# Integer Lists of Noah

## Introduction:

I think we've all heard of it, but here a very brief summary: Noah gathered two of every species of animal on the planet, male and female, to save in his Ark during a great flood. The actual quote from the Bible is:

Genesis 7:2-3
You must take with you seven of every kind of clean animal, the male and its mate, two of every kind of unclean animal, the male and its mate, and also seven of every kind of bird in the sky, male and female, to preserve their offspring on the face of the earth.
source

But for the sake of this challenge we will ignore the clean/unclean part and the part where he took seven of each animal. This challenge is only about this part:

two of every kind of unclean animal, the male and its mate

## Challenge:

Input:

You are given a list of positive integers (in random order).

Output:

Two distinct values indicating whether it's a 'List of Noah' or not. This doesn't necessary have to be a truthy/falsey value, so could also be 0/1 in Java/C#, or 'A'/'B' in any language, to give some examples.

When is a list a 'List of Noah'? When there are exactly two of every integer in the list.

## Challenge rules:

• I/O is flexible. Input can be a list/array/stream of integers/floats/strings, or read one by one from STDIN. Output can be any two distinct values, returned from a function or output to STDOUT / a file.
• The integers in the input-list are in random order, and are guaranteed to be positive within the range $$\1\leq n\leq100000\$$.
• The input-list is guaranteed to be non-empty.
• Having an integer a multiple of two times present above 2 (i.e. 4, 6, 8, etc.) will be falsey. I.e. [6,4,4,6,4,7,4,7] is falsey, although you could still create equal pairs like this: [[4,4],[4,4],[6,6],[7,7]].

## General rules:

• This is , so shortest answer in bytes wins.
Don't let code-golf languages discourage you from posting answers with non-codegolfing languages. Try to come up with an as short as possible answer for 'any' programming language.
• Standard rules apply for your answer with default I/O rules, so you are allowed to use STDIN/STDOUT, functions/method with the proper parameters and return-type, full programs. Your call.
• Default Loopholes are forbidden.

## Test cases:

Truthy:
[7,13,9,2,10,2,4,10,7,13,4,9]
[1,2,3,1,2,3]
[10,100,1000,1,100,10,1000,1]
[123,123]
[8,22,57189,492,22,57188,8,492,57188,57189,1,1]

Falsey:
[6,4,4,6,4,7,4,7]
[2,2,2,2,2,2]
[5,1,4,5,1,1,4]
[77,31,5,31,80,77,5,8,8]
[1,2,3,2,1]
[44,4,4]
[500,30,1]
[1,2,1,1]
[2,4,6,4,4,4]
[2,23,34,4]
[2,23,3,3,34,4]

• And in Quran also; Surah Al-Mumenoon, Verse 27: So We inspired him (with this message): "Construct the Ark within Our sight and under Our guidance: then when comes Our Command, and the fountains of the earth gush forth, take thou on board pairs of every species, male and female, and thy family- except those of them against whom the Word has already gone forth: And address Me not in favour of the wrong-doers; for they shall be drowned (in the Flood). (Yusuf Ali) Jul 8, 2019 at 10:12

# Python 3, 31 bytes

lambda l:{*map(l.count,l)}=={2}


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# Python 2, 33 bytes

lambda l:set(map(l.count,l))=={2}


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• Cool, didn't know the splat operator worked inside set literals, if I'm interpreting this correctly. Jul 11, 2019 at 0:18

# Python 3.8 (pre-release), 62 bytes (non-competing)

lambda x:{*[y.count(C)for C	in	(y:=x)]}!={*[2.]}##!2bcdfilmrtu


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Just for fun, a solution that is itself a "List of Noah".

