=c99 foo.c (though, with plenty of warnings). Do you get any errors? I don't know C well enough to gurantee that I don't depend on undefined behaviour, but I believe I don't do that. \$\endgroup\$
– FireFly
Jan 24, 2014 at 19:30
1

\$\begingroup\$ Hrm, apparently it's not sanctioned by any of the standards--I thought it was legal in C90 at least, but alas, it isn't. So it's just a legacy thing left from pre-ANSI-C that most compilers support anyway (see [this footnote](en.wikipedia.org/wiki/… on wikipedia e.g.). \$\endgroup\$
– FireFly
Jan 24, 2014 at 19:53

Add a comment |

Siva · Accepted Answer · 2014-01-23 14:23:11Z

Ruby - 113 Characters

l=->a,b=28,c=1{puts (("Love"*a).center(b))*c};l.call(2,14,2);l.call(3,14,2);[7,7,7,6,5,4,3,2,1].map{|x|l.call(x)}

Output:

1.9.3p448 :811 > l=->a,b=28,c=1{puts (("Love"*a).center(b))*c};l.call(2,14,2);l.call(3,14,2);[7,7,7,6,5,4,3,2,1].map{|x|l.call(x)}
   LoveLove      LoveLove   
 LoveLoveLove  LoveLoveLove 
LoveLoveLoveLoveLoveLoveLove
LoveLoveLoveLoveLoveLoveLove
LoveLoveLoveLoveLoveLoveLove
  LoveLoveLoveLoveLoveLove  
    LoveLoveLoveLoveLove    
      LoveLoveLoveLove      
        LoveLoveLove        
          LoveLove          
            Love

To be more clear

enter image description here

tobyink · Accepted Answer · 2014-01-23 16:10:00Z

Perl - 159 characters

Not massively golfed...

printf"%-14s%14s\n",$_,~~reverse for map{($.,$i,$c)=split',';($"x$i).($.x$c)}qw(L,5,3 o,3,8 v,1,11 e,0,13 L,1,13 o,3,11 v,5,9 e,7,7 L,8,6 o,10,4 v,12,2 e,13,1)

Here's the same with added whitespace for slightly better readability...

printf "%-14s%14s\n", $_, ~~reverse
   for map {
      ($.,$i,$c) = split',';
      ($"x$i).($.x$c)
   } qw(
      L,5,3
      o,3,8
      v,1,11
      e,0,13
      L,1,13
      o,3,11
      v,5,9
      e,7,7
      L,8,6
      o,10,4
      v,12,2
      e,13,1
   )

Output is...

     LLL            LLL     
   oooooooo      oooooooo   
 vvvvvvvvvvv    vvvvvvvvvvv 
eeeeeeeeeeeee  eeeeeeeeeeeee
 LLLLLLLLLLLLLLLLLLLLLLLLLL 
   oooooooooooooooooooooo   
     vvvvvvvvvvvvvvvvvv     
       eeeeeeeeeeeeee       
        LLLLLLLLLLLL        
          oooooooo          
            vvvv            
             ee

The complete word "Love" is contained within (vertically) 22 times, plus numerous partials.

+1 for creativity. I wouldn't have thought to make it vertical. — Andrew Gies, Jan 23, 2014 at 15:55

Tobia · Accepted Answer · 2014-01-24 20:04:39Z

3

APL, 36 chars / bytes*

7 16⍴∊'  ' 'Love'[20400948744⊤⍨36/2]

Must be evaluated with ⎕IO←0 (the default varies by implementation)

*APL can be written in a single-byte charset if needed (as long as you don't use any other Unicode character) so N chars = N bytes for the purpose of counting.

Output:

Contains exactly 20 "Love"

  Love    Love
LoveLoveLoveLove
LoveLoveLoveLove
LoveLoveLoveLove
  LoveLoveLove
    LoveLove
      Love

answered Jan 24, 2014 at 20:04

Tobia

5,68122 silver badges39 bronze badges

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Community · Accepted Answer · 2020-06-17 09:04:33Z

Extended BrainFuck : 193 (counted without non essential whitespace)

    {h]<[<]<        [<}>>-->
-3>->-3>+9>+9>+>-7>+>->-5>+>->->
-3>+>+>>4->->6+>5+>>4+[-<4+>]<[-
<4+<5+<5+<5+4>&h++]>[-[-[<10+.[-]
    >-[[-]3<[-]]>[<4+3<[[->>
    +<<]<]]]>[[>]>[.>&h]<<++
        >]]>[<<4+[->8+<]
        >....[-]<<+>>]>]

Turns into:

Brainfuck: 264 (counted without non essential whitespace)

    >>-->->>        >->->>>+
    >>>>>>>>        >+>>>>>>
>>>+>->>>>>>>+>->->>>>>+>->->->>>
+>+>>---->->++++++>+++++>>++++[-<
++++>]<[-<++++<+++++<+++++<+++++>
>>>]<[<]<[<++]>[-[-[<++++++++++.[
    -]>-[[-]<<<[-]]>[<++++<<<
    [[->>+<<]<]]]>[[>]>[.>]<[
        <]<[<]<<++>]]>[<<
        ++++[->++++++++<]
            >....[-]<
             <+>>]>]

