FizzBuzz but time-based

Question

Make a program that outputs the number of seconds from the beginning of today (00:00:00 of the day you run it) to the second you ran it. However, if this number is divisible by three, print Fizz instead. If it is divisible by five, print Buzz instead. If it is divisible by three and five, print FizzBuzz.

Don't pad the number printed with extra zeroes (44 instead of 00044). You don't need to take leap seconds into account (saying for the universe in which people answer this years after I post it). Standard loopholes apply, shortest program wins.

Answer 1

Jelly, 26 bytes

A simple port of Dennis's "1-2-fizz-4-buzz" solution which evaluates the formatted time as seconds first

7ŒTṣ”:Vḅ60µ3,5ḍTị“¡Ṭ4“Ụp»ȯ

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Answer 2

05AB1E, 33 30 bytes

-3 bytes from Grimy

žažbžc)60βÐ3Öi"Fizz"?}5Öi”ÒÖ”,

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Answer 3

Python 2, 73 bytes

import time
a=time.time()%86400//1
print(a%3<1)*"Fizz"+(a%5<1)*"Buzz"or a

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-37 bytes using time.time instead of datetime thanks to negative seven
-4 bytes thanks to ArBo (switched to Python 2)

Answer 4

Batch, 145 bytes

@set s=%time:~,8%
@set/as=((%s::=)*60+%,f=s%%3,b=s%%5,t=f+b
@for %%a in (Fizz.%f% Buzz.%b% FizzBuzz.%t%)do @if %%~xa==.0 set s=%%~na
@echo %s%

Explanation: %time% is (at least on my system) formatted hh:mm:ss.ff so we start by chopping off the fractions of seconds. Then the shortest way to do the base 60 conversion is to replace the :s with operators and evaluate, and the divisibility by 3, 5 and 15 is also calculated. This is then tested and the number of seconds replaced with the appropriate string if necessary before being printed.

Answer 5

MathGolf, 24 bytes

t♪/╔%_╕Σ╠δ╕┌╠δ`+Γ\35α÷ä§

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Explanation

t                          unix timestamp as integer milliseconds
 ♪/                        divide by 1000
   ╔%                      modulo 86400
     _                     duplicate TOS
      ╕Σ╠δ                 Decompress "Σ╠" and capitalize to get "Fizz"
          ╕┌╠δ             Decompress "┌╠" and capitalize to get "Buzz"
              `            duplicate the top two items
               +           pop a, b : push(a+b)
                Γ          wrap last four elements in array
                 \         swap top elements (swaps 2nd copy of time to TOS)
                  35α      push [3, 5]
                     ÷     is divisible
                      ä    convert from binary
                       §   get from array

Answer 6

PowerShell, 117 94 90 71 bytes

^{-23 bytes thanks to mazzy
-4 bytes thanks to AdmBorkBork
-19 bytes thanks to mazzy again}

(([int]$x=date|% tim*|% t*ls*),('Fizz'*!($x%3)+'Buzz'*!($x%5))|sort)[1]

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An even cheaper way to compute the day's seconds. TotalSeconds also returns as a float so that had to be truncated as well. Plugs that value into this Fizzbuzz answer by AdmBorkBork so give him a thumbs-up as well.

Answer 7

Jelly, 45 bytes

%3,5¬ȧ"“Fizz“Buzz”o"““”Fȯ⁸
7ŒTṣ”:V×⁽½c,60,1SÇ

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This is so bad

34 bytes if I steal Dennis's FizzBuzz

Answer 8

Bash, 154

z=$(($(date +%s)-$(date -d "$(date +%F) 0" +%s)))
[[ 0 -eq "($z%3)" ]]&&a=1&&echo -n "fizz"
[[ 0 -eq "($z%5)" ]]&&echo "buzz"||[ $a -eq 1 ]&&echo||echo $z

could probably golf down last two lines...

Answer 9

JavaScript (Node.js), 125 120 bytes

x=Date().match(/\d\d/g).slice(3,6).reduce((a,j,i)=>a+=60**(2-i)*j)
console.log((x%3==0?'Fizz':'')+(x%5==0?'Buzz':'')||x)

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---

First line parses a date string for [hours, minutes, seconds] and adds them together, second line is just FizzBuzz.

Answer 10

Perl 5, 74 bytes

$t+=$_*60**$g++for(gmtime)[0..2];say+(($t%3==0&&Fizz).($t%5==0&&Buzz))||$t

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Answer 11

Bash, 76 bytes

date +'%H 60*%M+60*%S+[p]sc[[]sc[Fizz]n]sa[[]sc[Buzz]n]sbd3%0=ad5%0=blcx'|dc

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Answer 12

APL (Dyalog Unicode), 40 bytes^SBCS

{∨/d←0=4/3 5|⍵:d/'FizzBuzz'⋄⍵}60⊥3↑3↓⎕TS

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⎕TS Time Stamp; e.g. [2019,06,14,07,48,20,317]

3↓ drop three; e.g. [07,48,20,317]

3↑ take three; e.g. [07,48,20]

60⊥ evaluate as base-60 digits; e.g. 28100

{…} apply the following anonymous lambda to that:

 ⍵ the argument; e.g. 28100

 3 5| the division remainder when that is divided by 3 and 5; e.g. [2,0]

 0= Boolean mask where that is equal to 0; e.g. [0,1]

 4/ replicate those numbers for 4 copies of each; e.g. [0,0,0,0,1,1,1,1]

 d← assign that to d

 ∨/…: if any of those are true (OR-reduction); e.g. true:

  d/'FizzBuzz' use d to mask the characters of the string; e.g. "Buzz"

⋄ else:

 ⍵ the argument; e.g. 28100

Answer 13

AutoIt, 90 bytes

$a=(@HOUR*60+@MIN)*60+@SEC
ConsoleWrite($a&(Mod($a,3)=0?"Fizz":"")&(Mod($a,5)=0?"Buzz":""))

It looks really bad without whitespace.

(FYI: AutoIt is a Windows basic-like scripting language)

Answer 14

Pyth, 36 bytes

Js%.dZ84600|+*!%J3"Fizz"*!%J5"Buzz"J

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Loosely based on the Python 2 answer.