• While fun, this breaks the rules by not being a serious contender.
Jul 8, 2019 at 9:32
• @Adám For code golf, e.g., this is limited to answers that do not even attempt to golf the code. Answers that are simply poorly golfed are not invalid. This answer is definitely well golfed and also introduces additional restriction of being list-of-Noah-truthy, which makes it even stronger contender than other solutions. So this rule does not apply here. Jul 8, 2019 at 10:10
• @DaniilTutubalin No, removing comments is an obvious way to shorten code, so it isn't well-golfed. And one cannot just make up restricted-source requirements on a pure code-golf challenge and claim superiority based on that. If the author of this answer wants to do so, they may ask the challenge author to (or for permission to) post such a challenge.
Jul 8, 2019 at 10:13
• I think the best way to satisfy everybody: put 2 solutions in one answer, one is competing and follows specs, another is with extra restriction followed. Jul 8, 2019 at 11:46
• @Adám IMO, having a self-imposed restricted-source requirement is more akin to using a different language. There is a serious attempt to golf here, but he's not golfing Python 3.8 per se, but rather a subset of it governed by the restricted source. I see nothing wrong with this answer. Jul 8, 2019 at 20:46

# 05AB1E, 4 bytes

¢<PΘ


Try it online! or as a Test Suite

Explanation

¢      # count all occurrences of each element in the input list
<     # decrement each
P    # product
Θ   # is equal to 1

• Ah, I had prepared ¢2QP, but using Θ is also a nice alternative. :) Jul 8, 2019 at 9:42
• Thought I had a 3 with {ιË, but of course that fails when integers occur 4 times. Jul 8, 2019 at 10:21

# Brachylog, 4 bytes

ọtᵛ2


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### Explanation

ọ           Get the list of occurences of elements in the input: [[x,2], [y,2], …]
ᵛ         Verify that for each of those pairs…
t          …the tail (i.e. the number of occurences)
2        …is 2


# R, 20 bytes

-6 bytes thanks to digEmAll by changing the input method

any(table(scan())-2)


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Outputs FALSE if it is a list of Noah, and TRUE otherwise. Works for any input type, not only integers.

Computes the count of each value in the list, and checks whether any of the counts are different from 2.

• You could take input from stdin saving 6 bytes : Try it online! Jul 8, 2019 at 11:40
• @digEmAll Thanks; I misread the challenge rules and thought this was not allowed. Jul 8, 2019 at 12:39

# APL (Dyalog Extended), 5 bytesSBCS

2¨≡⍧⍨


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Is it true that…

2¨ two for each element

≡ is identical to

⍧⍨ the count-in selfie (count of own elements in self)

?

# C# (Visual C# Interactive Compiler), 39, 32 bytes

l=>l.All(x=>l.Count(y=>y==x)==2)


Thanks to @Expired_Data

Try it online!

• 32 bytes Jul 8, 2019 at 9:41

f x=and[sum[1|b<-x,b==a]==2|a<-x]


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For each element of the input we ensure it appears twice in the input list.

sum[1|b<-x,b==a] is just a golfier version of length(filter(==a)x).

# Perl 6, 18 bytes

{so.Bag{*}.all==2}


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• .Bag converts the input list to a Bag--a set with multiplicity.
• {*} extracts all of the multiplicities.
• .all creates an and-junction of the multiplicities.
• == 2 results in another and-junction of Booleans, each true if the multiplicity is 2.
• so collapses the junction to a single Boolean.

# J, 10 bytes

[:*/2=#/.~


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• also 10 bytes: [:*/2=1#.= I really want to remove that cap but can’t figure out how.
– cole
Jul 8, 2019 at 22:57
• @cole when I tried this, I got your solution. If you really wanted to remove the cap you could do 2*/@:=1#.=, also 10 bytes Jul 9, 2019 at 6:08
• @cole Nice alternative! Jul 9, 2019 at 6:24
• @ConorO'Brien Yes, @: comes handy here too. Jul 9, 2019 at 6:24
• @GalenIvanov gotta love monadic =, so strangely useful in niche golfing scenarios
– cole
Jul 9, 2019 at 6:34

# APL (Dyalog Unicode), 8 bytesSBCS

Anonymous tacit prefix function. Returns 0/1.

∧/2=⊢∘≢⌸


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⌸ for each value as left argument and indices of occurrences of that value as right argument, call:

≢ tally the right argument (the occurrences)
∘ then
⊢ return that, ignoring the left argument

2= Boolean list indicating which tallies are 2

∧/ AND-reduction (i.e. are they all true?)