You run it with any bf interpreter. Ubuntu has bf and beef and both works nicely.

bf heart.bf

The output (344 bytes):

    LOVELOVE        LOVELOVE
    LOVELOVE        LOVELOVE
LOVELOVELOVELOVELOVELOVELOVELOVE
LOVELOVELOVELOVELOVELOVELOVELOVE
LOVELOVELOVELOVELOVELOVELOVELOVE
LOVELOVELOVELOVELOVELOVELOVELOVE
    LOVELOVELOVELOVELOVELOVE
    LOVELOVELOVELOVELOVELOVE
        LOVELOVELOVELOVE
        LOVELOVELOVELOVE
            LOVELOVE
            LOVELOVE

Ungolfed EBF code:

>>--> ; mark

;; ##  ##@   
;;########@
;;########@
;; ######@
;;  ####@
;;   ##@
;; the block below is the art above 
;; where space is replaced with ->
;; # with > and @ with +>
->>>->->>>+>
>>>>>>>>+>
>>>>>>>>+>
->>>>>>>+>
->->>>>>+>
->->->>>+>+>

;; we store the string LOVE after a blank
>
~"LOVE"<[<]<
[<++] ;; add 2 to every cell until mark

;; Variables
:new
:zero
:in
:next

@zero
$in(
  -[ ; 1
     -[ ; 2
        $zero 10+.[-]
        $in-[#[-]$new<[-] @in] ; its second round lf
        $next[#$in++++$new<[[->>+<<]<]]@new     ; 2   
      ]
      >[[>]>[.>]<[<]<[<]<<++>   ]@new
  ]>[@next $zero 4+(-$in 8+) $in.... (-) $new+ $in]@zero
)

RobIII · Accepted Answer · 2014-02-14 16:35:56Z

C# 224

class P{static void Main(){for(int i=0,m=1;i<30;i++)for(int l=0;l<new[]{5,6,7,6,8,10,3,10,4,13,1,13,1,87,1,27,4,23,7,20,11,16,16,11,20,7,24,3,27,1}[i];l++,m++)System.Console.Write((i%2>0?"love"[m%4]:' ')+(m%29>0?"":"\n"));}}

Formatted:

class P
{
    static void Main()
    {
        for (int i = 0, m = 1; i < 30; i++)
            for (int l = 0; l < new[] { 5, 6, 7, 6, 8, 10, 3, 10, 4, 13, 1, 13, 1, 87, 1, 27, 4, 23, 7, 20, 11, 16, 16, 11, 20, 7, 24, 3, 27, 1 }[i]; l++, m++)
                System.Console.Write((i % 2 > 0 ? "love"[m % 4] : ' ') + (m % 29 > 0 ? "" : "\n"));
    }
}

Output:

     velove       elovel
   ovelovelov   velovelove
 lovelovelovel velovelovelov
lovelovelovelovelovelovelovel
ovelovelovelovelovelovelovelo
velovelovelovelovelovelovelov
 lovelovelovelovelovelovelov
   elovelovelovelovelovelo
    ovelovelovelovelovel
      lovelovelovelove
         lovelovelov
           elovelo
             vel
              l

tobyink · Accepted Answer · 2014-01-23 16:38:04Z

Perl - 97 characters

This answer is based on @Wasi's 121 character Python solution.

$.=love;say"   $.    $.$/$. $.$. $.$/$.   $.   $.";say$"x$_,$.,$"x(9-$_*2),$.for 0..4;say$"x 6,$.

You need to run perl with the -M5.010 option to enable 5.10-specific features. This is apparently allowed.

Interesting features:

I use the variable $. to store the word "love". This is because it can be immediately followed by another word if necessary. $.for is unambiguously tokenized as $. followed by for; $_for would not be tokenized as $_ followed by for because $_for is itself a legal variable name.
$", a built-in variable representing that character that arrays will be joined with when interpolated into a string (and defaults to a single space character) is used instead of " " for savings of one character here and there.
Perl's string interpolation beats the python .replace method significantly in code golfing.
Perl's for 0..4 similarly wins over for i in range(5)

aditsu quit because SE is EVIL · Accepted Answer · 2015-02-13 18:25:21Z

1

CJam - 33 bytes

19285703234336595Zb["Love"SS+N]f=

Try it online

Output:

  Love    Love
LoveLoveLoveLove
LoveLoveLoveLove
LoveLoveLoveLove
  LoveLoveLove
    LoveLove
      Love

Explanation:

19285703234336595    number that contains the pattern as base-3 digits
Zb                   converts to base 3 (Z=3)
["Love"SS+N]         creates an array containing "Love", "  " and a newline
f=                   replaces the base-3 digits with the corresponding strings
                     (0 -> "Love", 1 -> "  ", 2 -> newline)

edited Feb 13, 2015 at 18:25

answered Feb 13, 2015 at 15:13

aditsu quit because SE is EVIL

22.8k4 gold badges59 silver badges101 bronze badges

Add a comment |

Community · Accepted Answer · 2020-06-17 09:04:33Z

1

Python, 334 Bytes

x = "love"
print("\t  love\t      love")
print("\t"+str(x*2)+"    "+str(x*2))
print("      "+str(x*6))
print(str(" "*5)+str(x*6)+"lo")
print(str(" "*5)+str(x*6)+"lo")
print("      "+str(x*6))
print("\t"+str(x*5))
print("\t"+str(" "*2)+str(x*4)+"l")
print("\t"+str(" "*4)+str(x*3)+"l")
print("\t"+str(" "*7)+str(x*2))
print("\t"+str(" "*10)+"v")

output:

enter image description here

edited Jun 17, 2020 at 9:04

CommunityBot

1

answered Feb 12, 2015 at 23:00

Yanti

192 bronze badges

1

\$\begingroup\$ Welcome to PPCG. This is code golf, so please include the number of bytes of your code in the answer. Please also state what language this is. \$\endgroup\$
– Martin Ender
Feb 12, 2015 at 23:24
\$\begingroup\$ @MartinBüttner what language do you meant? and this is 334 bytes \$\endgroup\$
– Yanti
Feb 13, 2015 at 10:49
1

\$\begingroup\$ The programming language you've written this code in. \$\endgroup\$
– Martin Ender
Feb 13, 2015 at 10:50
\$\begingroup\$ I know ! This is Python ! Oh and you can remove the str call with string repetions, because * has a higher precedence than +. \$\endgroup\$
– TuxCrafting
Jun 17, 2016 at 19:04
\$\begingroup\$ Actually, this code is 682 bytes long. \$\endgroup\$
– TuxCrafting
Jun 17, 2016 at 20:32

Add a comment |

Newbrict · Accepted Answer · 2015-02-13 17:02:13Z

0

Bash, 170 bytes

totally a copy of programFOX's :)

echo '\x1f\x8b\x08\x00\x95\x10\xe0R\x02\xffSPP\xf0\xc9/KU\x80\x03\x10\x8f\x0bB\xa1c.l\x82dJ\xe0\xb0\x01\xe6\x02\x0cATa.T\xf7\x02\x00\xd9\x91g\x05\xc5\x00\x00\x00'|gunzip

answered Feb 13, 2015 at 17:02

Newbrict

9615 silver badges8 bronze badges

Add a comment |

Venom37222 · Accepted Answer · 2021-01-14 05:34:51Z

0

print('\n'.join([''.join([(' Your text here'[(x-y) % len(' Enter same text here')] if ((x0.05)**2+(y0.1)**2-1)**3-(x*0.05)2(y0.1)**3 <= 0 else ' ') for x in range(-30, 30)]) for y in range(30, -30, -1)])) enter image description here

answered Jan 14, 2021 at 5:34

Venom37222

1

\$\begingroup\$ Welcome to the site. Is this python? Could you use proper formatting and say a little bit about your answer? You can get the formatting a couple of ways but you should be able to highlight your code and select a button in the ui to make it format as code. \$\endgroup\$
– Wheat Wizard ♦
Jan 14, 2021 at 6:55

Add a comment |

Stack Exchange Network

Draw the Heart Shape [closed]

Challenge

Rules

23 Answers 23

JavaScript [160 bytes]

GolfScript: 62 57 54 characters

C - 183 bytes

Scala - 273 Characters

Python, 210 characters

Python 2, 117

Perl - 36 bytes

Perl - 60 bytes

Wolfram Language (Mathematica) - 111

Javascript - 147 141 137 133 characters

Ruby, 47, or Golfscript, 41

Sclipting — 28 chars / 56 bytes

JavaScript - 136 121 115 113 characters

C, 116 chars

Ruby - 113 Characters

APL, 36 chars / bytes*

Extended BrainFuck : 193 (counted without non essential whitespace)

Brainfuck: 264 (counted without non essential whitespace)

C# 224

CJam - 33 bytes

Python, 334 Bytes

Not the answer you're looking for? Browse other questions tagged
code-golf
ascii-art
or ask your own question.

Linked

Hot Network Questions

Draw the Heart Shape [closed]

Challenge

Rules

23 Answers 23

JavaScript [160 bytes]

GolfScript: 62 57 54 characters

C - 183 bytes

Scala - 273 Characters

Python, 210 characters

Python 2, 117

Perl - 36 bytes

Perl - 60 bytes

Wolfram Language (Mathematica) - 111

Javascript - 147 141 137 133 characters

Ruby, 47, or Golfscript, 41

Sclipting — 28 chars / 56 bytes

JavaScript - 136 121 115 113 characters

C, 116 chars

Ruby - 113 Characters

APL, 36 chars / bytes*

Extended BrainFuck : 193 (counted without non essential whitespace)

Brainfuck: 264 (counted without non essential whitespace)

C# 224

CJam - 33 bytes

Python, 334 Bytes

Not the answer you're looking for? Browse other questions tagged code-golfascii-art or ask your own question.

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Not the answer you're looking for? Browse other questions tagged
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or ask your own question.