# MS SQL Server 2017, 152150 146 bytes

CREATE FUNCTION f(@ NVARCHAR(MAX))RETURNS
TABLE RETURN SELECT IIF(2=ALL(SELECT
COUNT(*)FROM STRING_SPLIT(@,',')GROUP BY
PARSE(value AS INT)),1,0)r


CREATE FUNCTION f(@ NVARCHAR(MAX)) RETURNS TABLE RETURN
SELECT IIF(2 = ALL(SELECT COUNT(*)
FROM STRING_SPLIT(@, ',')
GROUP BY PARSE(value AS INT)), 1, 0) AS r


Try it on SQL Fiddle!

-2 bytes thanks to Kevin Cruijssen

• Since you don't use the alias, can't the c be removed after the COUNT(*)? Jul 8, 2019 at 11:09
• @KevinCruijssen, you are right, thank you. Jul 8, 2019 at 11:29

import Data.List
all((2==).length).group.sort


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Thanks to @KevinCruijssen for 12 bytes, and @nimi for another 4.

First Haskell answer, but it was surprisingly easy to do. Can probably be golfed a lot. Case in point...

• I don't know Haskell, but I'm pretty sure all(True==).map(2==) can be all(2==). :) Jul 8, 2019 at 13:45
• ... and move length to all: all((2==).length).group.sort. No need to give the function a name, i.e. drop the f=.
– nimi
Jul 8, 2019 at 13:47
• Indeed, I overlooked the all(2==) when I was testing in GHCi. Thanks Kevin and Nimi, I'll update the answer. Jul 8, 2019 at 13:49
• ... oh and for future use: all(True==) is and.
– nimi
Jul 8, 2019 at 13:49

# JavaScript (ES6), 37 bytes

Returns false for Noah or true for non-Noah.

a=>a.some(v=>a.map(x=>t-=v==x,t=2)|t)


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### Commented

a =>               // a[] = input
a.some(v =>      // for each value v in a[]:
a.map(x =>     //   for each value x in a[]:
t -= v == x, //     decrement t if v is equal to x
//     (i.e. if v appears exactly twice, t is decremented twice)
)              //   end of map()
| t            //   yield t, which is supposed to be equal to 0
)                // end of some()


## TI-Basic, 47 Bytes

Input(L1
SortA(L1
not(remainder(dim(L1,2)) and prod(not(△List(L1))=seq(remainder(I,2),I,1,-1+dim(L1


I am a big of fan of TI-Basic. It's not a great language for really any purpose, but I enjoy programming (and golfing) in it.

How does this code work?

First, it sorts the list.

Second, it uses the △List function to generate another list, which is the difference between elements of the sorted list. (For example, △List({1,3,7,8}) would yield {2,4,1}). Applies not to this list, which converts every non-zero element of the list to zero and every zero to one.

Then, the program checks that the resultant list fits the pattern {1, 0, 1, 0, ...}, which will only be true if the original list is a Noah list.

There is also an additional check that the length of the list is even, to catch some edge cases.

Here are some screenshots of test cases:

# Julia, 30 characters 26 bytes

!a=all(x->2==sum(a.==x),a)


Thank you, H.PWiz for this trick!

Try it online!

• You can have !a=all(x->2==sum(a.==x),a) for 26 bytes. NB. that I recommend counting in bytes on this site Aug 6, 2019 at 16:06
• Thank you very much! I didn't know you could (ab)use ! for anonymous functions Aug 6, 2019 at 16:15

# VDM-SL, 64 bytes

f(a)==forall y in set inds a&card{x|x in set inds a&a(x)=a(y)}=2


### Explanation

VDM works predominantly like second order logic statements.

forall y in set inds a                //Bind y to each of the indices of a

{x|x in set inds a&a(x)=a(y)}         //build a set of the indices of a who have the same
//value as the value at y

card {...} = 2                        //and check the cardinality of that set is 2


### Since you can't TIO VDM here's output from a debug session

• I know there probably isn't any online compiler for it, but could you perhaps add some screenshots of (some of) the test cases as verification? :) Jul 8, 2019 at 11:07
• @KevinCruijssen saved some bytes fixing the bug, which probably made the code itself easier to understand. I'll add an explanation too :) Jul 8, 2019 at 11:41

# PowerShell, 6637 26 bytes

-11 bytes thanks to mazzy

!(($args|group|% c*t)-ne2)  Try it online! Groups up $l and grabs all the counts of matching values. It then filters out all counts of 2 from this list. If the list is empty, it's a Noah number; otherwise, it'll be populated still with non-2 counts. Not-ing the list will yield True if it's empty and False if it's populated

• Fails if the values balance each other out.. i.e [1,2,1,1] so the count is 4, the count of unique is 2 and hence will resolve as noah despite not being noah. Jul 8, 2019 at 12:42
• @ExpiredData Heck Jul 8, 2019 at 12:43
• I tried this approach in another language before realising it just won't work... Jul 8, 2019 at 12:43
• ¯\_(ツ)_/¯ 26 Jul 8, 2019 at 13:47
• @mazzy Thanks. Forgot all about group being a thing that exists Jul 8, 2019 at 13:54

# Elixir, 52 bytes

fn v->Enum.all?v,fn x->2==Enum.count v,&x==&1end end


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Complete Elixir noob here :-D.

# PHP, 60 bytes

function($a){return!array_diff(array_count_values($a),[2]);}


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PHP has great built-ins for this, though at 20 chars, array_count_values() is not a very golfy one.

• PHP always has great built-ins, with long names, sigh! Aug 6, 2019 at 11:06

## Mathematica, 25 24 bytes

MatchQ[{{_,2}..}]@*Tally


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The Tally function returns a list of the form {{element, count}, ...}, which is then matched against a pattern that checks whether all count are 2.

# Attache, 16 bytes

${All&x!{_~x=2}}  Try it online! ## Explanation ${All&x!{_~x=2}}
\${             }    lambda with input x
All&x!{     }     over each element _ of x:
_~x            check that the number of occurrences of _ in x
=2          is 2


## Alternatives

17 bytes: {All&_!=&2@~&_}

18 bytes: {All[=&2@~&_,_]}

23 bytes: Same@2&'@Sum@Table[=]

25 bytes: Same«2'Sum@Table[=,_]»

25 bytes: Same<~2'Sum@Table[=,_]~>

25 bytes: {Same[2'Sum@Table[=,_]]}

35 bytes: {Commonest@_==Unique@_and _[0]~_=2}

# Julia 1.0, 32 bytes

l->sum(isone,l./l')/length(l)==2


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Divides each element of the input array l by the transpose l' giving a matrix. Summing over this matrix while applying isone to each element gives twice the length of l if each element appears exactly twice.

# K (oK), 9 bytes

Solution:

&/2=#:'.=


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Explanation:

&/2=#:'.= / the solution
= / group
.  / value
#:'   / count (length of) each
2=      / equal to 2?
&/        / take minimum


# Wolfram Language (Mathematica), 17 bytes

2==##&@@Counts@#&


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Counts returns an association of <| (value)->(# occurences), ... |>. Then 2==##& checks if those occurence-counts are all equal to 2.

• 2==##&@@ is brilliant! Aug 6, 2019 at 12:20

# Elm 0.19, 66 bytes

n a=List.all(\x->List.foldl(\y c->if x==y then c+1 else c)0 a==2)a


Verify all test cases here.

For every item, iterate over the list and count how many items it is equal to. Return True if the count is exactly 2 for each item, False otherwise.

# Pyth, 7 bytes

!n#2/LQ


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!n#2/LQQ   Implicit: Q=eval(input())
Trailing Q inferred
L Q   For each element of Q...
/ Q    ... count its occurrences in Q
#        Filter keep those elements...
n 2       ... which are not equal to 2
!          NOT - maps [] to True, others to False
Implicit print

• Another 7-byte solution is !smtt/Q
– RK.
Jul 11, 2019 at 14:11
• @RK Unfortunately.that one fails for input [1,2,2,2,3,4] :(
– Sok
Jul 11, 2019 at 15:27

# Jelly, 5 bytes

ĠẈ=2Ạ


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A monadic link that takes a list of integers and returns 1 if a Noah list and 0 if not.

# MATL, 6 bytes

8#uqqa


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0 for truthy, 1 for falsy. Ports Robin Ryder's answer.

# MATL, 6 bytes

&=s2=A


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1 for truthy, 0 for falsy. Ports Luis Mendo's answer.

# Ruby, 29 bytes

->a{a.all?{|e|a.count(e)==2}}
`

Try it online!